OpenXML Property to Indent Nested List - openxml

I created a bullet list with OpenXML. However, I can't figure out how to enable indentation when tab is pressed on a bullet.
Here is the code snippet to create bullet rows:
var abstractLevel1 = new Level(new NumberingFormat() {Val = NumberFormatValues.Bullet}, new LevelText() {Val = "●"}) {LevelIndex = 0};
var abstractLevel2 = new Level(new NumberingFormat() {Val = NumberFormatValues.Bullet}, new LevelText() {Val = "○"}) {LevelIndex = 1};
var abstractLevel3 = new Level(new NumberingFormat() {Val = NumberFormatValues.Bullet}, new LevelText() {Val = "■"}) {LevelIndex = 2};
var abstractNum1 = new AbstractNum(abstractLevel1, abstractLevel2, abstractLevel3) {AbstractNumberId = abstractNumberId};
In the created document, when I try to create a sub/nested bullet by hitting tab, it results in the following:
● Apples
○ Green Apples
● Pears
The bullet type changes as I expect but the indentation is wrong for Green Apples.
I took a document that has a working bullet list and converted it to an XML. Here is the section for the bullet list style:
<text:list-style style:name="WWNum1">
<text:list-level-style-bullet text:level="1" text:style-name="ListLabel_20_1" style:num-suffix="●" text:bullet-char="●">
<style:list-level-properties text:list-level-position-and-space-mode="label-alignment">
<style:list-level-label-alignment text:label-followed-by="listtab" fo:text-indent="-0.25in" fo:margin-left="0.5in"/>
</style:list-level-properties>
</text:list-level-style-bullet>
<text:list-level-style-bullet text:level="2" text:style-name="ListLabel_20_2" style:num-suffix="○" text:bullet-char="○">
<style:list-level-properties text:list-level-position-and-space-mode="label-alignment">
<style:list-level-label-alignment text:label-followed-by="listtab" fo:text-indent="-0.25in" fo:margin-left="1in"/>
</style:list-level-properties>
</text:list-level-style-bullet>
<text:list-level-style-bullet text:level="3" text:style-name="ListLabel_20_3" style:num-suffix="■" text:bullet-char="■">
<style:list-level-properties text:list-level-position-and-space-mode="label-alignment">
<style:list-level-label-alignment text:label-followed-by="listtab" fo:text-indent="-0.25in" fo:margin-left="1.5in"/>
</style:list-level-properties>
Notice the properties fo:text-indent and fo:margin-left. These properties are missing in the XML document produced by my code. I suspect this is the reason why sub/nested bullets are not being indented as shown in the example above. I searched through the OpenXML documentation and I could not find any information on these 2 properties. Which OpenXML class is responsible for those properties? I'm sure I need to add another argument when I instantiate a Level class but I could not figure out from the doc what it needs to be. Any ideas?
So far I've tried playing around with the ParagraphStyleIdInLevel and Indentation classes to no success.

Related

vscode API: get Position of last character of line

Following up on this still unanswered question regarding VS Code Extensions with the VS Code API. I didn't answer it because it specifically asked for a solution using the with method of the Position object. I couldn't make that work, nor was I able to loop through the object to get the last character. Trying to manipulate the selection with vscode.commands.executeCommand didn't work either, because vscode.window.activeTextEditor doesn't appear to reflect the actual selection in the window as soon as the Execution Development Host starts running. The only solution I could find was the hoop-jumping exercise below, which gets the first character of one line and the first character of the next line, sets a Range, gets the text of that Range, then reduces the length of that text string by 1 to get the last character of the previous line.
function getCursorPosition() {
const position = editor.selection.active;
curPos = selection.start;
return curPos;
}
curPos = getCursorPosition();
var curLineStart = new vscode.Position(curPos.line, 0);
var nextLineStart = new vscode.Position(curPos.line + 1, 0);
var rangeWithFirstCharOfNextLine = new vscode.Range( curLineStart, nextLineStart);
var contentWithFirstCharOfNextLine = editor.document.getText(rangeWithFirstCharOfNextLine);
var firstLineLength = contentWithFirstCharOfNextLine.length - 1;
var curLinePos = new vscode.Position(curPos.line, firstLineLength);
var curLineEndPos = curLinePos.character;
console.log('curLineEndPos :>> ' + curLineEndPos);
I'm obviously missing something - it can't be impossible to get the last character of a line using the VSCode API without mickey-mousing the thing like this. So the question is simply, what is the right way to do this?
Once you have the cursor Position the TextDocument.lineAt() function returns a TextLine. From which you can get its range and that range.end.character will give you the character number of the last character. - not including the linebreak which if you want to include that see TextLine.rangeIncludingLineBreak().
const editor = vscode.window.activeTextEditor;
const document = editor.document;
const cursorPos = editor.selection.active;
document.lineAt(cursorPos).range.end.character;
Note (from [TextDocument.lineAt documentation][1] ):
Returns a text line denoted by the position. Note that the returned
object is not live and changes to the document are not reflected.

