Documentation on Swift provides the following code for spacing Examples in Markup:
/*:
- example: *A simple `for` loop.*\
This example shows a `for` loop that prints the numbers 1 to 5.\
\
`for index in 1...5 {`\
` print("index = \(index)")`\
`}`}
*/
In rendered Markup no spaces appear:
How do you put spaces in code snippets, especially examples with custom callouts(), in Markup?
So to show the spaces in your code example try to do it like that regarding to your example:
/*:
A simple for loop.\
This example shows a for loop that prints the numbers 1 to 5.
for index in 1...5 {
print("index = \(index)")
}
*/
Result looks in Rendered Markup like this (the spaces appear in the code block):
Edit after comment:
The only way I found out, so that your first two lines of Markup are also inside of the example and also to simulate spaces is to use this code (in the line of the print, first two backquotes and between them one space, then after that eight spaces until the opening backquote of the print):
/*:
- example: *A simple `for` loop.*\
This example shows a `for` loop that prints the numbers 1 to 5.\
\
`for index in 1...5 {`\
` ` `print("index = \(index)")`\
`}`}
*/
This results to:
Related
I have two questions for vscode snippets+regex;
I have a pathname like some-component and I need to generate an output like SomeComponent using vscode snippet.
I need to input sendData and return an string like const sendData = createMessage(SEND_DATA);
How can I do this using regex on vscode snippet?
"${TM_DIRECTORY/(.*)/${1:/pascalcase}/g}" you didn't really provide enough info on how you are getting your pathName, so this is just one possibility, perhaps RELATIVE_FILEPATH` works for you.
"$1 = createMessage(${1/(([^A-Z]+)(\\w*))/${2:/upcase}_${3:/upcase}/});"
split the input sendData into 2 capture groups $2 and $3. Upcase them both in the transform.
"sendData": {
"prefix": "cm",
"body": [
"${TM_DIRECTORY/(.*)/${1:/pascalcase}/}",
// simpler form if ONLY two "words" like "sendData"
"$1 = createMessage(${1/(([^A-Z]+)(\\w*))/${2:/upcase}_${3:/upcase}/});",
// for any number of words, like "sendDataTwoThreeFour" use this:
"$1 = createMessage(${1/([a-z]*)([A-Z][a-z]*)/${1:/upcase}${2:+_}${2:/upcase}/g});"
]
}
${1/([a-z]*)([A-Z][a-z]*)/${1:/upcase}${2:+_}${2:/upcase}/g} get the first word "send" into capture group 1 and the other words like "Data" or "Two", etc. into subsequent matches' capture group 2. [So the g flag at the end is very important.]
Upcase group1. Then if there is a group 2 ${2:+_} add _. Then upcase group2.
The only case this will not work on is send with nothing else. It still prints out the all the text just doesn't upcase send if it is by itself. There is probably a way to include that...
Edit: And here it is:
"$1 = createMessage(${1/([a-z]*)([A-Z][a-z]*)|([a-z]+)/${1:/upcase}${3:/upcase}${2:+_}${2:/upcase}/g});"
now a bare send will be put into group 3 and upcased. For the rest of the matches there will not be a group 3 so ${3:/upcase} returns nothing.
I'm using AutoHotkey for this as the code is the most understandable to me. So I have a document with numbers and text, for example like this
120344 text text text
234000 text text
and the desired output is
12:03:44 text text text
23:40:00 text text
I'm sure StrReplace can be used to insert the colons in, but I'm not sure how to specify the position of the colons or ask AHK to 'find' specific strings of 6 digit numbers. Before, I would have highlighted the text I want to apply StrReplace to and then press a hotkey, but I was wondering if there is a more efficient way to do this that doesn't need my interaction. Even just pointing to the relevant functions I would need to look into to do this would be helpful! Thanks so much, I'm still very new to programming.
hfontanez's answer was very helpful in figuring out that for this problem, I had to use a loop and substring function. I'm sure there are much less messy ways to write this code, but this is the final version of what worked for my purposes:
Loop, read, C:\[location of input file]
{
{ If A_LoopReadLine = ;
Continue ; this part is to ignore the blank lines in the file
}
{
one := A_LoopReadLine
x := SubStr(one, 1, 2)
y := SubStr(one, 3, 2)
z := SubStr(one, 5)
two := x . ":" . y . ":" . z
FileAppend, %two%`r`n, C:\[location of output file]
}
}
return
Assuming that the "timestamp" component is always 6 characters long and always at the beginning of the string, this solution should work just fine.
String test = "012345 test test test";
test = test.substring(0, 2) + ":" + test.substring(2, 4) + ":" + test.substring(4, test.length());
This outputs 01:23:45 test test test
Why? Because you are temporarily creating a String object that it's two characters long and then you insert the colon before taking the next pair. Lastly, you append the rest of the String and assign it to whichever String variable you want. Remember, the substring method doesn't modify the String object you are calling the method on. This method returns a "new" String object. Therefore, the variable test is unmodified until the assignment operation kicks in at the end.
