How to remove element from a String with Int index - swift

I'm trying to count identical elements in two strings by comparing them in Int range. I solved the issue of subscripting, but I'm now getting an "extra" element. Here's my code:
func getResult(s: String, k: Int, stringGoal: String) -> Int {
var identiticalSymbols = 0
var deletionsLimit = k
var string = s
if string.count <= 19, deletionsLimit <= 9{
for i in 0...string.count-1 {
if string[i] == stringGoal[i] {
identiticalSymbols += i
}
else {
string.remove(at: String.Index(utf16Offset: i, in: string))
deletionsLimit -= 1
}
}
}
return identiticalSymbols
}
}
extension String {
subscript(_ i: Int) -> String {
let idx1 = index(startIndex, offsetBy: i)
return String(self[idx1..<endIndex])
}
subscript (r: Range<Int>) -> String {
let start = index(startIndex, offsetBy: r.lowerBound)
let end = index(startIndex, offsetBy: r.upperBound)
return String(self[start ..< end])
}
}
My input:
let result = getResult(s: "agdd", k: 4, stringGoal: "gdd")
s is initial string, k is deletion limit and goalString is string for comparison.
I'm getting 6 identical symbols instead of 3

I have this code but I'm not using the k, I'm counting the repetitions and remove the repetitions that I already count.
func getRepetitions(firstString: String, comparativeString: String) -> Int {
var repetitions = 0
var comparativeStringName = Array(comparativeString)
for character in firstString {
if comparativeStringName.contains(character),
let index = comparativeStringName.firstIndex(of: character){
comparativeStringName.remove(at: index)
repetitions += 1
}
}
return repetitions
}

It helped me.
func getResult(s: String, k: Int, stringGoal: String) -> Int {
var identiticalSymbols = 0
var deletionsLimit = k
var string = s
if string.count <= 19, deletionsLimit <= 9{
for i in 0...string.count-1 {
if string[i] == stringGoal[i] {
identiticalSymbols += 1
}
else {
string.remove(at: String(string[i]).startIndex)
deletionsLimit -= 1
}
}
}
return identiticalSymbols
}
}
extension String {
var length: Int {
return count
}
subscript (i: Int) -> String {
return self[i ..< i + 1]
}
func substring(fromIndex: Int) -> String {
return self[min(fromIndex, length) ..< length]
}
func substring(toIndex: Int) -> String {
return self[0 ..< max(0, toIndex)]
}
subscript (r: Range<Int>) -> String {
let range = Range(uncheckedBounds: (lower: max(0, min(length, r.lowerBound)),
upper: min(length, max(0, r.upperBound))))
let start = index(startIndex, offsetBy: range.lowerBound)
let end = index(start, offsetBy: range.upperBound - range.lowerBound)
return String(self[start ..< end])
}
}

Related

Type 'MatchedValue' does not conform to protocol 'Decodable'

