How to destructure variable into function's parameter? - swift

Question

How can I pass the value of all key from object as functions parameters? like python did.
I have one function getNameInfo with parameter with default value firstName, lastName, age and one object with key firstName, lastName, age how is the best way for me to descture the pbject and pass all value of key into function? in python i can do something like getNameInfo(**a.__dict__.values()) but
class Person {
public var firstName = "firstName"
public var lastName = "lastName"
public var age = 12
public init(firstName: String, lastName: String, age: Int){
self.firstName = firstName
self.lastName = lastName
self.age = age
}
}
let a = Person(firstName: "firstName", lastName: "lastName", age: 12)
func getNameInfo(firstName: String = "i am first", lastName: String = "I am lat", age: Int = 50) {
print("\(fName), \(lName), \(age)")
}
getNameInfo()
// getNameInfo(a) // expect to print out firstName, lastName, 12

Answer 1

There is no similar feature in Swift. The closest version is to use protocols:
protocol NameInfoProviding {
var firstName: String { get }
var lastName: String { get }
var age: Int { get }
}
extension Person: NameInfoProviding {}
func getNameInfo(_ nameInfo: some NameInfoProviding) {
print("\(nameInfo.firstName), \(nameInfo.lastName), \(nameInfo.age)")
}
getNameInfo(a)
But yes, this is a different feature and used in different ways.