PowerShell Array to Table like output -- Possible ForEach problem - powershell

Question

I'm trying to run a sql query via PowerShell and return the results in a table-like format.
It's putting multiple results in one field. I suspect there's something wrong with the 'foreach' loops. What am I missing, please?
To use the code below, just change the server names from 'server1'/'server2' for your sql server instances.
$query = "
SELECT ##SERVERNAME AS ServerName
, (SELECT DB_NAME ()) AS DBName
, s.name AS SchemaName
, st.name AS TableName
, RIGHT(st.name, 8) AS Rgt8
, TRY_CONVERT(DATE, RIGHT(st.name, 8), 103) AS Rgt8Date
FROM sys.tables AS st
INNER JOIN sys.objects AS so ON so.object_id = st.object_id
INNER JOIN sys.schemas AS s ON s.schema_id = st.schema_id
"
$instanceNameList = #('server1', 'server2')
$report = #()
foreach ($instanceName in $instanceNameList) {
write-host "Executing query against SERVER/INSTANCE: " $instanceName
$dbNames = Invoke-DbaQuery -SqlInstance $InstanceName -Database "master" -Query "select name from sys.databases where database_id > 4 and name <> 'TEST'"
foreach ($database in $dbNames.Name ) {
Write-host -Activity "Current DATABASE $database" -Status "Querying: $database"
$results = Invoke-DbaQuery -SqlInstance $InstanceName -Database $database -Query $query
# <#
if ($results -is [array]) {
$CustomObject = [pscustomobject] #{
ServerName = $results.ServerName
DBName = $results.DBName
SchemaName = $results.SchemaName
TableName = $results.TableName
Rgt8 = $results.Rgt8
Rgt8Date = $results.Rgt8Date
OverOneYearOld = $results.OverOneYearOld
Drop_Table = $results.Drop_Table
}
## ADDING EACH ROW/JOB OBJECT THAT HAS BEEN REPORTED, TO THE REPORT ARRAY
$report += $CustomObject
}
}
}
$report | Select-Object ServerName, DbName, TableName | Out-GridView

Answer 1

Basically, you're doing the opposite of what you wanted to do, if $results -is [array] you want to iterate over it instead of add it as is to to your $report array.
On the other hand, adding elements to a fixed collection (+=) is a terrible idea.
$dbquery = #'
select name from
sys.databases
where database_id > 4 and name <> 'TEST'"
'#
$result = foreach ($instanceName in $instanceNameList) {
$params = #{
SqlInstance = $InstanceName
Database = "master"
Query = $dbquery
}
$dbNames = Invoke-DbaQuery #params
foreach ($database in $dbNames.Name) {
$params.Database = $database
$params.Query = $query
Invoke-DbaQuery #params | Select-Object #(
'ServerName'
'DBName'
'SchemaName'
'TableName'
'Rgt8'
'Rgt8Date'
'OverOneYearOld'
'Drop_Table'
)
}
}
$result | Format-Table