I have a table in Postgres 14.2
Table name is test
There are 3 columns: date, high, and five_day_mavg (date is PK if it matters)
I have a select statement which properly calculates a 5 day moving average based on the data in high.
select date,
avg(high) over (order by date rows between 4 preceding and current row) as mavg_calc
from test
It products output as such:
I have 2 goals:
First to store the output of the query in five_day_mavg.
Second to store this in such a way that when I a new row with data
in high, it automatically calculates that value
The closest I got was:
update test set five_day_mavg = a.mav_calc
from (
select date,
avg(high) over (order by date rows between 4 preceding and current row) as mav_calc
from test
) a;
but all that does is sets the value of every row in five_day_mavg to entire average of high
Thanks to #a_horse_with_no_name
I played around with the WHERE clause
update test l set five_day_mavg = b.five_day_mavg from (select date, avg(high) over (order by date rows between 4 preceding and current row) as five_day_mavg from test )b where l.date = b.date;
a couple of things. I defined each table. The original table I aliased as l, the temporary table created by doing a windows function (the select statement in parenthesis) I aliased as b and I joined with the WHERE clause on date which is the index/primary key.
Also, I was using 'a' as the letter for alias, and I think that may have contributed to the issue.
Either way, solved now.
Related
I have a calendar table called CalendarInformation that gives me a list of dates from 2015 to 2025. This table has a column called BusinessDay that shows what dates are weekends or holidays. I have another table called OpenProblemtimeDiffTable with a column called number for my problem number and a date for when the problem was opened called ProblemNew and another date for the current column called Now. What I want to do is for each problem number grab its date ranges and find the dates between and then sum them up to give me the number of business days. Then I want to insert these values in another table with the problem number associated with the business day.
Thanks in advance and I hope I was clear.
TRUNCATE TABLE ProblemsMoreThan7BusinessDays
DECLARE #date AS date
DECLARE #businessday AS INT
DECLARE #Startdate as DATE, #EndDate as DATE
DECLARE CONTACT_CURSOR CURSOR FOR
SELECT date, businessday
FROM CalendarInformation
OPEN contact_cursor
FETCH NEXT FROM Contact_cursor INTO #date, #businessday
WHILE (##FETCH_STATUS=0)
BEGIN
SELECT #enddate= now FROM OpenProblemtimeDiffTable
SELECT #Startdate= problemnew FROM OpenProblemtimeDiffTable
SET #Date=#Startdate
PRINT #enddate
PRINT #startdate
SELECT #businessday= SUM (businessday) FROM CalendarInformation WHERE date > #startdate AND date <= #Enddate
INSERT INTO ProblemsMoreThan7BusinessDays (businessdays, number)
SELECT #businessday, number
FROM OpenProblemtimeDiffTable
FETCH NEXT FROM CONTACT_CURSOR INTO #date, #businessday
END
CLOSE CONTACT_CURSOR
DEALLOCATE CONTACT_CURSOR
I tried this code using a cursor and I'm close, but I cannot get the date ranges to change for each row.
So if I have a problemnumber with date ranges between 02-07-2018 and 05-20-2019, I would want in my new table the sum of business days from the calendar along with the problem number. So my output would be column number PROB0421 businessdays (with the correct sum). Then the next problem PRB0422 with date ranges of 11-6-18 to 5-20-19. So my output would be PROB0422 with the correct sum of business days.
Rather than doing this in with a cursor, you should approach this in a set based manner. That you already have a calendar table makes this a lot easier. The basic approach is to select from your data table and join into your calendar table to return all the rows in the calendar table that sit within your date range. From here you can then aggregate as you require.
This would look something like the below, though apply it to your situation and adjust as required:
select p.ProblemNow
,p.Now
,sum(c.BusinessDay) as BusinessDays
from dbo.Problems as p
join dbo.calendar as c
on c.CalendarDate between p.ProblemNow and p.Now
and c.BusinessDay = 1
group by p.ProblemNow
,p.Now
I think you can do this without a cursor. Should only require a single insert..select statement.
I assume your "businessday" column is just a bit or flag-type field that is 1 if the date is a business day and 0 if not? If so, this should work (or something close to it if I'm not understanding your environment properly).:
insert ProblemsMoreThan7BusinessDays
(
businessdays
, number
)
select
number
, sum( businessday ) -- or count(*)
from OpenProblemtimeDiffTable op
inner join CalendarInformation ci on op.problem_new >= ci.[date]
and op.[now] <= ci.[date]
and ci.businessday = 1
group by
problem_number
I usually try to avoid the use of cursors and working with data in a procedural manner, especially if I can handle the task as above. Dont think of the data as 1000's of individual rows, but think of the data as only two sets of data. How do they relate?
