Shuffle a list in Flutter - flutter

Question

I want to shuffle list called "Travel". So, user will see random members of widget every time.
However, when i do final _list = Travel.generateMembersMain().shuffle(); I came error on this line on widget: itemCount: _list.length, and var travel = _list[index];
This expression has a type of 'void' so its value can't be used.
I will be so happy if someone can help.
List Class:
class Travel { String name;
String location;
String url;
String placedetails_start;
String placedetails_end;
String places_url;
Travel(this.name,
this.location,
this.url,
this.placedetails_start,
this.placedetails_end,
this.places_url,);
static List<Travel> generateMembersMain() {
return [
Travel("Place 1", "XXX", "XXXX",
"XXXXX", "XXXXXX", "XXXXXXX"),
Travel("Place 2", "XXX", "XXXX",
"XXXXX", "XXXXXX", "XXXXXXX"),
]; }
Widget:
class Travelblog extends StatelessWidget {
final _list = Travel.generateMembersMain();
final _pageCtrl = PageController(viewportFraction: 0.9);
#override
Widget build(BuildContext context) {
return PageView.builder(
controller: _pageCtrl,
itemCount: _list.length,
itemBuilder: (context, index) {
var travel = _list[index];
return GestureDetector(
onTap: () {
Navigator.of(context)
.push(MaterialPageRoute(builder: (context) {
return DetailPage(
travel: travel,
);
}));
},
child: Stack(
children: [
Padding(
padding:
const EdgeInsets.only(top: 10, right: 20, bottom: 30),
child: ClipRRect(
borderRadius: BorderRadius.circular(5),
child: Image.asset(travel.url,
width: MediaQuery.of(context).size.width,
fit: BoxFit.cover),
),
),
Positioned(
bottom: 50,
left: 15,
child: Column(
crossAxisAlignment: CrossAxisAlignment.start,
children: [
Material(
color: Colors.transparent,
child: Text(
travel.location,
style:
TextStyle(color: Colors.white, fontSize: 20),
)),
Material(
color: Colors.transparent,
child: Text(
travel.location,
style: TextStyle(
color: Colors.white,
fontWeight: FontWeight.bold,
fontSize: 35),
)),
],
),
),
Positioned(
bottom: 0,
right: 30,
child: Container(
width: 60,
height: 60,
decoration: BoxDecoration(
color: Colors.deepOrange,
borderRadius: BorderRadius.circular(30)),
child: Icon(
Icons.arrow_forward,
color: Colors.white,
size: 30,
),
),
)
],
));
});
}
}

Answer 1

change generateMembersMain to
static List<Travel> generateMembersMain() {
var travels = [
Travel("Place 1", "XXX", "XXXX", "XXXXX", "XXXXXX", "XXXXXXX"),
Travel("Place 2", "XXX", "XXXX", "XXXXX", "XXXXXX", "XXXXXXX"),
];
travels.shuffle();
return travels;
}
Hope helpful to you.

Answer 2

I found the answer, sorry for bothering here.
I write to shuffle() inside of widget:
Widget build(BuildContext context) {
_list.shuffle(); //Here
return PageView.builder(
controller: _pageCtrl,
itemCount: _list.length,
itemBuilder: (context, index) {
var travel = _list[index];

Answer 3

I generally keep in mind these two simple rules when I look for a suitable List method:
Some List methods return a value, however, some do not.
Also, some
of them change the list, but some do not.
For example, the return type of shuffle is void. And it changes the list also.
void shuffle(
[Random? random]
)
Another example:
The return type is bool and it also changes the list (removes the item)
bool remove(
Object? value
)
Another one: firstWhere
Returns the first instance/Element(E below) searched for, however, it has no effect on the list.
E firstWhere(
bool test(E element),
{E orElse()?}
)