How can I create a function that automatically takes data from Google Sheets and replaces the tags in a Slides template?

I am new to Google Apps Script and coding in general and wasn't entirely sure how to do this. I want to create code that allows me to create a new set of Google Slides based on a Slides template using the relevant rows from a Google Sheets document.
function generateNewSlides() {
var wsID = "would insert worksheet URL ID here";
var ws = SpreadsheetApp.openById(wsID).getSheetByName("Data");
var data = ws.getRange(2, 1, ws.getLastRow()-1, 5).getValues();
>the above should get the relevant table from the sheet
data.forEach(function(info){
if(info[0]){
var firstname = info[0];
var surname = info[1];
var email = info[2];
var phone = info[3];
var image = info[4];
var presName = info[5];
>the above are columns where the different pieces of data would be taken from for the placeholders in the Slides template
var slidesTemplateID = "would insert slides template URL ID here";
var slidesTemplate = SlidesApp.openById(slidesTemplateID);
var template = slidesTemplate.getSlides();
var folderID = "would insert desired folder ID for saving in here";
>the above should get me the Slides template
template.makeCopy(presName,DriveApp.getFolderById(folderID)); **>line where error occurred**
var newPresentation = DriveApp.getFilesByName(presName).next().getUrl();
var Presentation = SlidesApp.openByUrl(newPresentation);
>the above should create a copy and then open it
var shapes = (Presentation.getShapes());
shapes.forEach(function(shape){
shape.getText().replaceAllText('{{firstname}}',firstname);
shape.getText().replaceAllText('{{surname}}',surname);
shape.getText().replaceAllText('{{email}}',email);
shape.getText().replaceAllText('{{phone}}',phone);
shape.getText().replaceAllText('{{presname}}', presName)
});
>the above should replace all the placeholder tags in the template with the row data
}
});
}
Above is the code I have so far. The worksheet I am extracting data from has columns: first name, surname, email address, phone number, image (URL), and presentation name. When I try to run it I encounter an error on line 37 where it says template.makeCopy is not a function, however I am certain .makeCopy should be able to create a copy for it, no?
My main questions are:
1) What should I change to make it work, generating a new set slides for each row in the worksheet?
2) How can I add images to it replacing placeholder tags I've added in squares (not textboxes) in the template?
Thanks in advance!
Issue 1. makeCopy:
makeCopy(name, destination) is a method of the class File, which belongs to the Drive Service, not to the Slides Service. In your code, template is a list of Slides (you retrieve it by calling the method getSlides() from a Presentation). makeCopy cannot work here.
In order to make a copy of a Presentation, you should be using the Drive Service instead. You should replace these lines:
var slidesTemplate = SlidesApp.openById(slidesTemplateID);
var template = slidesTemplate.getSlides();
With this one:
var template = DriveApp.getFileById(slidesTemplateID);
Issue 2. Iterating through all shapes:
Next, you want to iterate through all shapes in your Presentation, and replace all placeholder tags with your desired text. In order to do that, you are using Presentation.getShapes(), which cannot work, since getShapes() is not a method of Presentation, but of Slide.
You should first iterate through all Slides in the Presentation, and for each Slide, iterate through all Shapes. You should replace these lines:
var shapes = (Presentation.getShapes());
shapes.forEach(function(shape){
// Replacing text lines
});
With these ones:
Presentation.getSlides().forEach(function(slide) {
slide.getShapes().forEach(function(shape) {
// Replacing text lines
})
});
Note:
In order to retrieve the copied presentation, you are currently doing this:
template.makeCopy(presName,DriveApp.getFolderById(folderID));
var newPresentation = DriveApp.getFilesByName(presName).next().getUrl();
var Presentation = SlidesApp.openByUrl(newPresentation);
There is no need to do this, you can just retrieve the ID of the created template, and open by ID, like this:
var copiedTemplate = template.makeCopy(presName,DriveApp.getFolderById(folderID));
var Presentation = SlidesApp.openById(copiedTemplate.getId());
Reference:
Slides Service
Drive Service

LibreOffice how to recup the current element

I want to retrieve the current element in LibreOffice Impress to apply changes to it.
For example, I'm trying to retrieve this shape to change the text in it with macros.
I tried to find information with the X-ray tool but without success.
To get the currently selected shape:
oSel = ThisComponent.getCurrentController.getSelection()
oShape = oSel.getByIndex(0)
Print oShape.getString()
To iterate through all shapes in the slide, start with ThisComponent.getDrawPages() and then use XrayTool.
You may also find the following snippet of python code helpful:
def iterate_draw_shapes():
oDrawPage = oDrawPages.getByIndex(1)
for oShape in oDrawPage:
if oShape.supportsService("com.sun.star.drawing.TextShape"):
oTexts = oShape.createEnumeration()
while oTexts.hasMoreElements():
oText = oTexts.nextElement()
oTextPortions = oText.createEnumeration()
while oTextPortions.hasMoreElements():
oTextPortion = oTextPortions.nextElement()

