I have a long list of numbers that I need added and subtracted inside powershell but when I paste the numbers in to the shell they all end up showing on new lines.
It looks like:
+15
-14
+2
I want it to look like +15-14+2 without having to go in and format each number. How would I do this?
I've tried running this as one variable and powershell reads each line as a separate number to echo and print rather than process.
Assuming you trust what is on the clipboard, you can use Invoke-Expression (iex) as follows - though note that use of this cmdlet is generally to be avoided:
(Get-Clipboard) -join ' ' | Invoke-Expression
Get-Clipboard streams what is on the clipboard line by line.
-join ' ' joins the resulting lines to form a single-line string, with the input lines separated with ' ' (a single space).
Invoke-Expression evaluates the resulting single-line string as PowerShell code.
Related
I need to swap place of 2 or more regex strings in one line or some lines in a txt file in powershell.
In npp i just find ^(String 1.*)\r\n(String 2.*)\r\n(String 3.*)$ and replace with \3\r\n\1\r\n\2:
String 1 aksdfh435##%$dsf
String 2 aksddfgdfg$dsf
String 3 aksddfl;gksf
Turns to:
String 3 aksddfl;gksf
String 1 aksdfh435##%$dsf
String 2 aksddfgdfg$dsf
So how can I do it in Powershell? And if possible can I use the command by calling powershell -command in cmd?
It's basically exactly the same in PowerShell, eg:
$Content = #'
Unrelated data 1
Unrelated data 2
aksdfh435##%$dsf
aksddfgdfg$dsf
aksddfl;gksf
Unrelated data 3
'#
$LB = [System.Environment]::NewLine
$String1= [regex]::Escape('aksdfh435##%$dsf')
$String2= [regex]::Escape('aksddfgdfg$dsf')
$String3= [regex]::Escape('aksddfl;gksf')
$RegexMatch = "($String1.*)$LB($String2.*)$LB($String3.*)$LB"
$Content -replace $RegexMatch,"`$3$LB`$1$LB`$2$LB"
outputs:
Unrelated data 1
Unrelated data 2
aksddfl;gksf
aksdfh435##%$dsf
aksddfgdfg$dsf
Unrelated data 3
I used [System.Environment]::NewLine since it uses the default line break no matter what system you're on. Bound to a variable for easier to read code. Either
\r\n
or
`r`n
would've worked as well. The former if using single quotes and the latter (using backticks) when using double quotes. The backtick is what I use to escape $1, $2 and so on as well, that being the format to use when grabbing the first, second, third group from the regex.
I also use the [regex]::Escape('STRING') method to escape the strings to avoid special characters messing things up.
To use file input instead replace $Content with something like this:
$Content = Get-Content -Path 'C:\script\lab\Tests\testfile.txt' -Raw
and replace the last line with something like:
$Content -replace $RegexMatch,"`$3$LB`$1$LB`$2$LB" | Set-Content -Path 'C:\script\lab\Tests\testfile.txt'
In PowerShell it is not very different.
The replacement string needs to be inside double-qoutes (") here because of the newline characters and because of that, you need to backtick-escape the backreference variables $1, $2 and $3:
$str -replace '^(String 1.*)\r?\n(String 2.*)\r?\n(String 3.*)$', "`$3`r`n`$1`r`n`$2"
This is assuming your $str is a single multiline string as the question implies.
I've read in the docs for PSReadLineOption that I can amend empty lines below the prompt to separate output from the next input. So I've tried the following.
Set-PSReadLineOption -ExtraPromptLineCount 3
As far I can tell, there's not empty lines appearing and I'm uncertain if I'm doing it wrong, if I'm imagining the result differently than intended or whatever is up with this.
I believe what you're trying to accomplish can be done in a simpler way. At the end of your output, just write a newline "`n" to stdout.
Write-Host "`n"
Sequences such as `n which use the back tick ` which is the PowerShell escape character, and a letter to make an escape sequence. These are called special characters. In the specific case of `n, it represents a newline. In the docs I linked, it lists the escape sequences that you can use within PowerShell, to implement these special characters.
I've been messing arround with Powershell and googling various things as I go along. This one is a little hard to put into words that google woule understand. I can get the indevidual lines of a text file in powershell by indexing:
$textFile = Get-Content "myText.txt"
$textFile[0]
This would output the first line of the text file. But when I put the text file in quotes it will output all lines, even with the index
"$textFile[0]"
How can I still get only get the line I want, while wrapping the variable in quotes? If I try "$textFile"[0] it will just give me the whole file as before. The reason I'm trying to do this is because I'm trying to make that one line of the text file part of a bigger string that I can execute
$remote = "Enter-PSSession -ComputerName`", textFile[0]"
Invoke-Expression $remote
This is my way of illustrating what I'm trying to do.
