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I've made a calendar sheet and would like to fill it using an Arrayformula or some kind of Lookup.
The problem is, the code in each cell is different, do I need it all to be the same code or is it possible to do an Arrayformula that does a different formula for each line?
I spent ages getting the calendar code working but would now like to simplify the code and I'm not sure what my next step should be:
https://docs.google.com/spreadsheets/d/1u_J7bmOFyDlYXhcL5dW3CHFJ1esySAKK_yPc6nFTdLA/edit?usp=sharing
Any advice would be much appreciated.
I've added a new sheet in your file called 'Aresvik'.
The green cells have new formula.
Cell B3 can be =date(B1,1,1)
Then each successive month can be =eomonth(B3,0)+1, =eomonth(J3,0)+1 etc.
The date formula in cell B5 is:
=arrayformula(iferror(vlookup(sequence(7,7,1),{array_constrain(sequence(40,1),day(eomonth(B3,0))+weekday(B3,3),1),query({flatten(split(rept(",",day(eomonth(B3,0))-1),",",0,0));sequence(day(eomonth(B3,0)),1,1)},"offset "&day(eomonth(B3,0))-weekday(B3,3)&" ",0)},2,false),))
It can be copied to each other cell below Mo, so B5 will change to J5, R5, Z5 etc.
Notes
The concept revolves around using the SEQUENCE function to generate a grid of numbers, 6 rows, 7 columns:
sequence(6,7)
which looks like this:
1 2 3 4 5 6 7
8 9 10 11 12 13 14
15 16 17 18 19 20 21
22 23 24 25 26 27 28
29 30 31 32 33 34 35
36 37 38 39 40 41 42
Then using these numbers in a VLOOKUP to get a corresponding date for the calendar. If the first of the month falls on a Thursday (April 2021), the vlookup range needs 3 gaps at the top of the list of dates. player0 has a more elegant solution than my original query using offset, so I've incorporated it below. Cell Z3 is the date 1/4/2021:
=arrayformula(
iferror(
vlookup(sequence(6,7),
{sequence(day(eomonth(Z3,0))+weekday(Z3,2),1,0),
{iferror(sequence(weekday(Z3,2),1)/0,);sequence(day(eomonth(Z3,0)),1,Z3)}},
2,false)
,))
The first column in the vlookup range is:
sequence(day(eomonth(Z3,0))+weekday(Z3,2),1,0)
which is an array of numbers from 0, corresponding with the number of days in the month plus the number of gaps before the 1st day.
The second column in the vlookup range is:
{iferror(sequence(weekday(Z3,2),1)/0,);sequence(day(eomonth(Z3,0)),1,Z3)}},
It is an array of 2 columns in this format: {x;y}, where y sits below x because of the ;.
These are the gaps: iferror(sequence(weekday(Z3,2),1)/0,), followed by the date numbers: sequence(day(eomonth(Z3,0)),1,Z3)
(Example below is April 2021):
0
1
2
3
4
5
6 44317
7 44318
8 44319
9 44320
10 44321
11 44322
12 44323
13 44324
14 44325
15 44326
16 44327
17 44328
18 44329
19 44330
20 44331
21 44332
22 44333
23 44334
24 44335
25 44336
26 44337
27 44338
28 44339
29 44340
30 44341
31 44342
32 44343
33 44344
34 44345
35 44346
36 44347
The vlookup takes each number in the initial sequence (6x7 layout), and brings back the corresponding date from col2 in the range, based on a match in col1.
When the first day of the month is a Monday, iferror(sequence(weekday(BB1,2),1)/0,) generates a gap in col2 of the vlookup range. This is why col1 in the vlookup range has to start with 0.
I've updated the sheet at https://docs.google.com/spreadsheets/d/1u_J7bmOFyDlYXhcL5dW3CHFJ1esySAKK_yPc6nFTdLA/edit#gid=68642071
Values on the calendar are dates so the formatting has to be d.
If you want numbers, then use:
=arrayformula(
iferror(
vlookup(sequence(6,7),
{sequence(day(eomonth(Z3,0))+weekday(Z3,2),1,0),
{iferror(sequence(weekday(Z3,2),1)/0,);sequence(day(eomonth(Z3,0)),1)}},
2,false)
,))
shorter solution:
=INDEX(IFNA(VLOOKUP(SEQUENCE(6, 7), {SEQUENCE(DAY(EOMONTH(B3, ))+WEEKDAY(B3, 2), 1, ),
{IFERROR(ROW(INDIRECT("1:"&WEEKDAY(B3, 2)))/0); SEQUENCE(DAY(EOMONTH(B3, )), 1, B3)}}, 2, )))
Want to convert the alphabet to numerical values and transform it back to alphabets using some mathematical techniques like fast Fourier transform in MATLAB.
