I use spring boot with spring data jpa and mariadb 10.7
I have a class with a lot of relation.
public class Testament {
#Id
#GeneratedValue(generator="testament_id_seq")
#SequenceGenerator(name="testament_id_seq",sequenceName="testament_id_seq", allocationSize=1)
Long id;
#OneToOne
#MapsId
#JoinColumn(name = "user_id")
User user;
TestamentInfo testamentInfo;
}
public class TestamentInfo{
#OneToOne(mappedBy="testament", fetch=FetchType.LAZY, optional=false)
TestamentOwner owner;
#OneToMany(mappedBy="testament", orphanRemoval = true)
List<Donation> donations;
#OneToMany(mappedBy="testament", orphanRemoval = true)
List<Person> executors;
#OneToMany(mappedBy="testament", orphanRemoval = true)
List<Person> alternativeExecutor;
#OneToMany(mappedBy="testament", orphanRemoval = true)
List<RestHeritage> restHeritages;
#OneToMany(mappedBy="testament", orphanRemoval = true)
List<String> otherDisposition;
LocalDate signedDate;
String signedCity;
#CreatedDate
LocalDate createdAt;
#LastModifiedDate
LocalDate updatedAt;
}
This class is used to generated a pdf document.
A lot of query is done on the db.
I would like to have TestamentInfo like a json column in db.
Related
Suppose we have audited entities with #OneToOne relation:
#Entity
#Audited
#Table(name = "product")
public class Product {
#Id
#GeneratedValue
#Column(name = "id")
private Long id;
#Column(name = "name")
private String name;
#Column(name = "active")
private boolean active;
#OneToOne(mappedBy="product", cascade = CascadeType.ALL, fetch = FetchType.LAZY, orphanRemoval = true)
private ProductPrice productPrice;
}
#Audited
#Entity
#Table(name = "product_price")
public class ProductPrice {
#Id
#GeneratedValue
#Column(name = "id")
private Long id;
#Column(name = "amount")
private Long amount;
#OneToOne(optional = false, fetch = FetchType.LAZY)
#JoinColumn(name = "product_id", nullable = false)
private Product product;
}
And RevisionService with the method to get revisions and find changes:
#Transactional
public Page<Revision<Long, Product>> getGroupRevisions(Long productId, int page) {
Page<Revision<Long, Product>> revisions = productRepository.findRevisions(productId, PageRequest.of(page, 5, RevisionSort.desc()));
Long priceId = revisions.getContent().get(0).getEntity().getProductPrice().getId();
Page<Revision<Long, ProductPrice>> priceRevisions = productPriceRepository.findRevisions(priceId, PageRequest.of(page, 5, RevisionSort.desc()));
return revisions;
}
Now, If I create new Product and ProductPrice records and then make changes into Product more then 5 times (5 RevInfo records would generated), I get exception:
java.lang.IllegalArgumentException: Entity must not be null!
at org.springframework.util.Assert.notNull(Assert.java:198)
at org.springframework.data.history.AnnotationRevisionMetadata.<init>(AnnotationRevisionMetadata.java:55)
at org.springframework.data.envers.repository.support.EnversRevisionRepositoryImpl.getRevisionMetadata(EnversRevisionRepositoryImpl.java:237)
at org.springframework.data.envers.repository.support.EnversRevisionRepositoryImpl.lambda$toRevisions$1(EnversRevisionRepositoryImpl.java:223)
at java.base/java.util.stream.ReferencePipeline$3$1.accept(ReferencePipeline.java:195)
at java.base/java.util.HashMap$EntrySpliterator.forEachRemaining(HashMap.java:1837)
at java.base/java.util.stream.AbstractPipeline.copyInto(AbstractPipeline.java:484)
at java.base/java.util.stream.AbstractPipeline.wrapAndCopyInto(AbstractPipeline.java:474)
at java.base/java.util.stream.ReduceOps$ReduceOp.evaluateSequential(ReduceOps.java:913)
at java.base/java.util.stream.AbstractPipeline.evaluate(AbstractPipeline.java:234)
at java.base/java.util.stream.ReferencePipeline.collect(ReferencePipeline.java:578)
at org.springframework.data.envers.repository.support.EnversRevisionRepositoryImpl.toRevisions(EnversRevisionRepositoryImpl.java:226)
at org.springframework.data.envers.repository.support.EnversRevisionRepositoryImpl.getEntitiesForRevisions(EnversRevisionRepositoryImpl.java:196)
at org.springframework.data.envers.repository.support.EnversRevisionRepositoryImpl.findRevisions(EnversRevisionRepositoryImpl.java:163)
After debugging I saw that this "null" entity was proxied by Hibernate and Spring Data envers could not resolve revision number in this point:
Number revNo = this.enversService.getRevisionInfoNumberReader().getRevisionNumber(revision);
Here is the link to github test project: https://github.com/aquariusmaster/spring-data-envers-bug
So my question is this a bug in Spring Data Envers or I miss something in the configuration?
