I am trying to change the date format in txmlmap component but its not working
i want change date format
from yyyy-MM-dd'T'HH:mm:ss.SSSz to yyyy-mm-dd HH:mm:ss
expected output:- yyyy-mm-dd HH:mm:ss
You can parse your string to a date using your source pattern and then format that date to a string using your target pattern:
TalendDate.formatDate("yyyy-mm-dd HH:mm:ss", TalendDate.parseDate("yyyy-MM-dd'T'HH:mm:ss.SSSz", myDateString))
In almost all coding languages format is text, while date is a double. That means you must first make a date of the first expression, before setting the new format of that date. But in Your case the 'T' is some kind of special format that need to be replaced with a blanck space. I have no idea about what it would look like in talend but in VB it would look like this:
' from yyyy-MM-dd'T'HH:mm:ss.SSSz to yyyy-mm-dd HH:mm:ss
DateTxt = "2022-12-01'T'22:45:10"
DateTxt = Replace(DateTxt, "'T'", " ")
MyDate = CDate(DateTxt)
MsgBox Format(MyDate, "yyyy-mm-dd HH:mm:ss")
Related
I am working with a dataset with the following Timestamp format: yyyy-MM-dd HH:mm:ss
When I output the data to csv the format changes to something like this: 2019-04-29T00:15:00.000Z
Is there any way to get it to the original format like: 2019-04-29 00:15:00
Do I need to convert that column to string and then push it to csv?
I am saying my file to csv like so:
df.coalesce(1).write.format("com.databricks.spark.csv"
).mode('overwrite'
).option("header", "true"
).save("date_fix.csv")
Alternative
spark >=2.0.0
set option("timestampFormat", "yyyy-MM-dd HH:mm:ss") for format("csv")
df.coalesce(1).write.format("csv"
).mode('overwrite'
).option("header", "true"
).option("timestampFormat", "yyyy-MM-dd HH:mm:ss"
).save("date_fix.csv")
As per documentation-
timestampFormat (default yyyy-MM-dd'T'HH:mm:ss.SSSXXX): sets the string that indicates a timestamp format. Custom date formats follow the formats at java.text.SimpleDateFormat. This applies to timestamp type.
spark < 2.0.0
set option("dateFormat", "yyyy-MM-dd HH:mm:ss") for format("csv")
df.coalesce(1).write.format("com.databricks.spark.csv"
).mode('overwrite'
).option("header", "true"
).option("dateFormat", "yyyy-MM-dd HH:mm:ss"
).save("date_fix.csv")
As per documentation-
dateFormat: specifies a string that indicates the date format to use when reading dates or timestamps. Custom date formats follow the formats at java.text.SimpleDateFormat. This applies to both DateType and TimestampType. By default, it is null which means trying to parse times and date by java.sql.Timestamp.valueOf() and java.sql.Date.valueOf()
ref - readme
Yes, that's correct. The easiest way to achieve this is using pyspark.sql.functions.date_format such as:
import pyspark.sql.functions as f
df.withColumn(
"date_column_formatted",
f.date_format(f.col("timestamp"), "yyyy-MM-dd HH:mm:ss")
)
More info about it here https://spark.apache.org/docs/latest/api/python/pyspark.sql.html#pyspark.sql.functions.date_format.
Hope this helps!
I want to convert string
1516270217
to date format
hh:mm dd-MM-YY
You can do that in a tmap for example.
TalendDate.formatDate("hh:mm dd-MM-YY",TalendDate.parseDate("HHmmddMMyy",row21.newColumn))
I am converting a date into unix timestamp and fetching the date using split as follows
tm := time.Unix(1470009600, 0).UTC()
dateString := strings.Split(tm.String(), " ")
The output of dateString is 2016-07-15 i.e. YYYY-MM-DD format. How can I convert this into DD-MMM-YY format? eg: 15-Jul-16?
Use Format method with the appropriate format:
fmt.Println(tm.Format("02-Jan-06")) // Prints "01-Aug-16".
Playground: https://play.golang.org/p/uYDYzPwnbJ.
Anybody converted a date from mm/dd/yyyy hh:mm format to
yyyy-mm-dd hh:mm:ss format using hive query ?
I have a string with date in the / format need to add some duration in it
Do this:
select
regexp_replace('2015/04/15','(\\d{4})\\/{1}(\\d{2})\\/{1}(\\d{2})','$1-$2-$3') as dt
from x;
INPUT:2015/04/05
OUTPUT:2015-04-05
Grab four numeric digits (\d{4}), two (\d{2}), and two more (\d{2}) from the original string and put them in that order seperated by dashes.
I want to filter my View according to selected date which is in the format "DD/MM/YYYY", but my dataview column has date in "DD/MM/YYYY hh:mm:ss" format.I want to filter the view according to selected date irrespective of time.How do i convert MATCH_DATE column to the format "DD/MM/YYYY" format in RowFilter.
dtFixt.DefaultView.RowFilter = "MATCH_DATE='" & CType(calSeason.SelectedDate,DateTime).ToString("dd/MM/yyyy") & "'"
You can convert the MATCH_DATE column to "DD/MM/YYYY" format in your view, using CONVERT function as follows:
CONVERT(VARCHAR(10), MATCH_COLUMN, 103)
103 is a Date Format Code that converts the any date in "DD/MM/YYYY" format.
For more details on different date formats, refer article Date Formats.