flutter checkbox checked on container clicked - flutter

When I click on the checkbox it checked. What I want is even if I click on the entire container wrapping the checkbox, it checked also. But I can't seem to find a way.
Here is my code:
InkWell(
onTap: () {},
child: Container(
child: Checkbox(
activeColor: Color(0xFF2481CF),
shape: CircleBorder(
side: BorderSide(
color: Colors.grey
)
),
checkColor: Colors.white,
value: contactList[index].select,
onChanged: (value) {
var query = mains.objectbox.boxContact.query(ContactModel_.email.equals(contactList[index].email.toString())).build();
setState(() {
...
})
...
Is there any solution?

You can update the Checkbox value when it was tapped - which I see you already have an InkWell wrapping the Checkbox.
Assuming that contactList[index].select contains a bool, you can do something similar to this.
Inkwell(
onTap: () {
setState((){
contactList[index].select = !contactList[index].select;
});
},
...
)

Related

How do i put checks in my state-management in flutter?

i have a controller that's responsible for hiding and showing a checkbox when a button is pressed.
This is the Controller
class CustomersController extends GetxController {
var isCheboxVisible = false.obs;
void toggleCheckbarVisibility() {
isCheboxVisible.value = !isCheboxVisible.value;
}
}
This is the view
Visibility(
visible: controller.isCheboxVisible.value,
child: Transform.scale(
scale: 1.3,
child: Checkbox(
side: MaterialStateBorderSide.resolveWith(
(Set<MaterialState> states) {
if (states.contains(MaterialState.selected)) {
return const BorderSide(
width: 2, color: Color(0xff34495E));
}
return const BorderSide(
width: 1, color: Color(0xffB0BEC1));
},
),
shape: RoundedRectangleBorder(
borderRadius: BorderRadius.circular(5)),
activeColor: Color(0xff34495E),
//materialTapTargetSize: MaterialTapTargetSize.shrinkWrap,
//visualDensity: VisualDensity(horizontal: -4, vertical: -4),
value: isChecked,
onChanged: (value) {
setState(() {
this.isChecked = value;
});
},
),
),
)
This is the button that changes the state when clicked
onPressed: () {
customersController.toggleCheckbarVisibility();
},
The problem i have is, sometimes before clicking the button to show the checkbox, the checkbox is already visible and then clicking the button will hide the checkbox which is the opposite of what i want to do.
I want the checkbox to be hidden all the time, and only show when the button is clicked, and then hide when the button is clicked again and this should only be the case.
How do i put this checks in place? Thanks.
I have tried using if's statements in place but i don't seem to be getting it right.

How to make a container as a radio button in Flutter and make sure it doesn't deselect

I have used a package group_button 4.2.1 but once i select the textfields the radio buttons deselect and i have to select again, i have tried using the controller property of the Widget but i didn't get it to work.
I was thinking if i can make a container from scratch that is a radio button and can retain the value once i finish filling the form to be submitted to my firestore database.
You can use List of button text and keep tract of selectedIndex.
Run on dartPad
int? _selectedValueIndex;
List<String> buttonText = ["ForSale", "For rent"];
Widget button({required String text, required int index}) {
return InkWell(
splashColor: Colors.cyanAccent,
onTap: () {
setState(() {
_selectedValueIndex = index;
});
},
child: Container(
padding: const EdgeInsets.all(12),
color: index == _selectedValueIndex ? Colors.blue : Colors.white,
child: Text(
text,
style: TextStyle(
color: index == _selectedValueIndex ? Colors.white : Colors.black,
),
),
),
);
}
Inside build method to use this,
Row(
children: [
...List.generate(
buttonText.length,
(index) => button(
index: index,
text: buttonText[index],
),
)
],
),

Change state of clicked button inside StreamBuilder list in Flutter

I have a StreamBuilder which returns me a ListView of items.
For each item I also have ElevatedButton button.
ElevatedButton(
onPressed: () {
setState(() {
pressGeoON = !pressGeoON;
if (pressGeoON == true) {
favoriteDataList.add(snapshot
.data?.docs[index].id);
} else {
favoriteDataList.removeWhere(
(item) =>
item ==
snapshot.data
?.docs[index].id);
}
});
},
style: ButtonStyle(
backgroundColor:
MaterialStateProperty.all<
Color>(
Colors.deepPurple,
),
),
child: Icon(
Icons.favorite,
color: pressGeoON
? Colors.blue
: Colors.red,
),
)
I'm trying to change state of only clicked button, but so far with my code it always changes state of all buttons inside of list.
How can I change state only of clicked button and not all of them?

On web, how do I control the visibility icon that automatically appears on a focused TextFormField that has an obscureText property set to true?

