I'm trying to integrate spring-boot-admin with my corporate SSO, does spring-boot-admin support sso login? I cannot find documentation about it.
I got it to work. Steps to implement:
Create controller with an endpoint that the sso provider will call.
In the endpoint, put the logic for sso integration,
On success, redirect to /applications
On failure, throw an exception
#Controller
public class SsoIntegration {
// this does addition authentication stuff, like sets up the
// right authorities...etc
#Autowired
private AuthenticationProvider authenticationProvider;
// my sso provider creates a vanity url that redirects to
// this endpoint and passes 2 request params using POST
#RequestMapping(value={"/sso"}, method = {RequestMethod.POST})
public String ssologin (
#RequestParam(name="param1") String param1,
#RequestParam(name="param2") String param2 )
{
// do your sso integration logic here
// eg...
SsoUtil util = new SsoUtil();
String userInfo = util.decrypt(param1, param2, ...);
...
if (authenticationProvider.authenticate( userInfo )) {
Authentication postAuthentication = ...// populate your successfully authenticated user
// these next lines are the important stuff
// 1. set the postAuthentication into the security context
SecurityContextHolder.getContext().setAuthentication(postAuthentication);
// 2. redirect to the applications page
return "redirect:/applications";
}
// authentication failed, throw an exception...
throw new RuntimeException ("Sso Authentication failed");
}
}
I am writing a REST client in C#.Net using RestSharp. There are two API calls - one is "Auth" call and second is "getKey" call. The "Auth" call throws back a "Auth token"in the response, and I'd like to parse that token from the response, and pass it as an header to the second "getkey" call. Please advise with examples
I have given some sample to achieve your scenario. Please use the below example and do the modification as per your requirement.
RestUtils Class:
Add the Request Header, If your application is expected some additional headers.
class RestUtils
{
private static readonly RestClient _restClient = new RestClient();
public static void SetBaseURL(String host)
{
_restClient.BaseUrl = new Uri(host);
}
public static string GetResponse(String endpoint, String token)
{
var request = new RestRequest(endpoint, Method.GET);
request.AddHeader("Accept", "application/json");
request.AddHeader("Authorization", token);
IRestResponse response = _restClient.Execute(request);
return response.Content;
}
public static string GetToken(String endpoint)
{
var request = new RestRequest(endpoint, Method.GET);
request.AddHeader("Accept", "application/json");
IRestResponse response = _restClient.Execute(request);
return response.Content;
}
}
TestClass:
In your test class you can add the below steps and you can get the result as expected. First two lines will be executed and give the authentication token as output. So, you can use the retrieved token in the subsequent lines for other API. In another way, you can create one property class and set the retrieved token value .So, that you can access the token from various class.
//Specify the Base URI of your Token Specific API
RestUtils.SetBaseURL("https://login.microsoftonline.com/");
//Specify the End Point of your Token Specific API
String token = RestUtils.GetToken("/oauth2/token");
//Specify the Base URI of your actual Test API
RestUtils.SetBaseURL("XXXXXXX");
String response = RestUtils.GetResponse(token);
I am using Angular 5 + spring REST.
I have created rest service, and keeping some data in session.
#RequestMapping(value ="/controls" , method= RequestMethod.GET)
#ResponseBody
public List<InputBase> onLoadResponse(#RequestParam (value = "userId") String inputParam ,HttpServletRequest httpServletReques,HttpServletResponse httpServletResponse, HttpSession session){
super.responseHeader(httpServletReques, httpServletResponse);
session.setAttribute("root", "root");
return controlService.getControl(inputParam, session);
}
Issue is that when I hit this request form Postman i get same session, but from angular if get different session for every request.
This new session is created by browser or angular ? and is it possible to keep same session for each request ?
Adding proxy configuration resolved the issue. Here is the link : Link
I am trying to call a web service from my Angular 2 app.
private baseUrl: string = 'http://localhost:3000/api';
getPatterns(): Observable<Pattern[]> {
const patterns$ = this.http
.get(`${this.baseUrl}/pattern`, {headers: this.getHeaders()})
.map(this.mapPatterns)
.catch(this.handleError);
return patterns$;
}
private getHeaders() {
const headers = new Headers();
headers.append('Accept', 'application/json');
return headers;
}
This gives me a 404 error for URL: http://localhost:3000/api/pattern even though I get a valid response when I open the URL in browser or try to call it from POSTMAN.