I have a struct that must conform to Codable protocol.
However, I get the error:
Type 'MatchedValue' does not conform to protocol 'Decodable'**
How can I make String.Index conform to Codable?
Thanks
struct MatchedValue: Codable {
let value: String
let range: Range<String.Index>
}
Try using Int instead of String.Index.
First, extensions to get the position of an element or string as Int and the ability to use integer ranges:
extension StringProtocol {
func distance(of element: Element) -> Int? { firstIndex(of: element)?.distance(in: self) }
func distance<S: StringProtocol>(of string: S) -> Int? { range(of: string)?.lowerBound.distance(in: self) }
func substring(with range: Range<Int>) -> String? {
guard range.lowerBound >= 0 && range.upperBound <= self.count else { return nil }
let lowerBoundStringIndex = self.index(self.startIndex, offsetBy: range.lowerBound)
let upperBoundStringIndex = self.index(lowerBoundStringIndex, offsetBy: range.upperBound - range.lowerBound)
return String(self[lowerBoundStringIndex..<upperBoundStringIndex])
}
subscript(r: Range<Int>) -> String? { substring(with: r) }
func substring(with range: ClosedRange<Int>) -> String? {
guard range.lowerBound >= 0 && range.upperBound < self.count else { return nil }
if range.lowerBound == range.upperBound { return "" }
let lowerBoundStringIndex = self.index(self.startIndex, offsetBy: range.lowerBound)
let upperBoundStringIndex = self.index(lowerBoundStringIndex, offsetBy: range.upperBound + 1 - range.lowerBound)
return String(self[lowerBoundStringIndex..<upperBoundStringIndex])
}
subscript(r: ClosedRange<Int>) -> String? { substring(with: r) }
}
extension Collection {
func distance(to index: Index) -> Int { distance(from: startIndex, to: index) }
}
extension String.Index {
func distance<S: StringProtocol>(in string: S) -> Int { string.distance(to: self) }
}
Now you can use this new implementation:
let letters = "My string"
letters.count // 9
// get range
let lowerBound: Int? = letters.distance(of: "M")
let upperBound: Int? = letters.distance(of: "g")
let intRange: Range<Int> = lowerBound!..<upperBound!
let intClosedRange: ClosedRange<Int> = lowerBound!...upperBound!
// get substring
letters.substring(with: intRange) // "My strin"
letters.substring(with: intClosedRange) // "My string"
// or
letters[intRange] // "My strin"
letters[intClosedRange] // "My string"
I also include a comparison using String.Index and other tests.
// For comparison purposes only
let lowerIndex = letters.firstIndex(of: "M")
let upperIndex = letters.firstIndex(of: "g")
let range: Range<String.Index> = lowerIndex!..<upperIndex!
let closedRange: ClosedRange<String.Index> = lowerIndex!...upperIndex!
letters[range] // "My strin"
letters[closedRange] // "My string"
// Additional implementation tests
letters.substring(with: 3...5) // "str"
letters.substring(with: 3..<5) // "st"
letters.substring(with: 0...9) // nil
letters.substring(with: 0..<9) // "My string"
letters.substring(with: 2...2) // ""
letters.substring(with: 2..<2) // ""
Here is my
gist.

Generate random String without repeating in swift

I want the function to generate random String without repeating.
For example this function maybe will print: ABCC
func randomString(length:Int) -> String {
let charSet = "ABCDEF"
var c = charSet.characters.map { String($0) }
var s:String = ""
for _ in (1...length) {
s.append(c[Int(arc4random()) % c.count])
}
return s
} print(randomString(length: 4))
and i want print random unique string only, E.g : ABCD
import GameplayKit
func randomString(length : Int) -> String {
let charSet = Array("ABCDEFGHIJKLMNOPQRSTUVWXYZ".characters)
let shuffled = GKRandomSource.sharedRandom().arrayByShufflingObjects(in: charSet) as! [Character]
let array = shuffled.prefix(length)
return String(array)
}
print(randomString(length: 4))
func randomString(length: Int) -> String {
let charSet = "ABCDEF"
var charSetArray = charSet.characters.map { String($0) }
var randArray: [String] = []
while charSetArray.count > 0 {
let i = Int(arc4random_uniform(UInt32(charSetArray.count)))
randArray.append(charSetArray[i])
charSetArray.remove(at: i)
}
var output: String = ""
for i in 0..<length {
output.append(randArray[i])
}
return output
}
How to use:
let randomString = "ABCDEF".random(length: 3)!
The return value is optional because the length might exceed the length of provided string.
Check out the full implementation:
import UIKit
import PlaygroundSupport
extension MutableCollection where Indices.Iterator.Element == Index {
mutating func shuffle() {
let c = count
guard c > 1 else { return }
for (firstUnshuffled , unshuffledCount) in zip(indices, stride(from: c, to: 1, by: -1)) {
let d: IndexDistance = numericCast(arc4random_uniform(numericCast(unshuffledCount)))
guard d != 0 else { continue }
let i = index(firstUnshuffled, offsetBy: d)
swap(&self[firstUnshuffled], &self[i])
}
}
}
extension Sequence {
func shuffled() -> [Iterator.Element] {
var result = Array(self)
result.shuffle()
return result
}
}
extension String {
func random(length: Int) -> String? {
let uniqueCharacters = Array(Set(characters.map({ String($0) })))
guard length <= uniqueCharacters.count else { return nil }
guard length > 0 else { return nil }
return uniqueCharacters[0..<length].shuffled().joined()
}
}

Swift3 & Xcode8: ’subscript' is unavailable: cannot subscript String with a CountableClosedRange<Int>,

