I am trying to emulate a typewriter in Processing, similar to this one.
Since I write mostly in Portuguese, I need the diacritics, which in typewriters is implemented as a non-advancing key (it prints the accent, and then the next key is printed under it, for example "pé pão pátria".
When I simply use the following line to print key values and codes, when I type ~, even repeatedly, I get nothing, and when I type ~ + a I get only the a:
void keyPressed()
println("key: " + String.valueOf(key) + " value: " + int(key) + " code: " + keyCode);
}
So the question is:
How to capture diacritic accent keystrokes in a latin layout keyboard (french, spanish, portuguese), and how to compose unicode accented characters with from them?
If the keyboard is set to the correct language and the font support the characters, it should be possible to use those characters.
Here's an example based on the link you provided:
String text1 = " ";
PFont font;
int bfill = 150;
boolean randomizer = false;
void setup() {
size(400, 400);
smooth();
font = createFont("Arial",48);//loadFont("Arial-Black-48.vlw");
textFont(font, 20);
}
void draw() {
background(bfill);
fill(255);
text(text1, 0, 40, width, height);
if(randomizer) {
for(int j = 0; j < 400; j++) {
text1 += char(int(random(18, 126)));
}
text(text1, 0, 40, width, height);
text1 = " ";
}
}
void keyPressed() {
if (key == BACKSPACE) {
if(text1.length() > 0) {
text1 = text1.substring(0, text1.length() - 1);
}
}
else if (key == '1') {
randomizer = true;
}
else {
text1 += key;
if(key == 'ă') println("got ă");
}
}
I simply changed the keyboard input to Romanian (which also has diacritics, such as ăâîșț).
I also see the message printed to the console as expected on the ă character:
got ă
Related
I'm making a game, but I can't change the letter that matches more than once.
I don't know what I'm doing wrong, I hope someone can help me, thanks.
I leave a demonstration video, the result of the word is DOMINGO
The problem I perceive is that when I press the key or it is assigned only at the beginning.
When it must be completed with all possible matches.
YouTube Video Here
This is my dart function.
String word = 'domingo';
String key = 'o'; // OnTap button "O"
List<Word> positionsFound = List<Word>();
_word(){
String wordEmpty = '';
for(int i=0; i<word.length; i++){
if(key.isEmpty){
wordEmpty = wordEmpty+'_';
} else {
wordEmpty = wordEmpty+'_';
int position = word.toLowerCase().indexOf(key.toLowerCase());
if(position == i){
positionsFound.add(Word(key, position));
print(position); // The position must be 1 and 6, it only gives me 1.
}
}
}
for(int i=0; i<positionsFound.length; i++){
wordEmpty = wordEmpty.replaceFirst('_', positionsFound[i].key, positionsFound[i].position);
}
return wordEmpty;
}
class Word {
String key;
int position;
Word(this.key, this.position);
}
After a while, I realized that indexof allows you to start from the last search you performed.
if(key.isNotEmpty){
int position = word.toLowerCase().indexOf(key.toLowerCase());
while(position != -1){
if(position != -1){
positionsFound.add(Word(key, position));
}
position = word.toLowerCase().indexOf(key.toLowerCase(), position+1);
}
}
Is there any way that I can detect color pages in a PDF file?
For example I have a PDF file with 5 pages, and the first and last page are in color. How can I detect the color pages? Can iText do it?
Now my solution is to convert PDF to images and then detect images color or black&white, but it takes too long time to do it, I need a fast way.
