I'm trying to create a query where it extracts the country only from a column. The column looks as follow.
Label:
456.United_States.NYC
4589.United_States
789.United_States.NYC.Manhattan_Level
506.India.Bangladesh_3
demo:db<>fiddle
You can use split_part()
SELECT
split_part(my_column, '.', 2) as country
FROM mytable
Related
I have the table with the column value as below:
data_as_of_date:20210202 unique_cc:3999
data_as_of_date:20220202 unique_cc:1999
i need to convert this column into like this:
data_as_of_date unique_cc
20210202 3999
20220202 1999
Sample data:
create table test (val varchar);
insert into test(val) values ('data_as_of_date:20210202 unique_cc:3999');
insert into test(val) values ('data_as_of_date:20220202 unique_cc:1999');
I have tried with unnest with string_to_array & crosstab functions, but it is not working.
You don't need unnest or a crosstab for this. A simple regular expression should do the trick:
select substring(the_column from 'data_as_of_date:([0-9]{8})') as data_as_of_date,
substring(the_column from 'unique_cc:([0-9]{4})') as unqiue_cc
from the_table;
Say I have a varchar column let's say religions that looks like this: ["Christianity", "Buddhism", "Judaism"] (yes it has a bracket in the string) and I want the string (not array) split into multiple rows like "Christianity", "Buddhism", "Judaism" so it can be used in a WHERE clause.
Eventually I want to use the results of the query in a where clause like this:
SELECT ...
FROM religions
WHERE name in
(
<this subquery>
)
How can one do this?
You can use the function JSON_PARSE to convert the varchar string into an array. Then you can use the strategy described in Convert varchar array to rows in redshift - Stack Overflow to convert the array to separate rows.
You can do the following.
Create a temporary table with sequence of numbers
Using the sequence and split_part function available in redshift, you can split the values based on the numbers generated in the temporary table by doing a cross join.
To replace the double quote and square brackets, you can use the regexp_replace function in Redshift.
create temp table seq as
with recursive numbers(NUMBER) as
(
select 1 UNION ALL
select NUMBER + 1 from numbers where NUMBER < 28
)
select * from numbers;
select regexp_replace(split_part(val,',',seq.number),'[]["]','') as value
from
(select '["christianity","Buddhism","Judaism"]' as val) -- You can select the actual column from the table here.
cross join
seq
where seq.number <= regexp_count(val,'[,]')+1;
I have this type of string in the field of my table.
type_no
2345-ABC-3210002478
and I want to select only the last 10 digits number of the string, I expect it would be:
type_no_id
3210002478
how can I do this in PostgreSQL?
Thanks in advance
Use RIGHT() for getting desired output.
SELECT RIGHT('2345-ABC-3210002478', 10) type_no_id
If using column of a table then follow the below example
create table test (type_no varchar(100));
insert into test values ('2345-ABC-3210002478');
SELECT RIGHT(type_no, 10) type_no_id
FROM test
I have a table named `test' which has following structure.
category key value
name real_name:Brad,nick_name:Brady,name_type:small NOVALUE
other description cool
But I want to break key column into multiple rows based on , delimiter and value after : delimiter should be a part of value column where value is equal to NOVALUE. So output should look like:
category key value
name real_name Brad
name nick_name Brady
name name_type small
other description cool
How to write sql query for this . I am using postgresql.
Any help ? Thanks in advance.
You can use string_to_array and unnest to do this:
select ts.category,
split_part(key_value, ':', 1) as key,
split_part(key_value, ':', 2) as value
from test ts
cross join lateral unnest(string_to_array(ts.key, ',')) as t (key_value)
where ts.value = 'NOVALUE'
union all
select category,
key,
value
from test
where value <> 'NOVALUE';
SQLFiddle example: http://sqlfiddle.com/#!15/6f1e6/1
select category,
split_part(key_value, ':', 1) as key,
case when value = 'NOVALUE' then split_part(key_value, ':', 2) else value end
from test
cross join lateral unnest(string_to_array(key, ',')) as t (key_value)
I am trying to combine rows and concatenate two columns (name, vorname) in a Postgres query.
This works good like this:
SELECT nummer,
array_to_string(array_agg(name|| ', ' ||vorname), '\n') as name
FROM (
SELECT DISTINCT
nummer, name, vorname
FROM myTable
) AS m
GROUP BY nummer
ORDER BY nummer;
Unfortunately, if "vorname" is empty I get no results although name has a value.
Is it possible get this working:
array_to_string(array_agg(name|| ', ' ||vorname), '\n') as name
also if one column is empty?
Use coalesce to convert NULL values to something that you can concatenate:
array_to_string(array_agg(name|| ', ' ||coalesce(vorname, '<missing>')), '\n')
Also, you can concatenate strings directly without collecting them to an array by using the string_agg function.
If you have 9.1, then you can use third parameter for array_to_string - null string
array_to_string(array_agg(name), ',', '<missing>') from bbb