I'm new, and I need to do something for my master, but I really don't have idea!!
I want to put a new characteristic in a breed.... like make a difference between people (who have more money and who have less) but I was trying everything and always i have a new problem.
What do you recommend to me? What do I need to put?
I have "compradores" but now I want to put a difference on them (and I don't know how) (in the space we have stores and list of shop).
ask patches [ set pcolor yellow ]
set productos ["aceite" "bebidas" "cerveza" "detergente" "especias" "flores" "gasoil" "huevos" "infusiones" "jamon" "kafe" "levadura"]
set-default-shape compradores "person"
create-compradores 10 [
set color pink set heading 0 set size 2
setxy (random world-width) + min-pxcor (random world-height) + min-pycor
set lista-de-compra n-values 10 [item (random (length productos)) productos]
set memoria []
]
Related
I'm new to NetLogo and I'm trying to create 2 sub-breeds (denoted by different shapes) within each breed for 2 breeds total (i.e. sharks and fishes). The chunks of code work as expected when ran individually, however, when running both chunks the first sub-breed of the fishes does not seem to initialise in the interface tab. For some reason the initialisation of the shark breed seems to interfere with the initiation of the fishes breed.
Any idea what i'm doing wrong? Code below.
; Create the agents
breed [sharks shark]
breed [fishes fish]
; Create the agents' variables
fishes-own
[
x0
y0
]
globals
[
species
species-f
]
to setup
; Always start with this
clear-all
reset-ticks
; Create sharks and species
create-sharks N-sharks ; N-sharks is a slider
[
set color blue
setxy random-xcor random-ycor
set species N-sharks
ask sharks
[
set shape "default"
set size 2.5
]
ask sharks with [who >= (species * (1 / 2))]
[
set shape "square"
set size 2
]
ask sharks with [who < (species * (1 / 6))]
[
set shape "star"
set size 3
]
] ; End create sharks and species
; Create fishes
create-fishes N-fishes
[
setxy random-xcor random-ycor
set x0 xcor
set y0 ycor
set species-f (N-fishes * species-ratio)
ifelse who <= species-f
[
set shape "sheep"
set size 5
]
[
set shape "cow"
set size 3
]
set color white
] ; End create fishes
end
There seem to be a number of misunderstandings about what code is run when by NetLogo, and what some pieces of code do: when you use create-turtles *number* [*commands*] (or with breeds, as in your case), commands is run once by every turtle being created (first the new turtles are created, then they run the commands in turn).
That means that every time you use ask sharks within the create-sharks' command block, every new shark will ask all other sharks to set shape and size. For example, if you create 100 sharks, instead of setting the shape and size only once you are doing it 10,000 times (100 * 100).
So you need to put all those commands out of their respective create-<breed>'s command blocks; for example:
create-sharks N-sharks [
set color blue
setxy random-xcor random-ycor
]
ask sharks [
set size 2.5
]
ask sharks with [who >= (species * (1 / 2))] [
set shape "square"
set size 2
]
ask sharks with [who < (species * (1 / 6))] [
set shape "star"
set size 3
]
This is still improvable code, but it shows how to achieve exactly the same thing by doing it once and not doing it N-sharks ^ 2 times.
A better way to do it is to bring those commands back inside the create-<breed>'s command block, but letting each agent carry out the task for itself only. That is, without using ask sharks but using ifelse, so that each shark will check its own condition:
create-sharks N-sharks [
set color blue
setxy random-xcor random-ycor
(ifelse
who >= (species * (1 / 2)) ; the first condition
[set shape "square" set size 2]
who < (species * (1 / 6)) ; the second condition
[set shape "star" set size 3]
; else
[set size 2.5])
]
All of this applies to the other breed too.
It is generally said that using who is a sign that the code should be improved, but let's not focus on this now.
You will have noticed that I omitted the part where you set species N-sharks. This is because I think there is another misunderstanding here and it is not clear to me what you wanted to do: species (such as species-f for the other breed) is a global variable. You are basically asking each of the 100 sharks (again, 100 for example) to do the same thing: set the value of a global variable to equal the value of another global variable. In this case, you are asking each shark to set species 100. This seems very unnecessary, especially considering that N-sharks is a slider used for setup and thus probably won't be changed during the simulation (which means that there is probably no need to store the current value of N-sharks as a separate global variable).
Why are you basing the repartition of your sub-breeds on the value of species? What do you want species to represent? Is it correct for it to be a separate variable from N-sharks? If yes, then it is not clear what is its point; if no, then it can be eliminated.
You need to make sure that whatever you wanted to do with N-sharks & species, and with N-fishes and species-f, is better reflected in your code.
Also because I think this is the reason why your first fish sub-breed isn't showing. First of all, what is species-ratio? It is not present in your example, but it seems to be relevant for your question. In any case, if your first fish sub-breed isn't showing, it means that there is no fish who satisfies the condition who <= species-f.