Example:
The following is the text saved in "text2figure.txt" file
Hi how r u am fine take care of your health
thank u very much
am 2.0
Reading it in MATLAB:
data=fopen('text2figure.txt','r')
d=fscanf(data,'%s')
temp = fileread( 'text2figure.txt' )
temp = regexprep( temp, ' {6}', ' NaN' )
c=cellstr(temp(:))'
Now I wish to convert cell array with spaces to numerical values/integers:
coding = 'abcdefghijklmnñopqrstuvwxyz .,;'
str = temp %// example text
[~, result] = ismember(str, coding)
y=result
result =
Columns 1 through 18
0 9 28 8 16 24 28 19 28 22 28 1 13 28 6 9 14 5
Columns 19 through 36
28 21 1 11 5 28 3 1 19 5 28 16 6 28 26 16 22 19
Columns 37 through 54
28 8 5 1 12 21 8 28 0 0 21 8 1 14 11 28 22 28
Columns 55 through 71
23 5 19 26 28 13 22 3 8 0 0 1 13 28 0 29 0
Now I wish to convert the numerical values back to alphabets:
Hi how r u am fine take care of your health
thank u very much
am 2.0
How to write a MATLAB code to return the numerical values in the variable result to alphabets?
Most of the code in the question doesn't have any useful effects. These three lines are the ones that lead to result:
str = fileread('test2figure.txt');
coding = 'abcdefghijklmnñopqrstuvwxyz .,;';
[~, result] = ismember(str, coding);
ismember returns, in the second output argument, the indices into coding for each element of str. Thus, result are indices that we can use to index into coding:
out = coding(result);
However, this does not work because some elements of str do not occur in coding, and for those elements ismember returns 0, which is not a valid index. We can replace the zeros with a new character:
coding = ['*',coding];
out = coding(result+1);
Basically, we're shifting each code by one, adding a new code for 1.
One of the characters we're missing here is the newline character. Thus the three lines have become one line. You can add a code for the newline character by adding it to the coding table:
str = fileread('test2figure.txt');
coding = ['abcdefghijklmnñopqrstuvwxyz .,;',char(10)]; % char(10) is the newline character
[~, result] = ismember(str, coding);
coding = ['*',coding];
out = coding(result+1);
All of this is easier to achieve just using the ASCII code table:
str = fileread('test2figure.txt');
result = double(str);
out = char(result);
Say I have the following data, S =
Year Week Postcode
2009 24 2035
2009 24 4114
2009 24 4127
2009 26 4114
2009 26 4556
2009 27 7054
2009 27 6061
2009 27 4114
2009 27 2092
2009 27 2315
2009 27 7054
2009 27 4217
2009 27 4551
2009 27 2035
2010 1 4132
2010 1 2155
2010 5 4114 ... (>60000 rows)
In Matlab, I would like to create a matrix with:
column 1: year (2006-2014)
column 2: week (1-52 for each year)
then the next n columns are unique postcodes where the data in each of these columns counts the occurrences from my data, S.
For example:
year week 2035 4114 4127 4556 7054
2009 24 1 1 1 0 0
2009 25 0 0 0 0 0
2009 26 0 1 0 1 0
2009 27 1 1 0 0 2
2009 28 0 0 0 0 0
Thanks if you can help!
Here is a working script which achieves this tabulation. The output is in the data table. You should:
Read the documentation on unique, tables, logical indexing, sortrows. As these are the key tools I used below.
Adapt the script to work with your data. This may involve changing matrices to cell arrays to deal with string inputs etc.
Possibly adapt this to be a function, for cleaner use if this is used regularly / on different data.
Code, fully commented for explanation:
% Use rng for repeatability in rand, n = num data entries
rng('default')
n = 100;
% Set up test data. You would use 3 equal length vectors of real data here
years = floor(rand(n,1)*9 + 2006); % random integer between 2006,2014
weeks = floor(rand(n,1)*52 + 1); % random integer between 1, 52
postcodes = floor(rand(n,1)*10)*7 + 4000; % arbitrary integers over 4000
% Create year/week values like 2017.13, get unique indices
[~, idx, ~] = unique(years + weeks/100);
% Set up table with year/week data
data = table();
data.Year = years(idx);
data.Week = weeks(idx);
% Get columns
uniquepostcodes = unique(postcodes);
% Cycle over unique columns, assign data
for ii = 1:numel(uniquepostcodes)
% Variable names cannot start with a numeric value, make start with 'p'
postcode = ['p', num2str(uniquepostcodes(ii))];
% Create data column variable for each unique postcode
data.(postcode) = zeros(size(data.Year,1),1);
% Count occurences of postcode in each date row
% This uses logical indexing of original data, looking for all rows
% which satisfy year and week of current row, and postcode of column.
