How can i access the exception chain (SEH) using masm64?
Using masm32, I get the first exception looking into fs:[0]
But when I checked in Windbg if fs:[0] still pointed at the first exception in x64, I figured that it wasn't.
I'd like to set an exception in x64 the same way I did in x86. Is it feasible (maybe looking at gs register)?
If this is coding related then you use
ml64seh PROC FRAME:ExceptionFilter
this adds your exception handler to .PDATA section RUNTIME_FUNCTION
if this is how to find this exception handler in windbg when the exception has been raised
use !exchain command
or if you want to find it before executing a specific function use .fnent command
a sample for x64 seh and finding it in windbg is as follows
;assemble and link with
;ml64 /Zi ml64seh.asm /link /debug /entry:ml64seh /subsystem:console
.data
safeplace DWORD ?
.code
ExceptionFilter PROC
jmp Handler
ExceptionFilter ENDP
PUBLIC ml64seh
ml64seh PROC FRAME:ExceptionFilter
.ENDPROLOG
mov rax, 0
mov [rax], rax ;access violation
jmp exit
Handler::
lea rax, safeplace
mov [r8+078h], rax ; replacing rax in exception handler so access is possible
mov rax, 0
ret
Exit:
ret
ml64seh ENDP
END
run without stopping in windbg
:\>cdb -g ml64seh.exe
(2aa0.3024): Access violation - code c0000005 (first chance)
ml64seh!ml64seh+0x7:
00007ff7`0e3b1029 488900 mov qword ptr [rax],rax ds:00000000`00000000=????????????????
0:000>
it crashed and broke now locating exception handlers
0:000> .fnent .
Debugger function entry 0000020b`e36c47a8 for:
(00007ff7`0e3b1022) ml64seh!ml64seh+0x7 | (00007ff7`0e3b32b0) ml64seh!$xdatasym
BeginAddress = 00000000`00001022
EndAddress = 00000000`00001042
UnwindInfoAddress = 00000000`000032b0
Unwind info at 00007ff7`0e3b32b0, c bytes
version 1, flags 3, prolog 0, codes 0
handler routine: ml64seh!ILT+0(ExceptionFilter) (00007ff7`0e3b1005), data 0 <<<<<<<<<
0:000> !exchain
3 stack frames, scanning for handlers...
Frame 0x00: ml64seh!ml64seh+0x7 (00007ff7`0e3b1029)
ehandler ml64seh!ILT+0(ExceptionFilter) (00007ff7`0e3b1005) <<<<<<<<<<<<
Frame 0x02: ntdll!RtlUserThreadStart+0x21 (00007ffe`213c26a1)
ehandler ntdll!_C_specific_handler (00007ffe`213fc720)
0:000>
lets see if we go to the handler and return back to re access the faulting place
0:000> bp .
0:000> bp 00007ff7`0e3b1005
0:000> bl
0 e 00007ff7`0e3b1029 0001 (0001) 0:**** ml64seh!ml64seh+0x7
1 e 00007ff7`0e3b1005 0001 (0001) 0:**** ml64seh!ILT+0(ExceptionFilter)
0:000> g
Breakpoint 1 hit
ml64seh!ILT+0(ExceptionFilter):
00007ff7`0e3b1005 e916000000 jmp ml64seh!ExceptionFilter (00007ff7`0e3b1020)
0:000> g
Breakpoint 0 hit
ml64seh!ml64seh+0x7: is accessible now
00007ff7`0e3b1029 488900 mov qword ptr [rax],rax ds:00007ff7`0e3b4000=0000000000000000
0:000>
btw you can use dumpbin or linker to spit out all the unwindinfos in a specific binary using -unwindinfo switch
:\>dumpbin /unwindinfo ml64seh.exe
Microsoft (R) COFF/PE Dumper Version 14.29.30146.0
Copyright (C) Microsoft Corporation. All rights reserved.
Dump of file ml64seh.exe
File Type: EXECUTABLE IMAGE
Function Table (1)
Begin End Info Function Name
00000000 00001022 00001042 000032B0 ml64seh
Unwind version: 1
Unwind flags: EHANDLER UHANDLER
Size of prologue: 0x00
Count of codes: 0
Handler: 00001005 #ILT+0(ExceptionFilter)
Related
I'm trying to find the address of the API HeapAlloc in Windbg using the following syntax u Kernel32!HeapAllocStub but windbg cannot resolve that. I have reloded the symbols and the error persist, for the Other api this method is working fine.
Can you point me what I'm doing wrong ?