This doesn't surprise me. who numbers are progressive for turtles: if you create 15 sharks and later you create 10 fish...
... the oldest shark will have who = 0
... the youngest shark will have who = 14
... the oldest fish will have who = 15
... the youngest fish will have who = 24
As you can see in this example, there is no fish for which who <= N-fishes (where N-fishes = 10). Let alone that in your case you set species-f (N-fishes * species-ratio) and, although you didn't tell what species-ratio is, I imagine it is a value between 0 and 1 - thus making the value of species-f even smaller.
The problem is that you are using who to determine your fishes. To quote the Netlogo programming guide: "Who numbers are assigned irrespective of breeds. If you already have a frog 0, then the first mouse will be mouse 1, not mouse 0, since the who number 0 is already taken."
As such, you need to take the number of sharks into account for determining the cutoff point for your fish species
set species-f (N-fishes * species-ratio) + N-sharks - 1
One other comment I have on your code is that you use the following structure:
create-sharks N-shark [
ask sharks [...]
]
Every shark executes the entire command block of create-sharks. That means that every shark asks every shark to do something. Thus follows that every shark sets their shape to default N-shark times.
It is much more efficient to use one of the following constructions
create-sharks N-shark [...]
ask sharks [...]
or
create-sharks N-shark [
if <condition> [<reshape-self>]
]
I'd need to pick an object in a bag containing 20 elements with attributes c (color) and s (size). Both color and size are numbers (e.g. c= {red = 256, black = 0, ... } = {256, 0, ...}).
As in Python I'd use random.choice in numpy library, I found on the web that the corresponding function in Netlogo is the extension rnd.
Struggling along a possible solution, I did
Edited:
breed[people person]
people-own
[
ball
size
color
bag
]
to setup
create-people 5
[ set color gray
setxy random-xcor random-ycor
]
ask people[
set bag [ ] ; 0 items
]
end
To create the balls:
to create-balls
set color random 300 ; color
set size random-float 5 ; size
let this-ball self
ask one-of people [ ; ask one of people to put the ball created into the bag
set bag fput this-ball bag ; add ball to the bag
]
end
The code below should include the part of drawing:
to draw
ask one-of people [
rnd:weighted-one-of bag [ ] ; I do not know what I'd write in the brackets
]
end
As you can easily see, I've many doubts about how to implement the code.
How can I select one item from the bag depending on its size (or color)?
Can you please help me out with it?
Here is a complete model that creates people and balls as turtle agents and has 30 of the balls get chosen weighted by their size. It then opens an inspect window for the person who has chosen the most balls.
extensions [rnd]
breed [people person]
people-own [ my-balls ]
breed [balls ball]
balls-own [ chosen? ]
to setup
clear-all
create-people 20
[ setxy random-xcor random-ycor
set my-balls (turtle-set nobody)
]
create-balls 50
[ hide-turtle
set size one-of [1 2 3 4 5]
set color one-of [red white blue yellow]
set chosen? false
]
repeat 30 [draw-ball]
inspect max-one-of people [count my-balls]
end
to draw-ball
ask one-of people
[ let bag-of-balls balls with [not chosen?]
let choice rnd:weighted-one-of bag-of-balls [size]
ask choice [set chosen? true]
set my-balls (turtle-set my-balls choice)
]
end
Some things to notice:
There are NO lists in this code. There are situations where you should use lists. Common uses include memory where the order is important (eg you only want to keep track of the last 5 other people seen) or where the same agent can appear multiple times. And the list commands are very powerful. However, unless you need a list then you should use agentsets.
Each person has their own bag called 'my-balls' that contains the balls they select. That is initialised as a turtle-list as part of the setup.
I used a variable called 'chosen?' that is owned by each ball to track whether it is still in the bag for the next person to choose. Then the bag-of-balls is created only as all the balls not yet chosen.
The code for weighted random choice (when choosing from agentsets) simply has the name of the variable holding the weight as the reporter, but you could use some function such as rnd:weighted-one-of bag-of-balls [size ^ 2] if you wanted a more complicated weighting scheme.
I'm trying to calculate and report the distance (link-length) between specific agentsets in NetLogo? Is there a way to calculate link length into a list?
