Scala 3 : Finding functions with the given annotation - scala

For Scala 3 macros, does anyone know of a way to find all functions with a given annotation?
For instance:
#fruit
def apple(): Int = ???
#fruit
def banana(): Int = ???
#fruit
def coconut(): Int = ???
#fruit
def durian(): Int = ???
def elephant(): Int = ???
#fruit
def fig(): Int = ???
I would want to find a list of apple, banana, coconut, durian, fig. They could be defined anywhere, but in my case they will all be in a single package.

This solution will extract all the definitions with some annotation from a given package. I will leverage also the compile-time reflection.
This solution will extract all the definitions with some annotations from a given package. I will also leverage the compile-time reflection.
So, To solve your problem, we need to divide it in:
methods gathering from a package;
filter only methods with a given annotation;
transform symbols in function application.
I suppose that you can pass the package and the annotation (and also the return type) as a type argument. So the macro signature is something like that:
inline def findAllFunction[P, A <: ConstantAnnotation, R]: List[() => R] =
${Implementation.myMacroImpl[P, A, R]()}
The first point is straightforward. we could extract all the methods defined as:
def methodsFromPackage(packageSymbol: Symbol): List[Symbol] =
packageSymbol.declaredTypes
.filter(_.isClassDef)
.flatMap(_.declaredMethods)
The second point is also quite easy. Symbol class has the method hasAnnotation that could be used in this case:
def methodsAnnotatatedWith(
methods: List[Symbol],
annotation: Symbol
): List[Symbol] =
methods.filter(_.hasAnnotation(annotation))
The last point is a little bit challenging. Here we should construct the method call. So we need to create the AST that correspond to the method call. Inspired by this example, we can call definition using Apply. Select and This serve to select the correct method that will be called:
def transformToFunctionApplication(methods: List[Symbol]): Expr[List[() => R]] =
val appliedDef = methods
.map(definition => Select(This(definition.owner), definition))
.map(select => Apply(select, List.empty))
.map(apply => '{ () => ${ apply.asExprOf[R] } })
Expr.ofList(appliedDef)
Here I used lamba call, if you want to return directly the value you should change the last two instructions:
def transformToFunctionApplication(methods: List[Symbol]): Expr[List[R]] =
val appliedDef = methods
.map(definition => Select(This(definition.owner), definition))
.map(select => Apply(select, List.empty))
.map(apply => apply.asExprOf[R])
Expr.ofList(appliedDef)
To sum up, the all methods could be defined as:
def myMacroImpl[P: Type, A: Type, R: Type]()(using
Quotes
): Expr[List[() => R]] = {
import quotes.reflect.*
val annotation = TypeRepr.of[A].typeSymbol
val moduleTarget = TypeRepr.of[P].typeSymbol
def methodsFromPackage(packageSymbol: Symbol): List[Symbol] =
packageSymbol.declaredTypes
.filter(_.isClassDef)
.flatMap(_.declaredMethods)
def methodsAnnotatatedWith(
methods: List[Symbol],
annotation: Symbol
): List[Symbol] =
methods.filter(_.hasAnnotation(annotation))
def transformToFunctionApplication(
methods: List[Symbol]
): Expr[List[() => R]] =
val appliedDef = methods
.map(definition => Select(This(definition.owner), definition))
.map(select => Apply(select, List.empty))
.map(apply => '{ () => ${ apply.asExprOf[R] } })
Expr.ofList(appliedDef)
val methods = methodsFromPackage(moduleTarget)
val annotatedMethod = methodsAnnotatatedWith(methods, annotation)
transformToFunctionApplication(annotatedMethod)
}
Finally, you can use the macro as:
package org.tests
import org.tests.Macros.fruit
package foo {
#fruit
def check(): Int = 10
#fruit
def other(): Int = 11
}
#main def hello: Unit =
println("Hello world!")
println(Macros.findAllFunction[org.tests.foo, fruit, Int].map(_.apply())) /// List(10, 11)
Scastie

Related

Scala 3 quotes: get default case class field value [duplicate]

Is there a clean way to access the default values of a case class fields when performing type class derivation in Scala 3 using Mirrors? For example:
case class Foo(s: String = "bar", i: Int, d: Double = Math.PI)
Mirror.Product.MirroredElemLabels will be set to ("s", "i", "d"). Is there anything like: (Some["bar"], None, Some[3.141592653589793])?
If not could this be achieved using Macros? Can I use the Mirrors and Macros simultaneously to derive a type class instance?
