I have a question about sed.
Output:
Filesystem avail
rpool/ROOT/s10_u11_201704 244719726
Wanted information:
s10_u11_201704
I tried:
df -b / | sed '1d;s/.*\/\(*\ \)\ .*/\1/g'
The \(*\ \) does not work.
using awk :
df -b / |awk -F'/' 'NR>1{split($NF,a," ");print a[1]}'
s10_u11_201704
Using sed:
df -b / |sed -r '1d;s|(^.*)/([^ ]+).*|\2|g'
s10_u11_201704
Disclaimer: df -b is not available in any of available distros to me.
Short awk approach:
df --output=source | awk -F'/' '{print $NF}'
--output=source (--output[=FIELD_LIST]) - use the output format defined by FIELD_LIST
-F'/' - treating / as field separator
$NF - the last field value
Related
I have lines that start like this: 2141058222 11/22/2017 and I want to append a ; at the end of the ten digit number like this: 2141058222; 11/22/2017.
I've tried sed with sed -i 's/^[0-9]\{10\}\\$/;&/g' which does nothing.
What am I missing?
Try this:
echo "2141058222 11/22/2017" | sed -r 's/^([0-9]{10})/&;/'
echo "2141058222 11/22/2017" | sed 's/ /; /'
Output:
2141058222; 11/22/2017
If the input is always in the format specified, GNU cut works, and might even be more efficient than sed:
cut -c -10,11- --output-delimiter ';' <<< "2141058222 11/22/2017"
Output:
2141058222; 11/22/2017
For an input file that'd be:
cut -c -10,11- --output-delimiter ';' file
I'm trying to extract data/urls (in this case - someurl) from a file that contains them within some tag ie.
xyz>someurl>xyz
I don't mind using either awk or sed.
I think the best, easiest, way is with cut:
$ echo "xyz>someurl>xyz" | cut -d'>' -f2
someurl
With awk can be done like:
$ echo "xyz>someurl>xyz" | awk 'BEGIN { FS = ">" } ; { print $2 }'
someurl
And with sed is a little bit more tricky:
$ echo "xyz>someurl>xyz" | sed 's/\(.*\)>\(.*\)>\(.*\)/\2/g'
someurl
we get blocks of something1<something2<something3 and print the 2nd one.
grep was born to extract things:
kent$ echo "xyz>someurl>xyz"|grep -Po '>\K[^>]*(?=>)'
someurl
you could kill a fly with a bomb of course:
kent$ echo "xyz>someurl>xyz"|awk -F\> '$0=$2'
someurl
If your grep supports P option then you can use lookahead and lookbehind regular expression to identify the url.
$ echo "xyz>someurl>xyz" | grep -oP '(?<=xyz>).*(?=>xyz)'
someurl
This is just a sample to get you started not the final answer.
I have a file which looks like below:
memory=500G
brand=HP
color=black
battery=5 hours
For every line, I want to remove everything after = and also the =.
Eventually, I want to get something like:
memory:brand:color:battery:
(All on one line with colons after every word)
Is there a one-line sed command that I can use?
sed -e ':a;N;$!ba;s/=.\+\n\?/:/mg' /my/file
Adapted from this fine answer.
To be frank, however, I'd find something like this more readable:
cut -d = -f 1 /my/file | tr \\n :
Here's one way using GNU awk:
awk -F= '{ printf "%s:", $1 } END { printf "\n" }' file.txt
Result:
memory:brand:color:battery:
If you don't want a colon after the last word, you can use GNU sed like this:
sed -n 's/=.*//; H; $ { g; s/\n//; s/\n/:/g; p }' file.txt
Result:
memory:brand:color:battery
This might work for you (GNU sed):
sed -i ':a;$!N;s/=[^\n]*\n\?/:/;ta' file
perl -F= -ane '{print $F[0].":"}' your_file
tested below:
> cat temp
abc=def,100,200,dasdas
dasd=dsfsf,2312,123,
adasa=sdffs,1312,1231212,adsdasdasd
qeweqw=das,13123,13,asdadasds
dsadsaa=asdd,12312,123
> perl -F= -ane '{print $F[0].":"}' temp
abc:dasd:adasa:qeweqw:dsadsaa:
My command is
First step:
sed 's/([a-z]+)(\=.*)/\1:/g' Filename |cat >a
cat a
memory:
brand:
color:
battery:
Second step:
sed -e 'N;s/\n//' a | sed -e 'N;s/\n//'
My output is
memory:brand:color:battery:
The sed below will output the input exactly. What I'd like to do is replace all occurrences of _ with - in the first matching group (\1), but not in the second. Is this possible?
echo 'abc_foo_bar=one_two_three' | sed 's/\([^=]*\)\(=.*\)/\1\2/'
abc_foo_bar=one_two_three
So, the output I'm hoping for is:
abc-foo-bar=one_two_three
I'd prefer not to resort to awk since I'm doing a string of other sed commands too, but I'll resort to that if I have to.
Edit: Minor fix to RE
You can do this in sed using the hold space:
$ echo 'abc_foo_bar=one_two_three' | sed 'h; s/[^=]*//; x; s/=.*//; s/_/-/g; G; s/\n//g'
abc-foo-bar=one_two_three
You could use awk instead of sed as follows:
echo 'abc_foo_bar=one_two_three' | awk -F= -vOFS== '{gsub("_", "-", $1); print $1, $2}'
The output would be, as expected:
abc-foo-bar=one_two_three
You could use ghc instead of sed as follows:
echo "abc_foo_bar=one_two_three" | ghc -e "getLine >>= putStrLn . uncurry (++) . (map (\x -> if x == '_' then '-' else x) *** id) . break (== '=')"
The output would be, as expected:
abc-foo-bar=one_two_three
This might work for you:
echo 'abc_foo_bar=one_two_three' |
sed 's/^/\n/;:a;s/\n\([^_=]*\)_/\1-\n/;ta;s/\n//'
abc-foo-bar=one_two_three
Or this:
echo 'abc_foo_bar=one_two_three' |
sed 'h;s/=.*//;y/_/-/;G;s/\n.*=/=/'
abc-foo-bar=one_two_three
I have a file called data.txt.
I want to add the current date, or time, or both to the beginning or end of each line.
I have tried this:
awk -v v1=$var ' { printf("%s,%s\n", $0, v1) } ' data.txt > data.txt
I have tried this:
sed "s/$/,$var/" data.txt
Nothing works.
Can someone help me out here?
How about :
cat filename | sed "s/$/ `date`/"
The problem with this
awk -v v1=$var ' { printf("%s,%s\n", $0, v1) } ' data.txt > data.txt
is that the > redirection happens first, and the shell truncates the file. Only then does the shell exec awk, which then reads an empty file.
Choose one of these:
sed -i "s/\$/ $var/" data.txt
awk -v "date=$var" '{print $0, date}' data.txt > tmpfile && mv tmpfile data.txt
However, does your $var contain slashes (such as "10/04/2011 12:34") ? If yes, then choose a different delimiter for sed's s/// command: sed -i "s#\$# $var#" data.txt