Error 1:
When I am trying get the stringValue from Metadata shows above error in Swift3:
let myMetadata: AVMetadataMachineReadableCodeObject = metadataObjects[0] as! AVMetadataMachineReadableCodeObject
// take out the system and check-digits
let myBarcode = myMetadata.stringValue[1...11] //error
Error 2:
In extensions of String I write these to get right(x) and left(x) function to get substring:
extension String {
// length of string
var length: Int {
return self.characters.count
}
// right(x) and left(x) function to get substring
func right(_ i: Int) -> String?
{
return self[self.length-i ... self.length-1 ] //error
}
func left(_ i: Int) -> String?
{
return self[0 ... i-1] //error
}
}
Use this extension for the countable closed range [0...4] subscripting
extension String {
subscript (r: CountableClosedRange<Int>) -> String {
get {
let startIndex = self.index(self.startIndex, offsetBy: r.lowerBound)
let endIndex = self.index(startIndex, offsetBy: r.upperBound - r.lowerBound)
return self[startIndex...endIndex]
}
}
}
or a safer version which checks the bounds and returns nil rather than an out-of-range exception:
extension String {
subscript (r: CountableClosedRange<Int>) -> String? {
get {
guard r.lowerBound >= 0, let startIndex = self.index(self.startIndex, offsetBy: r.lowerBound, limitedBy: self.endIndex),
let endIndex = self.index(startIndex, offsetBy: r.upperBound - r.lowerBound, limitedBy: self.endIndex) else { return nil }
return self[startIndex...endIndex]
}
}
}
Swift 4 change: You need to create a new string from the result
return String(self[startIndex...endIndex])
I took inspiration from #vadian's answer and created a set of (Swift 4) extensions that make pulling substrings trivially easy. These do not bounds check, which is generally my preference since I shouldn't be deferring sanity checking to lower level utilities like these.
extension String {
subscript (_ index: Int) -> String {
return String(self[self.index(startIndex, offsetBy: index)])
}
subscript (_ range: CountableRange<Int>) -> String {
let lowerBound = index(startIndex, offsetBy: range.lowerBound)
let upperBound = index(startIndex, offsetBy: range.upperBound)
return String(self[lowerBound..<upperBound])
}
subscript (_ range: CountableClosedRange<Int>) -> String {
let lowerBound = index(startIndex, offsetBy: range.lowerBound)
let upperBound = index(startIndex, offsetBy: range.upperBound)
return String(self[lowerBound...upperBound])
}
subscript (_ range: CountablePartialRangeFrom<Int>) -> String {
return String(self[index(startIndex, offsetBy: range.lowerBound)...])
}
subscript (_ range: PartialRangeUpTo<Int>) -> String {
return String(self[..<index(startIndex, offsetBy: range.upperBound)])
}
subscript (_ range: PartialRangeThrough<Int>) -> String {
return String(self[...index(startIndex, offsetBy: range.upperBound)])
}
}

Swift 2.0 substringwithrange

I've Xcode 7 gm, with swift 2.0 what is equivalent espression of:
Let myNSString = "full text container"
myNSString.substringWithRange(NSRange(location: 0, length: 3))
With new string class?
Try this:
let myString = "full text container"
myString[myString.startIndex..<myString.startIndex.advancedBy(3)]
You can use these extensions:
Swift 2
extension String
{
func substringWithRange(start: Int, end: Int) -> String
{
if (start < 0 || start > self.characters.count)
{
print("start index \(start) out of bounds")
return ""
}
else if end < 0 || end > self.characters.count
{
print("end index \(end) out of bounds")
return ""
}
let range = Range(start: self.startIndex.advancedBy(start), end: self.startIndex.advancedBy(end))
return self.substringWithRange(range)
}
func substringWithRange(start: Int, location: Int) -> String
{
if (start < 0 || start > self.characters.count)
{
print("start index \(start) out of bounds")
return ""
}
else if location < 0 || start + location > self.characters.count
{
print("end index \(start + location) out of bounds")
return ""
}
let range = Range(start: self.startIndex.advancedBy(start), end: self.startIndex.advancedBy(start + location))
return self.substringWithRange(range)
}
}
Swift 3
extension String
{
func substring(start: Int, end: Int) -> String
{
if (start < 0 || start > self.characters.count)
{
print("start index \(start) out of bounds")
return ""
}
else if end < 0 || end > self.characters.count
{
print("end index \(end) out of bounds")
return ""
}
let startIndex = self.characters.index(self.startIndex, offsetBy: start)
let endIndex = self.characters.index(self.startIndex, offsetBy: end)
let range = startIndex..<endIndex
return self.substring(with: range)
}
func substring(start: Int, location: Int) -> String
{
if (start < 0 || start > self.characters.count)
{
print("start index \(start) out of bounds")
return ""
}
else if location < 0 || start + location > self.characters.count
{
print("end index \(start + location) out of bounds")
return ""
}
let startIndex = self.characters.index(self.startIndex, offsetBy: start)
let endIndex = self.characters.index(self.startIndex, offsetBy: start + location)
let range = startIndex..<endIndex
return self.substring(with: range)
}
}
And it will be more simple:
let substring = myNSString.substringWithRange(0, location: 3)

