Why does Groovy execute() hang? - scala

Question

I have the following Groovy script:
#!/opt/groovy-1.8.6/bin/groovy
final env = null // []
final command = ["./setter-for-catan.scala"]
final process = command.execute(env, null)
println (['echo', '********************** 0'].execute(env, null).text)
final stdout = process.inputStream
BufferedReader reader = new BufferedReader(new InputStreamReader(stdout))
while ((line = reader.readLine()) != null) {
System.out.println ("Stdout: " + line);
}
and the following Scala script:
#!/bin/bash
export SCALA_HOME=/opt/scala-2.10.1
echo '********************* 1' "$0" "$#"
${SCALA_HOME}/bin/scala -version 2>&1
exec ${SCALA_HOME}/bin/scala "$0" "$#" 2>&1
!#
println("******************* 2")
Calling the Groovy script outputs:
********************** 0
Stdout: ********************* 1 ./setter-for-catan.scala
Stdout: Scala code runner version 2.10.1 -- Copyright 2002-2013, LAMP/EPFL
Stdout: ******************* 2
If env is defined as [], the Groovy script hangs with the following output:
********************** 0
Stdout: ********************* 1 ./setter-for-catan.scala
Stdout: Scala code runner version 2.10.1 -- Copyright 2002-2013, LAMP/EPFL
What's going on and what needs to be done so that execute() doesn't hang when env is an Array?

Answer 1

JAVA_HOME isn't being inherited by the Scala script so it needs to be defined.
One way to do it would be in the Scala script:
#!/bin/bash
export JAVA_HOME=/Library/Java/Home
export SCALA_HOME=/opt/scala-2.10.1
echo '********************* 1' "$0" "$#"
${SCALA_HOME}/bin/scala -version 2>&1
exec ${SCALA_HOME}/bin/scala "$0" "$#" 2>&1
!#
Another way would be to do it in the Groovy script:
final env = ['JAVA_HOME=/Library/Java/Home']