Any help pointing out why this doesn't work would be appreciated.
Thanks!
Vetemi's answer solved the first step of this issue for me. I had built my Angular App following along with the Angular Tour Of Heroes tutorial and removing the dependencies on the In Memory web api service resolved the 404 error. After that I was getting a CORS error, specifically the error read:
No 'Access-Control-Allow-Origin' header is present on the requested resource.
My API is a .Net Core 2.0 API, so I needed to enable CORS which I did following the steps at this link
https://learn.microsoft.com/en-us/aspnet/core/security/cors
This is a trimmed down version of my Startup.cs file
public void ConfigureServices(IServiceCollection services)
{
services.AddCors();
services.AddMvc();
}
public void Configure(IApplicationBuilder app, IHostingEnvironment env)
{
app.UseCors(builder => builder.AllowAnyOrigin());
app.UseMvc();
}
In case, you haven't found the problem and for those who have the same problem.
Have you used the in memory database from the tutorial Angular Tour of Heroes? If yes, then this may be the problem. The dependency
"angular-in-memory-web-api": "~0.2.4",
intercepts your http requests. Removing this dependency might help. Solution was found here.
Your header contains nothing, so the response is 404. See the below change
private getHeaders() : Headers {
const headers = new Headers();
headers.append('Accept', 'application/json');
return headers;
}
Reason: Default return type of the methods are void, so when you are returning you need to explicitly have the return type
This is a question about generating CSRF tokens.
Usually I'd like to generate a token based off of a unique piece of data associated with the user's session, and hashed and salted with a secret key.
My question is in regards to generating tokens when there is NO unique user data to use. No sessions are available, cookies are not an option, IP address and things of that nature are not reliable.
Is there any reason why I cannot include the string to hash as part of the request as well?
Example pseudocode to generate the token and embed it:
var $stringToHash = random()
var $csrfToken = hash($stringToHash + $mySecretKey)
click me
Example server-side validation of the CSRF token
var $stringToHash = request.get('key')
var $isValidToken = hash($stringToHash + $mySecrtKey) == request.get('csrfToken')
The string being used in the hash would be different on each request. As long as it was included in each request, the CSRF token validation could proceed. Since it is new on each request and only embedded in the page, outside access to the token would not be available. Security of the token then falls to the $mySecretKey being known only to me.
Is this a naive approach? Am I missing some reason why this cannot work?
Thanks
Is there any reason why I cannot include the string to hash as part of the request as well?
CSRF tokens have two parts. The token embedded in the form, and a corresponding token somewhere else, be it in a cookie, stored in a session or elsewhere. This use of elsewhere stops a page being self contained.
If you include the string to hash in the request, then the request is self contained, so copying the form is all an attacker needs to do, as they have both parts of the token, and thus there is no protection.
Even putting it in the form URL means that it's self contained, the attacker simply copies the form and the submission URL.
Try base64_encode(openssl_random_pseudo_bytes(16)).
https://github.com/codeguy/php-the-right-way/issues/272#issuecomment-18688498 and I used it for my form example in https://gist.github.com/mikaelz/5668195
CSRF token meant to prevent (unintentional) data modifications, which are usually applied with POST requests.
Thus, you must include CSRF token for each request that changes data (either GET or POST request).
My question is in regards to
generating tokens when there is NO
unique user data to use. No sessions
are available, cookies are not an
option, IP address and things of that
nature are not reliable.
Then simply create a unique user id for each visitor.
Include that id in a cookie or in the URLs (if cookies are disabled).
Edit:
Consider the following event:
You have logged-in to your facebook account and then entered to some arbitrary website.
In that website there's a form that you submit, which tells your browser to send a POST request to your facebook account.
That POST request may change your password or add a comment etc, because that the facebook application recognized you as a registered & logged-in user. (unless there's another blocking mechanism, like CAPTCHA )
I think the best idea to make hash based on HMAC, i.e. make hash encrypted by some password this sequence: username+user_id+timestamp. Each request the hash must be different, timestamp must be if you don't want to get simple replay the hash in attack.
You simply just need the same "token" in the URL/form and in the cookie. This means that you could have your page setting the token cookie to whatever it wants to (preferably some random value) by JavaScript and then just pass the very same value in all requests that goes to your server (as a URI ?param or form-field). No need to have your server generating the cookie.
