I have the native static lib that has a few .h files as API, the dir structure looks like this
3rdParties -
- MyAPIHeader.h
- my.modulemap
my modulemap file looks like this
module MyAPIHeader {
header "MyAPIHeader.h"
export *
}
and everything works well, up until I need to add another API file to my modulemap structure that does not reside in the same dir.
anotherProjectDir -
- AnotherAPIHeader.h
3rdParties -
- MyAPIHeader.h
- my.modulemap
and my modulemap file looks like this
module MyAPIHeader {
header "MyAPIHeader.h"
export *
}
module AnotherAPIHeader {
header "AnotherAPIHeader.h"
export *
}
and then when I try to use AnotherAPIHeader functions, I got such an error in the modulemap file
Header 'AnotherAPIHeader.h' not found
I tried to set the path to the .h file in the module map as relative (not works) then I tried to set the path to the header file in the target (not works).
To sum up - when the .h file that is included in the module map resides in the same dir as a module map it works, when .h file resides in the other dir there is no way to set relative dir to that .h file.
What am I missing?
I think what you are looking for is an umbrella header. They basically allow you to specify what headers you want in a module. Here is a site explaining them.
Related
Hello i have one more problem with deploying my app by Streamlit. It works localy but when I want to upload it on git hub it doesnt work..Have no idea whats wrong. It seems that there is problem with path to the file:
"File "/app/streamlit/bobrza.py", line 14, in <module>
bobrza_locations = pd.read_csv(location)"
Here is link to my github repo. Will be very very grateful for help. Thank in advance.
https://github.com/Bordonous/streamlit
The problem is you are hard coding the path of the bobrza1.csv and route.csv to the path on your computer so when running the code on a different environment the path in not legal.
The solution is to make location independent from running environment, for this we will use the following:
__file__ variable - the path to the current python module (the .py file).
os.path.dirname() - a function to get directory name from path.
os.path.abspath() - a function to get a normalized absolutized version of path.
os.path.join() - a function to join one or more path components.
Now you need to change your location and location2 variables in the code to the following:
# get the absolute path to the directory contain the .csv file
dir_name = os.path.abspath(os.path.dirname(__file__))
# join the bobrza1.csv to directory to get file path
location = os.path.join(dir_name, 'bobrza1.csv')
# join the route.csv to directory to get file path
location2 = os.path.join(dir_name, 'route.csv')
Resulting in an independent path of the bobrza1.csv and route.csv.
I have a directory structure that looks like this:
Main/Include
Include/header.h
Include/header2.h
Main/Windows
Windows/code
/code/code.css
Windows/bin
/bin/bar.txt
Main/Mac
Mac/code
/code/code.css
Mac/bin
/bin/bar.txt
I want to zip everything up EXCEPT the Mac directory. So essentially I want to have Include and Windows/* in the zip folder like this:
.zip ---
code
code/code.css
bar
bin/bar.txt
Include
Include/header.h
Include/header2.h
My issue is I cannot seem to figure out how to get winzip to zip the include folder w/out include the mac (by doing Main/*)
This is what I am running:
c:\\progra~2\\winzip\\wzzip.exe -rp zip_win.zip Main\Include\\* Main\Windows\\*
Any ideas?
I can't load a file in Play:
val filePath1 = "/views/layouts/mylayout.scala.html"
val filePath2 = "views/layouts/mylayout.scala.html"
Play.getExistingFile(filePath1)
Play.getExistingFile(filePath2)
Play.resourceAsStream(filePath1)
Play.resourceAsStream(filePath2)
None of these works, they all return None.
You are essentially trying to read a source file at runtime. Which is not something you should usually do. If you want to read a file at runtime then I'd recommend putting it somewhere that will end up in the classpath and then use Play.resourceAsStream to read the file. The files in the conf directory and non-compiled files in the app dir should end up in the classpath.
While trying to compile a proto file named UserOptions.proto which has an import named Account.proto using the below command
protoc --proto_path=/home/project_new1/account --java_out=/home/project_new1/source /home/project_new1/settings/Useroptions.proto
I get the following error :
/home/project_new1/settings/UserOptions.proto: File does not reside within any path specified using --proto_path (or -I). You must specify a --proto_path which encompasses this file.
PS: UserOptions.proto present in the directory /home/project_new1/settings
imports Account.proto present in the directory
/home/project_new1/account
Proto descriptor files:
UserOptions.proto
package settings;
import "Account.proto";
option java_outer_classname = "UserOptionsVOProto";
Account.proto
package account;
option java_outer_classname = "AccountVOProto";
message Object
{
optional string userId = 1;
optional string service = 2;
}
As the error message states, the file you pass on the command line needs to be in one of the --proto_paths. In your case, you have only specified one --proto_path of:
/home/project_new1/
But the file you're passing is:
/home/project_new1/settings/UserOptions.proto
Notice that the file is not in the account subdirectory; it's in settings instead.
You have two options:
(Not recommended) Pass a second --proto_path argument to add .../settings to the path.
(Recommended) Use the root of your source tree as the proto path. E.g.:
protoc --proto_path=/home/project_new1/ --java_out=/home/project_new1 /home/project_new1/settings/UserOptions.proto
In this case, to import Account.proto, you'll need to write:
import "account/Account.proto";
For those of us who want this really spelled out, here is an example where I have installed the protoc beta for gRPC using NuGet Packages Google.Protobuf, Grpc.Core and Grpc.Tools. My solution packages are one level above my Grpc directory (i.e. at BruTrader\packages). My .proto files are at BruTrader\Grpc\protos.
