Extract date from pySpark timestamp column (no UTC timezone) in Palantir - date

Question

I have a timestamp of this type: 2022-11-09T23:19:32.000Z
When I cast to date, my output is "2022-11-10" but I wanna "2022-11-09". Is there a way to force utc 0 (not +1) or extract directly data with a regex to bring only date without consider timezone?
I have tried also substring('2022-11-09T23:19:32.000Z', 1, 10) or some function to extract string... but my output is the same: "2022-11-10".
Example:
Input
id
start_date
123
2020-04-10T23:55:19.000Z
My code:
df_output = df_input.withColumn('date', F.regex_extract(F.col('start_date', '(\\d{4})-(\\d{2})-(\\d{2})', 0))
Wrong Output
id
start_date
date
123
2020-04-10T23:55:19.000Z
2020-04-11
Desidered Output [I wanna extract string from timestamp without consider timezone]
id
start_date
date
123
2020-04-10T23:55:19.000Z
2020-04-10

Answer 1

Can't you use the to_date function? This here works for me:
from datetime import datetime
from pyspark.sql.functions import to_date
from pyspark.sql.types import StructType, StructField, StringType, TimestampType
df = spark.createDataFrame(
[
(
"123",
datetime.strptime("2020-04-10T23:55:19.000Z", '%Y-%m-%dT%H:%M:%S.%fZ')
)
],
StructType([
StructField("id", StringType()),
StructField("start_date", TimestampType()),
]))
df.withColumn("date", to_date("start_date", "%Y-%m-%d")).show()
Output:
+---+-------------------+----------+
| id| start_date| date|
+---+-------------------+----------+
|123|2020-04-10 23:55:19|2020-04-10|
+---+-------------------+----------+