Sorting by particular columns brings together all rows with the same tuple under those columns. I want to cluster all rows with the same value, but keep the groups in the same order in which their first member appeared.
Something like this:
import polars as pl
df = pl.DataFrame(dict(x=[1,0,1,0], y=[3,1,2,4]))
df.cluster('x')
# shape: (4, 2)
# ┌─────┬─────┐
# │ x ┆ y │
# │ --- ┆ --- │
# │ i64 ┆ i64 │
# ╞═════╪═════╡
# │ 1 ┆ 3 │
# ├╌╌╌╌╌┼╌╌╌╌╌┤
# │ 1 ┆ 2 │
# ├╌╌╌╌╌┼╌╌╌╌╌┤
# │ 0 ┆ 1 │
# ├╌╌╌╌╌┼╌╌╌╌╌┤
# │ 0 ┆ 4 │
# └─────┴─────┘
This can be done by:
Storing the row index temporarily
Setting the row index to the lowest value within a window over the columns of interest
Sorting by that minimum index
Deleting the temporary row index column
import polars as pl
df = pl.DataFrame(dict(x=[1,0,1,0], y=[3,1,2,4]))
(
df
.with_column(pl.arange(0, pl.count()).alias('_index'))
.with_column(pl.min('_index').over('x'))
.sort('_index')
.drop('_index')
)
# shape: (4, 2)
# ┌─────┬─────┐
# │ x ┆ y │
# │ --- ┆ --- │
# │ i64 ┆ i64 │
# ╞═════╪═════╡
# │ 1 ┆ 3 │
# ├╌╌╌╌╌┼╌╌╌╌╌┤
# │ 1 ┆ 2 │
# ├╌╌╌╌╌┼╌╌╌╌╌┤
# │ 0 ┆ 1 │
# ├╌╌╌╌╌┼╌╌╌╌╌┤
# │ 0 ┆ 4 │
# └─────┴─────┘
Related
I'm trying to build a histogram of some data in polars. As part of my histogram code, I need to duplicate some rows. I've got a column of values, where each row also has a weight that says how many times the row should be added to the histogram.
How can I duplicate my value rows according to the weight column?
Here is some example data, with a target series:
import polars as pl
df = pl.DataFrame({"value":[1,2,3], "weight":[2, 2, 1]})
print(df)
# shape: (3, 2)
# ┌───────┬────────┐
# │ value ┆ weight │
# │ --- ┆ --- │
# │ i64 ┆ i64 │
# ╞═══════╪════════╡
# │ 1 ┆ 2 │
# │ 2 ┆ 2 │
# │ 3 ┆ 1 │
# └───────┴────────┘
s_target = pl.Series(name="value", values=[1,1,2,2,3])
print(s_target)
# shape: (5,)
# Series: 'value' [i64]
# [
# 1
# 1
# 2
# 2
# 3
# ]
How about
(
df.with_columns(
pl.col("value").repeat_by(pl.col("weight"))
)
.select(pl.col("value").arr.explode())
)
In [11]: df.with_columns(pl.col('value').repeat_by(pl.col('weight'))).select(pl.col('value').arr.explode())
Out[11]:
shape: (5, 1)
┌───────┐
│ value │
│ --- │
│ i64 │
╞═══════╡
│ 1 │
│ 1 │
│ 2 │
│ 2 │
│ 3 │
└───────┘
I didn't know you could do this so easily, I only learned about it while writing the answer. Polars is so nice :)
Turns out repeat_by and a subsequent explode are the perfect building blocks for this transformation:
>>> df.select(pl.col('value').repeat_by('weight').arr.explode())
shape: (5, 1)
┌───────┐
│ value │
│ --- │
│ i64 │
╞═══════╡
│ 1 │
│ 1 │
│ 2 │
│ 2 │
│ 3 │
└───────┘
I would like to do an ordinal encoding of a column. Pandas has the nice and convenient method of pd.factorize(), however, I would like to achieve the same in polars.
