String can't find the value in a same line - perl

use strict;
use warnings;
my $str = "This is the test and new paragraph...\n";
if($str=~m/paragraph/gi) # First Loop
{
if($str=~m/test/gi) # Second Loop
{
print "Ok...\n";
}
else
{
print "Not Ok...\n";
}
}
if($str=~m/test/i) #it doesn't prints the value
Output is: Not Ok...
if($str=~m/test/gi) #it prints the value
Output is: Ok...
In above case if the string found the paragraph value and the second loop couldn't find the test value. However in the second loop if we inserted the global g it can.
Could you please someone can explain me whats happening. Thanks in advance.

/g is used for finding all matches of a pattern. It doesn't make sense to alter the pattern between matches. Generally speaking, if (/.../g) makes no sense and should be replaced with if (/.../).
There are advanced uses for if (/\G.../gc), but that's different. if (/.../g) only makes sense if you're unrolling a while loop. (e.g. while (1) { ...; last if !/.../g; ... }).
Here's what's happening in this specific circumstance:
Because you signaled you wanted to find all matches (by using /g), the position at which to start matching is set to the end of the match (denoted by ^ below).
This is the test and new paragraph...
---------^
You can see this using pos.
$ perl -e'
my $str = "This is the test and new paragraph...";
if ($str =~ /paragraph/g) {
CORE::say pos($str) // 0;
if ($str =~ /test/g) {
CORE::say pos($str) // 0;
}
}
'
34
The subsequent m/test/gi doesn't match because test does not appear at or after the position at which the last match ended.
The solution is to simply remove the g modifier from you match operators.
$ perl -e'
my $str = "This is the test and new paragraph...";
if ($str =~ /paragraph/) {
CORE::say pos($str) // 0;
if ($str =~ /test/) {
CORE::say pos($str) // 0;
}
}
'
0
0

From perldoc perlretut:
Global matching
The final two modifiers we will discuss here, //g and //c , concern multiple matches. The modifier //g stands for global matching and allows the matching operator to match within a string as many times as possible. In scalar context, successive invocations against a string will have //g jump from match to match, keeping track of position in the string as it goes along. You can get or set the position with the pos() function.
In the first test, you're using the global flag, then the position of cursor is memorized, so the second match doesn't find test because it is before paragraph.
You have to remove the global flag from the first match.
my $str = "This is the test and new paragraph...\n";
if ($str =~ /paragraph/i) {
if ($str =~ /test/i) {
print "Ok...\n";
} else {
print "Not Ok...\n";
}
}

