I am currently working on a project for watchOS that involves the creation of a new menu using SwiftUI. The issue I am encountering is that the new menu always displays a 'Cancel' button in the top left corner of the screen. This button allows the user to leave the menu, which I do not want to happen.
WatchOS Simulator displaying the cancel button
Button(action: {
self.showRide = true
}) {
Text("Start Ride")
}
.sheet(isPresented: $showRide) {
StartRide()
}
To address this, I would like to remove the 'Cancel' button from the screen and replace it with a custom button. I understand that there will be an 'Exit' button available in the view later on, but I would like to have more control over the user experience.
Is it possible to achieve the removal of the 'Cancel' button and replacement with a custom button in this scenario? I am eager to find a solution and would appreciate any help or guidance offered.
I initially attempted to use NavigationLink to open the new menu, however, it was not successful. Despite my efforts, the menu simply would not open. As a result, I decided to stick with my original code. While this solution may not be the most ideal, it has proven to be functional in opening the menu as intended. However, the main issue with my original code is the presence of the 'Cancel' button in the top left corner of the screen. I would like to remove this button and have more control over the user experience within the menu.
Related
I'm building a status bar app (windowless) on OSX and having trouble with a pesky little UI bug.
The application opens up a preferences window from the status bar menu when a certain menu item is clicked. The bug presents after the following scenario:
A user opens the preference window from the status bar menu
App resigns the active status when the user opens a browser or another app
User clicks the status bar item (to look at some info in the menu) but doesnt click the menuitem to show the preferenceswindow
User closes the other application and clicks on the already opened preferences window again
After this sequence the NSWindow representing the preferences window appears inactive while still accepting key events. By inactive I mean that the close button for the preferences NSWindow is gray unless hovered over, all the textfields don't get a blue focus ring when clicked and buttons with keyEquivalent = "\r" are not blue. The status bar item will also not highlight. It's like some other hidden window is hijacking the visuals of an active window.
This is what the preferences window looks like normally:
This is what it looks like after the scenario I just described:
How do I make it so that when the preferences NSWindow looks active when clicked even if the user has used other apps and clicked the status bar item in the meantime? Note that the window accepts keyevents normally, and the application is active. Even just a step further in how to debug this would be helpful. Ive logged the main/key window and the apps active status in multiple places and everything looks right.
I think I figured it out. Apparently the NSMenu pop up from the statusbar blocks the execution of the application code. Somehow the NSMenu was retaining the focus even if the menu had been closed if the application wasn't active.
Solution was to activate the app if windows are open when clicking on the NSMenu before popUpMenu is called. Note that the popUpMenu must be done slightly later to not block the activation of the app. Something like:
let noWindowsOpen = extraVisibleWindows.count == 0
if (!noWindowsOpen) {
NSApp.activate(ignoringOtherApps: true)
}
Timer.scheduledTimer(withTimeInterval: 0.04, repeats: false) { _ in
self.statusItem.popUp(self.menu)
}
I found the solution on Github for another app that was dealing with similar problems.
I have an app with 2 pages. The first page is the main menu, and when you navigate to the 2nd page, a keyboard open himself inside a TextField (autofocus).
What I want to do is disabling every ways of closing the keyboard. Right now, it doesn't close when you submit, but that's the only thing I achieved to do.
The user can still close it with every other ways (in my case, it's the android navigation bar who has the left button who can dismiss it).
Is there any ways to keep the keyboard open during the whole time an user stays on a page?
EDIT:
I found this package : keyboard_visibility to do that inside initState:
KeyboardVisibilityNotification().addNewListener(onHide: () {
setState(() {
FocusScope.of(context).requestFocus(_focus);
});
});
Each time I hide the keyboard, onHide is called and I can execute some code. Here I try to focus the TextInput again to re-open the keyboard immediately. When the keyboard is hided, the function is called, but requestFocus doesn't seems to work.