This is safe as long as we trust that the browser doesn't allow pages from a domain to edit/read cookies for other domains, and this is assumed to be quite secure today.
Having your server generating the token will assume that this token can be safely transmitted to your browser without being picked up by any CSRF attempts (why take the risk?). Though you could put more logic into a server generated token, but to prevent CSRF there is no need.
(If I'm wrong here please let me know)
I wanna say your approach works, because CSRF attack is the attacker utilizing victim's browser to forge a logged-in status, why can they do so? because on most server side the session check is based on a SessionID in cookie, and cookie is a piece of data will be automatically attached to a HTTP request sent to server.
Therefore, there are two key factors for defending CSRF
Generate a challenge token, and require client to pass it to server in a non-cookie way, either URL param or POST form is ok.
Keep the token safe as what you did to the SessionID, for instance, using SSL.
I recommend reading CSRF Prevention Cheat Sheet
There are multiple implementation of CSRF token. The key thing is whether this csrf token is generated on the client side or server side. Because the implementation changes drastically for these two scenarios and the entropy of the token as well.
For server side, SecureRandom is the preferred way but in your case you want to generate the CSRF token before any user is identified, window.crypto provides this functionality where you can generate a unguessable enough string to be used for CSRF token.
With the help of CSRF token we can sure incoming request is authenticated (know user not hacker)
Please note i have required below approach but google can't help me even on stackoverflow i did't get mentioned code below but after collection of stackoverflow answer i have made my day. So it's useful for further searching/ specially for beginners
I have described below Spring MVC with Spring Interceptor
Note - I have used google cache to store salt in cache for re verification
below dependency need to add pom.xml
<!-- https://mvnrepository.com/artifact/com.google.guava/guava -->
<dependency>
<groupId>com.google.guava</groupId>
<artifactId>guava</artifactId>
<version>28.0-jre</version>
</dependency>
below HandlerInterceptorAdapter implemention
package com.august.security;
import java.security.SecureRandom;
import java.util.Enumeration;
import java.util.LinkedList;
import java.util.List;
import java.util.concurrent.TimeUnit;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
import org.apache.commons.lang3.RandomStringUtils;
import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.handler.HandlerInterceptorAdapter;
import com.google.common.cache.Cache;
import com.google.common.cache.CacheBuilder;
public class CsrfSecurity extends HandlerInterceptorAdapter {
List<String> urlList= new LinkedList<>();
private static final String CSRF_TAG = "CSRF-CHECK";
#SuppressWarnings("unchecked")
#Override
public boolean preHandle(HttpServletRequest request, HttpServletResponse response, Object handleer)
throws Exception {
System.out.println("Inside Pre Handler");
String reqUrl = request.getRequestURI().toString();
System.out.println("Request URL : " + reqUrl);
String ipAddress = request.getHeader("X-FORWARDED-FOR");
if (ipAddress == null) {
ipAddress = request.getRemoteAddr();
}
//local host url http://localhost:8080/august/
if (request.getRequestURI().contains("/august/")) {
System.out.println("pre handler return true");
//it will return and next executed postHandelr method
//because of on above url my webApplication page working
return true;
}
if (ignoreUrl().contains(request.getRequestURI())) {
System.out.println("inside ignore uri");
return true;
} else {
System.out.println("CSRF Security intercepter preHandle method started.......");
String salt = request.getParameter("csrfPreventionSalt");
HttpSession sessionAttribute = request.getSession();
Cache<String, Boolean> csrfPreventionSalt = (Cache<String, Boolean>) sessionAttribute
.getAttribute("csrfPreventionSalt");
if (csrfPreventionSalt == null) {
System.out.println("Salt not matched session expired..");
parameterValuesPrint(request, "saltCacheNotFound");
response.sendRedirect("error");
return false;
} else if (salt == null) {
parameterValuesPrint(request, "noSaltValue");
System.out.println("Potential CSRF detected !! inform ASAP");
response.sendRedirect("error");
return false;
} else if (csrfPreventionSalt.getIfPresent(salt) == null) {
System.out.println("saltValueMisMatch");
System.out.println("Potential CSRF detected !! inform ASAP");
