How to convert numbers to letters in swift? - swift

Question

I'm stuck help. You have to use strings, but I haven't really found a logical way to make this work well.
var letters = ["Zero","One","Two","Three","Four","Five","Six","Seven","Eight","Nine","Ten"]
var str:String
print("Enter a number from 0 to 10: ")
str = readLine()!
print (letters[0])
...
print("Enter a number from 0 to 10: ")
str = readLine()!
print (letters[10])

Answer 1

Maybe this api is similar but not exactly what you need.
https://developer.apple.com/documentation/foundation/numberformatter/style/spellout
let formatter: NumberFormatter = {
let nf = NumberFormatter()
nf.numberStyle = .spellOut
nf.locale = Locale(identifier: "en_US")
return nf
}()
extension Numeric {
var spelledOut: String? {
return formatter.string(for: self)
}
}
let one = 1.spelledOut
print(one) //->one
print(25.spelledOut) //->twenty-five
print(1.5.spelledOut) //->one point five
https://developer.apple.com/forums/thread/121448

Answer 2

You can do it like this with String extension
extension String {
func wordToInteger() -> Int {
let numberFormatter = NumberFormatter()
numberFormatter.numberStyle = .spellOut
return numberFormatter.number(from: self.lowercased()) as? Int ?? 0
}
}
Use like this
let letters = ["Zero","One","Two","Three","Four","Five","Six","Seven","Eight","Nine","Ten"]
print(letters[10].wordToInteger()) // In your Case
print("Three".wordToInteger())
Output