You'll have to write a macro working with methods named like <init>$default$1, <init>$default$2, ... in companion object
import scala.quoted.*
inline def printDefaults[T]: Unit = ${printDefaultsImpl[T]}
def printDefaultsImpl[T](using Quotes, Type[T]): Expr[Unit] = {
import quotes.reflect.*
(1 to 3).map(i =>
TypeRepr.of[T].typeSymbol
.companionClass
.declaredMethod(s"$$lessinit$$greater$$default$$$i")
.headOption
.flatMap(_.tree.asInstanceOf[DefDef].rhs)
).foreach(println)
'{()}
}
printDefaults[Foo]
//Some(Literal(Constant(bar)))
//None
//Some(Select(Ident(Math),PI))
Mirrors and macros can work together:
import scala.quoted.*
import scala.deriving.*
trait Default[T] {
type Out <: Tuple
def defaults: Out
}
object Default {
transparent inline given mkDefault[T](using
m: Mirror.ProductOf[T],
s: ValueOf[Tuple.Size[m.MirroredElemTypes]]
): Default[T] =
new Default[T] {
type Out = Tuple.Map[m.MirroredElemTypes, Option]
def defaults = getDefaults[T](s.value).asInstanceOf[Out]
}
inline def getDefaults[T](inline s: Int): Tuple = ${getDefaultsImpl[T]('s)}
def getDefaultsImpl[T](s: Expr[Int])(using Quotes, Type[T]): Expr[Tuple] = {
import quotes.reflect.*
val n = s.asTerm.underlying.asInstanceOf[Literal].constant.value.asInstanceOf[Int]
val terms: List[Option[Term]] =
(1 to n).toList.map(i =>
TypeRepr.of[T].typeSymbol
.companionClass
.declaredMethod(s"$$lessinit$$greater$$default$$$i")
.headOption
.flatMap(_.tree.asInstanceOf[DefDef].rhs)
)
def exprOfOption[T](oet: Option[Expr[T]])(using Type[T], Quotes): Expr[Option[T]] = oet match {
case None => Expr(None)
case Some(et) => '{Some($et)}
}
val exprs: List[Option[Expr[Any]]] = terms.map(_.map(_.asExprOf[Any]))
val exprs1: List[Expr[Option[Any]]] = exprs.map(exprOfOption)
Expr.ofTupleFromSeq(exprs1)
}
}
Usage:
val d = summon[Default[Foo]]
summon[d.Out =:= (Option[String], Option[Int], Option[Double])] // compiles
d.defaults // (Some(bar),None,Some(3.141592653589793))
As Dmytro suggests, information is carried in methods <init>default$x of the class companion object.
However, Quotes discourages accessing a symbol's tree in a macro:
https://github.com/lampepfl/dotty/blob/main/library/src/scala/quoted/Quotes.scala#L3628.
Symbol's tree is lost, unless program is compiled with -Yretain-trees)
It is better to let the macro evaluate <init>default$x, rather than copy the right hand side of its definition.
One can do so by expressing terms as :
val terms: List[Option[Term]] =
(1 to n).toList.map(i =>
TypeRepr.of[T].typeSymbol
.companionClass
.declaredMethod(s"$$lessinit$$greater$$default$$$i")
.headOption
.map(Select(Ref(TypeRepr.of[T].typeSymbol.companionModule),_))
)

Type Class Derivation accessing default values

Is there a clean way to access the default values of a case class fields when performing type class derivation in Scala 3 using Mirrors? For example:
case class Foo(s: String = "bar", i: Int, d: Double = Math.PI)
Mirror.Product.MirroredElemLabels will be set to ("s", "i", "d"). Is there anything like: (Some["bar"], None, Some[3.141592653589793])?
If not could this be achieved using Macros? Can I use the Mirrors and Macros simultaneously to derive a type class instance?
You'll have to write a macro working with methods named like <init>$default$1, <init>$default$2, ... in companion object
import scala.quoted.*
inline def printDefaults[T]: Unit = ${printDefaultsImpl[T]}
def printDefaultsImpl[T](using Quotes, Type[T]): Expr[Unit] = {
import quotes.reflect.*
(1 to 3).map(i =>
TypeRepr.of[T].typeSymbol
.companionClass
.declaredMethod(s"$$lessinit$$greater$$default$$$i")
.headOption
.flatMap(_.tree.asInstanceOf[DefDef].rhs)
).foreach(println)
'{()}
}
printDefaults[Foo]
//Some(Literal(Constant(bar)))
//None
//Some(Select(Ident(Math),PI))
Mirrors and macros can work together:
import scala.quoted.*
import scala.deriving.*
trait Default[T] {
type Out <: Tuple
def defaults: Out
}
object Default {
transparent inline given mkDefault[T](using
m: Mirror.ProductOf[T],
s: ValueOf[Tuple.Size[m.MirroredElemTypes]]
): Default[T] =
new Default[T] {
type Out = Tuple.Map[m.MirroredElemTypes, Option]
def defaults = getDefaults[T](s.value).asInstanceOf[Out]
}
inline def getDefaults[T](inline s: Int): Tuple = ${getDefaultsImpl[T]('s)}
def getDefaultsImpl[T](s: Expr[Int])(using Quotes, Type[T]): Expr[Tuple] = {
import quotes.reflect.*
val n = s.asTerm.underlying.asInstanceOf[Literal].constant.value.asInstanceOf[Int]
val terms: List[Option[Term]] =
(1 to n).toList.map(i =>
TypeRepr.of[T].typeSymbol
.companionClass
.declaredMethod(s"$$lessinit$$greater$$default$$$i")
.headOption
.flatMap(_.tree.asInstanceOf[DefDef].rhs)
)
def exprOfOption[T](oet: Option[Expr[T]])(using Type[T], Quotes): Expr[Option[T]] = oet match {
case None => Expr(None)
case Some(et) => '{Some($et)}
}
val exprs: List[Option[Expr[Any]]] = terms.map(_.map(_.asExprOf[Any]))
val exprs1: List[Expr[Option[Any]]] = exprs.map(exprOfOption)
Expr.ofTupleFromSeq(exprs1)
}
}
Usage:
val d = summon[Default[Foo]]
summon[d.Out =:= (Option[String], Option[Int], Option[Double])] // compiles
d.defaults // (Some(bar),None,Some(3.141592653589793))
As Dmytro suggests, information is carried in methods <init>default$x of the class companion object.
