select
datum, naam,
to_char(verkocht::numeric/(verkocht+beschikbaar)*100, 'fm00D00%') rangen
from
(select
sr.namenl rang,
count((case when t.currentstatus is null then '1' end)) as beschikbaar,
count((case when t.currentstatus = 101 then '2' end)) as verkocht,
coalesce(e.namenl) || ' ' || coalesce(e.subtitlenl,'') naam,
e.startts datum,
sr.id seatrank
from
tm.ticket t
inner join
tm.tickettype tt on tt.id = t.tickettypeid
inner join
tm.event e on e.id = tt.eventid
inner join
tm.seatrank sr on sr.id = tt.seatrankid
where
e.id = 28744
group by
1, 4, 5, 6
order by
1 desc) sq1
group by
1, 2, 3
Current result (https://i.stack.imgur.com/1KPOi.png)
What I would like is to convert the 4 row result into 1 row. The 4 different outcomes in row "rangen" next to each other so that I have 1 row with 6 columns. Don't know if this is possible and I am fairly new to this as you can see :)
You can use string_agg function. For example, like as this query:
select
datum, naam,
string_agg(rangen, ', ') as rangen
from table
group by
datum, naam
Related
I have this query
the table flights also contains price column. I'd like to sum it all up and display. How can I solve this?
Can I do this by taking the values from SELECT * from get_cities; somehow or it should be done in the query?
Table img
I am trying to solve this
Write a query finding all the names of the cities City name can be reached by plane with 3 stops. Display all the cities where the stop took place and the total cost of the trip. Also sum up the journey cost.
WITH RECURSIVE get_cities AS (
SELECT 0 as count, city, cid from cities where CITY = 'Agat'
UNION ALL
SELECT c.count + 1, b.city, b.cid from get_cities c
JOIN flights t on t.departure = c.cid
JOIN cities b on t.arrival = b.cid
WHERE COUNT < 3
)
SELECT cid, sum(price) from get_cities
JOIN flights f on f.fid = cid
GROUP BY cid
;
You can sum the prices directly in the recursive cte :
WITH RECURSIVE get_cities AS (
SELECT 0 as count, array[city] as city_path, array[cid] as cid_path, 0 as total_price
FROM cities
WHERE CITY = 'Agat'
UNION ALL
SELECT c.count + 1, c.city_path || b.city, c.cid_path || b.cid, c.total_price + t.price
FROM get_cities c
JOIN flights t on t.departure = c.cid
JOIN cities b on t.arrival = b.cid
WHERE COUNT < 3
)
SELECT *
FROM get_cities
WHERE count = 2 -- select only the journey with 3 stops ;
I am trying to get the max date by account from 3 different tables and view those dates side by side. I created a separate query for each table, merged the results with UNION ALL, and then wrapped all that in a PIVOT.
The first 2 sections in the link/pic below show what I have been able to accomplish and the 3rd section is what I would like to do.
Query results by step
How can I get the results from 2 of the tables to repeat? Is that possible?
