I don't understand why I'm getting this error. It happens either on a virtual or real device. I try to uninstall the app and nothing change. Why a simple helloWord function throw this error. I have no console log displayed. In the log I have this message: "Request has invalid method. GET" then "Error: Invalid request, unable to process. at entryFromArgs..." Why redirect? Could it be related to the cloud region I change? How could I clean that. Thank you.
Below the cloud function.
exports.belleDiana = functions.region(CLOUD_REGION).https.onCall(async (data, context) : Promise<String> => {
console.log("belleDiana", data, context);
console.log("context.auth", context.auth?.uid, context);
return "belleDianaDone";
});
The call on flutter side.
try {
final result =
await FirebaseFunctions.instance.httpsCallable('belleDiana').call();
print("result: $result");
} on FirebaseFunctionsException catch (error) {
print(error);
print(error.code);
print(error.details);
print(error.message);
}
I switch to the original region 'us-central1'. When I change cloud region I have this message " Unhandled error cleaning up build images. This could result in a small monthly bill if not corrected. You can attempt to delete these images by redeploying or you can delete them manually at https://console.cloud.google.com/artifacts/docker/myproject/europe-west1/gcf-artifacts
"
After the deletion of that manually, every thing work as attended. I don't really understand why...
Related
I am implementing Facebook Sign In with Firebase in my Flutter App, and when a user signs in with Facebook Sign In for the first time I am changing the "emailverified" property to true. I do this through functions with the following code:
if (facebookUser.user?.emailVerified == false) {
try {
HttpsCallable callable = FirebaseFunctions.instance.httpsCallable('verifyFacebook');
await callable.call();
} on FirebaseFunctionsException catch (e) {
print(e.code);
print(e.plugin);
print(e.message);
}
}
where verifyFacebook is:
exports.verifyFacebook = functions.auth.user().onCreate(async (snap) => {
return await admin.auth().updateUser(snap.uid, {
emailVerified: true
});
})
What I do not understand is that a Firebase Function Exception of "unauthenticated" is printed in the console, but when I sign in for the second time the "emailverified" property is changed to true (meaning that the Firebase Function was executed properly)! How could this happen if in the try-catch part I was thrown an error?
I searched for other answers such as adding a permission in Google Cloud Console but none helped me :(
Thanks in advance!
In Google Cloud Console I added "allUsers" in the Permission property, and I expected my app to work fine without the "unauthenticated" error. However, the issue persisted.
The verifyFacebook function triggers every time a user is created with Firebase Authentication and is not a callable function. You don't have to call the function yourself. When you try to call it, the callable function does not exists and hence you get an error but the function triggered by Firebase Auth does run.
I am trying to implement deleteUser function in cognito which allows the user to delete their own account information by using this code
void deleteUser() async {
try {
await Amplify.Auth.deleteUser();
final state = AuthState(authFlowStatus: AuthFlowStatus.none);
authStateController.add(state);
print('Delete user succeeded');
} on AmplifyException catch (e) {
print('Delete user failed with error: $e');
}
}
However, this code of course is not working for some reason and I don't know why. I also have the user's database in Amplify datastore graphql so I tried deleting the user's datastore data first before getting rid of the user's congnito data but it still does not work. This is the code that I am using to delete user's data from datastore. Please help me out by telling me how I can delete a user's cognito and datastore data.
void deleteUser (DeleteUserData data) async {
(await Amplify.DataStore.query(User.classType, where: User.EMAIL.eq(data.email)))
.forEach((element) async {
try {
await Amplify.DataStore.delete(element);
print('Deleted a user');
} on DataStoreException catch (e) {
print('Delete failed: $e');
}
});
}
Please help me out.
I was facing the same problem, I took a look into the insides of deleteUser method in the AWS api, something I strongly recommend, and I discovered that this API is only available in iOS.
screenshot
I was using amplify_auth_cognito: 0.4.5 and amplify_flutter: 0.4.5.
Upgraded the libraries to 0.5.1 and the warning has disappeared, maybe you can try using a different version of yours (I'm not using Amplify, just simple Cognito).
Cheers.
Hi I tried to catch a socketException when the server I am consulting is not available, I tried with try{}catch{}, catchError and timeout, but it doesn't work
I need that if some time passes that the server does not respond, that it already stops waiting for it
The error is :
and I tried something like this
You are probably giving the code the wrong URL. Maybe this link will help You. Link. If You could just type in the URL and If You are using Python with flask or Django, or Node.js, that would help tremendously.
Update:
In the part where You say
final resp = await http.get(url).catchError({(onError) => print(onError)});
You should change it to this:
final resp = await http.get(url).catchError((onError) {
print(onError);
return null;
});
Because You are catching the Error in the response and only printing it. You should return null; and escape that function.
