i have a button which is rotating after click on it (code is shortened to be more readable).
What is the problem ?
When user clicks button, it rotates, ( function animation() does that ) and navigate to next page, but problem is when user clicks button few times before a full rotation, then after that 1000ms it opens a lot of FriendsPageEditable and he must to go back pressing navigation back button.
What i want :
i want to this "extra sites" won't show up.
Ways to resolve this problem which i can't implement bcs i dont know how:
Disable button after this first click to navigation.
Disable it off for a period of time for example that 1000 ms.
I guess stop using Future.delayed but i dont know what we could do later.
bool buttonEnabled = true;
floatingActionButton: FloatingActionButton(
onPressed: () async {
animation();
await Future.delayed(const Duration(milliseconds: 1000));
if (buttonEnabled) {
buttonEnabled = true;
Navigator.push(
context,
MaterialPageRoute(
builder: (context) => const FriendsPageEditable()));
} else {
null;
}
},
child: const Icon(
Icons.settings,
),
),
Malak try this:
bool buttonClicked = false;
floatingActionButton: FloatingActionButton(
onPressed: () async {
// Then check if the button has been clicked
if(!buttonClicked)
buttonClicked = true;
else
return;
animation();
await Future.delayed(const Duration(milliseconds: 1000), (){
Navigator.push(
context,
MaterialPageRoute(
builder: (context) => const FriendsPageEditable()));
});
buttonClicked = !buttonClicked;
},
child: const Icon(
Icons.settings,
),
),
Related
I want my ad to show every three clicks.
The first click should show an ad.
The next two clicks should not show any ad. and then the fourth should.
This process currently works fine, the only issue is that I want to navigate to the next page after the ad closes but currently, nothing happens when I close the ad. it just remains on the current page
So basically, the first click should show the ad and navigate to the next page when the interstitial ad is closed.
the second click should navigate alone.
the third click should navigate alone.
Then restart the process.
My code is below -
CategoryCardWithImage(
title: "networks",
image: "assets/images/networks.png",
press: () {
clickCount = clickCount + 1;
bool shouldDisplayAd =
clickCount == 1 || clickCount % 3 == 0;
if (shouldDisplayAd) return _showInterstitialAd();
Navigator.push(
context,
MaterialPageRoute(builder: (context) {
return NetworksPage();
}),
);
},
),
Help fix code
I use AlertDialog
to simulate what you would like to achieve.
You could add more if..else condition in the onPressed() function to know which page will be shown after selecting.
void router() {
var aaa = showDialog(
context: context,
builder: (BuildContext context) => AlertDialog(
title: Text('MyTitle'),
content: Text('sdf'),
actions: [
TextButton(
child: Text('ok'),
onPressed: () {
Navigator.pushNamed(context, creationCategory.id);
},),
],
));
}
return Scaffold(
appBar: AppBar(
title: const Text('Record'),
leading: null,
actions: <Widget>[
IconButton(
icon: const Icon(Icons.add),
onPressed: (){
Navigator.pushNamed(context, creationCategory.id);
},
),
IconButton(
icon: const Icon(Icons.settings),
onPressed: () async {
router();
},
),
],
),
Fig1. Pushing that button to invoke void router()
Fig2. Popping Ad
Fig3. To close the Ad and then go to that specific pages.
I am new to Flutter. I made my first pop out confirmation alert dialog (Figure 1) but I want to pop another alert dialog window after.
What I am trying to achieve, it's the following: after I click Yes (Figure 2) the app would lead me to my homescreen and pop out another alert dialog.
You could create a method for the second Alert to show up, and call it when you click "YES" on the first one.
void showSecond(BuildContext context) {
return showDialog(
context: context,
builder: (BuildContext context) => AlertDialog(
title: Text("Thank you for paying with us"),
content: Icon(Icons.check_circle_outline),
actions: [
TextButton(
onPressed: () {
Navigator.of(context).pop();
},
child: const Text('Okay'),
),
],
),
);
}
and your onPressed() of "YES" in the first alert should look something like:
onPressed: () {
Navigator.push(context, MaterialPageRoute(builder: (context) => const SuccessPay()));
showSecond(context);
},
It was a bit hard to replicate your code from an image, so if something it's not accurate let me now. For the next time, post your code in a code block instead of a picture :)
you can call showAlertDialog to show second popup.(you can create new method to show second popup as content is different)This line can be added after
Navigator.of(context).pop() of first popup
You can use the .then() method. Call it if the user pressed the "YES" button.
