TYPO3 : send data from extension to the backend layout - typo3

Question

I made an extension which display some data and I need to send them to my Layout.
In my file list.html I made a left column with some data, but finally I need this column in my layout.
there is some code :
Layouts/MyLayout.html
<f:render partial="Structure/Header" arguments="{_all}"/>
<f:render partial="Menus/Main" arguments="{_all}"/>
<!--the left column should be here -->
<f:render section="default" />
List.html
<f:layout name="Default"/>
<f:section name="main">
<aside>
<h2>Title</h2>
<ul>
<f:for each="{Mydata}" as="data">
<li>{data.title}</li>
</f:for>
</ul>
</aside>
</f:section>
That's why I would need to retrieve my extension data in my layout. It is possible to get I ?
If it's not possible, it is possible to get in list.html the name of the actual backend layout with some typoscript ?

Answer 1

There are multiple options to handle whether there are data for an additional column in layout.
first:
Even if in FLUID the files are stored in three folder (Layouts/, Partials/, Templates/) you are not forced to use it in that way. Meaning: you also can decide the layout in the template files.
In the default layout you just render a mainsection (from the template file). And in the different templates you decide whether a side column exist.
second:
extension data can be provided in multiple ways:
You can do the rendering completely in typoscript - or you use a content element with a plugin. The later would be more transparent for editors.
In your case you can provide a different BackEnd layout where editors can put a plugin in the additional column for that special 'layout'.
The rendering only occurs if that 'layout' is selected and a plugin is stored in that column.