However, Quotes discourages accessing a symbol's tree in a macro:
https://github.com/lampepfl/dotty/blob/main/library/src/scala/quoted/Quotes.scala#L3628.
Symbol's tree is lost, unless program is compiled with -Yretain-trees)
It is better to let the macro evaluate <init>default$x, rather than copy the right hand side of its definition.
One can do so by expressing terms as :
val terms: List[Option[Term]] =
(1 to n).toList.map(i =>
TypeRepr.of[T].typeSymbol
.companionClass
.declaredMethod(s"$$lessinit$$greater$$default$$$i")
.headOption
.map(Select(Ref(TypeRepr.of[T].typeSymbol.companionModule),_))
)

How to reflect concrete types that corresponds to the type parameters of an abstraction type in Scala?

Suppose we have a generic type (for example, Seq[E]) and a concrete subtype (for example, Seq[Int]). How can we extract concrete type that corresponds to the type parameters of the abstraction type. In other words, how can we know E -> Int.
Below is a minimal code example that tests for the desired behavior. The extractTypeBinding function would perform the transformation in question.
import scala.reflect.runtime.{universe => ru}
class MyFuncs
object MyFuncs {
def fn1[E](s: Seq[E]): E = ???
def fn2[K, V](m: Map[K, V]): Int = ???
}
object Scratch {
def extractTypeBinding(genType: ru.Type, typeParam: ru.Type)(concreteType: ru.Type): ru.Type = ???
def getArgTypes(methodSymbol: ru.MethodSymbol): Seq[ru.Type] =
methodSymbol.paramLists.headOption.getOrElse(Nil).map(_.typeSignature)
def main(a: Array[String]): Unit = {
// Grab the argument types of our methods.
val funcsType = ru.typeOf[MyFuncs].companion
val fn1ArgTypes = getArgTypes(funcsType.member(ru.TermName("fn1")).asMethod)
val fn2ArgTypes = getArgTypes(funcsType.member(ru.TermName("fn2")).asMethod)
val genericSeq = fn1ArgTypes.head // Seq[E]
val genericMap = fn2ArgTypes.head // Map[K, V]
// Create an extractor for the `E` in `Seq[E]`.
val seqElExtractor = extractTypeBinding(genericSeq, genericSeq.typeArgs.head) _
// Extractor for the `K` in `Map[K,V]`
val mapKeyExtractor = extractTypeBinding(genericMap, genericMap.typeArgs.head) _
// Extractor for the `V` in `Map[K,V]`
val mapValueExtractor = extractTypeBinding(genericMap, genericMap.typeArgs(1)) _
println(seqElExtractor(ru.typeOf[Seq[Int]])) // should be Int
println(seqElExtractor(ru.typeOf[Seq[Map[String, Double]]])) // should be Map[String, Double]
println(mapKeyExtractor(ru.typeOf[Map[String, Double]])) // should be String
println(mapKeyExtractor(ru.typeOf[Map[Int, Boolean]])) // should be Int
println(mapValueExtractor(ru.typeOf[Map[String, Double]])) // should be Double
println(mapValueExtractor(ru.typeOf[Map[Int, Boolean]])) // should be Boolean
}
}
Based on the docstrings, it seems like asSeenFrom should be the key to implementing extractTypeBinding. I tried the below implementation, but it returned the type parameter unchanged.
def extractTypeBinding(genType: ru.Type, typeParam: ru.Type)(concreteType: ru.Type): ru.Type =
typeParam.asSeenFrom(concreteType, genType.typeSymbol.asClass)
...
println(seqElExtractor(ru.typeOf[Seq[Int]])) // E
println(seqElExtractor(ru.typeOf[Seq[Map[String, Double]]])) // E
If asSeenFrom is the correct approach, what would the correct incantation be?
If not, then how should this be done?
The simplest solution came from the helpful prodding by Dmytro Mitin in the comments.
I had a couple misunderstandings about .typeArgs that were cleared up with some additional experimentation.
It returns all type arguments, not just the abstract ones.
It only returns the "top level" type arguments of the type you call it on. In other words, Map[A, Map[B, C]] only has 2 type args (A and Map[B, C])
Both of those seem very intuitive now, but I initially made some foolish assumptions. Below is a modified version of my test that more clearly achieves my original intent.
class MyFuncs
object MyFuncs {
def fn1[E](s: Seq[E]): E = ???
def fn2[K, V](m: Map[K, V]): Int = ???
}
object Scratch {
def typeArgBindings(genericType: ru.Type, concreteType: ru.Type): Map[ru.Type, ru.Type] =
// #todo consider validating both have the same base type.
genericType.typeArgs.zip(concreteType.typeArgs).toMap
def getArgTypes(methodSymbol: ru.MethodSymbol): Seq[ru.Type] =
methodSymbol.paramLists.headOption.getOrElse(Nil).map(_.typeSignature)
def main(a: Array[String]): Unit = {
// Grab the argument types of our methods.
val funcsType = ru.typeOf[MyFuncs].companion
val fn1ArgTypes = getArgTypes(funcsType.member(ru.TermName("fn1")).asMethod)
val fn2ArgTypes = getArgTypes(funcsType.member(ru.TermName("fn2")).asMethod)
val genericSeq = fn1ArgTypes.head // Seq[E]
val genericMap = fn2ArgTypes.head // Map[K, V]
println(typeArgBindings(genericSeq, ru.typeOf[Seq[Int]])) // Map(E -> Int)
println(typeArgBindings(genericSeq, ru.typeOf[Seq[Map[String, Double]]])) // Map(E -> Map[String,Double])
println(typeArgBindings(genericMap, ru.typeOf[Map[String, Double]])) // Map(K -> String, V -> Double)
println(typeArgBindings(genericMap, ru.typeOf[Map[Int, Boolean]])) // Map(K -> Int, V -> Boolean)
}
}

How to express Function type?