Related

Best way to parse string in perl

To achieve below task I have written below C like perl program (As I am new to Perl), But I am not sure if this is the best way to achieve.
Can someone please guide?
Note: Not with the full program, But where I can make improvement.
Thanks in advance
Input :
$str = "mail1, local<mail1#mail.local>, mail2#mail.local, <mail3#mail.local>, mail4 local<mail4#mail.local>"
Expected Output :
mail1, local<mail1#mail.local>
mail2#mail.local
<mail3#mail.local>
mail4, local<mail4#mail.local>
Sample Program
my $str="mail1, \#local<mail1\#mail.local>, mail2\#mail.local, <mail3\#mail.local>, mail4, local<mail4\#mail.local>";
my $count=0, #array, $flag=0, $tempStr="";
for my $c (split (//,$str)) {
if( ($count eq 0) and ($c eq ' ') ) {
next;
}
if($c) {
if( ($c eq ',') and ($flag eq 1) ) {
push #array, $tempStr;
$count=0;
$flag1=0;
$tempStr="";
next;
}
if( ($c eq '>' ) or ( $c eq '#' ) ) {
$flag=1;
}
$tempStr="$tempStr$c";
$count++;
}
}
if($count>0) {
push #array, $tempStr;
}
foreach my $var (#array) {
print "$var\n";
}
Edit:
Input:
Input is the output of above code.
Expected Output :
"mail1, local"<mail1#mail.local>
"mail4, local"<mail4#mail.local>
Sample Code:
$str =~ s/([^#>]+[#>][^,]+),\s*/$1\n/g;
my #addresses = split('\n',$str);
if(scalar #addresses) {
foreach my $address (#addresses) {
if (($address =~ /</) and ($address !~ /\"/) and ($address !~ /^</)){
$address="\"$address";
$address=~ s/</\"</g;
}
}
$str = join(',',#addresses);
}
print "$str\n";
As I see, you want to replace each:
comma and following spaces,
occurring after either # or >,
with a newline.
To make such replacement, instead of writing a parsing program, you can use
a regex.
The search part can be as follows:
([^#>]+[#>][^,]+),\s*
Details:
( - Start of the 1st capturing group.
[^#>]+ - A non-empty sequence of chars other than # or >.
[#>] - Either # or >.
[^,]+ - A non-empty sequence of chars other than a comma.
) - End of the 1st capturing group.
,\s* - A comma and optional sequence of spaces.
The replace part should be:
$1 - The 1st capturing group.
\n - A newline.
So the whole program, much shorter than yours, can be as follows:
my $str='mail1, local<mail1#mail.local>, mail2#mail.local, <mail3#mail.local>, mail4, local<mail4#mail.local>';
print "Before:\n$str\n";
$str =~ s/([^#>]+[#>][^,]+),\s*/$1\n/g;
print "After:\n$str\n";
To replace all needed commas I used g option.
Note that I put the source string in single quotes, otherwise Perl
would have complained about Possible unintended interpolation of #mail.
Edit
Your modified requirements must be handled different way.
"Ordinary" replacement is not an option, because now there are some
fragments to match and some framents to ignore.
So the basic idea is to write a while loop with a matching regex:
(\w+),?\s+(\w+)(<[^>]+>), meaning:
(\w+) - First capturing group - a sequence of word chars (e.g. mail1).
,?\s+ - Optional comma and a sequence of spaces.
(\w+) - Second capturing group - a sequence of word chars (e.g. local).
(<[^>]+>) - Third capturing group - a sequence of chars other than >
(actual mail address), enclosed in angle brackets, e.g. <mail1#mail.local>.
Within each execution of the loop you have access to the groups
captured in this particular match ($1, $2, ...).
So the content of this loop is to print all these captured groups,
with required additional chars.
The code (again much shorter than yours) should look like below:
my $str = 'mail1, local<mail1#mail.local>, mail2#mail.local, <mail3#mail.local>, mail4 local<mail4#mail.local>';
while ($str =~ /(\w+),?\s+(\w+)(<[^>]+>)/g) {
print "\"$1, $2\"$3\n";
}
Here is an approach using split, which in this case also needs a careful regex
use warnings;
use strict;
use feature 'say';
my $string = # broken into two parts for readabililty
q(mail1, local<mail1#mail.local>, mail2#mail.local, )
. q(<mail3#mail.local>, mail4, local<mail4#mail.local>);
my #addresses = split /#.+?\K,\s*/, $string;
say for #addresses;
The split takes a full regex in its delimiter specification. In this case I figure that each record is delimited by a comma which comes after the email address, so #.+?,
To match a pattern only when it is preceded by another brings to mind a negative lookbehind before the comma. But those can't be of variable length, which is precisely the case here.
We can instead normally match the pattern #.+? and then use the \K form (of the lookbehind) which drops all previous matches so that they are not taken out of the string. Thus the above splits on ,\s* when that is preceded by the email address, #... (what isn't consumed).
It prints
mail1, local<mail1#mail.local>
mail2#mail.local
<mail3#mail.local>
mail4, local<mail4#mail.local>
The edit asks about quoting the description preceding <...> when it's there. A simple way is to make another pass once addresses have been parsed out of the string as above. For example
my #addresses = split /#.+?\K,\s*/, $string; #/ stop syntax highlight
s/(.+?,\s*.+?)</"$1"</ for #addresses;
say for #addresses;
The regex in a loop is one way to change elements of an array. I use it for its efficiency (changes elements in place), conciseness, and as a demonstration of the following properties.
In a foreach loop the index variable (or $_) is an alias for the currently processed element – so changing it changes that element. This is a known source of bugs when allowed unknowingly, which was another reason to show it in the above form.
The statement also uses the statement modifier and it is equivalent to
foreach my $elem (#addresses) {
$elem =~ s/(.+?,\s*.+?)</"$1"</;
}
This is often considered a more proper way to write it but I find that the other form emphasizes more clearly that elements are being changed, when that is the sole purpose of the foreach.

Does perl cache regex generation?

