Opening multiple MS Access application with powershell - powershell

Question

Good day everyone. I'm new to powershell so I don't know what's wrong with this. I have this script to open multiple MS Access at once as you see in the script and it is save in my local drive. If I run this script in VS Code editor, the script is fine and two application is launch. Now if I run this script using mouse Right-Click and Run with powershell. At runtime, both application is visible but after the script completed/done, only one application is running and the other is closed.
$accessMenu = New-Object -ComObject Access.Application
$AccessPath1 = "G:\access1.MDB"
$accessMenu.OpenCurrentDatabase($AccessPath1, $false)
$accessMenu.Visible = $true
$accessLink = New-Object -ComObject Access.Application
$AccessPath2 = "G:\access2.accdb"
$accessLink.OpenCurrentDatabase($AccessPath2, $false)
$accessLink.Visible = $true
Am I missing something here? Thanks in advance for sharing your idea's.

Answer 1

Here is a VBScript that will open multiple dbs. It utilizes Windows Shell object. Create a text file and change the extension to vbs. Double click the file to run.
Dim objFSO1, objFS02, oShell1, oShell2
Set objFSO1 = CreateObject("Scripting.FileSystemObject")
Set oShell1 = CreateObject("WScript.Shell")
oShell1.Run """G:\access1.MDB"""
Set objFSO2 = CreateObject("Scripting.FileSystemObject")
Set oShell2 = CreateObject("WScript.Shell")
oShell2.Run """G:\access2.accdb"""
The only way I can get multiple databases to open and include a password is in VBA.
Option Compare Database
Option Explicit
Dim accdbObj1 As Access.Application
Dim accdbObj2 As Access.Application
____________________________________________________________________________
Sub test()
Set accdbObj1 = CreateObject("Access.Application")
accdbObj1.OpenCurrentDatabase "C:\Users\Owner\June\Forums\demofile.accdb", , "test"
accdbObj1.Application.Visible = True
Set accdbObj2 = CreateObject("Access.Application")
accdbObj2.OpenCurrentDatabase "C:\Users\Owner\June\DOT\Projects.accdb"
accdbObj2.Application.Visible = True
End Sub

Answer 2

For future preference:
As per #topsail said, by passing UserControl = $true in the instantiated variable of Access.Application it prevents the closing of object/application upon script termination/complete.
In powershell:
$accessObj = New-Object -ComObject Access.Application -Property #{UserControl = $true}
In VBA:
Dim accdbObj
Set accdbObj = CreateObject("Access.Application")
accdbObj.OpenCurrentDatabase "G:\path\test.mdb", , "password"
accdbObj.Application.Visible = True
accdbObj.UserControl = True