SELECT user_posts.id,
COUNT(user_post_comments.post_id) as number_of_comments,
COUNT(user_post_reactions.post_id) as number_of_reactions
FROM user_posts
LEFT JOIN user_post_comments
ON (user_posts.id = user_post_comments.post_id)
LEFT JOIN user_post_reactions
ON (user_posts.id = user_post_reactions.post_id)
WHERE user_posts.user_id = '850e6511-2f30-472d-95a1-59a02308b46a'
group by user_posts.id
I have this query for getting the number of comments and reactions from another table by post_id
current output screenshot
To caluclate number of comments and reactions just use subqueries. No need to join and group by.
SELECT user_posts.id,
( select COUNT(*) from user_post_comments
where user_posts.id = user_post_comments.post_id
) as number_of_comments,
( select COUNT(*) from user_post_reactions
where user_posts.id = user_post_reactions.post_id
) as number_of_reactions
FROM user_posts
WHERE user_posts.user_id = '850e6511-2f30-472d-95a1-59a02308b46a'
If both joins return non-null rows, what you get for each count is the product of the number of rows from each for a given user_posts.id. One way you could fix that is by counting distinct identifiers for each table, e.g.
COUNT(DISTINCT user_post_comments.id) as number_of_comments
(Assuming "id" exists as a primary key on that table). This may not be spectacularly efficient, but is relatively simple.
Related
SELECT lkey, max(votecount) FROM VOTES
WHERE ekey = (SELECT ekey FROM Elections where electionid='NR2019')
GROUP BY lkey
ORDER BY lkey ASC
Is there an easy way to get the pkey in this Statement?
Solution should look like this
Use DISTINCT ON:
SELECT DISTINCT ON (v.ikey) v.*
FROM VOTES v
INNER JOIN Elections e ON e.ekey = v.ekey
WHERE e.electionid = 'NR2019'
ORDER BY v.ikey, v.votecount DESC;
In plain English, the above query says to return the single record for each ikey value having the highest vote count.
Firstly, I'm so sorry with the basic question. I want to sum child data and count number of transaction as the following field:
amount (totally)
level (totalLevel)
number of trasanction (Transaction Times)
I have 2 table which related. One user has many transaction.
User Table
id
name
Transaction Table
id
user_id
amount
level
Here is query that I have test. But, it seem not work as expected:
const query = `
SELECT
u.*,
't.amount',
't.level'
COUNT('t.amountDiffCents') as "numberOfTransaction",
SUM('t.level') as "Total Level",
COUNT(u.*) OVER () as "totalCount"
FROM "LoyaltyUser" as u
INNER JOIN "Transaction" as t ON u.id = 't.userId'
GROUP BY u.id
LIMIT $limit
OFFSET $offset;
`;
Thank beforehand.
Aggregate the Transactions table separately, then JOIN Users only afterwards:
SELECT
u.*,
agg.txn_count,
agg.sum_level
FROM
(
SELECT
t.user_id,
COUNT(*) AS txn_count,
SUM( t.level ) AS sum_level
FROM
transaction AS t
GROUP BY
t.user_id
) AS agg
INNER JOIN loyalty_user AS u ON
u.uid = agg.user_id
Strictly speaking (ISO SQL) it is not possible to meaningfully include the total number of all transaction rows in this single result-set (at least, not without having a repeating value in every row, ew). Instead that can be trivially performed by application code - or use a second query in the same batch.
Query in English:
Retrieve a random row from stuff.
row is not mentioned in done.
row belongs to the highest* scored friend.
*if no rows that belong to highest scored friend are found, take the next friend, an so on.
My current query takes too long to complete, because it is randomly ordering all stuff, while it should randomly order batch after batch.
Here is an sqlfiddle with tables and data.
My query:
WITH ordered_friends AS (SELECT *
FROM friends
ORDER BY score DESC)
SELECT s.stuff_id
FROM ordered_friends
INNER JOIN (SELECT *
FROM stuff
ORDER BY random()) AS s ON s.owner = ordered_friends.friend
WHERE NOT EXISTS(
SELECT 1
FROM done
WHERE done.me = 42
AND done.friend = s.owner
AND done.stuff_id = s.stuff_id
)
-- but it should keep the order of ordered_friends (score)
-- it does not have to reorder all stuff
-- one batch for each friend is enough until a satisfying row is found.
LIMIT 1;
How about this?