df = pl.DataFrame({"a": [5, 8, 10], "b": ["hi", "hello", "hi"]})
┌─────┬───────┐
│ a ┆ b │
│ --- ┆ --- │
│ i64 ┆ str │
╞═════╪═══════╡
│ 5 ┆ hi │
├╌╌╌╌╌┼╌╌╌╌╌╌╌┤
│ 8 ┆ hello │
├╌╌╌╌╌┼╌╌╌╌╌╌╌┤
│ 10 ┆ hi │
└─────┴───────┘
desired result:
┌─────┬─────┐
│ a ┆ b │
│ --- ┆ --- │
│ i64 ┆ i64 │
╞═════╪═════╡
│ 0 ┆ 0 │
├╌╌╌╌╌┼╌╌╌╌╌┤
│ 1 ┆ 1 │
├╌╌╌╌╌┼╌╌╌╌╌┤
│ 2 ┆ 0 │
└─────┴─────┘
You can join with a dummy DataFrame that contains the unique values and the ordinal encoding you are interested in:
df = pl.DataFrame({"a": [5, 8, 10], "b": ["hi", "hello", "hi"]})
unique = df.select(
pl.col("b").unique(maintain_order=True)
).with_row_count(name="ordinal")
df.join(unique, on="b")
Or you could "misuse" the fact that categorical values are backed by u32 integers.
df.with_column(
pl.col("b").cast(pl.Categorical).to_physical().alias("ordinal")
)
Both methods output:
shape: (3, 3)
┌─────┬───────┬─────────┐
│ a ┆ b ┆ ordinal │
│ --- ┆ --- ┆ --- │
│ i64 ┆ str ┆ u32 │
╞═════╪═══════╪═════════╡
│ 5 ┆ hi ┆ 0 │
├╌╌╌╌╌┼╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌╌╌┤
│ 8 ┆ hello ┆ 1 │
├╌╌╌╌╌┼╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌╌╌┤
│ 10 ┆ hi ┆ 0 │
└─────┴───────┴─────────┘
Here's another way to do it although I doubt it's better than the dummy Dataframe from #ritchie46
df.with_columns([pl.col('b').unique().list().alias('uniq'),
pl.col('b').unique().list().arr.eval(pl.element().rank()).alias('uniqid')]).explode(['uniq','uniqid']).filter(pl.col('b')==pl.col('uniq')).select(pl.exclude('uniq')).with_column(pl.col('uniqid')-1)
There's almost certainly a way to improve this but basically it creates a new column called uniq which is a list of all the unique values of the column as well as uniqid which (I think, and seems to be) the 1-index based order of the values. It then explodes those creating a row for ever value in uniq and then filters out the ones rows that don't equal the column b. Since rank gives the 1-index (rather than 0-index) you have to subtract 1 and exclude the uniq column that we don't care about since it's the same as b.
If the order is not important you could use .rank(method="dense")
>>> df.select(pl.all().rank(method="dense") - 1)
shape: (3, 2)
┌─────┬─────┐
│ a ┆ b │
│ --- ┆ --- │
│ u32 ┆ u32 │
╞═════╪═════╡
│ 0 ┆ 1 │
├╌╌╌╌╌┼╌╌╌╌╌┤
│ 1 ┆ 0 │
├╌╌╌╌╌┼╌╌╌╌╌┤
│ 2 ┆ 1 │
└─────┴─────┘
If it is - you could:
>>> (
... df.with_row_count()
... .with_columns([
... pl.col("row_nr").first()
... .over(col)
... .rank(method="dense")
... .alias(col) - 1
... for col in df.columns
... ])
... .drop("row_nr")
... )
shape: (3, 2)
┌─────┬─────┐
│ a ┆ b │
│ --- ┆ --- │
│ u32 ┆ u32 │
╞═════╪═════╡
│ 0 ┆ 0 │
├╌╌╌╌╌┼╌╌╌╌╌┤
│ 1 ┆ 1 │
├╌╌╌╌╌┼╌╌╌╌╌┤
│ 2 ┆ 0 │
└─────┴─────┘
polars.LazyFrame.var will return variance value for each column in a table as below:
>>> df = pl.DataFrame({"a": [1, 2, 3, 4], "b": [1, 2, 1, 1], "c": [1, 1, 1, 1]}).lazy()
>>> df.collect()
shape: (4, 3)
┌─────┬─────┬─────┐
│ a ┆ b ┆ c │
│ --- ┆ --- ┆ --- │
│ i64 ┆ i64 ┆ i64 │
╞═════╪═════╪═════╡
│ 1 ┆ 1 ┆ 1 │
├╌╌╌╌╌┼╌╌╌╌╌┼╌╌╌╌╌┤
│ 2 ┆ 2 ┆ 1 │
├╌╌╌╌╌┼╌╌╌╌╌┼╌╌╌╌╌┤
│ 3 ┆ 1 ┆ 1 │
├╌╌╌╌╌┼╌╌╌╌╌┼╌╌╌╌╌┤
│ 4 ┆ 1 ┆ 1 │
└─────┴─────┴─────┘
>>> df.var().collect()
shape: (1, 3)
┌──────────┬──────┬─────┐
│ a ┆ b ┆ c │
│ --- ┆ --- ┆ --- │
│ f64 ┆ f64 ┆ f64 │
╞══════════╪══════╪═════╡
│ 1.666667 ┆ 0.25 ┆ 0.0 │
└──────────┴──────┴─────┘
I wish to select columns with value > 0 from LazyFrame but couldn't find the solution.
