Simplify expression with unknown [closed] - scala

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I am trying to simplify an expression which has an unknown varaible in it. I am doing it in scala and I am using case classes. The thing is I don't know how to handle an unknown variable e.g when 4 * 4 * x should become 16 * x but I don't know how to get the * x. Can anyone help

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Store x and y coordinates in field or array list from other class [closed]

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I want to store x and y coordinates from another class. I want to store it in a field or Array list. The coordinates should be taken from a click on a frame.
I got no idea how to do it.

Intertwine 0s betweeen bits SystemVerilog [closed]

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I want to intertwine 0s between the bits of a variable. For example, imagine I have a variable a as follows
a = 1101
Then, I want to obtain the following result
b = 1_000000_1_000000_0_000000_1
That results from intertwining 6 0s betwen each bit of a. I was wondering if there was any elegant way of doing this in SystemVerilog. Any help is appreciated.
b = 0;
foreach (a[i]) b[i*7] = a[i];

how to create a signal consisting of a delay of 1000 samples of zeros? [closed]

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How to write the MATLAB code
to create a signal consisting of a 'delay' of 1000 samples of zeros,
followed by variable which i found in previous part 'sss' of 1000 samples and the message I've created 'msg' ?
so there are three variables 'delay' , 'sss' , and 'msg'
please help. thanks
Concatenate them.
newSignal = [delay sss msg];

Multiplications of n matrices(2X2) [closed]

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I want to multiple n matrices(2X2).How to do that.it should start from 1 till nrlayer like M(1)*M(2)M(3) till *M(nrlayer)
T=1;
for i=1:nrlayer,
T=T*M{i};
end

loop to add present state with previous state [closed]

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I want to make a loop in order to add the current state with the previous state.
For example:
M=1000;
for i=1:M A=i*(x(i));
This formula will be for M=1 but when M=2 the formula will be like this:
A=(i*(x(i))+((i-1)*(x(i-1)))
and when M=3 the formula will be
A=(i*(x(i))+((i-1)*(x(i-1)))+((i-2)*(x(i-2))
and so on till reach the maximum length of M which is 1000.
Your question is quite vague but it sounds like you just want a cumulative sum of the i*x(i) series:
i = 1:M;
s = i.*x(i);
cumsum(s);