As spring-data-envers team replied, upgrading boot version to 2.3.1.RELEASE solve the problem:
https://github.com/spring-projects/spring-data-envers/issues/34#issuecomment-651681687
I have the following entity class.
#Data
#EqualsAndHashCode(callSuper=false)
#ToString(callSuper=true)
#Entity
#Table(name = "storeitem")
public class StoreItem extends SellableStoreItem {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private UUID id;
#EqualsAndHashCode.Exclude
#ToString.Exclude
#ManyToOne
#JoinColumn(name = "store_id")
private Store store;
#EqualsAndHashCode.Exclude
#ToString.Exclude
#ManyToOne
#JoinColumn(name = "storeitemcategory_id", nullable = true)
private StoreItemCategory storeItemCategory;
#EqualsAndHashCode.Exclude
#OneToMany(fetch = FetchType.EAGER, mappedBy = "storeItem")
private List<StoreItemTranslation> storeItemTranslationList = new ArrayList<>();
#EqualsAndHashCode.Exclude
#OneToMany(mappedBy = "storeItem",
cascade = CascadeType.ALL,
orphanRemoval = true)
private List<StoreItemOptionCollectionSelection> storeItemOptionCollectionSelections = new ArrayList<>();
#EqualsAndHashCode.Exclude
#Column(name = "uid")
private UUID uid = UUID.randomUUID();
#EqualsAndHashCode.Exclude
#CreationTimestamp
#Column(name = "createddate", nullable = false)
private LocalDateTime createdDate;
#EqualsAndHashCode.Exclude
#Column(name = "iscurrent", nullable = false)
private boolean isCurrent = true;
And in my service layer, I do the following.
private StoreItemResponse setStoreItemCreate(StoreItemDTO storeItemDTO, Store store, StoreItemCategory storeItemCategory) {
StoreItem storeItem = new StoreItem(storeItemDTO, store, storeItemCategory);
if(storeItemDTO.getUid() != null){
storeItem.setUid(storeItemDTO.getUid());
}
storeItem = storeItemRepository.save(storeItem);
// Create Translations for store Item
for (TranslationDTO translationDTO : storeItemDTO.getTranslationDTOs()) {
StoreItemTranslation translation = new StoreItemTranslation(translationDTO, storeItem);
storeItemTranslationRepository.save(translation);
}
return new StoreItemResponse(storeItem.getId(), DtoResponseStatus.OK);
}
However, when testing the code, I notice that there are times (not often but some cases) I see duplicate records (with different id) are being saved to database. And the duplicates are saved 2ms apart so I suspect storeItem = storeItemRepository.save(storeItem); created the duplicate records.
Why would this happen?
I have a case where I need to create a compatibility mapping between computer hardware parts.
The idea is to check for example if ComputerPart1(motherboard_yy) is compatible with ComputerPart1(hardrive_xx)
So I have an Entity called ComputerPart
#Entity
public class ComputerPart {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
#Column(nullable = false)
private String name;
#Column(nullable = false, unique = true)
private String serialNumber;
#Column(nullable = false)
private String manufacturer;
// getter and setters
I'm not sure about the best way to do next.
Do I create an object map of computerParts with a List?
Map<ComputerPart, List<ComputerPart>>
Or Do I create another Entity Called Compatible?
