Problem in AXI GPIO interrupt handling in ZYNQ - linux-device-driver

Question

I have a custom ZYNQ7000-based board. I want to insert an AXI GPIO that directly generate an interrupt. I want to handle the interrupt in a kernel module. All things sound to be correct but it does not work.
My Toolset:
Petalinux 2021.2 installed on Ubuntu 20.04.03
Vivado 2021.2
I have only one interrupt that I connect it to the processor interrupt input.
I connect a push button to AXI GPIO 1 and configure it to generate interrupt.
Based on my pl-DTS file
/ {
amba_pl: amba_pl {
#address-cells = <1>;
#size-cells = <1>;
compatible = "simple-bus";
ranges ;
axi_gpio_0: gpio#41200000 {
#gpio-cells = <3>;
clock-names = "s_axi_aclk";
clocks = <&clkc 15>;
compatible = "xlnx,axi-gpio-2.0", "xlnx,xps-gpio-1.00.a";
gpio-controller ;
reg = <0x41200000 0x10000>;
xlnx,all-inputs = <0x0>;
xlnx,all-inputs-2 = <0x0>;
xlnx,all-outputs = <0x1>;
xlnx,all-outputs-2 = <0x0>;
xlnx,dout-default = <0x00000000>;
xlnx,dout-default-2 = <0x00000000>;
xlnx,gpio-width = <0x4>;
xlnx,gpio2-width = <0x20>;
xlnx,interrupt-present = <0x0>;
xlnx,is-dual = <0x0>;
xlnx,tri-default = <0xFFFFFFFF>;
xlnx,tri-default-2 = <0xFFFFFFFF>;
};
axi_gpio_1: gpio#41210000 {
#gpio-cells = <3>;
#interrupt-cells = <2>;
clock-names = "s_axi_aclk";
clocks = <&clkc 15>;
compatible = "xlnx,axi-gpio-2.0", "xlnx,xps-gpio-1.00.a";
gpio-controller;
interrupt-controller;
interrupt-names = "ip2intc_irpt";
interrupt-parent = <&intc>;
interrupts = <0 29 4>;
reg = <0x41210000 0x10000>;
xlnx,all-inputs = <0x1>;
xlnx,all-inputs-2 = <0x0>;
xlnx,all-outputs = <0x0>;
xlnx,all-outputs-2 = <0x0>;
xlnx,dout-default = <0x00000000>;
xlnx,dout-default-2 = <0x00000000>;
xlnx,gpio-width = <0x1>;
xlnx,gpio2-width = <0x20>;
xlnx,interrupt-present = <0x1>;
xlnx,is-dual = <0x0>;
xlnx,tri-default = <0xFFFFFFFF>;
xlnx,tri-default-2 = <0xFFFFFFFF>;
};
};
};
The interrupt should be at 61 (29 + 32 = 61): interrupts = <0 29 4>;.
I enable the interrupt enable register and global interrupt register.
I want to write a kernel module and register the axi-gpio interrupt in that and register a ISR to handle it. the main part of my code is as follows:
if (request_irq(IRQ_NUM, isr, 0, DEVICE_NAME, NULL)) {
printk(KERN_ERR "my_init: Cannot register IRQ %d\n", IRQ_NUM);
return -EIO;
} else {
printk(KERN_INFO "my_init: Registered IRQ %d\n", IRQ_NUM);
}
printk(KERN_INFO "my_init: Initialize Module \"%s\"\n", DEVICE_NAME);
pdev = platform_device_register_simple(DEVICE_NAME, 0, NULL, 0);
if (pdev == NULL) {
printk(KERN_WARNING "my_init: Adding platform device \"%s\" failed\n", DEVICE_NAME);
kfree(pdev);
return -ENODEV;
}
PROBLEMS:
Interrupt 61 could not be registered.
In fact, I found "all free interrupts" and tried "all" with my axi-gpio. None of them works correctly.
I do not want to use GPIO-keys or UIO because they need a blocking read BUT I want to write a kernel module and register the axi-gpio interrupt in that by interrupt request function (request_irq()) and register a ISR for it.
I searched and read all previous problems in the Xilinx and other venders. I tried all solutions but I cannot find anything.
BTW:
The connection between push button and processor is okay because I could activate it by the GPIO-keys. GPIO-keys interrupt catches the push button actions.