I want to filter records so that the assigned user can only see the records that are assigned to him from the popup list view.
The reason why I'm not doing this in the roles management is because if I assigned a user to a client record then other users that have the same role wouldn't able to see it so I've set the role->list tab to "all" and added custom code in list view that only the login user can see their own records.
Here's what I've done.
<?php
require_once('include/MVC/View/views/view.popup.php');
class AccountsViewPopup extends ViewPopup
{
public function display()
{
parent::display(); // TODO: Change the autogenerated stub
require_once 'modules/ACLRoles/ACLRole.php';
$ACLRole = new ACLRole();
$roles = $ACLRole->getUserRoles($GLOBALS['current_user']->id);
if (in_array('User1', $roles)) {
global $db, $current_user;
$this->where .= " AND accounts.assigned_user_id = '$current_user->id' AND deleted=0 ";
}
}
}
But i get this error:
Undefined property: AccountsViewPopup::$where
For list view only: custom/modules/MODULE_NAME/views/view.list.php
and following is the helping code:
require_once('include/MVC/View/views/view.list.php');
class MODULE_NAMEViewList extends ViewList {
function listViewProcess() {
global $current_user;
$this->params['custom_where'] = ' AND module_name.name = "test" ';
parent::listViewProcess();
}
}
For list and popup view(both):
You need to change the logic inside create_new_list_query function which actually prepares a query. Some modules have override it a bean level(e.g. see modules/Leads/Lead.php).
If you want to override it in upgrade safe manner then create a file in custom directory e.g: custom/modules/Leads/Lead.php, then extend it from the core bean class like following:
<?php
if(!defined('sugarEntry') || !sugarEntry) die('Not A Valid Entry Point');
require_once('modules/Leads/Lead.php');
class CustomLead extends Lead {
function create_new_list_query($order_by, $where,$filter=array(),$params=array(), $show_deleted = 0,$join_type='', $return_array = false,$parentbean=null, $singleSelect = false, $ifListForExport = false)
{
// Code from create_new_list_query in and then modify it accordingly.
}
}
Register new bean class in this location: custom/Extension/application/Ext/Include/custom_leads_class.php and registration code will look like following:
<?php
$objectList['Leads'] = 'Lead';
$beanList['Leads'] = 'CustomLead';
$beanFiles['CustomLead'] = 'custom/modules/Leads/Lead.php';
?>
I know this has been answered, but decided to post my solution anyway. I had almost the same problem some time ago (7.10.7).
PopupView has method getCustomWhereClause() which you can implement in your custom view.
It has to return containing string with the conditions.
Example:
custom/modules/Meetings/views/view.popup.php
/*class declaration and other stuff*/
protected function getCustomWhereClause()
{
global $current_user;
return " ( {$this->bean->table_name}.assigned_user_id='{$current_user->id}') ";
}
Remember to leave at least one space at the start and the end because SuiteCRM actually forgets to add it and it may result in broken query (but it's fairly easy to find in logs).
What is the most straightforward way to get the current category in the view? I notice that there is a getTerm method in the Term class:
public function getEntity()
{
return $this->getTerm();
}
/**
* Returns the current Wordpress category
* This is just a wrapper for getCurrentCategory()
*
* #return \FishPig\WordPress\Model\Term
*/
public function getTerm()
{
if (!$this->hasTerm()) {
$this->setTerm($this->_registry->registry(Term::ENTITY));
}
return $this->_getData('term');
}
However if I try to utilize the method within a template (for example, the default post list wrapper.phtml template which utilizes the Term block in the layout) it throws an error:
<?php echo $this->getTerm() ?>
Recoverable Error: Object of class FishPig\WordPress\Model\Term could
not be converted to string in
I'm probably just missing something simple, any help would be greatly appreciated. Thanks!