I can iterate over columns in polars dataframe then filter columns by condition as below:
>>> data.var()
shape: (1, 3)
┌──────────┬──────┬─────┐
│ a ┆ b ┆ c │
│ --- ┆ --- ┆ --- │
│ f64 ┆ f64 ┆ f64 │
╞══════════╪══════╪═════╡
│ 1.666667 ┆ 0.25 ┆ 0.0 │
└──────────┴──────┴─────┘
>>> cols = pl.select([s for s in data.var() if (s > 0).all()]).columns
>>> cols
['a', 'b']
>>> data.select(cols)
shape: (4, 2)
┌─────┬─────┐
│ a ┆ b │
│ --- ┆ --- │
│ i64 ┆ i64 │
╞═════╪═════╡
│ 1 ┆ 1 │
├╌╌╌╌╌┼╌╌╌╌╌┤
│ 2 ┆ 2 │
├╌╌╌╌╌┼╌╌╌╌╌┤
│ 3 ┆ 1 │
├╌╌╌╌╌┼╌╌╌╌╌┤
│ 4 ┆ 1 │
└─────┴─────┘
But it doesn't work in LazyFrame:
>>> data = data.lazy()
>>> data
<polars.internals.lazyframe.frame.LazyFrame object at 0x7f0e3d9966a0>
>>> cols = pl.select([s for s in data.var() if (s > 0).all()]).columns
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 1, in <listcomp>
File "/home/jasmine/miniconda3/envs/jupyternb/lib/python3.9/site-packages/polars/internals/lazyframe/frame.py", line 421, in __getitem__
raise TypeError(
TypeError: 'LazyFrame' object is not subscriptable (aside from slicing). Use 'select()' or 'filter()' instead.
The reason for doing this in LazyFrame is that we want to maximize the performance. Any advice would be much appreciated. Thanks!
polars doesn't know what the variance is until after it is calculated but that's the same time that it is displaying the results so there's no way to filter the columns reported and also have it be more performant than just displaying all the columns, at least with respect to the polars calculation. It could be that python/jupyter takes longer to display more results than fewer.
With that said you could do something like this:
df.var().melt().filter(pl.col('value')>0).collect()
which gives you what you want in one line but it's a different shape.
