CASE on ORDER BY based on field type - postgresql

Question

How can one execute ORDER BY taking into consideration the field value type?
CREATE TABLE public.test(
data jsonb
);
TRUNCATE test;
INSERT INTO test (data) VALUES ('{"age":2, "name": "b"}');
INSERT INTO test (data) VALUES ('{"age":1, "name": "cc"}');
INSERT INTO test (data) VALUES ('{"age":4, "name": "d"}');
INSERT INTO test (data) VALUES ('{"age":33, "name": "a"}');
-- works
SELECT * FROM test ORDER BY data->>'name' ASC;
-- works
SELECT * FROM test ORDER BY (data->>'age')::numeric ASC;
-- does not work
/*
ERROR: CASE types text and numeric cannot be matched
LINE 5: WHEN 'number' THEN (data->>'age')::numeric
*/
SELECT data->>'name' as name, data->>'age' as age
FROM test
ORDER BY
CASE jsonb_typeof(data->'age')
WHEN 'number' THEN (data->>'age')::numeric
ELSE data->>'age'
END
ASC;
(The actual field name will be injected into the query from code)

Answer 1

You could simply order by data->'age' or data->'name' without casting it in some cases.
(note the use of the -> operator which returns a JSONB value, instead of the ->> which always returns text)
This seems to work in both cases:
SELECT data->>'name' as name, data->>'age' as age
FROM test
ORDER BY data->'age' ASC;
-- name age
-- cc 1
-- b 2
-- d 4
-- a 33
SELECT data->>'name' as name, data->>'age' as age
FROM test
ORDER BY data->'name' ASC;
-- name age
-- a 33
-- b 2
-- cc 1
-- d 4