I hope this helped.
I have a firebase cloud function to create a user document with user data whenever a user registers. How would I return an error when the set() fails? Since this is not an http request (an I don't want to use an http request in this case) I have no response. So how would I catch errors?
export const onUserCreated = functions.region('europe-west1').auth.user().onCreate(async user => {
const privateUserData = {
phoneNumber: user.phoneNumber
}
const publicUserData = {
name: 'Nameless'
}
try
{
await firestore.doc('users').collection('private').doc('data').set(privateUserData);
}catch(error)
{
//What do I put here?
}
try
{
await firestore.doc('users').collection('public').doc('data').set(publicUserData);
}catch(error)
{
//What do I put here?
}
});
You can't "return" an error, since the client doesn't even "know" about this function running, there is nobody to respond to.
You can make a registration collection, and in your function make a document there for the current user (using the uid as the document id). In that document, you can put any information you'd like your user to know (status, errors, etc).
So your clients would have to add a listener to this document to learn about their registration.
In your particular code, I think the error is in doc('users'). I guess you meant doc('users/'+user.uid).
Your catch -block will receive errors that occur on your set -call:
try {
await firestore.doc('users').collection('public').doc('data').set(publicUserData);
} catch (error) {
// here you have the error info.
}
I have the following code that I am using to log a user in silently
try {
result = await GoogleSignIn().signInSilently().catchError((x) {
print(x);
});
} catch (e) {
print(e);
}
If the user cannot sign in silently, it results in an error.
PlatformException (PlatformException(sign_in_required, com.google.android.gms.common.api.ApiException: 4: 4: , null))
The problem I am having is that I cannot seem to catch the exception. catchError nor the catch block are being hit. How do I catch this error?
Do the following in your method
try {
result = await GoogleSignIn().signInSilently(suppressErrors: false).catchError((x) {
print(x);
});
} catch (e) {
print(e);
}
By default suppressErrors = true suppressing the error messages you want to catch.
Looking at the source code
The SignInSilently method is used to suppress error messages thus not throwing the exception you want to catch.
From the docs of this method:
/// When [suppressErrors] is set to `false` and an error occurred during sign in
/// returned Future completes with [PlatformException] whose `code` can be
/// either [kSignInRequiredError] (when there is no authenticated user) or
/// [kSignInFailedError] (when an unknown error occurred).
Full Method
/// Attempts to sign in a previously authenticated user without interaction.
///
/// Returned Future resolves to an instance of [GoogleSignInAccount] for a
/// successful sign in or `null` if there is no previously authenticated user.
/// Use [signIn] method to trigger interactive sign in process.
///
/// Authentication process is triggered only if there is no currently signed in
/// user (that is when `currentUser == null`), otherwise this method returns
/// a Future which resolves to the same user instance.
///
/// Re-authentication can be triggered only after [signOut] or [disconnect].
///
/// When [suppressErrors] is set to `false` and an error occurred during sign in
/// returned Future completes with [PlatformException] whose `code` can be
/// either [kSignInRequiredError] (when there is no authenticated user) or
/// [kSignInFailedError] (when an unknown error occurred).
Future<GoogleSignInAccount> signInSilently({bool suppressErrors = true}) {
final Future<GoogleSignInAccount> result = _addMethodCall('signInSilently');
if (suppressErrors) {
return result.catchError((dynamic _) => null);
}
return result;
}
Reference
Google Sign In Plugin Repo
Method Source Code Starting Line 283
This might help.
Checklists :
Did not register a sha fingerprint.
Make sure to have my "support email" set.
Enable the Google Sign-in method.
The catchError block is actually getting hit if you use suppressErrors = false
Try the following code and see what it prints on your console.
result = await GoogleSignIn().signInSilently(suppressErrors: false).
catchError((x) {
print("inside catchError");
});
The problem is the print(e); line in the catch statement. 'e' is not a string so an error occurs. I don't know why but no breakpoints are hit in the catch statement for this error and no error is output to the console. If I put a catch statement around a function that calls the login code ie.
void tryLogin(){
try{
myLoginLogic();
} catch(e) {
print(e);
}
}
Then I do get an error message
Unhandled Exception: type '_TypeError' is not a subtype of type 'String'
So to be clear the correct code would be
try {
result = await GoogleSignIn().signInSilently().catchError((e) {
print(e.toString());
});
} catch (e) {
print(e.toString());
}
Why code doesn't break on error and no message is written to the console for the original function I don't know. Also what I don't understand is why, even when the catch statement is written without errors, in debug mode the code breaks on the signInSilently() line.