How do I dismiss the number pad keyboard? - swift

In Xcode I selected the Number Pad under Keyboard Type for a label. It works fine, but I cannot dismiss the keyboard and it's blocking important content. How do I get the number pad to close?

you can use to dismiss the keyboard
view.endEditing(true)

override func viewDidLoad() {
super.viewDidLoad()
let tap = UITapGestureRecognizer(target: self, action: #selector(UIInputViewController.dismissKb))
view.addGestureRecognizer(tap)
}
#objc func dismissKb() {
view.endEditing(true)
}

Related

UITapGestureRecognizer to hide keyboard taps on UITableViewCell

I have the below script, and when the keyboard is up, if I click around it in this UIController, it will hide the keyboard, but it will also click on the cell. I do not want that to happen.
I know that cancelsTouchesInView will control that feature... and if I set it to true, it wont click on the cell, BUT I can't click on the cell after the keyboard is hidden.
Is there a good solution for this?
extension UIViewController {
func hideKeyboardWhenTappedAround() {
let tap = UITapGestureRecognizer(target: self, action: #selector(UIViewController.dismissKeyboard2))
tap.cancelsTouchesInView = false
view.addGestureRecognizer(tap)
}
#objc func dismissKeyboard2() {
view.endEditing(true)
}
}
Your best bet may be to disable user interaction on your tableView when the keyboard is shown, and then re-enable it when you end editing.
However, you might give this a try and see if it does what you need.
Change your signature for the dismissKeyboard2 func to get a reference to the tap gesture recognizer and remove it when you end editing:
extension UIViewController {
func hideKeyboardWhenTappedAround() {
let tapGesture = UITapGestureRecognizer(target: self, action: #selector(dismissKeyboard2(_:)))
tapGesture.cancelsTouchesInView = true
view.addGestureRecognizer(tapGesture)
}
#objc func dismissKeyboard2(_ g: UITapGestureRecognizer) {
view.endEditing(true)
view.removeGestureRecognizer(g)
}
}

how to add pan gesture on long pressing a button [duplicate]

I want to trigger two action on button click and button long click. I have add a UIbutton in my interface builder. How can i trigger two action using IBAction can somebody tell me how to archive this ?
this is the code i have used for a button click
#IBAction func buttonPressed (sender: UIButton) {
....
}
can i use this method or do i have to use another method for long click ?
If you want to perform any action with single tap you and long press the you can add gestures into button this way:
#IBOutlet weak var btn: UIButton!
override func viewDidLoad() {
let tapGesture = UITapGestureRecognizer(target: self, #selector (tap)) //Tap function will call when user tap on button
let longGesture = UILongPressGestureRecognizer(target: self, #selector(long)) //Long function will call when user long press on button.
tapGesture.numberOfTapsRequired = 1
btn.addGestureRecognizer(tapGesture)
btn.addGestureRecognizer(longGesture)
}
#objc func tap() {
print("Tap happend")
}
#objc func long() {
print("Long press")
}
This way you can add multiple method for single button and you just need Outlet for that button for that..
#IBOutlet weak var countButton: UIButton!
override func viewDidLoad() {
super.viewDidLoad()
addLongPressGesture()
}
#IBAction func countAction(_ sender: UIButton) {
print("Single Tap")
}
#objc func longPress(gesture: UILongPressGestureRecognizer) {
if gesture.state == UIGestureRecognizerState.began {
print("Long Press")
}
}
func addLongPressGesture(){
let longPress = UILongPressGestureRecognizer(target: self, action: #selector(longPress(gesture:)))
longPress.minimumPressDuration = 1.5
self.countButton.addGestureRecognizer(longPress)
}
Why not create a custom UIButton class, create a protocol and let the button send back the info to delegte. Something like this:
//create your button using a factory (it'll be easier of course)
//For example you could have a variable in the custom class to have a unique identifier, or just use the tag property)
func createButtonWithInfo(buttonInfo: [String: Any]) -> CustomUIButton {
let button = UIButton(type: .custom)
button.tapDelegate = self
/*
Add gesture recognizers to the button as well as any other info in the buttonInfo
*/
return button
}
func buttonDelegateReceivedTapGestureRecognizerFrom(button: CustomUIButton){
//Whatever you want to do
}