--define var_ent_type = 'ACOM'
--define var_ent_id = '52766'
--define var_dict_id = 113
SELECT
*
FROM
(
SELECT
E.ENTITY_TYPE,
E.ENTITY_ID,
'PERF_SUMMARY' as "TableName",
PS.DICTIONARY_ID,
to_char(MAX(PS.END_EFFECTIVE_DATE), 'YYYY-MM-DD') as "MaxDate"
FROM
RULESDBO.ENTITY E
INNER JOIN PERFORMDBO.PERF_SUMMARY PS ON (PS.ENTITY_ID = E.ENTITY_ID)
WHERE
1=1
-- AND E.ENTITY_TYPE = '&var_ent_type'
-- AND E.ENTITY_ID = '&var_ent_id'
AND PS.DICTIONARY_ID >= 100
AND (E.ACTIVE_STATUS <> 'N' )--and E.TERMINATION_DATE is null )
GROUP BY
E.ENTITY_TYPE,
E.ENTITY_ID,
'PERF_SUMMARY',
PS.DICTIONARY_ID
union all
SELECT
E.ENTITY_TYPE,
E.ENTITY_ID,
'POSITION' as "TableName",
0 as DICTIONARY_ID,
to_char(MAX(H.EFFECTIVE_DATE), 'YYYY-MM-DD') as "MaxDate"
FROM
RULESDBO.ENTITY E
INNER JOIN HOLDINGDBO.POSITION H ON (H.ENTITY_ID = E.ENTITY_ID)
WHERE
1=1
-- AND E.ENTITY_TYPE = '&var_ent_type'
-- AND E.ENTITY_ID = '&var_ent_id'
AND (E.ACTIVE_STATUS <> 'N' )--and E.TERMINATION_DATE is null )
GROUP BY
E.ENTITY_TYPE,
E.ENTITY_ID,
'POSITION',
1
union all
SELECT
E.ENTITY_TYPE,
E.ENTITY_ID,
'CASH_ACTIVITY' as "TableName",
0 as DICTIONARY_ID,
to_char(MAX(C.EFFECTIVE_DATE), 'YYYY-MM-DD') as "MaxDate"
FROM
RULESDBO.ENTITY E
INNER JOIN CASHDBO.CASH_ACTIVITY C ON (C.ENTITY_ID = E.ENTITY_ID)
WHERE
1=1
-- AND E.ENTITY_TYPE = '&var_ent_type'
-- AND E.ENTITY_ID = '&var_ent_id'
AND (E.ACTIVE_STATUS <> 'N' )--and E.TERMINATION_DATE is null )
GROUP BY
E.ENTITY_TYPE,
E.ENTITY_ID,
'CASH_ACTIVITY',
1
--ORDER BY
-- 2,3, 4
)
PIVOT
(
MAX("MaxDate")
FOR "TableName"
IN ('CASH_ACTIVITY', 'PERF_SUMMARY','POSITION')
)
Everything is possible. You only need a window function to make the value repeat across rows w/o data.
--Assuming current query is QC
With QC as (
...
)
select code, account, grouping,
--cash,
first_value(cash) over (partition by code, account order by grouping asc rows unbounded preceding) as cash_repeat,
perf,
--pos,
first_value(pos) over (partition by code, account order by grouping asc rows unbounded preceding) as pos_repeat
from QC
;
See first_value() help here: https://docs.oracle.com/en/database/oracle/oracle-database/19/sqlrf/FIRST_VALUE.html#GUID-D454EC3F-370C-4C64-9B11-33FCB10D95EC
I can't replace every 2 characters of a string with a '.'
select STUFF('abcdefghi', 3, 1, '.') c3,STUFF('abcdefghi', 5, 1,
'.') c5,STUFF('abcdefghi', 7, 1, '.') c7,STUFF('abcdefghi', 9, 1, '.')
c9
if I use STUFF I should subsequently overlap the strings c3, c5, c7 and c9. but I can't find a method
can you help me?
initial string:
abcdefghi
the result I would like is
ab.de.gh.
the string can be up to 50 characters
Create a numbers / tally / digits table, if you don't have one already, then you can use this to target each character position:
with digits as ( /* This would be a real table, here it's just to test */
select n from (values(1),(2),(3),(4),(5),(6),(7),(8),(9),(10))x(n)
), t as (
select 'abcdefghi' as s
)
select String_Agg( case when d.n%3 = 0 then '.' else Substring(t.s, d.n, 1) end, '')
from t
cross apply digits d
where d.n <Len(t.s)
Using for xml with existing table
with digits as (
select n from (values(1),(2),(3),(4),(5),(6),(7),(8),(9),(10))x(n)
),
r as (
select t.id, case when d.n%3=0 then '.' else Substring(t.s, d.n, 1) end ch
from t
cross apply digits d
where d.n <Len(t.s)
)
select result=(select '' + ch
from r r2
where r2.id=r.id
for xml path('')
)
from r
group by r.id
You can try it like this:
Easiest might be a quirky update ike here:
DECLARE #string VARCHAR(100)='abcdefghijklmnopqrstuvwxyz';
SELECT #string = STUFF(#string,3*A.pos,1,'.')