Suppose I have a function that dynamically generates regular expressions and then matches against them.
For example, in the following function match_here a \G anchor is inserted at the beginning of the regex. This simplifies the API because the caller does not need to remember to include the pos anchor in the pattern.
#!/usr/bin/env perl
use strict;
use warnings;
use Carp;
use Data::Dumper;
sub match_here {
my ($str, $index, $rg) = #_;
pos($str) = $index;
croak "index ($index) out of bounds" unless pos($str) == $index;
my $out;
if ($str =~ /\G$rg/) {
$out = $+[0];
}
return $out;
}
# no match starting at position 0
# prints '$VAR1 = undef;'
print Dumper(match_here("abc", 0, "b+"));
# match from 1 to 2
# prints '$VAR1 = 2;'
print Dumper(match_here("abc", 1, "b+"));
I'm wondering whether an anonymous regex object is "compiled" every time the function is evaluated or if there's some caching so that identical strings will not cause additional regex objects to be compiled.
Also, assuming that no caching is done by the Perl interpreter, is compiling a regex object expensive enough to be worth caching (possibly in an XS extension)?
From perlop(1), under the m// operator:
PATTERN may contain variables, which will be interpolated every time the pattern search is evaluated
[...]
Perl will not recompile the pattern unless an interpolated variable that it contains changes. You can force Perl to skip the test and never recompile by adding a "/o" (which stands for "once") after the trailing delimiter. Once upon a time, Perl would recompile regular expressions unnecessarily, and this modifier was useful to tell it not to do so, in the interests of speed.
So yes, there is a cache, and you can even force the use of the cache even when it's invalid by saying /o, but you really shouldn't do that.
But that cache only stores one compiled regexp per instance of the m// or s/// operator, so it only helps if the regexp is used with the same variables (e.g. your $rg) many times consecutively. If you alternate between calling it with $rg='b+' and $rg='c+' you will get a recompile every time.
For that kind of situation, you can do your own caching with the qr// operator. It explicitly compiles the regexp and returns an object that you can store and use to execute the regexp later. That could be incorporated into your match_here like this:
use feature 'state';
sub match_here {
my ($str, $index, $rg) = #_;
pos($str) = $index;
croak "index ($index) out of bounds" unless pos($str) == $index;
my $out;
state %rg_cache;
my $crg = $rg_cache{$rg} ||= qr/\G$rg/;
if ($str =~ /$crg/) {
$out = $+[0];
}
return $out;
}
To add more detail on the basic cache (when not using qr//): the fact that $rg is a newly allocated lexical variable each time makes no difference. It only matters that the value is the same as the previous one.
Here's an example to prove the point:
use re qw(Debug COMPILE);
while(<>) {
chomp;
# Insane interpolation. Do not use anything remotely like this in real code
print "MATCHED: $_\n" if /^${\(`cat refile`)}/;
}
Every time the match operator executes, it reads refile. The regular expression is ^ followed by the contents of refile. The debugging output shows that it is recompiled only if the contents of the file have changed. If the file still has the same contents as the last time, the operator notices that the same string is being passed to the regexp compiler again, and reuses the cached result.
Or try this less dramatic example:
use re qw(Debug COMPILE);
#patterns = (
'\d{3}',
'\d{3}',
'[aeiou]',
'[aeiou]',
'\d{3}',
'\d{3}'
);
for ('xyz', '123', 'other') {
for $i (0..$#patterns) {
if(/$patterns[$i]/) {
print "$_ matches $patterns[$i]\n";
} else {
print "$_ does not match $patterns[$i]\n";
}
}
}
in which there are 18 compilations and 11 of them are cache hits, even though the same "variable" (the same element of the #patterns array) is never used twice in a row.