I am currently reading Hutton's and Meijer's paper on parsing combinators in Haskell http://www.cs.nott.ac.uk/~pszgmh/monparsing.pdf. For the sake of it I am trying to implement them in scala. I would like to construct something easy to code, extend and also simple and elegant. I have come up with two solutions for the following haskell code
/* Haskell Code */
type Parser a = String -> [(a,String)]
result :: a -> Parser a
result v = \inp -> [(v,inp)]
zero :: Parser a
zero = \inp -> []
item :: Parser Char
item = \inp -> case inp of
[] -> []
(x:xs) -> [(x,xs)]
/* Scala Code */
object Hutton1 {
type Parser[A] = String => List[(A, String)]
def Result[A](v: A): Parser[A] = str => List((v, str))
def Zero[A]: Parser[A] = str => List()
def Character: Parser[Char] = str => if (str.isEmpty) List() else List((str.head, str.tail))
}
object Hutton2 {
trait Parser[A] extends (String => List[(A, String)])
case class Result[A](v: A) extends Parser[A] {
def apply(str: String) = List((v, str))
}
case object Zero extends Parser[T forSome {type T}] {
def apply(str: String) = List()
}
case object Character extends Parser[Char] {
def apply(str: String) = if (str.isEmpty) List() else List((str.head, str.tail))
}
}
object Hutton extends App {
object T1 {
import Hutton1._
def run = {
val r: List[(Int, String)] = Zero("test") ++ Result(5)("test")
println(r.map(x => x._1 + 1) == List(6))
println(Character("abc") == List(('a', "bc")))
}
}
object T2 {
import Hutton2._
def run = {
val r: List[(Int, String)] = Zero("test") ++ Result(5)("test")
println(r.map(x => x._1 + 1) == List(6))
println(Character("abc") == List(('a', "bc")))
}
}
T1.run
T2.run
}
Question 1
In Haskell, zero is a function value that can be used as it is, expessing all failed parsers whether they are of type Parser[Int] or Parser[String]. In scala we achieve the same by calling the function Zero (1st approach) but in this way I believe that I just generate a different function everytime Zero is called. Is this statement true? Is there a way to mitigate this?
Question 2
In the second approach, the Zero case object is extending Parser with the usage of existential types Parser[T forSome {type T}] . If I replace the type with Parser[_] I get the compile error
Error:(19, 28) class type required but Hutton2.Parser[_] found
case object Zero extends Parser[_] {
^
I thought these two expressions where equivalent. Is this the case?
Question 3
Which approach out of the two do you think that will yield better results in expressing the combinators in terms of elegance and simplicity?
I use scala 2.11.8
Note: I didn't compile it, but I know the problem and can propose two solutions.
The more Haskellish way would be to not use subtyping, but to define zero as a polymorphic value. In that style, I would propose to define parsers not as objects deriving from a function type, but as values of one case class:
final case class Parser[T](run: String => List[(T, String)])
def zero[T]: Parser[T] = Parser(...)
As shown by #Alec, yes, this will produce a new value every time, since a def is compiled to a method.
If you want to use subtyping, you need to make Parser covariant. Then you can give zero a bottom result type:
trait Parser[+A] extends (String => List[(A, String)])
case object Zero extends Parser[Nothing] {...}
These are in some way quite related; in system F_<:, which is the base of what Scala uses, the types _|_ (aka Nothing) and \/T <: Any. T behave the same (this hinted at in Types and Programming Languages, chapter 28). The two possibilities given here are a consequence of this fact.
With existentials I'm not so familiar with, but I think that while unbounded T forSome {type T} will behave like Nothing, Scala does not allow inhertance from an existential type.
Question 1
I think that you are right, and here is why: Zero1 below prints hello every time you use it. The solution, Zero2, involves using a val instead.
def Zero1[A]: Parser[A] = { println("hi"); str => List() }
val Zero2: Parser[Nothing] = str => List()
Question 2
No idea. I'm still just starting out with Scala. Hope someone answers this.
Question 3
The trait one will play better with Scala's for (since you can define custom flatMap and map), which turns out to be (somewhat) like Haskell's do. The following is all you need.
trait Parser[A] extends (String => List[(A, String)]) {
def flatMap[B](f: A => Parser[B]): Parser[B] = {
val p1 = this
new Parser[B] {
def apply(s1: String) = for {
(a,s2) <- p1(s1)
p2 = f(a)
(b,s3) <- p2(s2)
} yield (b,s3)
}
}
def map[B](f: A => B): Parser[B] = {
val p = this
new Parser[B] {
def apply(s1: String) = for ((a,s2) <- p(s1)) yield (f(a),s2)
}
}
}
Of course, to do anything interesting you need more parsers. I'll propose to you one simple parser combinator: Choice(p1: Parser[A], p2: Parser[A]): Parser[A] which tries both parsers. (And rewrite your existing parsers more to my style).
def choice[A](p1: Parser[A], p2: Parser[A]): Parser[A] = new Parser[A] {
def apply(s: String): List[(A,String)] = { p1(s) ++ p2(s) }
}
def unit[A](x: A): Parser[A] = new Parser[A] {
def apply(s: String): List[(A,String)] = List((x,s))
}
val character: Parser[Char] = new Parser[Char] {
def apply(s: String): List[(Char,String)] = List((s.head,s.tail))
}
Then, you can write something like the following:
val parser: Parser[(Char,Char)] = for {
x <- choice(unit('x'),char)
y <- char
} yield (x,y)
And calling parser("xyz") gives you List((('x','x'),"yz"), (('x','y'),"z")).