swift UITapGestureRecognizer not working on view

I had to create a new thread bcoz it's driving me crazy and all the other answers online are exactly the same. I have done this countless of times but I cannot see what I am missing for the life of me. I am using a "test" view controller just to get the tap gesture working but it isn't working at all... I am fairly certain that I am setting this up correctly, as this is how I've always implemented it in the past: (yes, I have checked the box for isUserInteractionEnabled). I am even implementing this on a different viewcontroller this exact way and it is working...
class TestViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
view.addGestureRecognizer(tap)
}
let tap = UITapGestureRecognizer(target: self, action: #selector(wasTapped))
#objc func wasTapped() {
print("tapped")
}
}
I have also tried adding the parameters to wasTapped:
#objc func wasTapped(gestureRecognizer: UITapGestureRecognizer) {
print("tapped")
}
You are saying:
override func viewDidLoad() {
super.viewDidLoad()
view.addGestureRecognizer(tap)
}
let tap = UITapGestureRecognizer(target: self, action: #selector(wasTapped))
The problem is the last line:
let tap = UITapGestureRecognizer(target: self, action: #selector(wasTapped))
You cannot just say let tap like that in the middle of nowhere. You are implicitly making an instance property. But you cannot initialize an instance property with a target of self, because self does not exist at the time an instance property is initialized. (I regard the fact that that code even compiles as a bug, and have reported it as such.)
Move that line to the start of viewDidLoad, like this:
override func viewDidLoad() {
super.viewDidLoad()
let tap = UITapGestureRecognizer(target: self, action: #selector(wasTapped))
view.addGestureRecognizer(tap)
}
Try something like this
override func viewDidLoad() {
super.viewDidLoad()
let tap = UITapGestureRecognizer(target: self, action: #selector(wasTapped(sender:)))
tap.numberOfTapsRequired = 1 // Default value
view.isUserInteractionEnabled = true
view.addGestureRecognizer(tap)
}
#objc func wasTapped(sender: UITapGestureRecognizer) {
print("tapped")
}
You have to enable interaction if you want to use gesture recognizers for standard UIView's
Add view.isUserInteractionEnabled = true in your viewDidLoad.
var tapGesture = UITapGestureRecognizer()
take a view and set IBOutlet like:
#IBOutlet weak var viewTap: UIView!
Write pretty code on viewDidLoad() like:
tapGesture = UITapGestureRecognizer(target: self, action: #selector(self.myviewTapped(_:)))
tapGesture.numberOfTapsRequired = 1
tapGesture.numberOfTouchesRequired = 1
viewTap.addGestureRecognizer(tapGesture)
viewTap.isUserInteractionEnabled = true
this method is calling when tap gesture recognized:
#objc func myviewTapped(_ sender: UITapGestureRecognizer) {
if self.viewTap.backgroundColor == UIColor.yellow {
self.viewTap.backgroundColor = UIColor.green
}else{
self.viewTap.backgroundColor = UIColor.yellow
}
}

numeric keyboard resigns to normal key board in swift

I have a normal set up for a textfield with numberpad and the dismiss keyboard and resignFirstResponder actions in place, but when I tap on the background the numeric keyboard changes to the normal keyboard and then when I tap the background again the keyboard dismisses - STRANGE! How can I dismiss the numeric keyboard with one tap to the background?
self.textField.delegate = self
textField.keyboardType = UIKeyboardType.DecimalPad
#IBAction func tapBackground(sender: AnyObject) {
view.endEditing(true)
}
#IBAction func viewTapped(sender: AnyObject) {
textField.resignFirstResponder()
}
Try following this may help you :)
override func viewDidLoad() {
super.viewDidLoad()
let tap = UITapGestureRecognizer(target: self, action: "handleTapGesture:")
tap.delegate = self
self.view.addGestureRecognizer(tap)
}
// MARK: - UITapGestureRecognizer
func handleTapGesture(gesture : UITapGestureRecognizer) {
self.view.endEditing(true)
}
func gestureRecognizer(gestureRecognizer: UIGestureRecognizer, shouldReceiveTouch touch: UITouch) -> Bool
{
return true
}

How to make keyboard dismiss when I press out of searchbar on Swift?