Swift: easy way to substring?

I have a string:
myString = "mystring"
I would simply like to get the first 5 characters
which is the easiest way to do that in Swift?
Correct answer from Choppin, but if you want to do it in the pure swift way (without casting to NS String :
myString = myString.substringToIndex(advance(myString.startIndex, 5))
let substring: String = (myString as NSString).substringToIndex(5)
Use these extensions:
Swift 2.3
extension String
{
func substringFromIndex(index: Int) -> String
{
if (index < 0 || index > self.characters.count)
{
print("index \(index) out of bounds")
return ""
}
return self.substringFromIndex(self.startIndex.advancedBy(index))
}
func substringToIndex(index: Int) -> String
{
if (index < 0 || index > self.characters.count)
{
print("index \(index) out of bounds")
return ""
}
return self.substringToIndex(self.startIndex.advancedBy(index))
}
func substringWithRange(start: Int, end: Int) -> String
{
if (start < 0 || start > self.characters.count)
{
print("start index \(start) out of bounds")
return ""
}
else if end < 0 || end > self.characters.count
{
print("end index \(end) out of bounds")
return ""
}
let range = Range(start: self.startIndex.advancedBy(start), end: self.startIndex.advancedBy(end))
return self.substringWithRange(range)
}
func substringWithRange(start: Int, location: Int) -> String
{
if (start < 0 || start > self.characters.count)
{
print("start index \(start) out of bounds")
return ""
}
else if location < 0 || start + location > self.characters.count
{
print("end index \(start + location) out of bounds")
return ""
}
let range = Range(start: self.startIndex.advancedBy(start), end: self.startIndex.advancedBy(start + location))
return self.substringWithRange(range)
}
}
Swift 3
extension String
{
func substring(from index: Int) -> String
{
if (index < 0 || index > self.characters.count)
{
print("index \(index) out of bounds")
return ""
}
return self.substring(from: self.characters.index(self.startIndex, offsetBy: index))
}
func substring(to index: Int) -> String
{
if (index < 0 || index > self.characters.count)
{
print("index \(index) out of bounds")
return ""
}
return self.substring(to: self.characters.index(self.startIndex, offsetBy: index))
}
func substring(start: Int, end: Int) -> String
{
if (start < 0 || start > self.characters.count)
{
print("start index \(start) out of bounds")
return ""
}
else if end < 0 || end > self.characters.count
{
print("end index \(end) out of bounds")
return ""
}
let startIndex = self.characters.index(self.startIndex, offsetBy: start)
let endIndex = self.characters.index(self.startIndex, offsetBy: end)
let range = startIndex..<endIndex
return self.substring(with: range)
}
func substring(start: Int, location: Int) -> String
{
if (start < 0 || start > self.characters.count)
{
print("start index \(start) out of bounds")
return ""
}
else if location < 0 || start + location > self.characters.count
{
print("end index \(start + location) out of bounds")
return ""
}
let startIndex = self.characters.index(self.startIndex, offsetBy: start)
let endIndex = self.characters.index(self.startIndex, offsetBy: start + location)
let range = startIndex..<endIndex
return self.substring(with: range)
}
}
Usage:
let myString = "mystring"
let substring = myString.substringToIndex(5)