$term = \Magento\Framework\App\ObjectManager::getInstance()
->get('Magento\Framework\Registry')
->registry('wordpress_term');
In my form's model, I have a custom validation function for a field defined in this way
class SignupForm extends Model
{
public function rules()
{
return [
['birth_date', 'checkDateFormat'],
// other rules
];
}
public function checkDateFormat($attribute, $params)
{
// no real check at the moment to be sure that the error is triggered
$this->addError($attribute, Yii::t('user', 'You entered an invalid date format.'));
}
}
The error message doesn't appear under the field in the form view when I push the submit button, while other rules like the required email and password appear.
I'm working on the Signup native form, so to be sure that it is not a filed problem, I've set the rule
['username', 'checkDateFormat']
and removed all the other rules related to the username field, but the message doesn't appear either for it.
I've tried passing nothing as parameters to checkDateFormat, I've tried to explicitly pass the field's name to addError()
$this->addError('username', '....');
but nothing appears.
Which is the correct way to set a custom validation function?
Did you read documentation?
According to the above validation steps, an attribute will be
validated if and only if it is an active attribute declared in
scenarios() and is associated with one or multiple active rules
declared in rules().
So your code should looks like:
class SignupForm extends Model
{
public function rules()
{
return [
['birth_date', 'checkDateFormat'],
// other rules
];
}
public function scenarios()
{
$scenarios = [
'some_scenario' => ['birth_date'],
];
return array_merge(parent::scenarios(), $scenarios);
}
public function checkDateFormat($attribute, $params)
{
// no real check at the moment to be sure that the error is triggered
$this->addError($attribute, Yii::t('user', 'You entered an invalid date format.'));
}
}
And in controller set scenario, example:
$signupForm = new SignupForm(['scenario' => 'some_scenario']);
Try forcing the validation on empty field
['birth_date', 'checkDateFormat', 'skipOnEmpty' => false, 'skipOnError' => false],
Also, make sure you don't assign id to your birth_date field in your view.
If you do have id for your birth_date, you need to specify the selectors
<?= $form->field($model, 'birth_date', ['selectors' => ['input' => '#myBirthDate']])->textInput(['id' => 'myBirthDate']) ?>
To make custom validations in yii 2 , you can write custom function in model and assign that function in rule.
for eg. I have to apply password criteria in password field then I will write like this in model.
public function rules()
{
return [
['new_password','passwordCriteria'],
];
}
public function passwordCriteria()
{
if(!empty($this->new_password)){
if(strlen($this->new_password)<8){
$this->addError('new_password','Password must contains eight letters one digit and one character.');
}
else{
if(!preg_match('/[0-9]/',$this->new_password)){
$this->addError('new_password','Password must contain one digit.');
}
if(!preg_match('/[a-zA-Z]/', $this->new_password)){
$this->addError('new_password','Password must contain one character.');
}
}
}
}
You need to trigger $model->validate() somewhere if you are extending from class Model.
I stumbled on this when using the CRUD generator. The generated actionCreate() function doesn't include a model validation call so custom validators never get called. Also, the _form doesn't include and error summary.
So add the error summary to the _form.
<?= $form->errorSummary($model); ?>
...and add the validation call - $model->validate() - to the controller action
public function actionCreate()
{
$model = new YourModel();
if ($model->load(Yii::$app->request->post()) && $model->validate()) {...
Although it's an old post i thought I should answer.
You should create a Custom Validator Class and to create a validator that supports client-side validation, you should implement the yii\validators\Validator::clientValidateAttribute() method which returns a piece of JavaScript code that performs the validation on the client-side. Within the JavaScript code.
You may use the following predefined variables:
attribute: the name of the attribute being validated.
value: the value being validated.
messages: an array used to hold the validation error messages for
the attribute.
deferred: an array which deferred objects can be pushed into
(explained in the next subsection).
SO that means you can use messages array to push your messages to the client end on runtime within the javascript code block in this method.
I will create a class that includes dummy checks that could be replaced the way you want them to. and change the namespace according to your yii2 advanced or basic.