Hidden features of Scala

Locked. This question and its answers are locked because the question is off-topic but has historical significance. It is not currently accepting new answers or interactions.
What are the hidden features of Scala that every Scala developer should be aware of?
One hidden feature per answer, please.
Okay, I had to add one more. Every Regex object in Scala has an extractor (see answer from oxbox_lakes above) that gives you access to the match groups. So you can do something like:
// Regex to split a date in the format Y/M/D.
val regex = "(\\d+)/(\\d+)/(\\d+)".r
val regex(year, month, day) = "2010/1/13"
The second line looks confusing if you're not used to using pattern matching and extractors. Whenever you define a val or var, what comes after the keyword is not simply an identifier but rather a pattern. That's why this works:
val (a, b, c) = (1, 3.14159, "Hello, world")
The right hand expression creates a Tuple3[Int, Double, String] which can match the pattern (a, b, c).
Most of the time your patterns use extractors that are members of singleton objects. For example, if you write a pattern like
Some(value)
then you're implicitly calling the extractor Some.unapply.
But you can also use class instances in patterns, and that is what's happening here. The val regex is an instance of Regex, and when you use it in a pattern, you're implicitly calling regex.unapplySeq (unapply versus unapplySeq is beyond the scope of this answer), which extracts the match groups into a Seq[String], the elements of which are assigned in order to the variables year, month, and day.
Structural type definitions - i.e. a type described by what methods it supports. For example:
object Closer {
def using(closeable: { def close(): Unit }, f: => Unit) {
try {
f
} finally { closeable.close }
}
}
Notice that the type of the parameter closeable is not defined other than it has a close method
Type-Constructor Polymorphism (a.k.a. higher-kinded types)
Without this feature you can, for example, express the idea of mapping a function over a list to return another list, or mapping a function over a tree to return another tree. But you can't express this idea generally without higher kinds.
With higher kinds, you can capture the idea of any type that's parameterised with another type. A type constructor that takes one parameter is said to be of kind (*->*). For example, List. A type constructor that returns another type constructor is said to be of kind (*->*->*). For example, Function1. But in Scala, we have higher kinds, so we can have type constructors that are parameterised with other type constructors. So they're of kinds like ((*->*)->*).
For example:
trait Functor[F[_]] {
def fmap[A, B](f: A => B, fa: F[A]): F[B]
}
Now, if you have a Functor[List], you can map over lists. If you have a Functor[Tree], you can map over trees. But more importantly, if you have Functor[A] for any A of kind (*->*), you can map a function over A.
Extractors which allow you to replace messy if-elseif-else style code with patterns. I know that these are not exactly hidden but I've been using Scala for a few months without really understanding the power of them. For (a long) example I can replace:
val code: String = ...
val ps: ProductService = ...
var p: Product = null
if (code.endsWith("=")) {
p = ps.findCash(code.substring(0, 3)) //e.g. USD=, GBP= etc
}
else if (code.endsWith(".FWD")) {
//e.g. GBP20090625.FWD
p = ps.findForward(code.substring(0,3), code.substring(3, 9))
}
else {
p = ps.lookupProductByRic(code)
}
With this, which is much clearer in my opinion
implicit val ps: ProductService = ...
val p = code match {
case SyntheticCodes.Cash(c) => c
case SyntheticCodes.Forward(f) => f
case _ => ps.lookupProductByRic(code)
}
I have to do a bit of legwork in the background...
object SyntheticCodes {
// Synthetic Code for a CashProduct
object Cash extends (CashProduct => String) {
def apply(p: CashProduct) = p.currency.name + "="
//EXTRACTOR
def unapply(s: String)(implicit ps: ProductService): Option[CashProduct] = {
if (s.endsWith("=")
Some(ps.findCash(s.substring(0,3)))
else None
}
}
//Synthetic Code for a ForwardProduct
object Forward extends (ForwardProduct => String) {
def apply(p: ForwardProduct) = p.currency.name + p.date.toString + ".FWD"
//EXTRACTOR
def unapply(s: String)(implicit ps: ProductService): Option[ForwardProduct] = {
if (s.endsWith(".FWD")
Some(ps.findForward(s.substring(0,3), s.substring(3, 9))
else None
}
}
But the legwork is worth it for the fact that it separates a piece of business logic into a sensible place. I can implement my Product.getCode methods as follows..
class CashProduct {
def getCode = SyntheticCodes.Cash(this)
}
class ForwardProduct {
def getCode = SyntheticCodes.Forward(this)
}
Manifests which are a sort of way at getting the type information at runtime, as if Scala had reified types.
In scala 2.8 you can have tail-recursive methods by using the package scala.util.control.TailCalls (in fact it's trampolining).
