Unable to calculate compound interest in PostgreSQL - postgresql

Question

I have a table table1 which contains the details of any depositor like
Depositor
Deposit_Amount
Deposit_Date
Maturity_Date
Tenure
Rate
A
25000
2021-08-10
2022-08-10
12
10%
I have another table table2 which contains the interest due date as:
Interest_Due_Date
2021-09-30
2021-12-31
2022-03-31
2022-06-30
2022-08-10
My Code is:
with recursive recur (n, start_bal, days,principle,interest, end_bal) as
(
select sno,deposit_amount,rate,days,deposit_amount * (((rate::decimal(18,2))/100)/365)*days as interest, deposit_amount+(deposit_amount * (((rate::decimal(18,2))/100)/365)*days) as end_bal from (
SELECT
sno, COALESCE(DATE_PART('day', deposit_date::TIMESTAMP - lag(deposit_date::TIMESTAMP) over
(ORDER BY sno ASC rows BETWEEN UNBOUNDED PRECEDING AND CURRENT row)),0) AS
days, deposit_date, deposit_amount, rate
FROM
( SELECT
ROW_NUMBER () OVER (ORDER BY deposit_date) AS sno,
deposit_date,
deposit_amount,
rate
FROM
( SELECT
t1.deposit_date, t1.deposit_amount, t1.rate from table1 t1
UNION ALL
SELECT
t2.Interest_Due_Date AS idate, 0 as depo_amount, 0 as rate
FROM
table2 t2
ORDER BY
deposit_date) dep) calc) b where sno = 1 union all select b.sno, b.end_bal,b.days,b.prin_bal,(coalesce(a.end_bal,0)) * (((b.rate)/100)/365)*b.days as interest_NEW,
coalesce(a.end_bal,0)+ ((a.end_bal) * (((calc.rate)/100)/365)*calc.days) as end_bal_NEW
from b, recur as a
where calc.sno = a.n+1 ) select * from recur
"Every time when i try to execute the query its showing an error 'relation 'b' does not exist"
...
The result table should be
Deposit Amount
Date
Days
Interest
Total Amount
25000
2021-08-10
0
0
25000
0
2021-09-30
51
349.32
25349.32
0
2021-12-31
92
638.94
25988.26
0
2022-03-31
90
640.81
26629.06
0
2022-06-30
91
663.90
27292.97
0
2022-08-10
41
306.58
27599.54