Custom Client-side Validator
namespace common\components;
use yii\validators\Validator;
class DateFormatValidator extends Validator{
public function init() {
parent::init ();
$this->message = 'You entered an invalid date format.';
}
public function validateAttribute( $model , $attribute ) {
if ( /*SOME CONDITION TO CHECK*/) {
$model->addError ( $attribute , $this->message );
}
}
public function clientValidateAttribute( $model , $attribute , $view ) {
$message = json_encode ( $this->message , JSON_UNESCAPED_SLASHES | JSON_UNESCAPED_UNICODE );
return <<<JS
if ($("#DATE-1").val()=="" || $("#DATE-2").val() =="") {
messages.push($message);
}
JS;
}
}
and then inside your model SigupForm add the rule
['birth_date', 'common\components\DateFormatValidator'],
Deferred Validation
You can even add ajax calls inside the clientValidateAttribute function and on the base of the result of that ajax call you can push message to the client end but you can use the deferred object provided by yii that is an array of Deferred objects and you push your calls inside that array or explicitly create the Deferred Object and call its resolve() method.
Default Yii's deferred Object
public function clientValidateAttribute($model, $attribute, $view)
{
return <<<JS
deferred.push($.get("/check", {value: value}).done(function(data) {
if ('' !== data) {
messages.push(data);
}
}));
JS;
}
More about Deferred Validation
You need to render the model from controller. Without initializing the model in view. And in the controller you need to call the validate function
Are you sure the first parameter of addError shouldn't be like this
$this->addError(**'attribute'**, Yii::t('user', 'You entered an invalid date format.'));
I had common problem.
In your validation function:
public function checkDateFormat($attribute, $params)
{
// no real check at the moment to be sure that the error is triggered
$this->addError($attribute, Yii::t('user', 'You entered an invalid date format.'));
}
$params doesn`t get any value at all. It actually always equals to Null. You have to check for your attribute value in function:
public function checkDateFormat($attribute, $params)
{
if($this->birth_date == False)
{
$this->addError($attribute, Yii::t('user', 'You entered an invalid date format.'));
}
}
that`s how it worked for me.
If you don't use scenarios for your model, you must mark your atribute as 'safe':
['birth_date','safe'],
['birth_date', 'checkDateFormat'],
And, on the other hand, you can use this for date validation:
['birth_date','safe'],
[['birth_date'],'date', 'format'=>'php:Y-m-d'],
You can change format as you want.
**We should set attributes to the function to work with input value **
public function rules()
{
return [
['social_id','passwordCriteria'],
];
}
public function passwordCriteria($attribute, $params)
{
if(!empty($this->$attribute)){
$input_value = $this->$attribute;
//all good
}else{
//Error empty value
$this->addError('social_id','Error - value is empty');
}
}
Are you by any chance using client side validation? If you do then you have to write a javascript function that would validate the input. You can see how they do it here:
http://www.yiiframework.com/doc-2.0/guide-input-validation.html#conditional-validation
Another solution would be to disable client validation, use ajax validation, that should bring back the error too.
Also make sure that you have not overwritten the template of the input, meaning make sure you still have the {error} in there if you did overwrite it.
Your syntax on rules should be something like this man,
[['birth_date'], 'checkDateFormat']
not this
['birth_date', 'checkDateFormat']
So in your case, it should look like below
...
class SignupForm extends Model
{
public function rules()
{
// Notice the different with your previous code here
return [
[['birth_date'], 'checkDateFormat'],
// other rules
];
}
public function checkDateFormat($attribute, $params)
{
// no real check at the moment to be sure that the error is triggered
$this->addError($attribute, Yii::t('user', 'You entered an invalid date format.'));
}
}
I'm trying to set up an authentication system with Laravel 4 with a Facebook login. I am using the madewithlove/laravel-oauth2 package for Laravel 4.
Of course, there is no password to add to my database upon a user loggin in with Facebook. I am, however, trying to check to see if a user id is in the database already to determine if I should create a new entity, or just log in the current one. I would like to use the Auth commands to do this. I have a table called "fans".
