Hi everyone i build flutter app to download video .
the app save all video in this path :
/storage/emulated/0/Android/data/com.test.play/files/
and now i work to video downloaded page
how can i read just videos in app path
and display the videos in list ?
You can use file_picker to pick multiple files.
FilePickerResult? result = await FilePicker.platform.pickFiles(allowMultiple: true);
if (result != null) {
List<File> files = result.paths.map((path) => File(path)).toList();
} else {
// User canceled the picker
}
or if you want to pick files with extension filter
FilePickerResult? result = await FilePicker.platform.pickFiles(
type: FileType.custom,
allowedExtensions: ['mp4'],
);
Related
How to pick file with any extensions using of file_picker package. And filter with customize paramater extensions even if I open any directory.
Currently, it's working in case the first open. but when I change to other directory it still show files that I don't want.
Please you help to advice me how can I acheive this case.
Thank you.
Example:
When browse files by filter .pdf
When I choose Gallery.
.
Show .jpg extension. Filter .pdf is not working
Future<void> loadFiles(List<String> extensions) async {
try {
var platformFiles = await FilePicker.platform.pickFiles(type: FileType.custom, allowMultiple: true, allowedExtensions: extensions);
if (platformFiles != null) {
files.value = platformFiles.files;
Get.to(() => const ConverterScreen());
}
} catch {
print("[ERROR]${e.toString}");
}
}
Actually I'm very new in Flutter-Dart.
And I'm writing an web app. So I should pick images from file path in web. And I should convert the image to base64 code. because I will add the image to my PHP server with my php codes. PHP code is ready. but I don't know a lot of information about pick images and convert base64. Can anybody help me.
Add file_picker: ^4.3.0 to pubspec.yaml and try this:
void pickFile(){
FilePickerResult? result = await FilePicker.platform.pickFiles(
type: FileType.custom,
);
if (result != null) {
Uint8List? file = result.files.first.bytes!;
final x = base64Encode(file);
//do what you want with x.
}
}
How can I allow the user to save a file to a specific folder in Flutter?
I have built a simple desktop app for Mac that returns a file from an API.
Currently, it saves the file to a caches directory.
try {
io.Directory saveDir = await getTemporaryDirectory();
String filePath = saveDir.path;
io.File returnedFile = new io.File('$filePath/$filename.xlsx');
await returnedFile.writeAsBytes(result.bodyBytes);
print(saveDir);
} catch (e) {
print(e);
}
I played around with my original code and that provided by #Pavel and managed to write my solution to saving files to a custom user-picked directory in this fashion.
The first part opens a file picker dialogue that returns a path to a directory.
The second part provides the path to the File class that then writes the file to that directory.
Hope this helps anyone trying to save files.
String? outputFile = await FilePicker.platform.saveFile(
dialogTitle: 'Save Your File to desired location',
fileName: filename);
try {
io.File returnedFile = io.File('$outputFile');
await returnedFile.writeAsBytes(responsefile.bodyBytes);
} catch (e) {}
Use https://pub.dev/packages/file_picker
String? outputFile = await FilePicker.platform.saveFile(
dialogTitle: 'Please select an output file:',
fileName: 'output-file.pdf',
);
if (outputFile == null) {
// User canceled the picker
}
I have this page where the camera is initialized and ready with a button that will record and stop the video, so I tried this :
FlatButton(
onPressed: () => {
!isRecording
? {
setState(() {
isRecording = true;
}),
cameraController.prepareForVideoRecording(),
cameraController.startVideoRecording('assets/Videos/test.mp4')
}
: cameraController.stopVideoRecording(),
},
............
but throws this error : nhandled Exception: CameraException(videoRecordingFailed, assets/Videos/test.mp4: open failed: ENOENT (No such file or directory)).
I don't understand, I don't want to open this file I want to save it there, Is there sth wrong with my code ?
In the new version, static method startRecordingVideo doesn't take any string parameter.
When you want to start the recording just see whether a video is already getting recorded, if not start
if (!_controller.value.isRecordingVideo) {
_controller.startVideoRecording();
}
and when you want to finish the recording you can call the static method stopVideoRecording() and it will give you a object of the class XFile, it will have the path to your video.
if (_controller.value.isRecordingVideo) {
XFile videoFile = await _controller.stopVideoRecording();
print(videoFile.path);//and there is more in this XFile object
}
This thing has worked for me. I am new to flutter please improve my answer if you know more.
You are trying to save a video in your assets folder which is not possible ,
What you need to do is to save to device locally either common folders like downloads or app directory.
Here is an example of how to go about it
dependencies:
path_provider:
Flutter plugin for getting commonly used locations on host platform
file systems, such as the temp and app data directories.
We will be saving the video to app directory.
We need to get the path to the directory where the file is or will be. Usually a file is put in the application's document directory, in the application's cache directory, or in the external storage directory. To get the path easily and reduce the chance of type, we can use PathProvider
Future<String> _startVideoRecording() async {
if (!controller.value.isInitialized) {
return null;
}
// Do nothing if a recording is on progress
if (controller.value.isRecordingVideo) {
return null;
}
//get storage path
final Directory appDirectory = await getApplicationDocumentsDirectory();
final String videoDirectory = '${appDirectory.path}/Videos';
await Directory(videoDirectory).create(recursive: true);
final String currentTime = DateTime.now().millisecondsSinceEpoch.toString();
final String filePath = '$videoDirectory/${currentTime}.mp4';
try {
await controller.startVideoRecording(filePath);
videoPath = filePath;
} on CameraException catch (e) {
_showCameraException(e);
return null;
}
//gives you path of where the video was stored
return filePath;
}
I have an app that takes a photo.
I need that photo to be stored where all my assets/images/photos are.
So basically my question is :
a) how can I find the path where these assets are (on the phone)?
b) how can I add files to that same path?
Thanks
As per my knowledge you can not store image in assets package. Just because of when we build android/ios app after that assets folder is read only.
You need to store image in local mobile storage OR cloud OR catch memory
1) You can get storage path using :
Future<String> getStorageDirectory() async {
if (Platform.isAndroid) {
return (await getExternalStorageDirectory()).path; // OR return "/storage/emulated/0/Download";
} else {
return (await getApplicationDocumentsDirectory()).path;
}
}
2) Add image in path
createImage() async{
String dir= getStorageDirectory();
File directory = new File("$dir");
if (directory.exists() != true) {
directory.create();
}
File file = new File('$directory/image.jpeg');
var newFile = await file.writeAsBytes(/* image bytes*/);
await newFile.create();
}