An example:
def u(n:Int):TailRec[Int] = {
if (n==0) done(1)
else tailcall(v(n/2))
}
def v(n:Int):TailRec[Int] = {
if (n==0) done(5)
else tailcall(u(n-1))
}
val l=for(n<-0 to 5) yield (n,u(n).result,v(n).result)
println(l)
Case classes automatically mixin the Product trait, providing untyped, indexed access to the fields without any reflection:
case class Person(name: String, age: Int)
val p = Person("Aaron", 28)
val name = p.productElement(0) // name = "Aaron": Any
val age = p.productElement(1) // age = 28: Any
val fields = p.productIterator.toList // fields = List[Any]("Aaron", 28)
This feature also provides a simplified way to alter the output of the toString method:
case class Person(name: String, age: Int) {
override def productPrefix = "person: "
}
// prints "person: (Aaron,28)" instead of "Person(Aaron, 28)"
println(Person("Aaron", 28))
It's not exactly hidden, but certainly a under advertised feature: scalac -Xprint.
As a illustration of the use consider the following source:
class A { "xx".r }
Compiling this with scalac -Xprint:typer outputs:
package <empty> {
class A extends java.lang.Object with ScalaObject {
def this(): A = {
A.super.this();
()
};
scala.this.Predef.augmentString("xx").r
}
}
Notice scala.this.Predef.augmentString("xx").r, which is a the application of the implicit def augmentString present in Predef.scala.
scalac -Xprint:<phase> will print the syntax tree after some compiler phase. To see the available phases use scalac -Xshow-phases.
This is a great way to learn what is going on behind the scenes.
Try with
case class X(a:Int,b:String)
using the typer phase to really feel how useful it is.
You can define your own control structures. It's really just functions and objects and some syntactic sugar, but they look and behave like the real thing.
For example, the following code defines dont {...} unless (cond) and dont {...} until (cond):
def dont(code: => Unit) = new DontCommand(code)
class DontCommand(code: => Unit) {
def unless(condition: => Boolean) =
if (condition) code
def until(condition: => Boolean) = {
while (!condition) {}
code
}
}
Now you can do the following:
/* This will only get executed if the condition is true */
dont {
println("Yep, 2 really is greater than 1.")
} unless (2 > 1)
/* Just a helper function */
var number = 0;
def nextNumber() = {
number += 1
println(number)
number
}
/* This will not be printed until the condition is met. */
dont {
println("Done counting to 5!")
} until (nextNumber() == 5)
#switch annotation in Scala 2.8:
An annotation to be applied to a match
expression. If present, the compiler
will verify that the match has been
compiled to a tableswitch or
lookupswitch, and issue an error if it
instead compiles into a series of
conditional expressions.
Example:
scala> val n = 3
n: Int = 3
scala> import annotation.switch
import annotation.switch
scala> val s = (n: #switch) match {
| case 3 => "Three"
| case _ => "NoThree"
| }
<console>:6: error: could not emit switch for #switch annotated match
val s = (n: #switch) match {
Dunno if this is really hidden, but I find it quite nice.
Typeconstructors that take 2 type parameters can be written in infix notation
object Main {
class FooBar[A, B]
def main(args: Array[String]): Unit = {
var x: FooBar[Int, BigInt] = null
var y: Int FooBar BigInt = null
}
}
Scala 2.8 introduced default and named arguments, which made possible the addition of a new "copy" method that Scala adds to case classes. If you define this:
case class Foo(a: Int, b: Int, c: Int, ... z:Int)
and you want to create a new Foo that's like an existing Foo, only with a different "n" value, then you can just say:
foo.copy(n = 3)
in scala 2.8 you can add #specialized to your generic classes/methods. This will create special versions of the class for primitive types (extending AnyVal) and save the cost of un-necessary boxing/unboxing :
class Foo[#specialized T]...
You can select a subset of AnyVals :
class Foo[#specialized(Int,Boolean) T]...
Extending the language. I always wanted to do something like this in Java (couldn't). But in Scala I can have:
def timed[T](thunk: => T) = {
val t1 = System.nanoTime
val ret = thunk
val time = System.nanoTime - t1
println("Executed in: " + time/1000000.0 + " millisec")
ret
}
and then write:
val numbers = List(12, 42, 3, 11, 6, 3, 77, 44)
val sorted = timed { // "timed" is a new "keyword"!
numbers.sortWith(_<_)
}
println(sorted)
and get
Executed in: 6.410311 millisec
List(3, 3, 6, 11, 12, 42, 44, 77)
You can designate a call-by-name parameter (EDITED: this is different then a lazy parameter!) to a function and it will not be evaluated until used by the function (EDIT: in fact, it will be reevaluated every time it is used). See this faq for details
class Bar(i:Int) {
println("constructing bar " + i)
override def toString():String = {
"bar with value: " + i
}
}
// NOTE the => in the method declaration. It indicates a lazy paramter
def foo(x: => Bar) = {
println("foo called")
println("bar: " + x)
}
foo(new Bar(22))
/*
prints the following:
foo called
constructing bar 22
bar with value: 22
*/
You can use locally to introduce a local block without causing semicolon inference issues.
Usage:
scala> case class Dog(name: String) {
| def bark() {
| println("Bow Vow")
| }
| }
defined class Dog
scala> val d = Dog("Barnie")
d: Dog = Dog(Barnie)
scala> locally {
| import d._
| bark()
| bark()
| }
Bow Vow
Bow Vow
locally is defined in "Predef.scala" as:
#inline def locally[T](x: T): T = x
Being inline, it does not impose any additional overhead.