Create an Array from list of objects in MaxScript and add them to a new layer

I'm super new to Maxscript and want to automate a process, I've been looking at some tutorials, but I'm running into a issue with selection. What I'm trying to do, is I have a list of strings (that I might have to add to) that represent objects in the max file that I want to select (if they exist in that file) and then add to a new layer.
for instance:
/* I have a big long list of objects I want to mass select, this has to be hardcoded because its a similar list that exists in a ton of max files */
rObj1 = "testObj1"
rObj2 = "sampleObj2"
""
rObj99 = "newObj90"
/*I want to then add it to an array
removeList = #(rObj***)
/* Then run through each entry in the array to make sure it exists and then add it to my selection
for i in removeList do
(
if i != undefined then select (i)
)
/*Then Add what I have selected to a new layer
newLayer = LayerManager.newLayerFromName "removed_list"
for obj in selection do newLayer.addNode obj
I keep getting an error when it comes to selection, being new to Max I'm not sure what to do.
You are trying to select string where you should be selecting (or adding to the layer) an object:
newLayer = LayerManager.newLayerFromName "removed_list"
for objName in removeList where isValidNode (getNodeByName objName) do
newLayer.addNode (getNodeByName objName)

Get all outging connectors from a shape programmatically

I want to rename a connector after a shape has been dropped.
Lets say I have a shape1 and I dropped a shape2 connected with shape1.
I want the connector shape between shape1 and shape2 so that I can rename it.
I guess it depends on what stage you intercept the drop. If it's immediately, you might make some assumptions about how many connectors might be involved, but if if some time after the drop then you might want to determine how many connections are involved.
As an example, with the following shapes:
...you could approach this in a number of ways:
Use the GluedShapes method working back from ShapeTwo
Use the GluedShapes method including the 'from' shape
Iterate through the Connects collection of the Page
Iterate over the Connect objects in on your target shape (ShapeOne)
I would definitely try and use the GluedShapes method (which came into Visio in 2010) over the Connect objects, but I'm adding them here as they can be useful depending on what you're trying to achieve.
Here's an example using LINQPad:
void Main()
{
var vApp = MyExtensions.GetRunningVisio();
var vPag = vApp.ActivePage;
//For demo purposes I'm assuming the following shape IDs
//but in reality you'd get a reference by other methods
//such as Window.Selection, Page index or ID
var shpOne = vPag.Shapes.ItemFromID[1];
var shpTwo = vPag.Shapes.ItemFromID[2];
Array gluedIds;
Console.WriteLine("1) using GluedShapes with the 'to' shape only");
gluedIds = shpTwo.GluedShapes(Visio.VisGluedShapesFlags.visGluedShapesIncoming1D,"");
IterateByIds(vPag, gluedIds);
Console.WriteLine("\n2) using GluedShapes with the 'to' and 'from' shapes");
gluedIds = shpTwo.GluedShapes(Visio.VisGluedShapesFlags.visGluedShapesIncoming1D, "", shpOne);
IterateByIds(vPag, gluedIds);
Console.WriteLine("\n3) using the Connects collection on Page");
var pageConns = from c in vPag.Connects.Cast<Visio.Connect>()
where c.FromSheet.OneD != 0
group c by c.FromSheet into connectPair
where connectPair.Any(p => p.ToSheet.ID == shpOne.ID) && connectPair.Any(p => p.ToSheet.ID == shpTwo.ID)
select connectPair.Key.Text;
pageConns.Dump();
Console.WriteLine("\n4) using FromConnects and Linq to navigate from shpOne to shpTwo finding the connector in the middle");
var shpConns = from c in shpOne.FromConnects.Cast<Visio.Connect>()
where c.FromSheet.OneD != 0
let targetConnector = c.FromSheet
from c2 in targetConnector.Connects.Cast<Visio.Connect>()
where c2.ToSheet.Equals(shpTwo)
select targetConnector.Text;
shpConns.Dump();
}
private void IterateByIds(Visio.Page hostPage, Array shpIds)
{
if (shpIds.Length > 0)
{
for (int i = 0; i < shpIds.Length; i++)
{
//Report on the shape text (or change it as required)
Console.WriteLine(hostPage.Shapes.ItemFromID[(int)shpIds.GetValue(i)].Text);
}
}
}
Running the above will result in this output:
It's worth bearing in mind that the Connects code (3 and 4) makes the assumption that connector shape (1D) are being connected to the flowchart shapes (2D) and not the other way round (which is possible).
You can think of the connect objects as being analgous to connection points, so in the diagram, the three connector shapes generate six connect objects:
Anyway, hope that gets you unstuck.
UPDATE - Just to be clear (and to answer the original question properly), the code to get all outgoing connectors from ShapeOne would be:
Console.WriteLine("using GluedShapes to report outgoing connectors");
gluedIds = shpOne.GluedShapes(Visio.VisGluedShapesFlags.visGluedShapesOutgoing1D, "");
IterateByIds(vPag, gluedIds);