Thanks in advance
why are you looking for HeapAllocStub ?
do you have any reason that it should exist ?
and in latest windows kernel32.dll does not have any implementation
most of the functions are implemented in kernelbase.dll
almost most of the heap functions are forwarded to ntdll.dll
HeapAlloc is implemented in ntdll as RtlAllocateHeap
windbg has a very powerful wild card Search
you can use a command like x *!*Heap*All*
which would look for any function that has the regex Heap.*All.*
in all the loaded Modules
kernel32 imports the function HeapAlloc as can be seen below
0:000> x *k*32*!*heap*all*
00007ffe`44eefb94 KERNEL32!`WerpHeapAlloc'::`1'::fin$0 (void)
00007ffe`44ea6330 KERNEL32!BasepJobObjectHeapAlloc (BasepJobObjectHeapAlloc)
00007ffe`44f023f8 KERNEL32!_imp_HeapAlloc = <no type information>
00007ffe`44f023e8 KERNEL32!_imp_HeapReAlloc = <no type information>
00007ffe`44eef90c KERNEL32!WerpHeapAlloc (void * __cdecl WerpHeapAlloc(struct _WER_HEAP_MAIN_HEADER *,unsigned __int64))
and the imported function is implemented in ntdll.dll
0:000> dps KERNEL32!_imp_HeapAlloc l1
00007ffe`44f023f8 00007ffe`460fa9a0 ntdll!RtlAllocateHeap
0:000> dps KERNEL32!_imp_HeapReAlloc l1
00007ffe`44f023e8 00007ffe`460f3640 ntdll!RtlReAllocateHeap
0:000>
0:000> u poi(KERNEL32!_imp_HeapAlloc) l5
ntdll!RtlAllocateHeap:
00007ffe`460fa9a0 48895c2408 mov qword ptr [rsp+8],rbx
00007ffe`460fa9a5 4889742410 mov qword ptr [rsp+10h],rsi
00007ffe`460fa9aa 57 push rdi
00007ffe`460fa9ab 4883ec30 sub rsp,30h
00007ffe`460fa9af 498bf8 mov rdi,r8
0:000>
I want to do something like break at Process!Function+0x66 but only if [RDX + 0x01c] == 1.
What would the syntax of breakpoint like this be?
evaluate with ? Process!Function+0x66
copy the result for using in breakpoint 0x12345678`90abcdef
bp 0x12345678`90abcdef ".if ( poi(#rdx+0x1c) != 1) {gc}"
a sample flow
0:000> ? msvcrt!memcpy+0x40
Evaluate expression: 140735863146304 = 00007fff`9f214740
0:000> u msvcrt!memcpy+0x40 l1
msvcrt!memcpy+0x40:
00007fff`9f214740 8a0411 mov al,byte ptr [rcx+rdx]
0:000> bp 00007fff`9f214740 " .if( poi(#rcx+#rdx) != 0x20) {gc}"
0:000> bl 0 e 00007fff`9f214740 0001 (0001) msvcrt!memcpy+0x40 ".if( poi(#rcx+#rdx) != 0x20) {gc}"
0:000> g
Microsoft (R) Windows Debugger Version 10.0.17763.132 AMD64
msvcrt!memcpy+0x40:
00007fff`9f214740 8a0411 mov al,byte ptr [rcx+rdx] ds:000001d6`1ebc6ac1=20
0:000> .lastevent
Last event: 724.1718: Hit breakpoint 0
debugger time: Wed Jun 16 00:25:26.965 2021
0:000> g
msvcrt!memcpy+0x40:
00007fff`9f214740 8a0411 mov al,byte ptr [rcx+rdx] ds:000001d6`20407c4a=20
0:000> .lastevent
Last event: 724.1718: Hit breakpoint 0
debugger time: Wed Jun 16 00:25:45.283 2021
0:000>
I was analysing a complete memory dump and I applied Windbg uf command to see what a function does
0: kd> uf profsvc!CUserProfileService::_RegisterGPNotification
This is the part of the output. I wonder why the address in parentheses is different than the address of profsvc!CUserProfileService::_RegisterGPNotification+0x44 which should be
000007fe fb149276
but is
000007fe fb155019.
When I try to unassembled the address 000007fe fb155019 with u it points to
profsvc!CUserProfileService::_RegisterGPNotification+0x44:
I’m really puzzled, any help deeply appreciated.