Early Initialization:
trait AbstractT2 {
println("In AbstractT2:")
val value: Int
val inverse = 1.0/value
println("AbstractT2: value = "+value+", inverse = "+inverse)
}
val c2c = new {
// Only initializations are allowed in pre-init. blocks.
// println("In c2c:")
val value = 10
} with AbstractT2
println("c2c.value = "+c2c.value+", inverse = "+c2c.inverse)
Output:
In AbstractT2:
AbstractT2: value = 10, inverse = 0.1
c2c.value = 10, inverse = 0.1
We instantiate an anonymous inner
class, initializing the value field
in the block, before the with
AbstractT2 clause. This guarantees
that value is initialized before the
body of AbstractT2 is executed, as
shown when you run the script.
You can compose structural types with the 'with' keyword
object Main {
type A = {def foo: Unit}
type B = {def bar: Unit}
type C = A with B
class myA {
def foo: Unit = println("myA.foo")
}
class myB {
def bar: Unit = println("myB.bar")
}
class myC extends myB {
def foo: Unit = println("myC.foo")
}
def main(args: Array[String]): Unit = {
val a: A = new myA
a.foo
val b: C = new myC
b.bar
b.foo
}
}
placeholder syntax for anonymous functions
From The Scala Language Specification:
SimpleExpr1 ::= '_'
An expression (of syntactic category Expr) may contain embedded underscore symbols _ at places where identifiers are legal. Such an expression represents an anonymous function where subsequent occurrences of underscores denote successive parameters.
From Scala Language Changes:
_ + 1 x => x + 1
_ * _ (x1, x2) => x1 * x2
(_: Int) * 2 (x: Int) => x * 2
if (_) x else y z => if (z) x else y
_.map(f) x => x.map(f)
_.map(_ + 1) x => x.map(y => y + 1)
Using this you could do something like:
def filesEnding(query: String) =
filesMatching(_.endsWith(query))
Implicit definitions, particularly conversions.
For example, assume a function which will format an input string to fit to a size, by replacing the middle of it with "...":
def sizeBoundedString(s: String, n: Int): String = {
if (n < 5 && n < s.length) throw new IllegalArgumentException
if (s.length > n) {
val trailLength = ((n - 3) / 2) min 3
val headLength = n - 3 - trailLength
s.substring(0, headLength)+"..."+s.substring(s.length - trailLength, s.length)
} else s
}
You can use that with any String, and, of course, use the toString method to convert anything. But you could also write it like this:
def sizeBoundedString[T](s: T, n: Int)(implicit toStr: T => String): String = {
if (n < 5 && n < s.length) throw new IllegalArgumentException
if (s.length > n) {
val trailLength = ((n - 3) / 2) min 3
val headLength = n - 3 - trailLength
s.substring(0, headLength)+"..."+s.substring(s.length - trailLength, s.length)
} else s
}
And then, you could pass classes of other types by doing this:
implicit def double2String(d: Double) = d.toString
Now you can call that function passing a double:
sizeBoundedString(12345.12345D, 8)
The last argument is implicit, and is being passed automatically because of the implicit de declaration. Furthermore, "s" is being treated like a String inside sizeBoundedString because there is an implicit conversion from it to String.
Implicits of this type are better defined for uncommon types to avoid unexpected conversions. You can also explictly pass a conversion, and it will still be implicitly used inside sizeBoundedString:
sizeBoundedString(1234567890L, 8)((l : Long) => l.toString)
You can also have multiple implicit arguments, but then you must either pass all of them, or not pass any of them. There is also a shortcut syntax for implicit conversions:
def sizeBoundedString[T <% String](s: T, n: Int): String = {
if (n < 5 && n < s.length) throw new IllegalArgumentException
if (s.length > n) {
val trailLength = ((n - 3) / 2) min 3
val headLength = n - 3 - trailLength
s.substring(0, headLength)+"..."+s.substring(s.length - trailLength, s.length)
} else s
}
This is used exactly the same way.
Implicits can have any value. They can be used, for instance, to hide library information. Take the following example, for instance:
case class Daemon(name: String) {
def log(msg: String) = println(name+": "+msg)
}
object DefaultDaemon extends Daemon("Default")
trait Logger {
private var logd: Option[Daemon] = None
implicit def daemon: Daemon = logd getOrElse DefaultDaemon
def logTo(daemon: Daemon) =
if (logd == None) logd = Some(daemon)
else throw new IllegalArgumentException
def log(msg: String)(implicit daemon: Daemon) = daemon.log(msg)
}
class X extends Logger {
logTo(Daemon("X Daemon"))
def f = {
log("f called")
println("Stuff")
}
def g = {
log("g called")(DefaultDaemon)
}
}
class Y extends Logger {
def f = {
log("f called")
println("Stuff")
}
}
In this example, calling "f" in an Y object will send the log to the default daemon, and on an instance of X to the Daemon X daemon. But calling g on an instance of X will send the log to the explicitly given DefaultDaemon.
While this simple example can be re-written with overload and private state, implicits do not require private state, and can be brought into context with imports.
Maybe not too hidden, but I think this is useful:
#scala.reflect.BeanProperty
var firstName:String = _
This will automatically generate a getter and setter for the field that matches bean convention.