FROM (SELECT TOP(LEN(#string)/3) ROW_NUMBER() OVER(ORDER BY (SELECT NULL))
FROM master..spt_values) A(pos);
SELECT #string;
Better/Cleaner/Prettier was a recursive CTE:
We use a declared table to have some tabular sample data
DECLARE #tbl TABLE(ID INT IDENTITY, SomeString VARCHAR(200));
INSERT INTO #tbl VALUES('')
,('a')
,('ab')
,('abc')
,('abcd')
,('abcde')
,('abcdefghijklmnopqrstuvwxyz');
--the query
WITH recCTE AS
(
SELECT ID
,SomeString
,(LEN(SomeString)+1)/3 AS CountDots
,1 AS OccuranceOfDot
,SUBSTRING(SomeString,4,LEN(SomeString)) AS RestString
,CAST(LEFT(SomeString,2) AS VARCHAR(MAX)) AS Growing
FROM #tbl
UNION ALL
SELECT t.ID
,r.SomeString
,r.CountDots
,r.OccuranceOfDot+2
,SUBSTRING(RestString,4,LEN(RestString))
,CONCAT(Growing,'.',LEFT(r.RestString,2))
FROM #tbl t
INNER JOIN recCTE r ON t.ID=r.ID
WHERE r.OccuranceOfDot/2<r.CountDots-1
)
SELECT TOP 1 WITH TIES ID,Growing
FROM recCTE
ORDER BY ROW_NUMBER() OVER(PARTITION BY ID ORDER BY OccuranceOfDot DESC);
--the result
1
2 a
3 ab
4 ab
5 ab
6 ab.de
7 ab.de.gh.jk.mn.pq.st.vw.yz
The idea in short
We use a recursive CTE to walk along the string
we add the needed portion together with a dot
We stop, when the remaining length is to short to continue
a little magic is the ORDER BY ROW_NUMBER() OVER() together with TOP 1 WITH TIES. This will allow all first rows (frist per ID) to appear.
I'm trying to pull a dataset that returns records ONLY when there are two QUALIFERs present. I've tried left joins, populating data in temp tables then manipulating something, then numerous having clauses (resulting in subquery selects, and additional groups). I would appreciate any assistance on what I can do further.
Query:
Select E, CASE WHEN QUALIFER = '1' THEN 'NAME1' WHEN QUALIFER = '2' then 'NAME2' ELSE 'FINALNAME' END AS TYPE, count(rt.ID) 'Number '
from TABLE_ONE co (nolock)
join TABLE_TWO rt (nolock)
on co.ID = rt.ID
where co.E in (select * from #tempEmail)
AND convert(date,co.INSERTED_TIMESTAMP)between '1/1/2020' and '8/15/2020'
AND TRANS_STATUS = 'APPROVED'
group by E, QUALIFER
order by E, QUALIFER
Current resultset:
E TYPE Number
FAKEEMAIL1#Gmail NAME1 1
FAKEEMAIL1#Gmail NAME2 1
otheremailj#gmail.com Name1 21
Desired resultset:
E TYPE Number
FAKEEMAIL1#Gmail NAME1 1
FAKEEMAIL1#Gmail NAME2 1
Thank you.