1. My .proto file:
syntax = "proto3";
import "timestamp.proto";
import "enums.proto";
package BruTrader.Grpc;
message DividendMessage {
double amount = 1;
google.protobuf.Timestamp dateUnix = 2;
}
2. my GenerateProto.bat file:
..\packages\Google.Protobuf.3.0.0-beta2\tools\protoc.exe -I..\Grpc\protos -I..\packages\Google.Protobuf.3.0.0-beta2\tools\google\protobuf --csharp_out=..\Grpc\Generated --grpc_out=..\Grpc\Generated --plugin=protoc-gen-grpc=..\packages\Grpc.Tools.0.13.0\tools\grpc_csharp_plugin.exe %1
3. my BuildProtos.bat
call GenerateProto ..\Grpc\protos\masterinstrument.proto
call GenerateProto .\protos\instrument.proto
etc.
4. BuildProtos.bat is executed as a Pre-build event on my Grpc project like this:
CD $(ProjectDir)
CALL "$(ProjectDir)BuildProtos.bat"
For my environment, Windows 10 Pro operating system and C++ programming languaje, I used the protoc-3.12.2-win64.zip that you can downloat it from here. You should open a Windows PowerShell inside the protoc-3.12.2-win64\bin path and then you must execute one of the next commands:
.\protoc.exe -I=C:\Users\UserName\Desktop\SRC --cpp_out=C:\Users\UserName\Desktop\DST C:\Users\UserName\Desktop\SRC\addressbook.proto
Or
.\protoc.exe --proto_path=C:\Users\UserName\Desktop\SRC --cpp_out=C:\Users\UserName\Desktop\DST C:\Users\UserName\Desktop\SRC\addressbook.proto
Note:
1- My source folder is in: C:\Users\UserName\Desktop\SRC
2- My destination folder is in: C:\Users\UserName\Desktop\DST
3- My .proto file is in: C:\Users\UserName\Desktop\SRC\addressbook.proto
I get the following error messages:
Warning: include_once(Zend\Db.php) [function.include-once]:
failed to open stream: No such file or directory in
C:\EasyPHP3\www\VPZ\Lib\Zend_1.7.7\Loader.php on line 83
Warning: include_once() [function.include]:
Failed opening 'Zend\Db.php' for inclusion (include_path='VPZ/') in
C:\EasyPHP3\www\VPZ\Lib\Zend_1.7.7\Loader.php on line 83
Warning: require_once(Zend/Exception.php)
[function.require-once]: failed to open stream:
No such file or directory in
C:\EasyPHP3\www\VPZ\Lib\Zend_1.7.7\Loader.php on line 87
Fatal error: require_once() [function.require]:
Failed opening required 'Zend/Exception.php' (include_path='VPZ/') in
C:\EasyPHP3\www\VPZ\Lib\Zend_1.7.7\Loader.php on line 87
i want to include ZendXXX\Db.php
how to change it
create a directory (say 'lib'), and put your Zend directory in it. so your directory structure looks like this:
- application
- lib
|- Zend
- wwwroot
|- index.php
now you should add lib to your include path. edit your index.php file:
$includePath = array();
$includePath[] = '.';
$includePath[] = './../application';
$includePath[] = './../lib';
$includePath[] = get_include_path();
$includePath = implode(PATH_SEPARATOR,$includePath);
set_include_path($includePath);
now you have your lib in your include path. you can include all Zend components like this:
include 'Zend/Loader.php';
require_once 'Zend/Db.php';
the best way is too include Zend_Loader first and then use it to load classes. do this:
require_once 'Zend/Loader.php';
Zend_Loader::loadClass('Zend_Db');
you can also register to autoload classes. just add this line to your code after all those before:
Zend_Loader::registerAutoLoad('Zend_Loader',true);
now you do not need to include files to call classes. just instanciate your classes:
$session = new Zend_Session_Namespace('user');
there is no need to include 'Zend/Session/Namespace.php'.
Use set_include_path(). See PHP.net documentation
Example:
set_include_path(get_include_path() . PATH_SEPARATOR . '/path/to/Zend');
I usually store the framework files under a "library" folder:
application
public_html
library
Zend
Common
etc....
and then in my bootstrap file, or front controller, I add that "library" folder to the include path:
set_include_path(get_include_path() . PATH_SEPARATOR . '../library');
See also:
Choosing Your Application's Directory Layout.
Create the Filesystem Layout.
The reason the other suggestions say anything about doing that, is because it's a bad move - in other words, you're doing it wrong.
You can create a subdirectory and name it Zendxxx, but then you have to add that to your include_path, and change it, whenever you put a newly named version up.
I'd hazard a guess, and say that you don't have a good way to test the website (so you want to lock it to a particular version of ZF), and further, that you aren't using revision control, so you want all the previous versions of code in the site-directory to be able to go back to, if you find a problem when you change the live-running code directly on the server.
project without library And including library from one location
project C:\xampp\htdocs\my\application
library C:\xampp\Zend\library
make changes in index.php
// Ensure library/ is on include_path
set_include_path(implode(PATH_SEPARATOR,
array(realpath(APPLICATION_PATH.'/../../../Zend/library'),get_include_path(),)));