I have two tables with IDs and time stamps. Table 1 has two columns: ID and created_at. Table 2 has two columns: ID and post_date. I'd like to create a chart in Tableau that displays the Number of Records in Table 1 divided by Number of Records in Table 2, by week. How can I achieve this?
One way might be to use Custom SQL like this to create a new data source for your visualization:
SELECT created_table.created_date,
created_table.created_count,
posted_table.posted_count
FROM (SELECT TRUNC (created_at) AS created_date, COUNT (*) AS created_count
FROM Table1) created_table
LEFT JOIN
(SELECT TRUNC (post_date) AS posted_date, COUNT (*) AS posted_count
FROM Table2) posted_table
ON created_table.created_date = posted_table.posted_date
This would give you dates and counts from both tables for those dates, which you could group using Tableau's date functions in the visualization. I made created_table the first part of the left join on the assumption that some records would be created and not posted, but you wouldn't have posts without creations. If that isn't the case you will want a different join.
Hello everyone I have to get data from and to date, I tried using between clause which fails to retrieve data what I need. Here is what I need.
I have table called hall_info which has following structure
hall_info
id | hall_name |address |contact_no
1 | abc | India |XXXX-XXXX-XX
2 | xyz | India |XXXX-XXXX-XX
Now I have one more table which is events, that contains data about when and which hall is booked on what date, the structure is as follows.
id |hall_info_id |event_date(booked_date)| event_name
1 | 2 | 2015-10-25 | Marriage
2 | 1 | 2015-10-28 | Marriage
3 | 2 | 2015-10-26 | Marriage
So what I need now is I wanna show hall_names that are not booked on selected dates, suppose if user chooses from 2015-10-23 to 2015-10-30 so I wanna list all halls that are not booked on selected dates. In above case both the halls of hall_info_id 1 and 2 ids booked in given range but still I wanna show them because they are free on 23,24,27 and on 29 date.
In second case suppose if user chooses date from 2015-10-25 and 2015-10-26 then only hall_info_id 2 is booked on both the dates 25 and 26 so in this case i wanna show only hall_info_id 1 as hall_info_id 2 is booked.
I tried using inner query and between clause but I am not getting required result to simply i have given only selected fields I have more tables to join so i cant paste my query please help with this. Thanks in advance for all who are trying.
Some changes in Yasen Zhelev's code:
SELECT * FROM hall_info
WHERE id not IN (
SELECT hall_info_id FROM events
WHERE event_date >= '2015-10-23' AND event_date <= '2015-10-30'
GROUP BY hall_info_id
HAVING COUNT(DISTINCT event_date) > DATE_PART('day', '2015-10-30'::timestamp - '2015-10-23'::timestamp))
I have not tried it but how about checking if the number of bookings per hall is less than the actual days in the selected period.
SELECT * FROM hall_info WHERE id NOT IN
(SELECT hall_info_id FROM events
WHERE event_date >= '2015-10-23' AND event_date <= '2015-10-30'
GROUP BY hall_info_id
HAVING COUNT(id) < DATEDIFF(day, '2015-10-30', '2015-10-23')
);
That will only work if you have one booking per day per hall.
To get the "available dates" for the hall returned, your query needs a row source of all possible dates. For example, if you had a calendar table populated with possible date values, e.g.
CREATE TABLE cal (dt DATE NOT NULL PRIMARY KEY) Engine=InnoDB
;
INSERT INTO cal (dt) VALUES ('2015-10-23')
,('2015-10-24'),('2015-10-25'),('2015-10-26'),('2015-10-27')
,('2015-10-28'),('2015-10-29'),('2015-10-30'),('2015-10-31')
;
The you could use a query that performs a cross join between the calendar table and hall_info... to get every hall on every date... and an anti-join pattern to eliminate rows that are already booked.
The anti-join pattern is an outer join with a restriction in the WHERE clause to eliminate matching rows.
For example:
SELECT cal.dt, h.id, h.hall_name, h.address
FROM cal cal
CROSS
JOIN hall_info h
LEFT
JOIN events e
ON e.hall_id = h.id
AND e.event_date = cal.dt
WHERE e.id IS NULL
AND cal.dt >= '2015-10-23'
AND cal.dt <= '2015-10-30'
The cross join between cal and hall_info gets all halls for all dates (restricted in the WHERE clause to a specified range of dates.)
The outer join to events find matching rows in the events table (matching on hall_id and event_date. The trick is the predicate (condition) in the WHERE clause e.id IS NULL. That throws out any rows that had a match, leaving only rows that don't have a match.