Let's try the below query. I used a temp table to make things more simple for my mind.
if object_id('tempdb.dbo.#email') is not null drop table #email
create table #email
(
email varchar(50),
typeValue varchar(15),
Number int
)
insert into #email(email, typeValue, Number)
Select
E,
CASE WHEN QUALIFER = '1' THEN 'NAME1' WHEN QUALIFER = '2' then 'NAME2' ELSE 'FINALNAME' END AS TYPE,
count(rt.ID) 'Number '
from TABLE_ONE co (nolock)
join TABLE_TWO rt (nolock)
on co.ID = rt.ID
where co.E in (select * from #tempEmail)
AND convert(date,co.INSERTED_TIMESTAMP)between '1/1/2020' and '8/15/2020'
AND TRANS_STATUS = 'APPROVED'
group by E, QUALIFER
select a.email, a.typeValue
from #email a
inner join
(
select email, typeValue, rank() over (partition by email order by typeValue) as typeCount
from #email t
) as b
on b.email = a.email
and b.typeCount > 1
I have written a query in two models, but I can't figure out why the second query returns a greater number than the first one; while the number that the first one, COUNT(DISTINCT...) returns is correct:
WITH types(id) AS (VALUES('{1, 4, 5, 3}'::INTEGER[])),
date_gen64 AS
(
SELECT CAST (generate_series(date '10/1/2017', date '11/15/2017', interval
'1 day') AS date) as days ORDER BY days)
SELECT cl.class_date AS c_date,
count(DISTINCT (CASE WHEN co.id = 1 THEN p.id END)),
count(DISTINCT (CASE WHEN co.id = 2 THEN p.id END))
FROM person p
JOIN envelope e ON e.personID = p.id
JOIN "class" cl on cl.id = p.classID
JOIN course co ON co.id = cl.course_id AND co.id = 1
JOIN types ON cr.type_id = ANY (types.id)
RIGHT JOIN date_gen64 dg ON dg.days = cl.class_date
GROUP BY cl.class_date
ORDER BY cl.class_date
The above query returns 26 but following query returns 27!
The reason why I rewrote it with SUM is that the first query
was too slow. But my question is that why the second one counts more?
WITH types(id) AS (VALUES('{1, 4, 5, 3}'::INTEGER[]))
SELECT tmpcl.days,
SUM(CASE WHEN tmp80.course_id = 1 THEN 1
ELSE 0 END),
SUM(CASE WHEN tmp80.course_id = 2 THEN 1
ELSE 0 END)
FROM (
SELECT CAST (generate_series(date '10/1/2017', date '11/15/2017',
interval '1 day') AS date) as days ORDER BY days) tmpcl
LEFT JOIN (
SELECT DISTINCT p.id AS "person_id",
cl.class_date AS c_date,
co.id AS "course_id"
FROM person p
JOIN envelope e ON e.personID = p.id
JOIN "class" cl on cl.id = p.classID
JOIN course co ON co.id = cl.course_id
JOIN types ON cr.type_id = ANY (types.id)
WHERE co.id IN ( 1 , 2 )
) tmp80 ON tmpcl.days = tmp80.class_date
GROUP BY tmpcl.days
ORDER BY tmpcl.days
You can theoretically have multiple people enrolled in the same class on the same day. Indeed that would seem to be the main point of having classes. So each time there are multiple people assigned to the same class on the same day you can have a higher count than you would in your first query. Does that make sense?
You don't appear to be using p.id in that inner query so simply remove it and your counts should match.
WITH types(id) AS (VALUES('{1, 4, 5, 3}'::INTEGER[]))
SELECT tmpcl.days,
SUM(CASE WHEN tmp80.course_id = 1 THEN 1
ELSE 0 END),
SUM(CASE WHEN tmp80.course_id = 2 THEN 1
ELSE 0 END)
FROM (
SELECT CAST (generate_series(date '10/1/2017', date '11/15/2017',
interval '1 day') AS date) as days ORDER BY days) tmpcl
LEFT JOIN (
SELECT DISTINCT cl.class_date AS c_date,
co.id AS "course_id"
FROM person p
JOIN envelope e ON e.personID = p.id
JOIN "class" cl on cl.id = p.classID
JOIN course co ON co.id = cl.course_id
JOIN types ON cr.type_id = ANY (types.id)
WHERE co.id IN ( 1 , 2 )
) tmp80 ON tmpcl.days = tmp80.class_date
GROUP BY tmpcl.days
ORDER BY tmpcl.days