for example, I have to search for "2/2" and I get these results:
2/2 good result
11/2/2022 bad result
when I use Advance search in MS -word the "find the whole word" is disabled because my search contains special characters.
also, I tried wildcard search but I didn't know how to construct a good search string for that
is there a way to find an exact match for non-word search?
You could use wildcards, with:
.Text = "<2/2>"
With this expression, the < and > specify a word start & end, respectively.
Event that, however, is prone to false matches with strings like 2/2/2022, since the / after the 2/2 designates a word end. Clearly, your code would need some additional checking to check whether a given match is valid. Such checking might be done via a Find expression like:
.Text = "[!/0-9A-Za-z]2/2[!/0-9A-Za-z]"
This tells Word to find 2/2 only when the preceding and following characters are not a /, a number, or a letter. Then, to manipulate the found text, you'd simply move the start of the found range forward one character and the end of the found range back one character.
Related
I'm having trouble finding the proper Word wildcard string to find numbers that fit the following patterns:
"NN NN NN" or "NN NN NN.NN" (where N is any number 0-9)
The trouble is the first string is a subset of the second string. My goal is to find a single wildcard string that will capture both. Unfortunately, I need to use an operator that is zero or more occurrences for the ".NN" portion and that doesn't exist.
I'm having to do two searches, and I'm using the following patterns:
[0-9]{2}[^s ][0-9]{2}[^s ][0-9]{2}?[!0-9]
[0-9]{2}[^s ][0-9]{2}[^s ][0-9]{2}.[0-9]{2}
The problem is that first pattern (in bold). It works well unless I have the number in a table or something and there is nothing after it to match (or not match, if you will) the [!0-9].
You could use a single wildcard Find:
[0-9]{2}[^s ][0-9]{2}[^s ][0-9][0-9.]{1,4}
or:
[0-9]{2}[^s ][0-9]{2}[^s ][0-9][0-9.]{1;4}
to capture both. Which you use depends on your regional settings.
I want to search strings like "number 1" or "number 152" or "number 36985".
In all above strings "number " will be constant but digits will change and can have any length.
I tried Search option using wildcard but it doesn't seem to work.
basic regEx operators like + seem to not work.
I tried 'number*[1-9]*' and 'number*[1-9]+' but no luck.
This regular expression only selects upto one digit. e.g. If the string is 'number 12345' it only matches number 12345 (the part which is in bold).
Does anyone know how to do this?
Word doesn't use regular expressions in its search (Find) functionality. It has its own set of wildcard rules. These are very similar to RegEx, but not identical and not as powerful.
Using Word's wildcards, the search text below locates the examples given in the question. (Note that the semicolon separator in 1;100 may be soemthing else, depending on the list separator set in Windows (or on the Mac). My European locale uses a semicolon; the United States would use a comma, for example.
"number [0-9]{1;100}"
The 100 is an arbitrary number I chose for the maximum number of repeats of the search term just before it. Depending on how long you expect a number to be, this can be much smaller...
The logic of the search text is: number is a literal; the valid range of characters following the literal are 0 through 9; there may be one to one hundred of these characters - anything in that range is a match.
The only way RegEx can be used in Word is to extract a string and run the search on the string. But this dissociates the string from the document, meaning Word-specific content (formatting, fields, etc.) will be lost.
Try putting < and > on the ends of your search string to indicate the beginning and ending of the desired strings. This works for me: '<number [1-9]*>'. So does '<number [1-9]#>' which is probably what you want. Note that in Word wildcards the # is used where + is used in other RegEx systems.
I'm coming across a strange situation where I cannot search on string tags that end with a special character. So far I've tried ) and ].
For example, given a Fruit index with a record with a tag apple (red), if you query (using the JS library) with tagFilters: "apple (red)", no results will be returned even if there are records with this tag.
However, if you change the tag to apple (red (not ending with a special character), results will be returned.
Is this a known issue? Is there a way to get around this?
EDIT
I saw this FAQ on special characters. However, it seems as though even if I set () as separator characters to index that only effects the direct attriubtes that are searchable, not the tag. is this correct? can I change the separator characters to index on tags?
You should try using the array syntax for your tags:
tagFilters: ["apple (red)"]
The reason it is currently failing is because of the syntax of tagFilters. When you pass a string, it tries to parse it using a special syntax, documented here, where commas mean "AND" and parentheses delimit an "OR" group.
By the way, tagFilters is now deprecated for a much clearer syntax available with the filters parameter. For your specific example, you'd use it this way:
filters: '_tags:"apple (red)"'
How can I apply multiple search criteria to the document for obtaining a refined result/search? I 'tried' using wildcards -> ?[!a-z][!0-9][!^s] <- to find a character except from range a-z, range 0-9, and the non breaking space(^s). i.e. I do not want to find any character, any number or a space, but tabs, operators, special characters, etc. At least that's what I think it does. How can I use multiple "find what" criteria together in a document?
As a starting point, use wildcards and
[!0-9,a-z,A-Z, ]
should help. It may be possible to refine that further, but if not, VBA or equivalent and either a character-by-character check or multiple find loops are your options.
I'm using regular expression lib icucore via RegKit on the iPhone to
replace a pattern in a large string.
The Pattern i'm looking for looks some thing like this
| hello world (P1)|
I'm matching this pattern with the following regular expression
\|((\w*|.| )+)\((\w\d+)\)\|
This transforms the input string into 3 groups when a match is found, of which group 1(string) and group 3(string in parentheses) are of interest to me.
I'm converting these formated strings into html links so the above would be transformed into
Hello world
My problem is the trailing space in the third group. Which when the link is highlighted and underlined, results with the line extending beyond the printed characters.
While i know i could extract all the matches and process them manually, using the search and replace feature of the icu lib is a much cleaner solution, and i would rather not do that as a result.
Many thanks as always
Would the following work as an alternate regular expression?
\|((\w*|.| )+)\s+\((\w\d+)\)\| Where inserting the extra \s+ pulls the space outside the 1st grouping.
Though, given your example & regex, I'm not sure why you don't just do:
\|(.+)\s+\((\w\d+)\)\|
Which will have the same effect. However, both your original regex and my simpler one would both fail, however on:
| hello world (P1)| and on the same line | howdy world (P1)|
where it would roll it up into 1 match.
\|\s*([\w ,.-]+)\s+\((\w\d+)\)\|
will put the trailing space(s) outside the capturing group. This will of course only work if there always is a space. Can you guarantee that?
If not, use
\|\s*([\w ,.-]+(?<!\s))\s*\((\w\d+)\)\|
This uses a lookbehind assertion to make sure the capturing group ends in a non-space character.