Try this,
FocusScope.of(context).requestFocus(FocusNode());
I'd like to open an application/extension Window when user clicks toolbar item in safari. This is not question about extension's Popover feature. The main reason is to close/hide the window on deactivation AND user action (both conditions are required to work).
Safari App Extension (meaning the new preferred/forced way to create extensions for safari by Apple) can open a Popover or call a Command when toolbar item is clicked. But it cannot be hidden programatically (https://forums.developer.apple.com/thread/105817). Per answer by bweinstein it's work in progress by apple devs.
My use case is about Window containing WKWebView with loaded webpage. When user clicks anything in there I want to open a page in Safari's new tab (this part already works for me in Popover mode) and close the window immediately (this doesn't work for me yet)
So my thinking here was to avoid integrated Popover feature. I'd like to show Window instead when Command (override func toolbarItemClicked(in window: SFSafariWindow) {}) is called.
I know this is somehow doable as e.g. agilebits' 1Password extension is doing exactly this: when you click a toolbar item, window is displayed having no close/minimize buttons, no menu etc. It works exactly as I need, but I don't know how to achieve that.
I don't know whether to define the view as part of Safari extension or as part of Storyboard of containing app and how to access it programatically and show it on screen when user clicks the toolbar item.
As I am new to macos development I don't really have a code to share. Important part from my POV:
- Info.plist's NSExtension->SFSafariToolbarItem->Action is set to Command
As pointed above, feature I need to achieve is to open and close a Window programatically when user clicks toolbar item.
Thanks in advance
Could you not call SFSafarWindow.openTab("httxxx://mysite.com", true, ...) in your toolbarItemClicked
You could also call SFSafariApplication.openWindow API and close SFSafariWindow (by calling windowObject.close() ) -
I'm trying to make a Cocoa app with buttons that run simple command line scripts.
I can't seem to figure out how to add the action to my button.
I've read some docs that suggest holding down option and dragging the button into controller code but I think they are out of date. Can someone suggest how to get there from this screenshot?
You need to first select your button, then hold the control ⌃ button on your keyboard and then drag that across to your view controller. That will then give you the option of what to name your method etc.
Actually I had the same problem and the root cause was just the drag method. From the descriptions I had assumed that I need to press CTL and then drag while having the left mouse button pressed. This did not work at all (in my environment). Then I noticed that "it works" with the right mouse button. But the result was not correct. (E.g. I could not get "Action"). Finally I found: I have to use the right mouse button only for dragging without holding CTL. Then I got the correct result.
Is it possible to show a popup only in a certain gwt tab or a panel in that tab?
I've found methods to show a popups over the whole page, but not only in specific tabs.
When you switch the gwt tab, the popup should not be visible anymore and new popups should be able to be created, which again are only visible in the switched to gwt tab. Switching back to the other tab should then show the first popup again.
Optionally the rest of the tab, which is not covered by the popup, should not be clickable.
Are there any native methods for this? The gwt Popup Panel only seems to create popups for the whole page.
Edit: I've tried using smartgwts Window which seems to work just the way I want it to. When I switch the gwt-tab, the popup is no longer visible and returns when I switch back. The only problem is, that it isn't displayed right. The frame is placed on the far left side of the browser tab, while the content is displayed on the far left of the gwt-tab. If I move the content, the frame moves too. The frame is visible over the whole browser tab, while the content disappears if I drag it over the gwt-tab edge.
I guess it's because I'm adding a Window to a gwt-Panel. Is there any way to fix this without changing everything to smartgwt?
Not exactly, I think.
But, you can do something in the tab events, like hide the popup in tabs that it doesnt belongs. To avoid the lag of show/hide the popup, you can do this in the BeforeSelectionHandler, like this:
getView().getTabPanel().addBeforeSelectionHandler(new BeforeSelectionHandler<Integer>()
{
#Override
public void onBeforeSelection(BeforeSelectionEvent<Integer> event)
{
showPopupupsForTab(event.getItem());
}
});
In showPopupupsForTab you can show the popups for this tab (you can handle this with a map or something) and hide the others...
Something like this.
Hope it helps.