Convert pdf to image by Adobe Acrobat Code as fellows
public static void ConvertPDF2Image(string pdfInputPath, string imageOutputPath,
string imageName, int startPageNum, int endPageNum, ImageFormat imageFormat, double resolution)
{
Acrobat.CAcroPDDoc pdfDoc = null;
Acrobat.CAcroPDPage pdfPage = null;
Acrobat.CAcroRect pdfRect = null;
Acrobat.CAcroPoint pdfPoint = null;
// Create the document (Can only create the AcroExch.PDDoc object using late-binding)
// Note using VisualBasic helper functions, have to add reference to DLL
pdfDoc = (Acrobat.CAcroPDDoc)Microsoft.VisualBasic.Interaction.CreateObject("AcroExch.PDDoc", "");
// validate parameter
if (!pdfDoc.Open(pdfInputPath)) { throw new FileNotFoundException(); }
if (!Directory.Exists(imageOutputPath)) { Directory.CreateDirectory(imageOutputPath); }
if (startPageNum <= 0) { startPageNum = 1; }
if (endPageNum > pdfDoc.GetNumPages() || endPageNum <= 0) { endPageNum = pdfDoc.GetNumPages(); }
if (startPageNum > endPageNum) { int tempPageNum = startPageNum; startPageNum = endPageNum; endPageNum = startPageNum; }
if (imageFormat == null) { imageFormat = ImageFormat.Jpeg; }
if (resolution <= 0) { resolution = 1; }
// start to convert each page
for (int i = startPageNum; i <= endPageNum; i++)
{
pdfPage = (Acrobat.CAcroPDPage)pdfDoc.AcquirePage(i - 1);
pdfPoint = (Acrobat.CAcroPoint)pdfPage.GetSize();
pdfRect = (Acrobat.CAcroRect)Microsoft.VisualBasic.Interaction.CreateObject("AcroExch.Rect", "");
int imgWidth = (int)((double)pdfPoint.x * resolution);
int imgHeight = (int)((double)pdfPoint.y * resolution);
pdfRect.Left = 0;
pdfRect.right = (short)imgWidth;
pdfRect.Top = 0;
pdfRect.bottom = (short)imgHeight;
// Render to clipboard, scaled by 100 percent (ie. original size)
// Even though we want a smaller image, better for us to scale in .NET
// than Acrobat as it would greek out small text
pdfPage.CopyToClipboard(pdfRect, 0, 0, (short)(100 * resolution));
IDataObject clipboardData = Clipboard.GetDataObject();
if (clipboardData.GetDataPresent(DataFormats.Bitmap))
{
Bitmap pdfBitmap = (Bitmap)clipboardData.GetData(DataFormats.Bitmap);
pdfBitmap.Save(Path.Combine(imageOutputPath, imageName) + i.ToString() + "." + imageFormat.ToString(), imageFormat);
pdfBitmap.Dispose();
}
}
pdfDoc.Close();
Marshal.ReleaseComObject(pdfPage);
Marshal.ReleaseComObject(pdfRect);
Marshal.ReleaseComObject(pdfDoc);
Marshal.ReleaseComObject(pdfPoint);
}
////detect image Color or black and white as fellows
Bitmap box1 = new Bitmap(PictureBox1.Image);
Color c = new Color()
int rr, gg, bb;
for(int i=0;i<PictureBox1.Width;i++){
for(int j=0;j<PictureBox1.Height;j++){
c= box1.GetPixel(i,j);
rr= c.R; gg=c.g;bb=c.B;
if（c ==Color.Black||c= Color.White）{
MessageBox.Show("black and white dot")
}
else {
if(rr==gg==bb){
MessageBox.Show("Gray dot");
}
else {
MessageBOx.Show("Color dot")；
}
}
}
}
I'm implementing the show Deal Or No Deal, there's a class 'box' which in the main file i used to store the random values of the boxes and than, i saved each box in the vector. im trying now to print in the screen the boxes saved in the vector whit the iterator,without succeeding, any help???
//random assignation of pound value to the 22 boxes
for (int e = 1; e < 23; e++)
{
int pos;
bool op = true;
while (op)
{
pos = rand();
if (pos > 0 && pos < 23)
{
if (myArray[pos][1] == 0)
{
myArray[pos][1] = 1;
op = false;
}
}
}
box b(e, myArray[pos][0]); //creating the class box
game_box.push_back(b); //function of the vector to insert a data in it
}
//show boxes
for (auto a = game_box.begin(); a!= game_box.end(); a++)
{
cout << *a << endl;
}
You first need to remove the dereference operator (*) from the a.
Next you need to add an output operator for box. Assuming that box is a class with member data member1 and member2 this would look something like:
friend std::ostream& operator<< (std::ostream &out, const box& b)
{
out << box.memeber1 << " " << box.member2;
}
The key point is that you need to define this operator for every class.