Alternatively, you can use a StringBuilder and append each component like this:
StringBuilder sbuff = new StringBuilder();
sbuff.append(test.substring(0,2));
sbuff.append(":");
sbuff.append(test.substring(2,4));
sbuff.append(":");
sbuff.append(test.substring(4,test.length()));
test = sbuff.toString();
You could also use a "fancy" loop to do this, but I think for something this simple, looping is just overkill. Oh, I almost forgot, this should work with both of your test strings because after the last colon insert, the code takes the substring from index position 4 all the way to the end of the string indiscriminately.
How can I make a VSCode extension folding strategy based on the first blank line following a starting folding marker?
## Some section --|
Any text... | (this should fold)
...more text. --|
(blank line)
## Another section (next fold...)
I've tried lots of regex in the language-configuration.json.
"folding": {
"markers": {
"start": "^##",
"end": "^\\s*$"
} },
If I change things to test with something other than a blank (or whitespace) line as the end delimiter it works. Can't use the next start marker to mark the end of the last or it includes it in the fold (I tried look ahead regex, but I think the regex are applied line by line and the matches can't span lines?)
It's similar to the folding needed for Markdown which VSCode handles well (don't know if that's using a more complex method like https://code.visualstudio.com/api/references/vscode-api#FoldingRangeProvider).
Maybe something in the fixes for [folding] should not fold white space after function has something to do with it.
What I learned: 1. the begin and end regex are applied line by line. 2. tmLanguage start/end regex will work on blank lines, but currently language-configuration folding doesn't seem to work on blank lines.
And since blank lines are in this case a hack for ending at the next begin section:
To solve the problem of folding a section to the next similar section I used the FoldingRangeProvider.
disposable = vscode.languages.registerFoldingRangeProvider('myExt', {
provideFoldingRanges(document, context, token) {
//console.log('folding range invoked'); // comes here on every character edit
let sectionStart = 0, FR = [], re = /^## /; // regex to detect start of region
for (let i = 0; i < document.lineCount; i++) {
if (re.test(document.lineAt(i).text)) {
if (sectionStart > 0) {
FR.push(new vscode.FoldingRange(sectionStart, i - 1, vscode.FoldingRangeKind.Region));
}
sectionStart = i;
}
}
if (sectionStart > 0) { FR.push(new vscode.FoldingRange(sectionStart, document.lineCount - 1, vscode.FoldingRangeKind.Region)); }
return FR;
}
});
Set "editor.foldingStrategy": "auto". You can make it more sophisticated to preserve white space between sections.
I want to strip a string of all new lines and commas (and place it into an array), so I created this:
let results = text.componentsSeparatedByCharactersInSet(NSCharacterSet(charactersInString: ",\n"))
However, the newlines are still existing in my array (the commas are being removed). What's the correct way of adding newline to the NSCharacterSet? Or, how to add comma to NSCharacterSet.newLineCharacterSet.
Thanks.
Here is janky solution, but still looking for a more elegant one.
var results = text.componentsSeparatedByCharactersInSet(NSCharacterSet(charactersInString: ","))
text = results.joinWithSeparator(" ")
results = text.componentsSeparatedByCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet())
(one-line) SOLUTION:
var results = text.componentsSeparatedByCharactersInSet(NSCharacterSet(charactersInString: " ,\u{000A}\u{000B}\u{000C}\u{000D}\u{0085}"))
Explanation is below.
You can unite two NSCharacterSet by first using an NSMutableCharacterSet, for example:
let charset = NSMutableCharacterSet(charactersInString: ",")
charset.formUnionWithCharacterSet(NSCharacterSet.newlineCharacterSet())
let results = text.componentsSeparatedByCharactersInSet(charset)
So MartinR brought to my attention that there are more line feeds than just "\n".
I looked at the values used in NSCharacterSet.newlineCharacterSet and added them all, giving me:
var results = text.componentsSeparatedByCharactersInSet(NSCharacterSet(charactersInString: " ,\u{000A}\u{000B}\u{000C}\u{000D}\u{0085}"))
This got rid of all the whitespace, commas, and new lines. Interestingly - when I used all the newline values separately to see if I could figure out which newline was being used in my case, none of them worked. But when used all together, it strips my new lines.
I have a bunch of classes that I am iterating through and collecting which classes the student is failing in. If the student fails , I collect the name of the class in a vector called retake.
retake =[Math History Science]
I have line breaks so when the classes print in the command window it shows as:
retake=
Math
History
Science.
However, I am trying display retake in a static text box in Gui Guide so it looks like the above. Instead, the static text box is showing as:
MathHistoryScience
set(handles.text13,'String', retake) % this is what I tried
can you please show me so it prints:
Math
History
Science
It looks to me like you need to add carriage returns.
Assuming you have a cell array with strings (rather than concatenated strings using [], which will give you a single long line), you can do it as follows:
retake = {'Math', 'History', 'Science'};
rString = '';
for ii = 1:numel(retake)-1
rString = [rString sprintf('%s\n', retake{ii}];
end
rString = [rString retake{end}];
Notice the use of '' to denote strings, {} to denote a cell array, '\n' as the end-of-line character, and [a b] to do simple string concatenation.