This is what I'm working with:
$fan = Fan::where('fbid', '=', $user['uid']);
if(is_null($fan)) {
$fan = new Fan;
$fan->fbid = $user['uid'];
$fan->email = $user['email'];
$fan->first_name = $user['first_name'];
$fan->last_name = $user['last_name'];
$fan->gender = $user['gender'];
$fan->birthday = $user['birthday'];
$fan->age = $age;
$fan->city = $city;
$fan->state = $state;
$fan->image = $user['image'];
$fan->save();
return Redirect::to('fans/home');
}
else {
Auth::login($fan);
return Redirect::to('fans/home');
}
Fan Model:
<?php
class Fan extends Eloquent {
protected $guarded = array();
public static $rules = array();
}
When I run this, I get the error:
Argument 1 passed to Illuminate\Auth\Guard::login() must be an instance of Illuminate\Auth\UserInterface, instance of Illuminate\Database\Eloquent\Builder given
EDIT: When I use: $fan = Fan::where('fbid', '=', $user['uid'])->first();
I get the error:
Argument 1 passed to Illuminate\Auth\Guard::login() must be an instance of Illuminate\Auth\UserInterface, null given, called in /Applications/MAMP/htdocs/crowdsets/laravel-master/vendor/laravel/framework/src/Illuminate/Auth/Guard.php on line 368 and defined
I do not know why it is giving me this error. Do you have suggestions on how I can make this work? Thank you for your help.
You have to implement UserInterface to your model for Auth to work properly
use Illuminate\Auth\UserInterface;
class Fan extends Eloquent implements UserInterface{
...
public function getAuthIdentifier()
{
return $this->getKey();
}
/**
* Get the password for the user.
*
* #return string
*/
public function getAuthPassword()
{
return $this->password;
}
}
getAuthIdentifier and getAuthPassword are abstract method and must be implemented in you class implementing UserInterface
To login any user into the system, you need to use the User model, and I bet inherited classes will do the trick as well but I'm not sure.
Anyway, your Fan model does not associate with the User model/table in any way and that's a problem. If your model had a belong_to or has_one relationship and a user_id field then you could replace Auth::login($user) with Auth::loginUsingId(<some id>).
Original answer:
You are missing an extra method call: ->get() or ->first() to actually retrieve the results:
$fan = Fan::where('fbid', '=', $user['uid'])->first();
Alternatively, you can throw an exception to see what's going on:
$fan = Fan::where('fbid', '=', $user['uid'])->firstOrFail();
If you see different errors, update your question with those errors.
How can I implement mysqli in an extended class?
I am uploading an image and storing it in a MySQL database, but I get this error:
Notice: Undefined variable: mysqli in ...ecc/ecc/ on line 33
Fatal error: Call to a member function query() on a non-object in ...ecc/ecc/ on line 33
Here is my test code:
<?php
interface ICheckImage {
public function checkImage();
public function sendImage();
}
abstract class ACheckImage implements ICheckImage {
public $image;
private $mysqli;
public function _construct(){
$this->image = $_POST['image'];
$this->mysqli = new mysqli('localhost','test','test','test');
}
}
class Check extends ACheckImage {
public function checkImage() {
if($this->image > 102400) {
echo "File troppo grande";
}
}
public function sendImage() {
//This is the line 33 give me the error
if ($mysqli->query("INSERT INTO images (image) VALUES ('$this->image')")) {
echo "Upload avvenuto  ";
} else {
echo "Errore  " . $mysqli->error;
}
}
}
$form = new Check();
$form->checkImage();
$form->sendImage();
?>
There are some errors in your code.
The $mysqli member is private inside the abstract class. It will not be inherited by the Check class, so it does not exist there. Make it protected.
Access to the members of a class always needs $this-> in front, specifically $this->mysqli in this instance.
The constructor function must be named __construct with two underscores in front.
The image check looks wrong. $_POST['image'] does contain something that you expect to store in the database, but you also compare it with an integer value and seem to echo an error message if it is bigger. While the data handling will work, e.g. you can compare a string from POST data with an integer, it looks like you want something else.