This type of problem is similar to other "sparse data" problems. e.g. How do you return a zero total for sales by a given store on a given date, when there are no rows with that store and date...
In your case, the query needs a source of rows with available date values. That doesn't necessarily have to be a table named calendar. (Other databases give us the ability to dynamically generate a row source; someday, MySQL may have similar features.)
If you want the row source to be dynamic in MySQL, then one approach would be to create a temporary table, and populate it with the dates, run the query referencing the temporary table, and then dropping the temporary table.
Another approach is to use an inline view to return the rows...
SELECT cal.dt, h.id, h.hall_name, h.address
FROM (
SELECT '2015-10-23'+INTERVAL 0 DAY AS dt
UNION ALL SELECT '2015-10-24'
UNION ALL SELECT '2015-10-25'
UNION ALL SELECT '2015-10-26'
UNION ALL SELECT '2015-10-27'
UNION ALL SELECT '2015-10-28'
UNION ALL SELECT '2015-10-29'
UNION ALL SELECT '2015-10-30'
) cal
CROSS
JOIN hall_info h
LEFT
JOIN events e
ON e.hall_id = h.id
AND e.event_date = c.dt
WHERE e.id IS NULL
FOLLOWUP: When this question was originally posted, it was tagged with mysql. The SQL in the examples above is for MySQL.
In terms of writing a query to return the specified results, the general issue is still the same in PostgreSQL. The general problem is "sparse data".
The SQL query needs a row source for the "missing" date values, but the specification doesn't provide any source for those date values.
The answer above discusses several possible row sources in MySQL: 1) a table, 2) a temporary table, 3) an inline view.
The answer also mentions that some databases (not MySQL) provide other mechanisms that can be used as a row source.
For example, PostgreSQL provides a nifty generate_series function (Reference: http://www.postgresql.org/docs/9.1/static/functions-srf.html.
It should be possible to use the generate_series function as a row source, to supply a set of rows containing the date values needed by the query to produced the specified result.
This answer demonstrates the approach to solving the "sparse data" problem.
If the specification is to return just the list of halls, and not the dates they are available, the queries above can be easily modified to remove the date expression from the SELECT list, and add a GROUP BY clause to collapse the rows into a distinct list of halls.
I need to sum values that are + 2 months or within a quarter period (related date table)
is there a way to use dense rank to partition those periods (custom periods)?
select
FiscalMonth
,Value
from table
The sql will have to do the following:
Join the value table and the period table
Include the period in the select list and sum the value, grouping by the period
i.e
select b.period, sum(a.value)
from table a
inner join period b on a.FiscalMonth between b.StartMonth and b.EndMonth
group by b.period
Note: The join condition will have to be modified based on what data you actually have in the period table.
Hope this helps
Well, If you need value from an X interval, by month you could use something like:
SELECT *
FROM yourTable
MONTH(some_date) = MONTH(CURRENT_DATE - INTERVAL 1 MONTH) //Could be X interval!
This is an example (which show the results of the previous month, from the actual one). Just trying to write that it is possible to massage the query in functions on intervals.
Of course, you could use the SUMcommand for the adding.
I am trying to figure out how to select half the records where an ID is null. I want half because I am going to use that result set to update another ID field. Then I am going to update the rest with another value for that ID field.
So essentially I want to update half the records someFieldID with one number and the rest with another number splitting the update basically between two values for someFieldID the field I want to update.
In oracle you can use the ROWNUM psuedocolumn. I believe in sql server you can use TOP.
Example:
select TOP 50 PERCENT * from table
You can select by percent:
SELECT TOP 50 PERCENT *fields* FROM YourTable WHERE ...
update x set id=#value from (select top 50 percent * from table where id is null) x
The following SQL will return the col_ids of the first half of the table.
SELECT col_id FROM table
WHERE rownum <= (SELECT count(col_id)/2 FROM table);
If the total number of col_ids is an odd number then you will get the first half - 1. This is because, for instance, we have 51 total records, the count(col_id)/2 returns 25.5, and since there is no rownum equal to this result, we get everything equal to 25 and below. That means the other 26 are not returned.
However, I have not seen the reverse statement working:
SELECT col_id FROM table
WHERE rownum > (SELECT count(col_id)/2 FROM table);
So if you want the other half of the table, you could just store the first results into a temp table, lets call it TABLE_A. Then just do MINUS on the original table from this table:
SELECT col_id FROM table
MINUS
SELECT col_id FROM table_a
Hopefully this helps someone.