Add value when poping your dialog like this Navigator.of(dialogCtx).pop(true);
showDialog(
context: context,
builder: (dialogCtx) => AlertDialog(
// title:
// content:
),
actions: [
TextButton(
onPressed: () {
Navigator.of(dialogCtx).pop(false);
},
child: const Text('CANCEL'),
),
TextButton(
onPressed: () {
Navigator.of(dialogCtx).pop(true);
},
child: const Text('YES'),
),
],
),
).then(
(value) => {
if (value == true)
{
// display the next dialog with the scaffolds context
},
},
);
I want to update the color of the FloatingActionButton on certain conditions(after the user update his values) I manage to set the color but only if the user click on the button where should I put the setstate or how can I achieve that?
FloatingActionButton.extended(
onPressed: (){
setState(() {
if(departureCity!=null && arrivalCity!=null && bol){
bol2=true;
Navigator.push(
context,
//MaterialPageRoute(builder: (context) => const SeatScreen()),
MaterialPageRoute(builder: (context) => BusSearchResults(departureCity,arrivalCity,_date)),
);
}
});
},
label: const Text('Search'),
backgroundColor: bol2? Color(0xff5348bf):Color(0xffd3d3d3) ,
),
bol2 = !bol2;
just write this instead of (bol2 = true ;) in your setState();
Just change the value of bol2 to the opposite every time on click like given below. And try not to wrap everything in setState() since it's unnecessary.
FloatingActionButton.extended(
onPressed: (){
setState(() {
if(bol2){
bol2=false;
}
else{
bol2=true;
}
});
if(departureCity!=null && arrivalCity!=null){
bol2=true;
Navigator.push(
context,
MaterialPageRoute(builder: (context) =>BusSearchResults(departureCity,arrivalCity,_date)),
);
}
},
label: const Text('Search'),
backgroundColor: bol2? Color(0xff5348bf):Color(0xffd3d3d3),
),
I want to show an interstitial ads in 10 clicks. Is there a way to do this? Or how I can show only 1 time at the opening of the app? I'm just trying to find how to use it.
ElevatedButton(
child: Text("Ads"),
onPressed: () {
_interstitialAd.show();
Navigator.push(context,
MaterialPageRoute(builder: (context) => PageTwo()));
},
),
You need to keep a counter in your state somewhere and and call the method to show the ad only when it's a multiple of 10.
//A field of your state class
int counter = 0;
//...somewhere in build
ElevatedButton(
child: Text("Ads"),
onPressed: () {
if(counter%10 == 0) {
_interstitialAd.show();
}
counter++;
Navigator.push(context,
MaterialPageRoute(builder: (context) => PageTwo()));
},
),
I already read countless links like this one but it does not help.
The use case is very simple, I want to run a function AFTER the alert box has been dismissed.
void dummyFunc() {
sleep(Duration(seconds:3));
print("done");
}
Future<bool> displayDialog() async {
return showDialog<bool>(
context: context,
barrierDismissible: false, // user must tap button!
builder: (BuildContext context) {
return AlertDialog(
title: Text('AlertDialog Title'),
content: SingleChildScrollView(
child: ListBody(
children: <Widget>[
Text('This is a demo alert dialog.'),
Text('Would you like to approve of this message?'),
],
),
),
actions: <Widget>[
FlatButton(
child: Text('Decline'),
onPressed: () {
Navigator.of(context).pop(false);
},
),
FlatButton(
child: Text('Approve'),
onPressed: () {
Navigator.of(context).pop(true);
},
),
],
elevation: 24.0,
shape:RoundedRectangleBorder(),
);
},
);
}
var button = AnimatedOpacity(
opacity: 1.0,
duration: Duration(milliseconds: 500),
child: FloatingActionButton(
tooltip: 'Start',
child: Icon(iconShape),
onPressed: () async {
bool shouldUpdate = await displayDialog();
print(shouldUpdate);
if (shouldUpdate)
dummyFunc();
})
);
But the alert dialog is dismissed 3sd after.
Kindly let me know what I am doing wrong, Thank you~
I think this is happening because you are using sleep. Instead of that use Future delay.
void dummyFunc() {
print("done");
}
If you don't want delay, then you can also remove this future, this function will executed after dialog box dismissed.
Sleep will hold the process, that’s why you are facing this error.
Solved it thanks to Viren who gave me a good intuition, Timer works also nicely if you are not using a loop:
void dummyFunc() {
Timer(Duration(seconds: 3), () {
print("done");
});
}
Edit: Actually Viren's answer work better with loops! This can work also. Just avoid sleep. Spent 3h on this, now I hate sleep().