Retrieving file information of specific date using powershell - powershell

Question

I have a base folder as:
D:\St\Retail\AMS\AMS\FTP-FromClient\AMS
It contains various folders of dates:
2022-04-01
2022-04-02
...
...
2022-02-02
2021-05-05
2019-04-12
And each of these folders contains own files inside the folder. So, I want to retrieve all the filename inside the folder if it has 2022-04. So if the folder has '2022-04' as the base name ,I need to retreive all the file inside the folder like '2022-04-01','2022-04-02','2022-04-03'. The way I tried is:
cls
$folerPath = 'D:\St\Retail\AMS\AMS\FTP-FromClient\AMS'
$files = Get-ChildItem $folerPath
[System.Collections.ArrayList]$data = #()
foreach ($f in $files) {
$a = Get-ChildItem $f.FullName
foreach ($inner in $a) {
echo $inner.FullName
$outfile = $inner.FullName -match '*2022-04*'
$datepart = $inner.FullName.split('\')[-1]
if ($outfile) {
$data.add($datepart + '\' + $inner.Name.Trim())
}
}
}
My final $data may contains like this:
2022-04-01/abc.txt
2022-04-02/cde.pdf
2022-04-03/e.xls

Answer 1

You can do this by first collecting the directories you want to explore and then loop over these to get the files inside.
Using a calculated property you can output in whatever format you like:
$folderPath = 'D:\St\Retail\AMS\AMS\FTP-FromClient\AMS'
$data = Get-ChildItem -Path $folderPath -Filter '2022-04*' -Directory | ForEach-Object {
$dir = $_.Name
(Get-ChildItem -Path $_.FullName -File |
Select-Object #{Name = 'FolderFile'; Expression = {'{0}\{1}' -f $dir, $_.Name}}).FolderFile
}
After this, $data would be a string array with this content:
2022-04-01\abc.txt
2022-04-02\cde.pdf
2022-04-03\e.xls

Answer 2

By using wildcards for both directory and file name, you only need a single Get-ChildItem call:
$folderPath = 'D:\St\Retail\AMS\AMS\FTP-FromClient\AMS'
$folderDate = '2022-04'
[array] $data = Get-ChildItem "$folderPath/$folderDate*/*" -File | ForEach-Object{
# Join-Path's implicit output will be captured as an array in $data.
Join-Path $_.Directory.Name $_.Name
}
$data will be an array of file paths like this:
2022-04-01\abc.txt
2022-04-02\cde.pdf
2022-04-03\e.xls
Notes:
[array] $data makes sure that the variable always contains an array. Otherwise PowerShell would output a single string value when only a single file is found. This could cause problems, e. g. when you want to iterate over $data by index, you would iterate over the characters of the single string instead.
To make this answer platform-independent I'm using forward slashes in the Get-ChildItem call which work as path separators under both Windows and *nix platforms.
Join-Path is used to make sure the output paths use the expected default path separator (either / or \) of the platform.