for jj = 1:numel(data.Year)
data.(postcode)(jj) = sum(years == data.Year(jj) & ...
weeks == data.Week(jj) & ...
postcodes == uniquepostcodes(ii));
end
end
% Sort week/year data so all is chronological
data = sortrows(data, [1,2]);
% To check all original data was counted, you could run
% sum(sum(table2array(data(:,3:end))))
% ans = n, means that all data points were counted somewhere
On my PC, this takes less than 2.4 seconds for n = 60,000. There are almost definitely optimisations which can be made, but for something which may be used infrequently, this seems acceptable.
There is a linear increase in processing time, relative to the number of unique postcodes. This is because of the loop structure. So if you double the unique postcodes (20 rather than my example of 10) the time is nearer 4.8 seconds - twice as long.
If this solves your problem, consider accepting this as the answer.
I have a sparse matrix:
A=
(14,13) 0.5286
(15,14) 0.6781
(16,15) 0.5683
(17,16) 1.2773
(18,17) 1.0502
(19,18) 0.4966
(21,19) 0.9951
(21,20) 0.4522
(22,21) 0.8507
(23,22) 1.0727
(24,23) 0.8288
(25,24) 0.5811
(26,25) 0.8235
(28,26) 1.5128
(30,28) 0.7966
(30,29) 0.6363
(31,29) 0.8254
(32,31) 0.8573
(33,32) 1.0753
that is result of a minimum spanning tree. now I want to extract 13,14,15,...26,28,29,...33.
as seen 27 is not between numbers. so pred give: 13 14 15 16 17 18 19 21 22 23 24 25 26 28 29 30 31 32 that 20 and 33 is not.
how can I extract total of numbers that say in top?
[ii jj] = find(A);
answer = unique([ii(:); jj(:)]);
should do it.
Note that the find command with two outputs gives you the row and column index of all nonzero elements. Since you have a minimum spanning tree, each number you care about needs to occur at least once in the row or column (for example your matrix never has the number 29 in the first index, but it occurs in the second).
The unique function makes sure that each number that occurs is only represented once.
I have a large number of entries arranged in three columns. Sample of the data is:
A=[1 3 2 3 5 4 1 5 ;
22 25 27 20 22 21 23 27;
17 15 15 17 12 19 11 18]'
I want the first column (hours) to control the entire matrix to create new matrix as follows:
Anew=[1 2 3 4 5 ; 22.5 27 22.5 21 24.5; 14 15 16 19 15]'
Where the 2nd column of Anew is the average value of each corresponding hour for example:
from matrix A:
at hour 1, we have 2 values in 2nd column correspond to hour 1
which are 22 and 23 so the average is 22.5
Also the 3rd column: at hour 1 we have 17 and 11 and the
average is 14 and this continues to the hour 5 I am using Matlab
You can use ACCUMARRAY for this:
Anew = [unique(A(:,1)),...
cell2mat(accumarray(A(:,1),1:size(A,1),[],#(x){mean(A(x,2:3),2)}))]
This uses the first column A(:,1) as indices (x) to pick the values in columns 2 and 3 for averaging (mean(A(x,2:3),1)). The curly brackets and the call to cell2mat allow you to work on both columns at once. Otherwise, you could do each column individually, like this
Anew = [unique(A(:,1)), ...
accumarray(A(:,1),A(:,2),[],#mean), ...
accumarray(A(:,1),A(:,3),[],#mean)]
which may actually be a bit more readable.
EDIT
The above assumes that there's no missing entry for any of the hours. It will result in an error otherwise. Thus, a more robust way to calculate Anew is to allow for missing values. For easy identification of the missing values, we use the fillval input argument to accumarray and set it to NaN.
Anew = [(1:max(A(:,1)))', ...
accumarray(A(:,1),A(:,2),[],#mean,NaN), ...
accumarray(A(:,1),A(:,3),[],#mean,NaN)]
You can use consolidator to do the work for you.
[Afinal(:,1),Afinal(:,2:3)] = consolidator(A(:,1),A(:,2:3),#mean);
Afinal
Afinal =
1 22.5 14
2 27 15
3 22.5 16
4 21 19
5 24.5 15