play framework json lookup inside array - scala

Question

I have simple json:
{
"name": "John",
"placesVisited": [
{
"name": "Paris",
"data": {
"weather": "warm",
"date": "31/01/22"
}
},
{
"name": "New York",
"data": [
{
"weather": "warm",
"date": "31/01/21"
},
{
"weather": "cold",
"date": "28/01/21"
}
]
}
]
}
as you can see in this json there is placesVisited field, and if name is "New York" the "data" field is a List, and if the name is "Paris" its an object.
what I want to do is to pull the placesVisited object where "name": "New York" and then I will parse it to a case class I have, I can't use this case class for both objects in placesVisited cause they have diff types for the same name.
so what I thought is to do something like:
(myJson \ "placesVisited") and here I need to add something that will give me element where name is "New York", how can I do that?
my result should be this:
{
"name": "New York",
"data": [
{
"weather": "warm",
"date": "31/01/21"
},
{
"weather": "cold",
"date": "28/01/21"
}
]
}
something like this maybe can happen but its horrible haha:
(Json.parse(myjson) \ "placesVisited").as[List[JsObject]].find(item => {
item.value.get("name").toString.contains("New York")
}).getOrElse(throw Exception("could not find New York element")).as[NewYorkModel]

Answer 1

item.value.get("name").toString can slightly be simplified to (item \ "name").as[String] but otherwise there's not much to improve.
Another option is to use a case class Place(name: String, data: JsValue) and do it like this:
(Json.parse(myjson) \ "placesVisited")
.as[List[Place]]
.find(_.name == "New York")