SELECT s.stuff_id
FROM friends
CROSS JOIN LATERAL (SELECT stuff_id
FROM stuff
WHERE stuff.owner = friends.friend
AND NOT EXISTS(SELECT 1
FROM done
WHERE done.me = 42
AND done.friend = stuff.owner
AND done.stuff_id = stuff.stuff_id
)
ORDER BY random()
LIMIT 1
) s
ORDER BY friends.score DESC
LIMIT 1;
The following indexes would make it fast:
CREATE INDEX ON friends(score); -- for sorting
CREATE INDEX ON stuff(owner); -- for the nested loop
CREATE INDEX ON done(stuff_id, friend); -- for NOT EXISTS
I am trying to removing duplicate values which, for some reason, was imported in a specific Table.
There is no Primary Key in this table.
There is 27797 unique records.
Select distinct txdate, plunumber from itemaudit
Give me the correct records, but only displays the txdate, plunumber of course.
If it was possible to select all the fields but only select the distinct of txdate,plunumber I could export the values, delete the duplicated ones and re-import.
Or if its possible to delete the distinct values from the entire table.
If you select the distinct of all fields the value is incorrect.
To get all information on the duplicates, you simply need to query all information for the duplicate rows using a JOIN:
SELECT b.*
FROM (SELECT COUNT(*) as cnt, txdate, plunumber
FROM itemaudit
GROUP BY txdate, plunumber
HAVING COUNT(*) > 1) a
INNER JOIN itemaudit b ON a.txdate = b.txdate AND a.plunumber = b.plunumber
DELETE FROM itemaudit t1
WHERE EXISTS (
SELECT 1 FROM itemaudit t2
WHERE t1.txdate = t2.txdate and t1.plunumber = t2.plunumber
AND t1.RDB$DB_KEY < t2.RDB$DB_KEY
);
The query below returns 9,817 records. Now, I want to SELECT one more field from another table. See the 2 lines that are commented out, where I've simply selected this additional field and added a JOIN statement to bind this new columns. With these lines added, the query now returns 649,200 records and I can't figure out why! I guess something is wrong with my WHERE criteria in conjunction with the JOIN statement. Please help, thanks.
SELECT DISTINCT dbo.IMPORT_DOCUMENTS.ITEMID, BEGDOC, BATCHID
--, dbo.CATEGORY_COLLECTION_CATEGORY_RESULTS.CATEGORY_ID
FROM IMPORT_DOCUMENTS
--JOIN dbo.CATEGORY_COLLECTION_CATEGORY_RESULTS ON
dbo.CATEGORY_COLLECTION_CATEGORY_RESULTS.ITEMID = dbo.IMPORT_DOCUMENTS.ITEMID
WHERE (BATCHID LIKE 'IC0%' OR BATCHID LIKE 'LP0%')
AND dbo.IMPORT_DOCUMENTS.ITEMID IN
(SELECT dbo.CATEGORY_COLLECTION_CATEGORY_RESULTS.ITEMID FROM
CATEGORY_COLLECTION_CATEGORY_RESULTS
WHERE SCORE >= .7 AND SCORE <= .75 AND CATEGORY_ID IN(
SELECT CATEGORY_ID FROM CATEGORY_COLLECTION_CATS WHERE COLLECTION_ID IN (11,16))
AND Sample_Id > 0)
AND dbo.IMPORT_DOCUMENTS.ITEMID NOT IN
(SELECT ASSIGNMENT_FOLDER_DOCUMENTS.Item_Id FROM ASSIGNMENT_FOLDER_DOCUMENTS)
One possible reason is because one of your tables contains data at lower level, lower than your join key. For example, there may be multiple records per item id. The same item id is repeated X number of times. I would fix the query like the below. Without data knowledge, Try running the below modified query.... If output is not what you're looking for, convert it into SELECT Within a Select...
Hope this helps....
Try this SQL: SELECT DISTINCT a.ITEMID, a.BEGDOC, a.BATCHID, b.CATEGORY_ID FROM IMPORT_DOCUMENTS a JOIN (SELECT DISTINCT ITEMID FROM CATEGORY_COLLECTION_CATEGORY_RESULTS WHERE SCORE >= .7 AND SCORE <= .75 AND CATEGORY_ID IN (SELECT DISTINCT CATEGORY_ID FROM CATEGORY_COLLECTION_CATS WHERE COLLECTION_ID IN (11,16)) AND Sample_Id > 0) B ON a.ITEMID =b.ITEMID WHERE a.(a.BATCHID LIKE 'IC0%' OR a.BATCHID LIKE 'LP0%') AND a.ITEMID NOT IN (SELECT DIDTINCT Item_Id FROM ASSIGNMENT_FOLDER_DOCUMENTS)