I was trying to create a function to expand the brackets in a linear equation. Unfortunately, I couldn't get the function to function, and I have been getting errors. Below is the code I wrote:
List openBracket(List<String> equationComponents) {
List eqtComponents = [];
for (int i = 0; i < equationComponents.length; i++) {
if (containsBracket(equationComponents.get(i))) {
eqtComponents.addAll((equationComponents.get(i)));
} else {
eqtComponents.add(equationComponents.get(i));
}
}
return eqtComponents;
}
This is the error that I am facing:
"The method 'get' isn't defined for the type 'List'.
Try correcting the name to the name of an existing method, or defining a method named 'get'."
I can't seem to solve the problem.
I have searched on YouTube and Google but found no solutions to the problem. I Have been trying to find alternatives to the ".get" method but to no avail.
You can use myList.elementAt(x) or just myList[x] for list.
equationComponents.elementAt(x)
List openBracket(List<String> equationComponents) {
List eqtComponents = [];
for (int i = 0; i < equationComponents.length; i++) {
if (containsBracket(equationComponents.elementAt(i))) {
eqtComponents.addAll([equationComponents[i]]); // add all need list
} else {
eqtComponents.add(equationComponents.elementAt(i));
}
}
return eqtComponents;
}
More about List
Related
I'm a fairly new student in AP CSP, and I wanted to create a username/password system in code.org's App Lab, however, it requires me to get the readRecords() command to function first.
I have the code as such :
function read (array) {
var truth;
readRecords("loginarray", {}, function(records) {
if (records.length > 0) {
for (var i = 0; i < records.length; i++){
if (array.user == records[i].user){
if (array.pass == records[i].pass) {
truth = false;
hideElement("unverifiedtext");
hideElement("retrybutton");
setScreen("verifyscreen");
}
}
}
}
}
);
return truth;
}
But nothing I do seems to get the readRecords() command working. I'm rather confused, can this asynchronous timing be meddled with at all? If not, how should I go about fixing this issue?
Thanks in advance!
In programming, there are multiple ways of doing the same problem. The following problem is in regards to palindrome. Though I feel that I am on the right track, I am not able to completely solve the problem to get to requested solution.
What is a palindrome? A word written forward or backward is the same and returns true. Example, "racecar". Hence, I designed the following code in Javascript...
function palindrome(string) {
string = string.toLowerCase();
lowString = string.toLowerCase().split("").reverse().join("");
for (var i=0; i<string.length; i++) {
if (string[i] !== lowString[i]) {
return false;
}
}
}
return true;
}
The above code returns true if Palindrome exists and returns false if not.
Then, the problem says - Given various palindrome in a string or array, please return the longest palindrome. So, I wrote the following:
function longestPalindrome(newstring) {
splitString = newString.split(" ");
for (var i=0; i < splitString; i++) {
if (splitString[i] == palindrome(splitString[i]) {
console.log(splitString[i]);
}
}
}
longestPalindrome("This is a racecar ada");'
But in the above code, I am not able to get the required outcome because I believe I am not calling the function correctly.
I would appreciate clear directions or even a solution built off of my track as well as the track you deem fittest.
Here is some insight: I am working with UnityScript in Unity 4.6.3. I have one script called Pause.js and it contains this function:
function fadeMusicOut () {
while (audio.volume >= 0.005) {
yield WaitForSeconds(0.1);
Debug.Log("Loop Entered: " + audio.volume);
audio.volume = (audio.volume - 0.015);
}
Another script GameManager.js has this function:
static function Score (wallName : String) {
if (wallName == "rightWall") {
playerScore01 += 1;
}
else {
playerScore02 += 1;
}
if (playerScore01 == SettingsBack.scoreLimit || playerScore02 == SettingsBack.scoreLimit)
{
startParticles = 1;
SettingsBack.gameOver = 1;
BallControl.fadeSound = 1;
yield WaitForSeconds(4);
Camera.main.SendMessage("fadeOut");
Pause.fadeMusic = 1;
SettingsBack.soundVolume = 0;
yield WaitForSeconds(2);
playerScore01 = 0;
playerScore02 = 0;
SettingsBack.soundVolume = oldSoundVol;
Application.LoadLevel("_Menu");
}
}
So pretty much I want to call the fadeMusicOut() function from static function Score, but it will not let me because it says it needs an instance of that object.
The Pause.js script is not attached to any game objects, but it is attached to 2 buttons that call their specific functions. The GameManager.js script is attached to an object called GM. So how can I go about calling fadeMusicOut() from the Score function?
I have tried setting new vars that import the game object but still no luck. I tried making fadeMusicOut() a static function, but it creates many errors.
Any help at all is appreciated.
for ( i = 0; i < 100; i++) {
browser.manage().logs().get('browser').then(function(browserLog) {
console.log(i);
});
}
I am trying to run this using protractor, but i get hundred times 100 printed in console. I have some functionality which am trying to implement using looping.How can i do looping in protractor?
This is because the functions you're passing to then all close over the variable i, not the value that variable has when you create the functions. So later, when the functions are called, they all see the value of i as it is then, after the loop is complete (100).
If you want to capture the value of i as it is when you create the function, you can use ES5's Function#bind:
for ( i = 0; i < 100; i++) {
browser.manage().logs().get('browser').then(function(index, browserLog) {
console.log(index);
}.bind(null, i));
}
bind returns a new function that, when called, will call the original function with a given this value (in this case I'm using null) and any arguments you follow that with, followed by arguments given to the function bind returned.
Another approach is a builder function:
for ( i = 0; i < 100; i++) {
browser.manage().logs().get('browser').then(buildHandler(i));
}
function buildHandler(index) {
return function(browserLog) {
console.log(index);
};
}
That has the advantage of allowing the caller to control this.
I am trying to find a string in a javascript array in the transformer of a mirth channel. Mirth throws an error when I try to use indexOf function. My understanding is that indexOf is something that browsers add in, rather than a native part of the javascript language itself. ( How do I check if an array includes an object in JavaScript? )
So is array.indexOf just not supported in Mirth? Is there any way to use .indexOf in Mirth? Maybe an alternate syntax? Or do I need to just loop thru the array to search?
This is how I search arrays in a Mirth js transformer:
var Yak = [];
Yak.push('test');
if(Yak.indexOf('test') != -1)
{
// do something
}
Does this give you error?
Mirth uses the Rhino engine for Javascript, and on some earlier versions of the JVM, indexOf appeared to not be supported on arrays. Since upgrading our JVM to 1.6.23 (or higher), indexOf has started working. However, we still have legacy code that, when searching arrays of strings, I just use a loop each time:
var compareString = "blah";
var index = -1;
for (var i = 0; i < myArray.length; ++i)
{
if (myArray[i] == compareString)
{
index = i;
break;
}
}
If you need to do this frequently, you should be able to use a code template to manually add the indexOf function to Array.
Set the code template to global access, and try out something like this (untested code):
Array.prototype.indexOf = function(var compareObject)
{
for (var i = 0; i < myArray.length; ++i)
{
// I don't think this is actually the right way to compare
if (myArray[i] == compareObject)
{
return i;
}
}
return -1;
}
var arr = ['john',1,'Peter'];
if(arr.indexOf('john') > -1)
{
//match. what to do?
console.log("found");
}
else
{
console.log("not found");//not found .. do something
}
var i = ['a', 'b', 'c']
if(i.indexOf('a') > -1)
{
///do this, if it finds something in the array that matches what inside the indexOf()
}
else
{
//do something else if it theres no match in array
}