The solution that I will probably chose is having a list of the same Entity Type:
#Entity
public class ComputerPart {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
#Column(nullable = false)
private String name;
#Column(nullable = false, unique = true)
private String serialNumber;
#Column(nullable = false)
private String manufacturer;
#Column(nullable = false)
private String manufacturer;
// What #Annotation to put here?
//is it #ManyToMany ?
Set<ComputerPart> compatibles;
I'm not sure about the Annotation parameters.
#ManyToMany(targetEntity = ComputerPart.class, fetch = FetchType.LAZY)
#JoinTable(name = "??", joinColumns = {
#JoinColumn(name = "??", referencedColumnName = "??")},
inverseJoinColumns = {
#JoinColumn(name = "??", referencedColumnName = "??")})
I am having an issue in setting up a many to many relationship in my entities. And I don't understand why
failed; nested exception is org.hibernate.AnnotationException: mappedBy reference an unknown target entity property: cardgame.bean.User.card in cardgame.bean.Card.users
My Entities:
#MappedSuperclass
#Data
public class BaseEntity implements Serializable {
#Id
#Column(name = "id", nullable = false, unique = true)
private String id;
public BaseEntity() {
this.id = UUID.randomUUID().toString();
}
}
My user emtity:
#Data
#Entity
#Table(name = "users")
public class User extends BaseEntity {
#Column(name = "username", nullable = false, unique = true)
private String username;
#Column(name = "uuid", nullable = false)
private String uuid;
#Column(name = "email", nullable = false, unique = true)
private String email;
#OneToMany(mappedBy = "user", fetch = FetchType.LAZY, cascade = CascadeType.ALL, orphanRemoval = true)
private List<Card> cards;
#Column(name = "isActive", nullable = false)
private boolean isActive;
}
My card entity:
#Data
#Entity
#Table(name = "cards")
public class Card extends BaseEntity {
#OneToMany(mappedBy = "card")
private List<User> users;
#Column(name = "strength", nullable = false)
private int strength;
#Column(name = "isActive", nullable = false)
private boolean isActive;
}
The users and cards tables have a many-to-many relationship via user_card table:
#Data
#Entity
#Table(name = "user_card")
public class UserCard implements Serializable {
#Id
#ManyToOne
#JoinColumn(name = "user_id", nullable = false)
private User user;
#Id
#ManyToOne
#JoinColumn(name = "card_id", nullable = false)
private Card card;
#Column(name = "cardCount", nullable = false)
private int cardCount;
}
What am i doing incorrect. Please help me
I'm Using JPA 2.1. I have 3 entities: Dr01 , Dr02 and Dr03 with the following structure:
public class Dr01 implements Serializable {
#OneToMany(cascade = CascadeType.ALL, mappedBy = "dr01")
private List<Dr02> dr02List;
}
public class Dr02 implements Serializable {
#OneToMany(cascade = CascadeType.ALL, mappedBy = "dr02")
private List<Dr03> dr03List;
#JoinColumn(name = "DR2CLM", referencedColumnName = "DR1CLM", insertable = false, updatable = false)
#ManyToOne(optional = false)
private Dr01 dr01;
}
public class Dr03 implements Serializable {
#JoinColumns({
#JoinColumn(name = "DR3CLM", referencedColumnName = "DR2CLM", insertable = false, updatable = false),
#JoinColumn(name = "DR3PTFN", referencedColumnName = "DR2PTFN", insertable = false, updatable = false)})
#ManyToOne(optional = false)
private Dr02 dr02;
private elementOBJ element;
}
public class elementOBJ implements Serializable {
#Column(name = "XXX")
private int id;
#Column(name = "YYY")
private int status;
}
I want to select from Dr01 and get only the Dr03 objects that have element objects which contains a value of 1 inside the status field.
How do I retrieve dr03List filtered by it's status value? (filtered not after the select).
Thank's In Advance.
Options that may be of assistance:
Create a DB view based on status of DR03 table and map your
entity to that.
Use JPA Inheritance using status as a
DiscriminatorColumn.
If using Hibernate use the non-JPA #Where
annotation to filter the collection