Regular expression to print a string from a command outpout

I have written a function that uses regex and prints the required string from a command output.
The script works as expected. But it's does not support a dynamic output. currently, I use regex for "icmp" and "ok" and print the values. Now, type , destination and return code could change. There is a high chance that command doesn't return an output at all. How do I handle such scenarios ?
sub check_summary{
my ($self) = #_;
my $type = 0;
my $return_type = 0;
my $ipsla = $self->{'ssh_obj'}->exec('show ip sla');
foreach my $line( $ipsla) {
if ( $line =~ m/(icmp)/ ) {
$type = $1;
}
if ( $line =~ m/(OK)/ ) {
$return_type = $1;
}
}
INFO ($type,$return_type);
}
command Ouptut :
PSLAs Latest Operation Summary
Codes: * active, ^ inactive, ~ pending
ID Type Destination Stats Return Last
(ms) Code Run
-----------------------------------------------------------------------
*1 icmp 192.168.25.14 RTT=1 OK 1 second ago
Updated to some clarifications -- we need only the last line
As if often the case, you don't need a regex to parse the output as shown. You have space-separated fields and can just split the line and pick the elements you need.
We are told that the line of interest is the last line of the command output. Then we don't need the loop but can take the last element of the array with lines. It is still unclear how $ipsla contains the output -- as a multi-line string or perhaps as an arrayref. Since it is output of a command I'll treat it as a multi-line string, akin to what qx returns. Then, instead of the foreach loop
my #lines = split '\n', $ipsla; # if $ipsla is a multi-line string
# my #lines = #$ipsla; # if $ipsla is an arrayref
pop #lines while $line[-1] !~ /\S/; # remove possible empty lines at end
my ($type, $return_type) = (split ' ', $lines[-1])[1,4];
Here are some comments on the code. Let me know if more is needed.
We can see in the shown output that the fields up to what we need have no spaces. So we can split the last line on white space, by split ' ', $lines[-1], and take the 2nd and 5th element (indices 1 and 4), by ( ... )[1,4]. These are our two needed values and we assign them.
Just in case the output ends with empty lines we first remove them, by doing pop #lines as long as the last line has no non-space characters, while $lines[-1] !~ /\S/. That is the same as
while ( $lines[-1] !~ /\S/ ) { pop #lines }
Original version, edited for clarifications. It is also a valid way to do what is needed.
I assume that data starts after the line with only dashes. Set a flag once that line is reached, process the line(s) if the flag is set. Given the rest of your code, the loop
my $data_start;
foreach (#lines)
{
if (not $data_start) {
$data_start = 1 if /^\s* -+ \s*$/x; # only dashes and optional spaces
}
else {
my ($type, $return_type) = (split)[1,4];
print "type: $type, return code: $return_type\n";
}
}
This is a sketch until clarifications come. It also assumes that there are more lines than one.
I'm not sure of all possibilities of output from that command so my regular expression may need tweaking.
I assume the goal is to get the values of all columns in variables. I opted to store values in a hash using the column names as the hash keys. I printed the results for debugging / demonstration purposes.
use strict;
use warnings;
sub check_summary {
my ($self) = #_;
my %results = map { ($_,undef) } qw(Code ID Type Destination Stats Return_Code Last_Run); # Put results in hash, use column names for keys, set values to undef.
my $ipsla = $self->{ssh_obj}->exec('show ip sla');
foreach my $line (#$ipsla) {
chomp $line; # Remove newlines from last field
if($line =~ /^([*^~])([0-9]+)\s+([a-z]+)\s+([0-9]+\.[0-9]+\.[0-9]+\.[0-9]+)\s+([[:alnum:]=]+)\s+([A-Z]+)\s+([^\s].*)$/) {
$results{Code} = $1; # Code prefixing ID
$results{ID} = $2;
$results{Type} = $3;
$results{Destination} = $4;
$results{Stats} = $5;
$results{Return_Code} = $6;
$results{Last_Run} = $7;
}
}
# Testing
use Data::Dumper;
print Dumper(\%results);
}
# Demonstrate
check_summary();
# Commented for testing
#INFO ($type,$return_type);
Worked on the submitted test line.
EDIT:
Regular expressions allow you to specify patterns instead of the exact text you are attempting to match. This is powerful but complicated at times. You need to read the Perl Regular Expression documentation to really learn them.
Perl regular expressions also allow you to capture the matched text. This can be done multiple times in a single pattern which is how we were able to capture all the columns with one expression. The matches go into numbered variables...
$1
$2

How can i detect symbols using regular expression in perl?

Please how can i use regular expression to check if word starts or ends with a symbol character, also how to can i process the text within the symbol.
Example:
(text) or te-xt, or tex't. or text?
change it to
(<t>text</t>) or <t>te-xt</t>, or <t>tex't</t>. or <t>text</t>?
help me out?
Thanks
I assume that "word" means alphanumeric characters from your example? If you have a list of permitted characters which constitute a valid word, then this is enough:
my $string = "x1 .text1; 'text2 \"text3;\"";
$string =~ s/([a-zA-Z0-9]+)/<t>$1<\/t>/g;
# Add more to character class [a-zA-Z0-9] if needed
print "$string\n";
# OUTPUT: <t>x1</t> .<t>text1</t>; '<t>text2</t> "<t>text3</t>;"
UPDATE
Based on your example you seem to want to DELETE dashes and apostrophes, if you want to delete them globally (e.g. whether they are inside the word or not), before the first regex, you do
$string =~ s/['-]//g;
I am using DVK's approach here, but with a slight modification. The difference is that her/his code would also put the tags around all words that don't contain/are next to a symbol, which (according to the example given in the question) is not desired.
#!/usr/bin/perl
use strict;
use warnings;
sub modify {
my $input = shift;
my $text_char = 'a-zA-Z0-9\-\''; # characters that are considered text
# if there is no symbol, don't change anything
if ($input =~ /^[a-zA-Z0-9]+$/) {
return $input;
}
else {
$input =~ s/([$text_char]+)/<t>$1<\/t>/g;
return $input;
}
}
my $initial_string = "(text) or te-xt, or tex't. or text?";
my $expected_string = "(<t>text</t>) or <t>te-xt</t>, or <t>tex't</t>. or <t>text</t>?";
# version BEFORE edit 1:
#my #aux;
# take the initial string apart and process it one word at a time
#my #string_list = split/\s+/, $initial_string;
#
#foreach my $string (#string_list) {
# $string = modify($string);
# push #aux, $string;
#}
#
# put the string together again
#my $final_string = join(' ', #aux);
# ************ EDIT 1 version ************
my $final_string = join ' ', map { modify($_) } split/\s+/, $initial_string;
if ($final_string eq $expected_string) {
print "it worked\n";
}
This strikes me as a somewhat long-winded way of doing it, but it seemed quicker than drawing up a more sophisticated regex...
EDIT 1: I have incorporated the changes suggested by DVK (using map instead of foreach). Now the syntax highlighting is looking even worse than before; I hope it doesn't obscure anything...
This takes standard input and processes it to and prints on Standard output.
while (<>) {
s {
( [a-zA-z]+ ) # word
(?= [,.)?] ) # a symbol
}
{<t>$1</t>}gx ;
print ;
}
You might need to change the bit to match the concept of word.
I have use the x modifeid to allow the regexx to be spaced over more than one line.
If the input is in a Perl variable, try
$string =~ s{
( [a-zA-z]+ ) # word
(?= [,.)?] ) # a symbol
}
{<t>$1</t>}gx ;

