displaying current logged user data - flutter

Question

i need assistance on how i could possibly query a current logged in / signed in users data so i can display their specific data using the snippet of code below -
class AddStore extends StatelessWidget {
AddStore({Key? key}) : super(key: key);
final CollectionReference _user =
FirebaseFirestore.instance.collection("users");
#override
Widget build(BuildContext context) {
return Scaffold(
body: StreamBuilder(
stream: _user.snapshots(),
builder: (context, AsyncSnapshot<QuerySnapshot> streamSnapshot) {
if (!streamSnapshot.hasData) {
return const SizedBox(
height: 250,
child: Center(
child: CircularProgressIndicator(),
),
);
} else {
return ListView.builder(
itemCount: streamSnapshot.data!.docs.length,
itemBuilder: ((context, index) {
final DocumentSnapshot documentSnapshot =
streamSnapshot.data!.docs[index];
return Column(
children: [
Text(documentSnapshot['fullName']),
],
);
}));
}
}));
}
}

Answer 1

You need to add the current user id i.e FirebaseAuth.instance.currentUser!.uid while querying the data from users collection. And this results in single document so you should avoid using ListView
Change the StreamBuilder to this
StreamBuilder<DocumentSnapshot<Map<String, dynamic>>>(
stream: FirebaseFirestore.instance
.collection('users')
.doc(FirebaseAuth.instance.currentUser!.uid).snapshots(),
builder:
(BuildContext context, AsyncSnapshot<DocumentSnapshot> snapshot) {
if (snapshot.hasError) {
return const Text('Something went wrong');
}
if (snapshot.connectionState == ConnectionState.waiting) {
return const Text("Loading");
}
Map<String, dynamic> data =
snapshot.data!.data()! as Map<String, dynamic>;
return Text(data['fullName']);
},
)