I have flutter app with firebase firestore in firestore I have on collection inside the collection there is few documents I want to get these documents IDs and put them in list<Strings> to use them in listview.seperated so I can click on one Item and move to another page where I can find the fields of specefic documents but I can't achieve that is there anyway to do that thanks
I try every thing to get the documents Id but nothing work with me I am new to flutter and firebase please help thanks
use doc.id to get ID of document:
List<String> iDs = [];
FirebaseFirestore.instance
.collection('buying2')
.get()
.then((QuerySnapshot querySnapshot) {
querySnapshot.docs.forEach((doc) {
print(doc.id); //this is document ID
iDs.add(doc.id);
});
});
Related
I want to delete document inside subcollection using where, how can I achieve this?
I can delete document inside subcollection using their document Id, but in some case if we don't know the id, we need to use where method.
This is direct method.
await FirebaseFirestore.instance
.collection('customerDB')
.doc(customerId)
.delete();
I have to achieve in this case:
await FirebaseFirestore.instance
.collection('merchantDB')
.doc(merchantId)
.collection('store')
.doc(storeId).collection('customers')
.where('customerId',isEqualTo:customerId).
Use get() to get snapshot from query, then you can delete the returned result.
// return a QuerySnapshot future, which contain list of matches documents
final snapshot = await FirebaseFirestore.instance
.collection('merchantDB')
.doc(merchantId)
.collection('store')
.doc(storeId).collection('customers')
.where('customerId',isEqualTo:customerId).get()
// delete all matches
for (var doc in snapshot.docs) {
doc.reference.delete();
}
On the explore page, I get() the entire users collection to create a user list and search results. Inside each of those user documents is a collection posts that I also need to get to create a GridView of each post. I want to reuse that users collection QuerySnapshot instead of fetching each posts collection again to save money. Is this possible?
Here is my current function:
void fetchUsers() async {
final userRef = FirebaseFirestore.instance.collection('users');
final QuerySnapshot result = await userRef.get();
final docs = result.docs.asMap();
docs.forEach((index, value) {
final profile =
ProfileObject.fromJson(value.data() as Map<String, dynamic>);
usersList.add(UserSearchResult(profile, value.id));
/// Below is the code for getting the posts, not working, need ideas
final QuerySnapshot postsResult = value.get('posts');
final posts = postsResult.docs.asMap();
posts.forEach((index, value) {
final post = Post.fromJson(value.data() as Map<String, dynamic>);
postsList.add(post);
});
});
print(usersList);
print(postsList);
}
Here is the structure of my Firestore:
users
uid (doc)
posts (collection)
info (fields)
uid (doc)
posts (collection)
info (fields)
It is not possible to call a collection to get all sub-collections. You should restructure your database to include sub-collection data in document itself. You can use a map or list for that. But remember, calling everything in one go may end up in slow performance and you might end up losing your customers. So the best way is to include the info in every posts' documents. That way, you won't loss your money and user won't feel lag in performance.
It is not possible. You fetch a document, then fetch the (sub)collection under it.
Subcollection data are not included in the initial document snapshots because Firestore queries are shallow. There shouldn't be any cost savings that you can do there?