perl split on empty file

I have basically the following perl I'm working with:
open I,$coupon_file or die "Error: File $coupon_file will not Open: $! \n";
while (<I>) {
$lctr++;
chomp;
my #line = split/,/;
if (!#line) {
print E "Error: $coupon_file is empty!\n\n";
$processFile = 0; last;
}
}
I'm having trouble determining what the split/,/ function is returning if an empty file is given to it. The code block if (!#line) is never being executed. If I change that to be
if (#line)
than the code block is executed. I've read information on the perl split function over at
http://perldoc.perl.org/functions/split.html and the discussion here about testing for an empty array but not sure what is going on here.
I am new to Perl so am probably missing something straightforward here.
If the file is empty, the while loop body will not run at all.
Evaluating an array in scalar context returns the number of elements in the array.
split /,/ always returns a 1+ elements list if $_ is defined.
You might try some debugging:
...
chomp;
use Data::Dumper;
$Data::Dumper::Useqq = 1;
print Dumper( { "line is" => $_ } );
my #line = split/,/;
print Dumper( { "split into" => \#line } );
if (!#line) {
...
Below are a few tips to make your code more idiomatic:
The special variable $. already holds the current line number, so you can likely get rid of $lctr.
Are empty lines really errors, or can you ignore them?
Pull apart the list returned from split and give the pieces names.
Let Perl do the opening with the "diamond operator":
The null filehandle <> is special: it can be used to emulate the behavior of sed and awk. Input from <> comes either from standard input, or from each file listed on the command line. Here's how it works: the first time <> is evaluated, the #ARGV array is checked, and if it is empty, $ARGV[0] is set to "-", which when opened gives you standard input. The #ARGV array is then processed as a list of filenames. The loop
while (<>) {
... # code for each line
}
is equivalent to the following Perl-like pseudo code:
unshift(#ARGV, '-') unless #ARGV;
while ($ARGV = shift) {
open(ARGV, $ARGV);
while (<ARGV>) {
... # code for each line
}
}
except that it isn't so cumbersome to say, and will actually work.
Say your input is in a file named input and contains
Campbell's soup,0.50
Mac & Cheese,0.25
Then with
#! /usr/bin/perl
use warnings;
use strict;
die "Usage: $0 coupon-file\n" unless #ARGV == 1;
while (<>) {
chomp;
my($product,$discount) = split /,/;
next unless defined $product && defined $discount;
print "$product => $discount\n";
}
that we run as below on Unix:
$ ./coupons input
Campbell's soup => 0.50
Mac & Cheese => 0.25
Empty file or empty line? Regardless, try this test instead of !#line.
if (scalar(#line) == 0) {
...
}
The scalar method returns the array's length in perl.
Some clarification:
if (#line) {
}
Is the same as:
if (scalar(#line)) {
}
In a scalar context, arrays (#line) return the length of the array. So scalar(#line) forces #line to evaluate in a scalar context and returns the length of the array.
I'm not sure whether you're trying to detect if the line is empty (which your code is trying to) or whether the whole file is empty (which is what the error says).
If the line, please fix your error text and the logic should be like the other posters said (or you can put if ($line =~ /^\s*$/) as your if).
If the file, you simply need to test if (!$lctr) {} after the end of your loop - as noted in another answer, the loop will not be entered if there's no lines in the file.