response.sendRedirect("error");
} else {
request.setAttribute("csrfPreventionSalt", csrfPreventionSalt);
}
return true;
}
}
#SuppressWarnings("unchecked")
#Override
public void postHandle(HttpServletRequest request, HttpServletResponse response, Object handler,
ModelAndView modelAndView) {
System.out.println("Inside post Handler");
System.out.println("CSRF Security key generator method started");
try {
//localhost url http://localhost:8080/august/
//api is my controller path so no need to genrate token for api
if (request.getRequestURI().contains("/august/api/")) {
System.out.println("No need to genrate salt for api");
} else {
HttpSession sessionAttribute = request.getSession();
Cache<String, Boolean> csrfPreventionSaltCache = (Cache<String, Boolean>) sessionAttribute
.getAttribute("csrfPreventionSalt");
System.out.println("csrfPreventionSaltCache ::: " + csrfPreventionSaltCache);
if (csrfPreventionSaltCache == null) {
csrfPreventionSaltCache = CacheBuilder.newBuilder().maximumSize(5000)
.expireAfterWrite(20, TimeUnit.MINUTES).build();
request.getSession().setAttribute("csrfPreventionSaltCache", csrfPreventionSaltCache);
}
String salt = RandomStringUtils.random(20, 0, 0, true, true, null, new SecureRandom());
System.out.println("csrfPreventionSalt genrated ::: " + salt);
csrfPreventionSaltCache.put(salt, Boolean.TRUE);
if (modelAndView != null) {
System.out.println("Model and view not null and salt is added in modelAndView");
modelAndView.addObject("csrfPreventionSalt", salt);
}
}
} catch (Exception ex) {
System.out.println(ex.getMessage());
ex.printStackTrace();
}
}
#Override
public void afterCompletion(HttpServletRequest request, HttpServletResponse response, Object handler, Exception ex)
throws Exception {
System.out.println("afterCompletion : ");
if (ex != null) {
System.out.println("exception : " + ex.getMessage());
ex.printStackTrace();
}
}
private List<String> ignoreUrl() {
if(urlList == null) {
urlList.add("/august/error");
//add here your ignored url.
}
return urlList;
}
private void parameterValuesPrint(HttpServletRequest request, String err) {
StringBuilder reqParamAndValue = new StringBuilder();
Enumeration<?> params = request.getParameterNames();
while (params.hasMoreElements()) {
Object objOri = params.nextElement();
String param = (String) objOri;
String value = request.getParameter(param);
reqParamAndValue = reqParamAndValue.append(param + "=" + value + ",");
}
System.out.println(CSRF_TAG + " " + err + "RequestedURL : " + request.getRequestURL());
}
}
Below is Interceptor registration with spring context
package com.august.configuration;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
import org.springframework.web.servlet.ViewResolver;
import org.springframework.web.servlet.config.annotation.EnableWebMvc;
import org.springframework.web.servlet.config.annotation.InterceptorRegistry;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurerAdapter;
import org.springframework.web.servlet.view.InternalResourceViewResolver;
import com.august.security.CsrfSecurity;
#Configuration
#EnableWebMvc
#ComponentScan(basePackages="com.august")
public class SpringConfiguration extends WebMvcConfigurerAdapter {
#Bean
public ViewResolver viewResolver() {
InternalResourceViewResolver viewResolver = new InternalResourceViewResolver();
//viewResolver.setViewClass(JstlView.class);
viewResolver.setPrefix("/WEB-INF/views/");
viewResolver.setSuffix(".jsp");
return viewResolver;
}
#Bean
public CsrfSecurity csrfSecurity() {
return new CsrfSecurity();
}
#Override
public void addInterceptors(InterceptorRegistry registry) {
registry.addInterceptor(new CsrfSecurity());
}
}
below is my controller
package com.august.v1.appcontroller;
import javax.servlet.http.HttpSession;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.ui.Model;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
#Controller
public class HomeController {
#Autowired
HttpSession httpSession;
#RequestMapping("/")
public String index(Model model) {
httpSession.invalidate();
System.out.println("Home page loaded");
return "index";
}
}
below is my index.jsp jsp page
<%# page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1" isELIgnored="false"%>
//don't forget to add isELIgnored="false" on old(version) jsp page because of i
//have wasted 1 hour for this
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>ADS Home</title>
</head>
<body>
<h1>${csrfPreventionSalt}</h1>
<input type="hidden" name="csrfPreventionSalt" value=${csrfPreventionSalt}>
</body>
</html>
For Understanding about CSRF - CSRF explanation
CSRF utilizes the user's session, so, if you don't have one, there is no CSRF.