CREATE TABLE youth(
yh_id int NOT NULL,
surname VARCHAR(30) NOT NULL,
post VARCHAR(30) NOT NULL,
PRIMARY KEY (yh_id), REFERENCES members (mbrs_id) FOREIGN KEY (mbrs_id);
ERROR: syntax error at or near "REFERENCES"
LINE 5: PRIMARY KEY (yh_id), REFERENCES members (mbrs_id) FOREIGN ...
^
SQL state: 42601
Character: 128
Here is an example with the correct syntax.
create table members (
mbrs_id int primary key);
CREATE TABLE youth(
yh_id int NOT NULL,
surname VARCHAR(30) NOT NULL,
post VARCHAR(30) NOT NULL,
CONSTRAINT pk_youth_yh_id PRIMARY KEY (yh_id),
CONSTRAINT fk_youth_members_mbrs_id FOREIGN KEY (yh_id) REFERENCES members (mbrs_id) );
✓
✓
insert into members values(1);
insert into youth values
(1,'Jones','manager');
1 rows affected
1 rows affected
insert into youth values
(2,'Smith','chairman');
ERROR: insert or update on table "youth" violates foreign key constraint "fk_youth_members_mbrs_id"
DETAIL: Key (yh_id)=(2) is not present in table "members".
db<>fiddle here
Related
I can not add a referential constraint, both tables has the two columns id and version as primary key. I will only check the integrity that the row is existing without checking version.
CREATE TABLE TABLEE
(ID INTEGER NOT NULL,
VERSION INTEGER NOT NULL,
PRIMARY KEY (ID , VERSION);
CREATE TABLE CHAIR
(ID INTEGER NOT NULL,
VERSION INTEGER NOT NULL,
ID_TABLEE INTEGER,
PRIMARY KEY (ID , VERSION);
ALTER Chair
ADD constraint MYC FOREIGN KEY (ID)
REFERENCES TABLEE (ID)
ON DELETE RESTRICT
Got this error
[Code: -573, SQL State: 42890] A column list specified in the references clause of constraint "MYC " does not identify a unique constraint of the parent table or nickname "TABLEE".. SQLCODE=-573, SQLSTATE=42890, DRIVER=4.28.11
The problem here is that Tablee its primary key consists of two columns id and version. But the integrity check should only be made on the referenced id, not version.
To establish a foreign key on a table the referenced column needs to:
Be a primary key on the other table.
...or at least act as one.
Since you already have a primary key on the referenced table, you can use the second approach and add a UNIQUE and NOT NULL constraints on ID.
For example:
CREATE TABLE TABLEE (
ID INTEGER NOT NULL,
VERSION INTEGER NOT NULL,
PRIMARY KEY (ID , VERSION),
constraint uq1 unique (id) -- added UNIQUE constraint on ID
);
CREATE TABLE CHAIR (
ID INTEGER NOT NULL,
VERSION INTEGER NOT NULL,
ID_TABLEE INTEGER,
PRIMARY KEY (ID , VERSION)
);
ALTER table Chair
ADD constraint MYC FOREIGN KEY (ID)
REFERENCES TABLEE (ID)
ON DELETE RESTRICT;
See running example at db<>fiddle.
Note: If you want ID to have repeated values over the table, then ID is not a key, and cannot be referenced as one.
I'm trying to transform my MySQL design to PostgreSQL but when I try to create the table "index":
CREATE TABLE "model1"."index" (
"id_index" INT GENERATED ALWAYS AS IDENTITY ,
"index_name" VARCHAR(5) NOT NULL,
"index_type_id_index_type" INT NOT NULL,
"index_provider_id_index_provider" INT NOT NULL,
"miseq" VARCHAR(45) NOT NULL,
"nextseq" VARCHAR(45) NOT NULL,
PRIMARY KEY ("id_index"),
CONSTRAINT "fk_index_index_type"
FOREIGN KEY ("index_type_id_index_type")
REFERENCES "model1"."index_type" ("id_index_type")
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT "fk_index_index_provider"
FOREIGN KEY ("index_provider_id_index_provider")
REFERENCES "model1"."index_provider" ("id_index_provider")
ON DELETE NO ACTION
ON UPDATE NO ACTION);
I got this error: ERROR: there is no unique constraint matching given keys for referenced table "index".