Further description at developerworks
Implicit arguments in closures.
A function argument can be marked as implicit just as with methods. Within the scope of the body of the function the implicit parameter is visible and eligible for implicit resolution:
trait Foo { def bar }
trait Base {
def callBar(implicit foo: Foo) = foo.bar
}
object Test extends Base {
val f: Foo => Unit = { implicit foo =>
callBar
}
def test = f(new Foo {
def bar = println("Hello")
})
}
Build infinite data structures with Scala's Streams :
http://www.codecommit.com/blog/scala/infinite-lists-for-the-finitely-patient
Result types are dependent on implicit resolution. This can give you a form of multiple dispatch:
scala> trait PerformFunc[A,B] { def perform(a : A) : B }
defined trait PerformFunc
scala> implicit val stringToInt = new PerformFunc[String,Int] {
def perform(a : String) = 5
}
stringToInt: java.lang.Object with PerformFunc[String,Int] = $anon$1#13ccf137
scala> implicit val intToDouble = new PerformFunc[Int,Double] {
def perform(a : Int) = 1.0
}
intToDouble: java.lang.Object with PerformFunc[Int,Double] = $anon$1#74e551a4
scala> def foo[A, B](x : A)(implicit z : PerformFunc[A,B]) : B = z.perform(x)
foo: [A,B](x: A)(implicit z: PerformFunc[A,B])B
scala> foo("HAI")
res16: Int = 5
scala> foo(1)
res17: Double = 1.0
Scala's equivalent of Java double brace initializer.
Scala allows you to create an anonymous subclass with the body of the class (the constructor) containing statements to initialize the instance of that class.
This pattern is very useful when building component-based user interfaces (for example Swing , Vaadin) as it allows to create UI components and declare their properties more concisely.
See http://spot.colorado.edu/~reids/papers/how-scala-experience-improved-our-java-development-reid-2011.pdf for more information.
Here is an example of creating a Vaadin button:
val button = new Button("Click me"){
setWidth("20px")
setDescription("Click on this")
setIcon(new ThemeResource("icons/ok.png"))
}
Excluding members from import statements
Suppose you want to use a Logger that contains a println and a printerr method, but you only want to use the one for error messages, and keep the good old Predef.println for standard output. You could do this:
val logger = new Logger(...)
import logger.printerr
but if logger also contains another twelve methods that you would like to import and use, it becomes inconvenient to list them. You could instead try:
import logger.{println => donotuseprintlnt, _}
but this still "pollutes" the list of imported members. Enter the über-powerful wildcard:
import logger.{println => _, _}
and that will do just the right thing™.
require method (defined in Predef) that allow you to define additional function constraints that would be checked during run-time. Imagine that you developing yet another twitter client and you need to limit tweet length up to 140 symbols. Moreover you can't post empty tweet.
def post(tweet: String) = {
require(tweet.length < 140 && tweet.length > 0)
println(tweet)
}
Now calling post with inappropriate length argument will cause an exception:
scala> post("that's ok")
that's ok
scala> post("")
java.lang.IllegalArgumentException: requirement failed
at scala.Predef$.require(Predef.scala:145)
at .post(<console>:8)
scala> post("way to looooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooong tweet")
java.lang.IllegalArgumentException: requirement failed
at scala.Predef$.require(Predef.scala:145)
at .post(<console>:8)
You can write multiple requirements or even add description to each:
def post(tweet: String) = {
require(tweet.length > 0, "too short message")
require(tweet.length < 140, "too long message")
println(tweet)
}
Now exceptions are verbose:
scala> post("")
java.lang.IllegalArgumentException: requirement failed: too short message
at scala.Predef$.require(Predef.scala:157)
at .post(<console>:8)
One more example is here.
Bonus
You can perform an action every time requirement fails:
scala> var errorcount = 0
errorcount: Int = 0
def post(tweet: String) = {
require(tweet.length > 0, {errorcount+=1})
println(tweet)
}
scala> errorcount
res14: Int = 0
scala> post("")
java.lang.IllegalArgumentException: requirement failed: ()
at scala.Predef$.require(Predef.scala:157)
at .post(<console>:9)
...
scala> errorcount
res16: Int = 1
Traits with abstract override methods are a feature in Scala that is as not widely advertised as many others. The intend of methods with the abstract override modifier is to do some operations and delegating the call to super. Then these traits have to be mixed-in with concrete implementations of their abstract override methods.
trait A {
def a(s : String) : String
}
trait TimingA extends A {
abstract override def a(s : String) = {
val start = System.currentTimeMillis
val result = super.a(s)
val dur = System.currentTimeMillis-start
println("Executed a in %s ms".format(dur))
result
}
}
trait ParameterPrintingA extends A {
abstract override def a(s : String) = {
println("Called a with s=%s".format(s))
super.a(s)
}
}
trait ImplementingA extends A {
def a(s: String) = s.reverse
}
scala> val a = new ImplementingA with TimingA with ParameterPrintingA
scala> a.a("a lotta as")
Called a with s=a lotta as
Executed a in 0 ms
res4: String = sa attol a
While my example is really not much more than a poor mans AOP, I used these Stackable Traits much to my liking to build Scala interpreter instances with predefined imports, custom bindings and classpathes. The Stackable Traits made it possible to create my factory along the lines of new InterpreterFactory with JsonLibs with LuceneLibs and then have useful imports and scope varibles for the users scripts.