You can use any of the following methods:
# Sub-expression operator
"Some Text $($textFile[0])"
# String format operator
"My Text {0}" -f $textFile[0]
# Concatenation
("Text"+$textFile[0])
Surrounding double quotes tells PowerShell to expand the string inside. Any variables within will be interpolated. Variables begin with $ and their following names can only have certain characters without requiring a special escape. [ would require an escape and since it isn't escaped, PowerShell interprets the variable name ending with the character just before the [. Therefore $textFile is interpolated, the whole file contents are converted into a string, and [0] is appended to the end of the string.
You can see details of the operators at About_Operators.
See About_Variables for how to create a variable including cases with special characters even if that doesn't directly apply here.
I need to output the content of a powershell variable to the clipboard, preserving all the newline characters except for the last -trailing- one.
At the moment I am just piping the output of a variable readout to clip.exe, but that gives a trailing newline.
$Text = "line1`nline2"
$Text | clip.exe
gives the following:
"line1,
line2
"
I would like it to output
"line1,
line2"
How might I achieve this?
Using the pipeline can result in a new line being added by powershell. You can use Set-Clipboard and it should avoid the newline issue.
You can also use the .NET option as well:
[System.Windows.Forms.Clipboard]::SetText("line1`r`nline2")
Get-Content $user| Foreach-Object{
$user = $_.Split('=')
New-Variable -Name $user[0] -Value $user[1]}
Im trying to work on a script and have it split a text file into an array, splitting the file based on each new line
What should I change the "=" sign to
It depends on the exact encoding of the textfile, but [Environment]::NewLine usually does the trick.
"This is `r`na string.".Split([Environment]::NewLine)
Output:
This is
a string.
The problem with the String.Split method is that it splits on each character in the given string. Hence, if the text file has CRLF line separators, you will get empty elements.
Better solution, using the -Split operator.
"This is `r`na string." -Split "`r`n" #[Environment]::NewLine, if you prefer
You can use the String.Split method to split on CRLF and not end up with the empty elements by using the Split(String[], StringSplitOptions) method overload.
There are a couple different ways you can use this method to do it.
Option 1
$input.Split([string[]]"`r`n", [StringSplitOptions]::None)
This will split on the combined CRLF (Carriage Return and Line Feed) string represented by `r`n. The [StringSplitOptions]::None option will allow the Split method to return empty elements in the array, but there should not be any if all the lines end with a CRLF.
Option 2
$input.Split([Environment]::NewLine, [StringSplitOptions]::RemoveEmptyEntries)
This will split on either a Carriage Return or a Line Feed. So the array will end up with empty elements interspersed with the actual strings. The [StringSplitOptions]::RemoveEmptyEntries option instructs the Split method to not include empty elements.
The answers given so far consider only Windows as the running environment. If your script needs to run in a variety of environments (Linux, Mac and Windows), consider using the following snippet:
$lines = $input.Split(
#("`r`n", "`r", "`n"),
[StringSplitOptions]::None)
There is a simple and unusual way to do this.
$lines = [string[]]$input
This will split $input like:
$input.Split(#("`r`n", "`n"))
This is undocumented at least in docs for Conversions.
Beware, this will not remove empty entries.
And it doesn't work for Carriage Return (\r) line ending at least on Windows.
Experimented in Powershell 7.2.
This article also explains a lot about how it works with carriage return and line ends. https://virot.eu/powershell-and-newlines/
having some issues with additional empty lines and such i found the solution to understanding the issue. Excerpt from virot.eu:
So what makes up a new line. Here comes the tricky part, it depends.
To understand this we need to go to the line feed the character.
Line feed is the ASCII character 10. It in most programming languages
escaped by writing \n, but in powershell it is `n. But Windows is not
content with just one character, Windows also uses carriage return
which is ASCII character 13. Escaped \r. So what is the difference?
Line feed advances the pointer down one row and carriage return
returns it to the left side again. If you store a file in Windows by
default are linebreaks are stored as first a carriage return and then
a line feed (\r\n). When we aren’t using any parameters for the
split() command it will split on all white-space characters, that is
both carriage return, linefeed, tabs and a few more. This is why we
are getting 5 results when there is both carriage return and line
feeds.