OUTPUT from WinDBG
….
profsvc!CUserProfileService::_RegisterGPNotification+0x2e:
000007fe`fb14925e ba01000000 mov edx,1
000007fe`fb149263 488bc8 mov rcx,rax
000007fe`fb149266 ff157c410200 call qword ptr [profsvc!_imp_RegisterGPNotification (000007fe`fb16d3e8)]
000007fe`fb14926c 85c0 test eax,eax
000007fe`fb14926e 0f84a5bd0000 je profsvc!CUserProfileService::_RegisterGPNotification+0x44 (**000007fe`fb155019**)
profsvc!CUserProfileService::_RegisterGPNotification+0x40:
000007fe`fb149274 33db xor ebx,ebx
000007fe`fb149276 eb00 jmp profsvc!CUserProfileService::_RegisterGPNotification+0x66 (000007fe`fb149278) Branch
profsvc!CUserProfileService::_RegisterGPNotification+0x66:
000007fe`fb149278 488b0d31b00200 mov rcx,qword ptr [profsvc!WPP_GLOBAL_Control (000007fe`fb1742b0)]
000007fe`fb14927f 488d052ab00200 lea rax,[profsvc!WPP_GLOBAL_Control (000007fe`fb1742b0)]
000007fe`fb149286 483bc8 cmp rcx,rax
000007fe`fb149289 740a je profsvc!CUserProfileService::_RegisterGPNotification+0x94 (000007fe`fb149295) Branch
0: kd> u 000007fe`fb155019
profsvc!CUserProfileService::_RegisterGPNotification+0x44:
000007fe`fb155019 ?? ???
^ Memory access error in 'u 000007fe`fb155019'
This is due to optimization, see the following MSDN article:
https://msdn.microsoft.com/en-us/library/windows/hardware/ff541382(v=vs.85).aspx
%include "init.inc"
[org 0x0]
[bits 16]
jmp 0x07C0:start_boot
start_boot:
mov ax, cs
mov ds, ax
mov es, ax
load_setup:
mov ax, SETUP_SEG
mov es, ax
xor bx, bx
mov ah, 2 ; copy data to es:bx from disk.
mov al, 1 ; read a sector.
mov ch, 0 ; cylinder 0
mov cl, 2 ; read data since sector 2.
mov dh, 0 ; Head = 0
mov dl, 0 ; Drive = 0
int 0x13 ; BIOS call.
jc load_setup
lea si, [msg_load_setup]
call print
jmp $
print:
print_beg:
mov ax, 0xB800
mov es, ax
xor di, di
print_msg:
mov al, byte [si]
mov byte [es:di], al
or al, al
jz print_end
inc di
mov byte [es:di], BG_TEXT_COLOR
inc di
inc si
jmp print_msg
print_end:
ret
msg_load_setup db "Loading setup.bin was completed." , 0
times 510-($-$$) db 0
dw 0xAA55
I want to load setup.bin to memory address zero. So, I input 0 value to es register (SETUP_SEG = 0). bx, too. But it didn't work. then, I have a question about this issue. My test is below.
SETUP_SEG's value
0x0000 : fail
0x0010 : success
0x0020 : fail
0x0030 : fail
0x0040 : fail
0x0050 : success
I can't understand why this situation was happened. All test was carried out on VMware. Does anyone have an idea ?
I'm not sure if this is your problem, but your trying to load setup.bin in the Real Mode IVT (Interrupt Vector Table). The IVT contains the location of each interrupt, so I'm assuming that your boatloader is overwriting them when it loads setup.bin into memory! Interrupts can be sneaky and tricky, since they can be called even if you didn't call them. Any interrupt vector you overwrote will likely cause undefined behavior when called, which will cause some problems.
I suggest setting SETUP_SEG to a higher number like 0x2000 or 0x3000, but the lowest you could safely go is 0x07E0. The Osdev Wiki and Wikipedia have some helpful information on conventional memory and memory mapping.
I hope this helps!
So I have a crash dump, and using WinDbg, I am able to get the stack trace. However, it appears to be skipping every other function. For instance if the actual code is:
void a()
{
b();
}
void b()
{
c();
}
void c(){}
The stack trace would have a, and c in the stack frame and not b. Is this expected behavior, and is there something I can do to see the entire stack trace? I have using the command "kn" to view the stack trace.
The compiler may optimize the code. One optimization is to inline methods so that call and ret statements and everything related (push, pop etc.) are removed.
For demonstration purposes, I have added a std::cout statement to your code which we can identify so that the full code now reads
#include "stdafx.h"
#include <iostream>
void c()
{
std::cout << "Hello world";
}
void b()
{
c();
}
void a()
{
b();
}
int _tmain(int argc, _TCHAR* argv[])
{
a();
return 0;
}
Walkthrough in debug build
In a typical debug build, there are no optimizations and you can see the methods. To follow the example, start WinDbg first and run the executable via File/Open executable....
