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This is some of the strange issue, the program is only printing hello scala, but it seems that I am getting syntax weird error. Please correct me if I miss anything
Program
object hello{
def main(args:Array[String]){
println("Hello Scala")
}
}
Error:- '=' expected, but '{' found
As the error message suggests, you need a = before the {:
def main(args: Array[String]) = {
println("Hello Scala")
}
The syntax you used was originally supported so you might see it in some example code. But it was deprecated in later versions and is now no longer allowed.
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Closed 1 year ago.
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Tried to get integers from a list of Array with letters. While I can use "a".toInt to get 97, why cant I use the map function on an Array to get Array(97,98,99)?
Are you sure you can use "a".toInt? Because here a is a string and cannot be converted.
'a'.toInt on the other hand, works perfectly
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Closed 2 years ago.
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What am i doing wrong here? I am trying to explode the json column, it looks ok to me, but keep getting this error? Can someone help me please?
import org.apache.spark.sql.functions._
import spark.implicits._
val yearname = baby_names.withColumn("data".explode($"data"))
.withColumn("year",$"data"(8))
.withColumn("name",$"data"(9))
.select("year","name")
command-3936897808825418:4: error: not enough arguments for method withColumn: (colName: String, col: org.apache.spark.sql.Column)org.apache.spark.sql.DataFrame.
Unspecified value parameter col.
val yearname = baby_names.withColumn("data".explode($"data"))
I think you mean withColumn("data",explode($"data")) with a comma , separating the 2 arguments. That way it matches the profile:
def withColumn(colName: String, col: Column): DataFrame
The problem is due to the third line , I suggest to change it to:
import org.apache.spark.sql.{functions => F}
val yearname = baby_names.withColumn("data", F.explode(F.col("data")))
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Closed 5 years ago.
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function found = find(property)
res = 0;
if subject(1).property == 20
res = res + 1;
end
end
Hey guys, I am trying to get the substructure to be identified through this function's argument. Any ideas on how to implement this? Thank you.
if subject(1).(property) == 20
I finally figured it out, I just had to put parentheses.
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Closed 6 years ago.
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I am beginner in Swift and learning swift from "The Swift Programming language(Swift 3 beta)". In this book, there is one example of creating generic function but I am getting the above mentioned error.
func makeArray<Item>(repeating item: Item, numberOfTimes: Int)->[Item]
{
var result = [Item]()
for _ in 0..<numberOfTimes {
return.append(item)//Error here.
}
return result
}
This line:
return.append(item)
should be:
result.append(item)
You cannot append to return, it only returns the value.
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Closed 3 years ago.
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I'm having a little problem with Scala Actors and blocking IO. I'm using an actor that itself has an anonymous actor that consumes an input stream. The problem is that this stream only reads one line and then blocks without waking up again. What confuses me is that it worked when the consumption took place in the act method (coincidence?). The application itself has some more actors and java threads doing some work.
My question is: What is the common practice to avoid such problems? Any pointers?
The code that causes this problem looks somewhat like this:
object TestActor extends Actor {
private val instream = actor {
loop {
try {
println(processInput(input.readLine)) //bufferedinputstream. blocks, no wakeup
} catch {
case e: Exception =>
println(e.toString)
}
}
}
def act(): Unit = {
react {
...
case _ => {}
}
}
}
Regards,
raichoo
The call to readLine is inside loop{} so it's going to happen over and over until it blocks.