The movement of the agents is based on whether the distance(connection) value is below/above a threshold. However, I'm having difficulty setting the values of the link length to variable connection. (preferably in a list). I'd appreciate any help.
globals[hourly-wage connection]
breed[offices office]
breed[employees employee]
offices-own [
pay-high ;; 7 offices pay well
pay-low ;; 3 offices dont pay well
]
to setup
clear-all
create-offices 10 [
set size 1.0
set color blue
set shape "house"
setxy random-xcor random-ycor
ask offices [create-link-with one-of other offices] ;; undirected links
ask links [set color red]
]
create-employees 2 [
set size 1
set color brown
set shape "person"
]
set hourly-wage 20
end
;;;;
to go
cal-dist
ask employees [
if connection > 15
move-to one-of high-pay office
if connection <= 15
move-to one-of low-pay office
]
end
to cal-dist
set connection [list print link-length] ;;
ask links [show link-length]
set salary (hourly-wage * connection) ;;; salary printed in a list
end
Not exactly sure what you're trying to do here with connection etc, but you can put any link variables into a list using of- for example:
to setup
ca
; First create the agents
crt 5 [
while [ any? other turtles in-radius 5 ] [
move-to one-of neighbors
]
set color blue
set shape "house"
]
; Once they're created, have them link with
; one of the other agents
ask turtles [
create-link-with one-of other turtles [
set color red
]
]
let link-lengths [ link-length ] of links
print link-lengths
reset-ticks
end
I don't know that this actually answers your question, so you may want to provide more detail as to what you're trying to accomplish with these links.
I have several turtles each with three variables opinion1, opinion2 and opinion3. I need them to:
identify which of these three variables has the highest value
find another turtle in their network with a value at least as high
as the one found in 1.
update its own value found in 1. with
respect to that of the turtle found in 2.
What I have done doesn't really work because it only updates looking at o1 without really having a look at which of the tree (opinion1, opinion2 or opinion3) is the highest and THEN looking for a neighbour.
to update-opinion
ask turtles [
let my-nearby-turtles nw:turtles-in-radius 1
let my-opinion1 opinion1
set neighbour one-of my-nearby-turtles with [ opinion1 > my-opinion1 ]
if neighbour != nobody [
let opinion_n [opinion1] of neighbour
set opinion1 ((opinion1 + opinion_n) / (2))
]
]
end
I don't know a simple way to do this with unique variables like opinion1 etc, but maybe having a list of opinions instead of individual variables for each opinion will work. For example, with this setup:
extensions [ nw ]
turtles-own [
opinions
]
to setup
ca
resize-world -5 5 -5 5
set-patch-size 30
crt 30 [
set shape "dot"
set opinions n-values 3 [ precision random-float 10 2]
set color scale-color blue sum opinions -5 35
while [ any? other turtles-here ] [
move-to one-of neighbors4
]
]
ask turtles [
create-links-with turtles-on neighbors4
]
reset-ticks
end
You get something like this:
Where each turtle has an opinions list variable that is three items long. Now, you can have each turtle determine its highest opinion value using max, get that maximum values index position in the list using position, and then query that turtle's neighbors to see if any of them have a higher value in the same index position. If they do, modify your asking turtles opinions list using replace-item to be the average of the two values:
to go
ask turtles [
; Get adjacent turtles
let my-nearby-turtles nw:turtles-in-radius 1
; Identify the highest highest value variable of
; the current turtle, and get its list position
let my-opinion max opinions
let my-op-ind position my-opinion opinions
; Pick one of the turtles whose value in the same indexed
; position is higher than my-opinion
let influence one-of my-nearby-turtles with [
item my-op-ind opinions > my-opinion
]
; If that turtle exists, update my own opinions list as appropriate
if influence != nobody [
let new-opinion precision (
( [ item my-op-ind opinions ] of influence + my-opinion ) / 2
) 2
set opinions replace-item my-op-ind opinions new-opinion
]
set color scale-color blue sum opinions -5 35
]
tick
end
Hopefully that is sort of on the right track, not sure if a list will work for what you need. If you must have the variables as standalone values at each tick, I suppose you could convert them to a list then follow the procedure above. If you only need them for output, you could just update your unique variables as needed based on the values in the list (as long as you are consistent with the order).
I have 200 turtles which represent producers. Each turtle, has 2 variables (sales of 2 prodcuts) and they are compared to let the prodcuer know which product was the most popular, so the turtle's color changes to the color representing that product.
I defined this loop :
while [counter < 201][
ask n-of 1 producers [
if (product1sales > product2sales)
[
set color green
]
if (product2sales > product1sales)
[
set color red
]
;
set counter counter + 1]
]
I assumed each time n-of is called, one turtle is chosen, but this specific turtle will not be chosen again. I also assumed that by running the code, all the turtles must be either green or red, but some are neither green nor red since n-of is not working as I assumed. one-of is not doing what I want either. Any ideas?
Thanks
If you just ask producers it will ask all of the producers in a random order, but without repeating- if you just want all of them to make a choice between the two choices you wouldn't even need the counter.
If either product1sales or product2salesis always higher, you could also trim a little by using ifelse. See if the example below would give you what you need:
breed [ producers producer ]
producers-own [ product1sales product2sales ]
to setup
ca
reset-ticks
create-producers 200 [
setxy random 30 - 15 random 30 - 15
set product1sales random-float 11
set product2sales random-float 11
set color white
]
end
to choose
ask producers [
ifelse product1sales > product2sales [
set color green
]
[
set color red
]
]
end