Here's my code for the password field:
TextFormField(
obscureText: isObscure,
decoration: InputDecoration(
suffix: TextButton(
child: isPasswordObscure
? Text(
'Show',
style: TextStyle(color: Colors.grey),
)
: Text(
'Hide',
style: TextStyle(color: Colors.grey),
),
onPressed: () {
setState(() { isObscure = !isObscure; });
},
),
),
)
If I run it, the password field would look like this:
If you review my code, I only specified a text button and not an icon as the suffix. The visibility icon was added by Flutter Edge and when I click on it, it only changes its icon and does not unobscure or obscure the text field.
What I want to know is how do I change or remove the icon? And maybe also give it a callback so it knows what to do when I click on it.
The problem doesn't exist on mobile, only on browsers desktop Edge.
Edit:
I tried setting suffix and suffixIcon to null but the visibility icon is still showing.
Update: I've discovered that the problem only exists on MS Edge.
If you wants to turn off the visibility icon set onPressed: () {},
also if you want to remove the visibility icon form overview wrap it with opacity widget
Opacity(
opacity: 0.0,
child: textButton(),
Please find the below code sample to include the visibility option for the textField. by including a variable _isObscured in a stateful widget. we have implemented it with the auto obscure after 2 second delay.
Center(child: TextField(
obscureText: _isObscured,
decoration : InputDecoration(
suffix:InkWell(
onTap: (){
setState(() => this._isObscured =
!this._isObscured);
Future.delayed(Duration(seconds: 2), (){
setState(() => this._isObscured =
!this._isObscured);
});
},
child: Icon( Icons.visibility),
),
),
),
),
),
I found a solution:
// the magic function
void fixEdgePasswordRevealButton(FocusNode passwordFocusNode) {
passwordFocusNode.unfocus();
Future.microtask(() {
passwordFocusNode.requestFocus();
js.context.callMethod("fixPasswordCss", []);
});
}
// widget code
child: TextField(
onChanged: (_) async {
fixEdgePasswordRevealButton(passwordFocusNode);
},
focusNode: passwordFocusNode,
obscureText: true,
// end of index.html
window.fixPasswordCss = () => {
let style = document.createElement('style');
style.innerHTML = '::-ms-reveal { display: none; }';
document.head.appendChild(style);
}
</script>
</body>
Also posted on the relevant issue.

Insert into TextField using buttons from another widget - Flutter

I have a TextField that serves as a search bar where the user can use the built in Android/iOS keyboard to type but also has the possibility to insert a special characters in the search bar from a button. In a way the typing and the other insertion is combined into one string
use case: The user types hell in the search bar then presses the button widget the search bar value becomes : hellö
I set up everything but when I click the button nothing happens (the typing from the keyboard works fine)
Here's my code:
//I have this as a global variable
TextEditingController _searchInputControllor = TextEditingController();
//This is the TextField
class _SearchBarState extends State<SearchBar> {
#override
Widget build(BuildContext context) {
return TextField(
enableInteractiveSelection: false,
controller: _searchInputControllor,
cursorColor: primaryDark,
decoration: InputDecoration(
contentPadding: EdgeInsets.symmetric(horizontal: 16.0, vertical: 15.0),
border: InputBorder.none,
hintText: "Search...",
suffixIcon: Material(
color: Colors.white,
elevation: 6.0,
borderRadius: BorderRadius.all(Radius.circular(6.0),),
child: InkWell(
splashColor: Colors.greenAccent,
onTap: () {},
child: Icon(Icons.search, color: primaryDark,),
),
),
),
);
}
}
//This is the button widget
//It is supposed to add to the search bar but nothing happens
class _SpecialCharState extends State<SpecialChar> {
#override
Widget build(BuildContext context) {
return ButtonTheme(
minWidth: 40.0,
child: FlatButton(
color: Colors.transparent,
textColor: Colors.black,
padding: EdgeInsets.all(8.0),
splashColor: Colors.blue,
onPressed: () {
setState(() {
_searchInputControllor.text = _searchInputControllor.text + widget.btnVal.toLowerCase();
});
},
child: Text(
widget.btnVal
),
)
);
}
}
A. No problem at all
I think your code is working well as I tried on my Android Phone Demo.
The text field is changed as I tap the buttons.
B. Change cursor position
Nonetheless, I add this code to make the cursor automatically placed on last character.
Rather than directly changed the text, we copy its value which contains selection.
Later we offset its selection by length of newText
void appendCharacters() {
String oldText = _searchInputControllor.text;
String newText = oldText + widget.btnVal.toLowerCase();
var newValue = _searchInputControllor.value.copyWith(
text: newText,
selection: TextSelection.collapsed(
offset: newText.length, //offset to Last Character
),
composing: TextRange.empty,
);
_searchInputControllor.value = newValue;
}
so we can trigger the method with code below :
Widget build(BuildContext context) {
return ButtonTheme(
minWidth: 40.0,
child: FlatButton(
onPressed: appendCharacters, // call a function
),
);
}
Working App Repository
You may look into this repo and build yourself. Github