See the similar Q&A:
Firestore: Get subcollection of document found with where
I want to order the documents in Firestore. The default Firestore documents list consist of alphabetic characters which get created automatically. But I don't want that. I just want to see my newly added document added at the top of my documents list. How do I do that in flutter? It would be very helpful if you provide me with a code for that. The code I use to create a collection is:
Future<void> userSetup() async {
String user = FirebaseAuth.instance.currentUser?.displayName as String;
CollectionReference users = FirebaseFirestore.instance.collection(user);
final hours = time?.hour.toString().padLeft(2, '0');
final minutes = time?.minute.toString().padLeft(2, '0');
users.add({
"customerId": FirebaseAuth.instance.currentUser?.uid.toString(),
"customerName": FirebaseAuth.instance.currentUser?.displayName,
"customerEmail": FirebaseAuth.instance.currentUser?.email,
"selectedTime": '${hours}:${minutes}',
"selectedDate": DateFormat('dd/MM/yyyy').format(date!),
});
return;
}
But I am unable to set my own document id. Please help me with the issue. Thanks in Advance
From the Flutterfire documentation, the set() method is the one you should be using to be able to specify your own document IDs instead of add(). Keep in mind that if the document ID you specify already exists in your database, the whole existing document will be replaced. This is a sample usage as found in the documentation:
CollectionReference users = FirebaseFirestore.instance.collection('users');
Future<void> addUser() {
return users
.doc('ABC123')
.set({
'full_name': "Mary Jane",
'age': 18
})
.then((value) => print("User Added"))
.catchError((error) => print("Failed to add user: $error"));
}
It seems that documents are ordered alphabetically in the Firestore console, so your custom document IDs should follow alphabetical order as you require. Not to be confused with retrieving documents from Firestore in a particular order, which is done with the orderBy() method.
I have Doctor collection when each doctor (represent by his email ) has a collection called patients_waiting.
Now, what I'm trying to do is delete one document from the paitents_waiting collection by field calls patients containing his email.
but I tried many solutions and none of them works for me now.
what I have tried to do :
Firestore.instance
.collection("Doctors")
.document(doctorEmail)
.collection("paitents_waiting")
.document(paitentEmail)
.delete();
now it's not good because the document is saved in uid and not by email but I tried to play with the where function but with no success.
how do I found this document by email and delete him?
I will mention that I'm doing it on flutter, but I think it doesn't matter.
as long as you have the patient's email address you can search with and delete it
Firestore.instance
.collection("Doctors")
. document(doctorEmail)
.collection("paitents_waiting")
.where('patient', isEqualTo:paitentEmail )
.get().then((value) => value.docs.single.reference.delete())
Nb: you are using an old version of firestore
Inside your paitents_waiting collection, the documents are NOT named according to patient email, they are randomly generated Firebase IDs. Take a closer look.
Firestore.instance
.collection("Doctors")
.document(doctorEmail)
.collection("paitents_waiting")
.document(paitentEmail) //this in your Firebase isn't an email, it's "xaErf43Asd..etc"
.delete();
If you want to follow this approach, which should be working otherwise, when you want to create a patient waiting document, use .set instead of .add, and set the document id to your pateint's email, like this:
Firestore.instance
.collection("Doctors")
.document(doctorEmail)
.collection("paitents_waiting")
.document(paitentEmail)
.set({your patient data here});
This should get things working for you.
To delete all patients for a doctor by the email you can use a combination of Firestore query and batch updates. The first one we need to get all patients with the same email and the other to delete them. A function for that would look like this:
Future<void> deletePatiensForDoctor(String docEmail, String patEmail) async {
WriteBatch batch = FirebaseFirestore.instance.batch();
QuerySnapshot querySnapshot = await Firestore.instance
.collection("Doctors")
.document(docEmail)
.collection("paitents_waiting")
.where('email', isEqualTo: patEmail)
.get();
querySnapshot.docs.forEach((doc) {
batch.delete(doc.reference);
});
return batch.commit();
}
I want to delete a document from a collection in Firebase Firestore. I wrote a method, but it's not working and does not delete anything. I need help, and this is my method:
final couponsReference = FirebaseFirestore.instance.collection("Coupons");
Future<void> Deletecoupon() async {
// displayToastMassage('try1', context);
String s=couponsReference.doc().id;
couponsReference.doc(s).delete().catchError((s){
print(s);
});
displayToastMassage('Coupn Code has been deleted sucsseflly', context);
To delete a document you need the documentId of that specific document. In your deletecoupon method you should pass in the documentId and could then use the await keyword to => await couponsReference.doc(documentId).delete();
To delete a particular document from a collection is very easy you just need one thing that documents documents I'd which you want to delete :
FirebaseFirestore.instance .collection("blogs").doc(widget.postid).delete();