Function enum parameter type - swift

Question

I am new on swift. I have 2+ enums and i would like to create enum to object generator function. I couldn't find what type I should use for the Enum parameter in my function.
My enums;
public enum Animal: String, CaseIterable {
case DOG = "dog"
case CAT = "cat"
case BIRD = "bird"
}
public enum Car: String, CaseIterable {
case BMW = "bmw"
case AUDI = "audi"
}
My Function;
func enumToObj(Enum:TYPE?) -> Dictionary <String, String> {
var enumsObject: [String:String] = [:];
for enumData in Enum.allCases {
let value = enumData.rawValue;
enumsObject[value] = value;
}
return enumsObject;
}
//my expectation
enumToObj(Animal) && enumToObj(Car)

Answer 1

You can define a generic function which take as argument a type that is CaseIterable and RawRepresentable:
func enumToObj<T>(_ Enum:T.Type) -> [String: T.RawValue]
where T: CaseIterable & RawRepresentable
{
var enumsObject: [String: T.RawValue] = [:];
for enumData in Enum.allCases {
let value = enumData.rawValue;
enumsObject["\(enumData)"] = value;
}
return enumsObject;
}
print(enumToObj(Animal.self))
// ["CAT": "cat", "DOG": "dog", "BIRD": "bird"]
print(enumToObj(Car.self))
// ["AUDI": "audi", "BMW": "bmw"]
Using reduce(into:_:) this can also be written as
func enumToObj<T>(_ Enum:T.Type) -> [String: T.RawValue]
where T: CaseIterable & RawRepresentable
{
return Enum.allCases.reduce(into: [:]) { (enumsObject, enumData) in
let value = enumData.rawValue;
enumsObject["\(enumData)"] = value;
}
}