0:000> .symfix e:\debug\symbols
0:000> lm
start end module name
010d0000 010f3000 OptimizedInlined (deferred)
...
0:000> ld OptimizedInlined
Symbols loaded for OptimizedInlined
0:000> x OptimizedInlined!c
010e50c0 OptimizedInlined!c (void)
0:000> bp OptimizedInlined!c
0:000> bl
0 e 010e50c0 0001 (0001) 0:**** OptimizedInlined!c
0:000> g
Breakpoint 0 hit
eax=cccccccc ebx=7efde000 ecx=00000000 edx=00000001 esi=00000000 edi=003ffa00
eip=010e50c0 esp=003ff930 ebp=003ffa00 iopl=0 nv up ei pl nz na po nc
cs=0023 ss=002b ds=002b es=002b fs=0053 gs=002b efl=00000202
OptimizedInlined!c:
010e50c0 55 push ebp
0:000> u eip L18
OptimizedInlined!c [e:\...\optimizedinlined.cpp # 8]:
010e50c0 55 push ebp
010e50c1 8bec mov ebp,esp
010e50c3 81ecc0000000 sub esp,0C0h
010e50c9 53 push ebx
010e50ca 56 push esi
010e50cb 57 push edi
010e50cc 8dbd40ffffff lea edi,[ebp-0C0h]
010e50d2 b930000000 mov ecx,30h
010e50d7 b8cccccccc mov eax,0CCCCCCCCh
010e50dc f3ab rep stos dword ptr es:[edi]
010e50de 6854ca0e01 push offset OptimizedInlined!`string' (010eca54)
010e50e3 a1e4000f01 mov eax,dword ptr [OptimizedInlined!_imp_?coutstd (010f00e4)]
010e50e8 50 push eax
010e50e9 e8c9c1ffff call OptimizedInlined!ILT+690(??$?6U?$char_traitsDstdstdYAAAV?$basic_ostreamDU?$char_traitsDstd (010e12b7)
010e50ee 83c408 add esp,8
010e50f1 5f pop edi
010e50f2 5e pop esi
010e50f3 5b pop ebx
010e50f4 81c4c0000000 add esp,0C0h
010e50fa 3bec cmp ebp,esp
010e50fc e838c2ffff call OptimizedInlined!ILT+820(__RTC_CheckEsp) (010e1339)
010e5101 8be5 mov esp,ebp
010e5103 5d pop ebp
010e5104 c3 ret
Walkthrough release build
In the release build, see how things change. The WinDbg commands are the same, but the methods c(), b() and a() cannot be found. The std::cout method call has been inlined into wmain():
0:000> .symfix e:\debug\symbols
0:000> lm
start end module name
01360000 01367000 OptimizedInlined (deferred)
...
0:000> ld OptimizedInlined
Symbols loaded for OptimizedInlined
0:000> x OptimizedInlined!c
0:000> x OptimizedInlined!b
0:000> x OptimizedInlined!a
0:000> x OptimizedInlined!wmain
013612a0 OptimizedInlined!wmain (int, wchar_t **)
0:000> bp OptimizedInlined!wmain
0:000> bl
0 e 013612a0 0001 (0001) 0:**** OptimizedInlined!wmain
0:000> g
Breakpoint 0 hit
eax=6142f628 ebx=00000000 ecx=0087a6e8 edx=0019def8 esi=00000001 edi=00000000
eip=013612a0 esp=0042f8f8 ebp=0042f934 iopl=0 nv up ei pl zr na pe nc
cs=0023 ss=002b ds=002b es=002b fs=0053 gs=002b efl=00000246
OptimizedInlined!wmain:
013612a0 8b0d44303601 mov ecx,dword ptr [OptimizedInlined!_imp_?coutstd (01363044)] ds:002b:01363044={MSVCP120!std::cout (646c6198)}
0:000> u eip L4
OptimizedInlined!wmain [e:\...\optimizedinlined.cpp # 23]:
013612a0 8b0d44303601 mov ecx,dword ptr [OptimizedInlined!_imp_?coutstd (01363044)]
013612a6 e895040000 call OptimizedInlined!std::operator<<<std::char_traits<char> > (01361740)
013612ab 33c0 xor eax,eax
013612ad c3 ret
Like already mentioned by Lieven. this is a case where compiler is making function calls inline.
There are 2 things that i would suggest:
a. If you have control over the code and build environment. Build a non-optimized/debug version of the code. This will ensure that compiler does not inline functions on its own.
b. In WinDBG you can see the disassembly under View --> Disassembly. Here you can see that code for function b() is actually in lined under a().
In case you are comfortable with assembly debugging you can get the value of locals as well :)