The two tables containing the foreign keys were created before the "index" table:
CREATE TABLE "model1"."index_type" (
"id_index_type" INT GENERATED ALWAYS AS IDENTITY ,
"name" VARCHAR(3) NOT NULL,
PRIMARY KEY ("id_index_type"));
CREATE TABLE "model1"."index_provider" (
"id_index_provider" INT GENERATED ALWAYS AS IDENTITY ,
"name" VARCHAR(40) NOT NULL,
PRIMARY KEY ("id_index_provider"));
Solved. The error was in another table as #a_horse_with_no_name suggested.
cannot add foreign key constraint to table
create table users
(
user_id int auto_increment primary key not null,
username varchar(50) unique null ,
email varchar(50) unique ,
passwords varchar(50) not null,
login_status boolean not null
);
create table category (
category_id int primary key not null,
category_name varchar(50) not null
);
create table answers (
id_answer int auto_increment primary key not null,
answer boolean not null
);
create table questions (
question_id int primary key not null,
category_name varchar(50) not null,
content varchar(50) not null ,
foreign key (category_name) references category (category_name)
);
You get this error because there's no index on category_name in the category table. Change that CREATE statement as follows:
create table category (
category_id int primary key not null,
category_name varchar(50) not null,
KEY category_name_index (category_name)
);
From the docs (8.0 version, but the statement is true for older versions):
MySQL requires indexes on foreign keys and referenced keys so that foreign key checks can be fast and not require a table scan. In the referencing table, there must be an index where the foreign key columns are listed as the first columns in the same order. Such an index is created on the referencing table automatically if it does not exist. This index might be silently dropped later, if you create another index that can be used to enforce the foreign key constraint. index_name, if given, is used as described previously.
Also, you're using a varchar(50) as your foreign key, which is not usually a great idea for a variety of reasons. You probably want to use a numeric value, such as category_id, instead.
I try to create code for postgresql
CREATE TABLE kaart (
kaartid integer NOT NULL,
naam character varying,
saldo real,
kaarthouderid integer
);
CREATE TABLE kaart_product (
kaartkaartid integer,
productid2 integer
);
CREATE TABLE kaarthouder (
id integer NOT NULL,
naam character varying(255),
naw character varying(255),
geslacht "char"
);
CREATE TABLE product (
naam character varying,
id integer NOT NULL
);
ALTER TABLE ONLY kaart
ADD CONSTRAINT kaart_pkey PRIMARY KEY (kaartid);
ALTER TABLE ONLY kaarthouder
ADD CONSTRAINT kaarthouder_pkey PRIMARY KEY (id);
ALTER TABLE ONLY product
ADD CONSTRAINT product_pkey PRIMARY KEY (id);
ALTER TABLE ONLY kaart
ADD CONSTRAINT kaartco FOREIGN KEY (kaartid) REFERENCES kaarthouder(id) ON UPDATE CASCADE ON DELETE CASCADE;
ALTER TABLE ONLY kaart_product
ADD CONSTRAINT kaartkaartidco FOREIGN KEY (kaartkaartid) REFERENCES kaart(kaartid) ON UPDATE CASCADE ON DELETE CASCADE;
ALTER TABLE ONLY kaart_product
ADD CONSTRAINT productidco FOREIGN KEY (kaartkaartid) REFERENCES product(id) ON UPDATE CASCADE ON DELETE CASCADE;
INSERT INTO kaart VALUES (1, 'Sander',50.00 ,1);
INSERT INTO kaart_product VALUES (1,1);
INSERT INTO kaarthouder VALUES (1, 'Sander','test,testing','man');
INSERT INTO product VALUES ('studentenproduct',1);
But whenever i try to run it it gives me this error:
23503: insert or update on table "kaart" violates foreign key constraint "kaartco"
But i really dont know why this happens since it is the same to the other foreign keys that are below it
So can someone help me fix this?
You try to link to a product and a kaart that doesn't exist yet.
Move:
INSERT INTO kaart_product VALUES (1,1);
Two lines down under:
INSERT INTO product VALUES ('studentenproduct',1);
That should do the job for you.
Try to search google for forgein key contstraints and how they work.
I have defined these tables:
CREATE TABLE "public".category (id BIGSERIAL NOT NULL, name varchar(255) NOT NULL, PRIMARY KEY (id));
CREATE UNIQUE INDEX category_name ON "public".category (name);
CREATE TABLE "public".clusters (id BIGSERIAL NOT NULL, name varchar(255) NOT NULL, PRIMARY KEY (id));
CREATE INDEX clusters_name ON "public".clusters (name);
CREATE TABLE "public".keywords (id BIGSERIAL NOT NULL, text varchar(255) NOT NULL, category_id int8 NOT NULL, top_results int4, cluster_id int8, month_requests int4, click_cost float8, PRIMARY KEY (id));
CREATE INDEX keywords_text ON "public".keywords (text);
ALTER TABLE "public".keywords ADD CONSTRAINT FKkeywords488682 FOREIGN KEY (cluster_id) REFERENCES "public".clusters (id);
ALTER TABLE "public".keywords ADD CONSTRAINT FKkeywords446526 FOREIGN KEY (category_id) REFERENCES "public".category (id) ON UPDATE CASCADE ON DELETE CASCADE;
added one record to category table:
INSERT INTO "public".category(id, name) VALUES (1, 'Test');
And now when I try to add record to keyword table
insert into "public"."keywords" ( "category_id", "text") values ( 1, 'testkey')
I got error:
ERROR: constraint 16959 is not a foreign key constraint
When I do
select * FROM pg_constraint;
I can't see constraint with this id. I can't understand what is the cause of this problem.