You could also do something like this:
dfvar=df.var()
dfvar.select(dfvar.melt().filter(pl.col('value')>0).select('variable').collect().to_series().to_list()).collect()
Building on the answer from #dean MacGregor, we:
do the var calculation
melt
apply the filter
extract the variable column with column names
pass it as a list to select
df.select(
(
df.var().melt().filter(pl.col('value')>0).collect()
["variable"]
)
.to_list()
).collect()
shape: (4, 2)
┌─────┬─────┐
│ a ┆ b │
│ --- ┆ --- │
│ i64 ┆ i64 │
╞═════╪═════╡
│ 1 ┆ 1 │
├╌╌╌╌╌┼╌╌╌╌╌┤
│ 2 ┆ 2 │
├╌╌╌╌╌┼╌╌╌╌╌┤
│ 3 ┆ 1 │
├╌╌╌╌╌┼╌╌╌╌╌┤
│ 4 ┆ 1 │
└─────┴─────┘
```
In Polars, the select and with_column methods broadcast any scalars that they get, including literals:
import polars as pl
df.with_column(pl.lit(1).alias("y"))
# shape: (3, 2)
# ┌─────┬─────┐
# │ x ┆ y │
# │ --- ┆ --- │
# │ i64 ┆ i64 │
# ╞═════╪═════╡
# │ 1 ┆ 1 │
# ├╌╌╌╌╌┼╌╌╌╌╌┤
# │ 2 ┆ 1 │
# ├╌╌╌╌╌┼╌╌╌╌╌┤
# │ 3 ┆ 1 │
# └─────┴─────┘
The agg method does not broadcast literals:
import polars as pl
df = pl.DataFrame(dict(x=[1,1,0,0])).groupby("x")
df.agg(pl.lit(1).alias("y"))
# exceptions.ComputeError: returned aggregation is a different length: 1 than the group lengths: 2
Is there an operation I can apply that will broadcast a scalar and ignore a non-scalar? Something like this:
df.agg(something(pl.lit(1)).alias("y"))
# shape: (2, 2)
# ┌─────┬─────┐
# │ x ┆ y │
# │ --- ┆ --- │
# │ i64 ┆ i64 │
# ╞═════╪═════╡
# │ 0 ┆ 1 │
# ├╌╌╌╌╌┼╌╌╌╌╌┤
# │ 1 ┆ 1 │
# └─────┴─────┘
You will need to use pl.repeat(1, pl.count()) to expand the literal to the group size.
(answer from the Polars Issue tracker - https://github.com/pola-rs/polars/issues/2987#issuecomment-1079617229)
df = pl.DataFrame(dict(x=[1,1,0,0])).groupby("x")
df.agg( pl.repeat(1, pl.count() ) ).explode(
pl.col('literal')
)
may be helpful
If I have a single column, I can sort that column within groups using the over method. For example,
import polars as pl
df = pl.DataFrame({'group': [2,2,1,1,2,2], 'value': [3,4,3,1,1,3]})
df.with_column(pl.col('value').sort().over('group'))
# shape: (6, 2)
# ┌───────┬───────┐
# │ group ┆ value │
# │ --- ┆ --- │
# │ i64 ┆ i64 │
# ╞═══════╪═══════╡
# │ 2 ┆ 1 │
# ├╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌┤
# │ 2 ┆ 3 │
# ├╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌┤
# │ 1 ┆ 1 │
# ├╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌┤
# │ 1 ┆ 3 │
# ├╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌┤
# │ 2 ┆ 3 │
# ├╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌┤
# │ 2 ┆ 4 │
# └───────┴───────┘
What is nice about operation is that it maintains the order of the groups (e.g. group=1 is still rows 3 and 4; group=2 is still rows 1, 2, 5, and 6).
But this only works to sort a single column. How do sort an entire table like this? I tried these things below, but none of them worked:
import polars as pl
df = pl.DataFrame({'group': [2,2,1,1,2,2], 'value': [3,4,3,1,1,3], 'value2': [5,4,3,2,1,0]})
df.groupby('group').sort(['value', 'value2'])
# errors
df.sort([pl.col('value').over('group'), pl.col('value2').over('group')])
# does not sort with groups
# Looking for this:
# shape: (6, 3)
# ┌───────┬───────┬────────┐
# │ group ┆ value ┆ value2 │
# │ --- ┆ --- ┆ --- │
# │ i64 ┆ i64 ┆ i64 │
# ╞═══════╪═══════╪════════╡
# │ 2 ┆ 1 ┆ 1 │
# ├╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌╌┤
# │ 2 ┆ 3 ┆ 0 │
# ├╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌╌┤
# │ 1 ┆ 1 ┆ 2 │
# ├╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌╌┤
# │ 1 ┆ 3 ┆ 3 │
# ├╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌╌┤
# │ 2 ┆ 3 ┆ 5 │
# ├╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌╌┤
# │ 2 ┆ 4 ┆ 4 │
# └───────┴───────┴────────┘
The solution to sorting an entire table in a grouped situation is pl.all().sort_by(sort_columns).over(group_columns).
import polars as pl
df = pl.DataFrame({
'group': [2,2,1,1,2,2],
'value': [3,4,3,1,1,3],
'value2': [5,4,3,2,1,0],
})
df.select(pl.all().sort_by(['value','value2']).over('group'))
df.select(
pl.all().sort_by(['value','value2']).over('group').sort_by(['group'])
)
may be helpful.