I am trying to replace a column with these characters --> "{,
I tried using both replace and regex_replace, I am getting the following error.
update mytable
set address = replace(address, ',','_');
this is the error I get.
ERROR: function replace(character varying[], unknown, unknown) does not exist
LINE 1: select replace(address,',','_') from mytable.
^
HINT: No function matches the given name and argument types.
You might need to add explicit type casts.
SQL state: 42883
Character: 8
Related
I am trying to use copy data from CSV to Postgres Table using the following command.
psql -c "\COPY team_cweo.bsa_mobile_pre_retention_asset FROM 'part-00199-8372009a-439d-49e0-9efc-141aead78131-c000.csv' CSV HEADER DELIMITER ','
The CSV file is the result oft Spark DataFrameWriter. I realized that for some fields there are null values which is represent as "" in the CSV file. But because of this I am getting the following error :
ERROR: invalid input syntax for type double precision: ""
CONTEXT: COPY bsa_mobile_pre_retention_asset, line 3, column 6281410000207
How should I do so that Postgresql knows that "" is null values instead of empty string. Or should I do something in the DataFrameWriter so that null values can be represent as something else in the CSV file.
Yes, it would be good if you could choose a different representation for NULL values, ideally an empty string. At any rate, it cannot contain the escape character (by default "). You can then use the NULL option of COPY, for example NULL '(null)' (the default value is the empty string).
If you cannot do that, you could define the column as type text and later convert it with
ALTER TABLE tab
ALTER col TYPE double precision USING CAST (nullif(col, '') AS double precision);
But that requires that the table gets rewritten, which can take a while.
This question already has answers here:
delete "column does not exist"
(1 answer)
SQL domain ERROR: column does not exist, setting default
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Closed last year.
I'm trying to delete a row at PostgreSQL using pgAdmin4.
Here is my command:
DELETE FROM commissions_user
WHERE first_name = "Steven";
For some reason, the error states that
ERROR: column "Steven" does not exist
LINE 2: WHERE first_name = "Steven";
^
SQL state: 42703
Character: 50
It's weird, why is "Steven" detected as a column name, shouldn't the column name be first_name?
Use single quotes instead
DELETE FROM commissions_user
WHERE first_name = 'Steven';
Double quotes can be used table and column, and single quotes can be used for strings.
ex.
DELETE FROM "commissions_user"
WHERE "first_name" = 'Steven';
https://www.postgresql.org/docs/current/sql-syntax-lexical.html
Double quote:
A convention often used is to write key words in upper case and names
in lower case, e.g.:
UPDATE my_table SET a = 5;
There is a second kind of identifier: the delimited identifier or
quoted identifier. It is formed by enclosing an arbitrary sequence of characters in double-quotes ("). A delimited identifier
is always an identifier, never a key word. So "select" could be used
to refer to a column or table named “select”, whereas an unquoted
select would be taken as a key word and would therefore provoke a
parse error when used where a table or column name is expected. The
example can be written with quoted identifiers like this:
UPDATE "my_table" SET "a" = 5;
Single Quote:
https://www.postgresql.org/docs/current/sql-syntax-lexical.html#SQL-SYNTAX-STRINGS
A string constant in SQL is an arbitrary sequence of characters
bounded by single quotes ('), for example 'This is a string'. To
include a single-quote character within a string constant, write two
adjacent single quotes, e.g., 'Dianne''s horse'. Note that this is not
the same as a double-quote character (")
I'm trying to nest functions in postgresql, trying to extract a directory name (actually the third one) from a path.
My starting SQL code was :
SELECT "Path", regexp_matches("Path", '^([^/]*/){3}.*') FROM ...
Since the returned value of my regex is delimited by curly brace and double-quote (when containing spaces), I'm trying to remove theses delimiters by nesting functions :
SELECT "Path", right(regexp_matches("Path", '^([^/]*/){3}.*'),2) FROM
But I've the following error :
ERROR: function right(text[], integer) does not exist
LINE 2: SELECT "Path", right(regexp_matches("Path", '^([^/]*/){3}.*'...
^
HINT: No function matches the given name and argument types. You might need to add explicit type casts.
État SQL :42883
Caractère :17
I don't know how to format the expression in order to be accepted...
Of course, if someone can give me a way to get exactly the nth field of a string separated by slashes, I would be happy !
ERROR: function dharani.fn_generate_ror_1b_citizen(bytea, character varying) does not exist at character 15
HINT: No function matches the given name and argument types. You might need to add explicit type casts.
STATEMENT: select * from dharani.fn_generate_ror_1b_citizen($1,$2)
ERROR: function dharani.fn_generate_pahani_citizen(bytea, bytea, character varying) does not exist at character 15
HINT: No function matches the given name and argument types. You might need to add explicit type casts.
STATEMENT: select * from dharani.fn_generate_pahani_citizen($1,$2,$3)
You have to supply function arguments of the appropriate type, if necessary using type casts as the hint says.
SQL is a typed language, and PostgreSQL uses function overloading, so it is essential the data types are resolved properly. The exact rules how this is done are in the documentation.
How do i get nextval without advancing the cursor in PostgreSQL?
This doesn't work:
pgdb=# SELECT curval('schemas.category_category_id_seq');
ERROR: function curval(unknown) does not exist
LINE 1: SELECT curval('schemas.category_category_id_seq');
^
HINT: No function matches the given name and argument types. You might need to add explicit type casts.
PostgreSQL's nextval() function is safe. But currval()+1 isn't.
From what I can tell, your function name is just wrong. It is "currval". See https://dba.stackexchange.com/questions/3281/how-do-i-use-currval-in-postgresql-to-get-the-last-inserted-id
BTW, if you can assume your sequence just increments by one, you can do:
select currval('schemas.category_category_id_seq') + 1;