I try to make my searchbar on swift, but I have a problem to dismiss keyboard on screen when I pressed out of searchbar. When I try with textfield, it works perfectly fine with this code.
override func touchesBegan(touches: NSSet, withEvent event: UIEvent) {
self.view.endEditing(true)
}
It work when i press out of my textfield and then the keyboard is gone. I want to make like that with my searchbar, because when I use searchbar and use the same way like textfield, it doesn't work at all. Any reference or code is very useful for me.
try this :
self.mySearchController.searchBar.endEditing(true)
replace mySearchController with your created controller name..
If you did not create it programmatically but instead you just dragged a search bar from library then IBoutlet your searchable to your class and reference it as:
self.mySearchBar.endEditing(true)
I found it easier and simplier to use Table View for dismissal. (If you're using table view)
Swift 4:
self.tableView.keyboardDismissMode = .onDrag
Tested and working!
func searchBarSearchButtonClicked(searchBar: UISearchBar)
{
searchActive = false;
self.mySearchBar.endEditing(true)
}
Edit for Swift 4.2
func searchBarSearchButtonClicked(_ searchBar: UISearchBar)
{
searchActive = false
self.searchBar.endEditing(true)
}
func searchBarSearchButtonClicked(searchBar: UISearchBar) {
searchActive = false;
searchProject.resignFirstResponder()
}
This method will be invoked when user click search button on keyboard.So here we can dismiss keyboard.I think this is the right method.
Firstly, Apple's UISearchBarDelegate is the correct solution to hide keyboard when users click a search button while UISearchBar's instance is the first responder (learn UIResponder). In short, searchBarSearchButtonClicked(_:) is what you need for this task.
func searchBarSearchButtonClicked(_ searchBar: UISearchBar) {
searchBar.resignFirstResponder() // hides the keyboard.
doThingsForSearching()
}
If it doesn't work, check, does your controller conform to UISearchBarDelegate and secondly, does UISearchBarDelegate know about your class implementation (if you don't quite understand what am I talking about, you should learn delegation pattern starting to read here):
class YourAwesomeViewController: UIViewController, UISearchBarDelegate { // pay attention here
#IBOutlet weak var yourSearchBar: UISearchBar!
override func viewDidLoad() {
super.viewDidLoad()
self.yourSearchBar.delegate = self // and it's important too
}
}
Further, if you need to hide the keyboard touching outside of search bar without touching the search button (the user may change his mind to search something), UITapGestureRecognizer is a simple way too to deal with that.
Ctrl-drag a Tap Gesture Recognizer from the Object Library to your View Controller.
Ctrl-drag the recently added Tap Gesture Recognizer from the document outline in the storyboard to your class implementation as IBAction.
Finally, write a code:
#IBAction func tapToHideKeyboard(_ sender: UITapGestureRecognizer) {
self.yourSearchBar.resignFirstResponder()
}
Also, don't forget to create #IBOutlet for the search bar to have an access inside your class implementation.
Both variants above work well in my project.
Swift 4+:
You can try, creating a tap gesture and add in the self.view
let singleTapGestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(self.singleTap(sender:)))
singleTapGestureRecognizer.numberOfTapsRequired = 1
singleTapGestureRecognizer.isEnabled = true
singleTapGestureRecognizer.cancelsTouchesInView = false
self.view.addGestureRecognizer(singleTapGestureRecognizer)
and in selector func you call self.searchBar.resignFirstResponder
#objc func singleTap(sender: UITapGestureRecognizer) {
self.searchBar.resignFirstResponder()
}
You can use a general UIViewController extension
Just add a new swift file on the project and paste the following code snippet
Code
extension UIViewController {
func hideKeyboardWhenTappedAround() {
let tap: UITapGestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(UIViewController.dismissKeyboard(_:)))
tap.cancelsTouchesInView = false
view.addGestureRecognizer(tap)
}
#objc func dismissKeyboard(_ sender: UITapGestureRecognizer) {
view.endEditing(true)
if let nav = self.navigationController {
nav.view.endEditing(true)
}
}
}
Now call hideKeyboardWhenTappedAround() from viewDidLoad method where you want keyboard hiding feature.
class MaCaveViewController: UIViewController, UISearchBarDelegate {
#IBOutlet weak var searchBar: UISearchBar!
override func viewDidLoad() {
super.viewDidLoad()
searchBar.delegate = self
}
// When button "Search" pressed
func searchBarSearchButtonClicked(_ searchBar: UISearchBar){
print("end searching --> Close Keyboard")
self.searchBar.endEditing(true)
}
}
This works very well for me.
we can do this with following methods
func searchBarTextDidBeginEditing(searchBar: UISearchBar) {
searchBar.showsCancelButton = true;
}
func searchBarTextDidEndEditing(searchBar: UISearchBar) {
searchBar.showsCancelButton = false;
}
This works for me in Swift 4
func searchBarSearchButtonClicked(_ searchBar: UISearchBar){
self.searchBar.endEditing(true)
}