Once you've done that and got it working you might also like to look at this library which defines << operators for all stl containers. This lets you replace
for (auto a = game_box.begin(); a!= game_box.end(); a++)
{
cout << *a << endl;
}
by simply
cout << game_box << endl;
this works..
class Box
{
float pound_contained;
int box_number;
public:
Box(int box_number, float pound_contained);
int getbox_number();
float getpound_contained();
};
int Box::getbox_number()
{
return this->box_number;
}
float Box::getpound_contained()
{
return this->pound_contained;
}
main()
{
vector<Box> game_box;
Box* boxes = &game_box[i];
cout <<boxes->getbox_number()<<endl;
}
I'm trying to write a program that asks the user to input the size of the array the user wants to create, and then asks the user to fill the array with elements, and then it should display the array with its elements and, ask the user to conduct a search for an integer. It should conduct a linear and binary search, while displaying how many probes it took to determine is the element is in the array. So far the only output i have gotten is that the element has not been found. If you could look at my code and see what the problem is, because i have tried for hours and i have changed everything i can think of. Any help would be greatly appreciated.
import java.util.Scanner;
public class Searching
{
public static int[] anArray = new int[100];
private int numberOfElements;
public int arraySize = numberOfElements;
public String linearSearch(int value)
{
int count = 0;
boolean valueInArray = false;
String indexOfValue = "";
System.out.print("The Value was Found in: ");
for(int i = 0; i < arraySize; i++)
{
if(anArray[i] == value)
{
valueInArray = true;
System.out.print(i + " ");
indexOfValue += i + " ";
}
count ++;
}
if(!valueInArray)
{
indexOfValue = " None found";
System.out.print(indexOfValue);
}
System.out.println("\nIt took " + count + " probes with a linear search to find");
return indexOfValue;
}
public void binarySearch(int value)
{
int min = 0;
int max = arraySize - 1;
int count = 0;
while(min <= max)
{
int mid = (max + min) / 2;
if(anArray[mid] < value) min = mid + 1;
else if(anArray[mid] > value) max = mid - 1;
else
{
System.out.println("\nFound a Match for " + value + " at Index " + mid);
min = max + 1;
}
count ++;
}
System.out.println("It took " + count + " probes with a binary search to find");
}
public static void main(String[] args)
{
#SuppressWarnings("resource")
Scanner scan = new Scanner(System.in);
System.out.println("Input the number of elements in your Array");
int numberOfElements = scan.nextInt();
if(numberOfElements <= 0)
{
System.exit(0);
}
int[] anArray = new int[numberOfElements];
System.out.println("\nEnter " + numberOfElements + " Integers");
for(int i = 0; i < anArray.length; i ++)
{
System.out.println("Int # " + (i + 1) + ": ");
anArray[i] = scan.nextInt();
}
System.out.println("\nThe integers you entered are: ");
for(int i = 0; i < anArray.length; i ++) // for loop used to print out each element on a different line
{
System.out.println(anArray[i]);
}
System.out.println("Which element would you like to find?");
int value = scan.nextInt();
Wee3Q2JOSHBALBOA newArray = new Wee3Q2JOSHBALBOA();
newArray.linearSearch(3);
newArray.binarySearch(value);
}
}
hmm I am not sure you are using an array the correct way, you see an Array is a set size and I dont think you can expand like they way you are doing...
Instead try setting the size of the array to certain length.
Or use vectors
I'm currently working on a string tokenizer in C++ and am getting a strange result.
char *mystrtok(char *str, const char *delim)
{
char * LeftOver;
bool lastToken;
int i=0;
if(str != NULL)
{
LeftOver = str;
lastToken = false;
}else
{
str = LeftOver;
}
for(i = 0; str[i] != '\0'; i++)
{
for(int j=0; delim[j] != '\0'; j++)
{
//If I take out this line then it returns weird characters
cout << "\tstr[" << i <<" ]" << "=" << str[i] << endl;
if(LeftOver[i] == delim[j])
{
str[i] = '\0';
LeftOver = str + i+1;
return str;
}
}
}
if(LeftOver[i] == '\0' && !lastToken)
{
lastToken = true;
return str;
}
return NULL;
}
What's really weird is that if I take out the cout then it returns weird characters
Any idea what could be causing this?
Here's a sample output
//passed
"ls -l -a | wc -c >> myfile"
returned: ls
▒M.▒
I saw several problems with this code, first
str = LeftOver;
At this line, LeftOver has not been initialized at all. But you use it to initialize str. You want to make LeftOver static?
Second, your test for LastToken,
if(LeftOver[i] == '\0' && !lastToken)
It will aways true for !lastToken since before this line it is always false, you want to make it static too?