I try to use sed with special character:
sed -i -e "1i$jtempo" $file
$file is my file.
$jtempo is my variable with special character like: " or [ or (
But, when I run this script, I have this error:
sed: -e expression #1, char 17: unknown command: `"'
My file:
"desc_test":[
"id",
"name",
],
In my script bash:
jtempo=`cat myfile`
An idea ?
Thanks you !
$ cat f1
"desc_test":[
"id",
"name",
],
$ cat ip.txt
1
2
3
I would suggest to avoid i command and use r command which will be robust regardless of file content
$ # to insert before first line
$ cat f1 ip.txt
"desc_test":[
"id",
"name",
],
1
2
3
$ # to insert any other line number, use line_num-1
$ # for example, to insert before 2nd line, use 1r
$ # r command will read entire contents from a file
$ sed '1r f1' ip.txt
1
"desc_test":[
"id",
"name",
],
2
3
Related
I am trying to insert a new row on 2nd line of text file using perl . But it keeps failing.
I am using below command to achieve the same.
perl -ni -e "print; print \"permissibleCars = [ ${part[*]} ]\n\" if $. == 2" query/containerId_count.js
But I keep getting error :--
root#vm-test-001:~/mongosearch# distinct_array=`sed ':a;N;$!ba;s/\n/ /g' output/ontainerId_distinct.txt`
root#vm-test-001:~/mongosearch# declare -a arr=($distinct_array)
root#vm-test-001:~/mongosearch# batchsize=1
root#vm-test-001:~/mongosearch# IFS=,
root#vm-test-001:~/mongosearch# part=( "${arr[#]:i:batchsize}" )
root#vm-test-001:~/mongosearch# echo $part
"C:00000092666270:53882159774"
root#vm-test-001:~/mongosearch# perl -ni -e "print; print \"permissibleCars = [ ${part[*]} ]\n\" if $. == 2" query/containerId_count.js
Bareword found where operator expected at -e line 1, near ""permissibleCars = [ "C"
(Missing operator before C?)
String found where operator expected at -e line 1, near "53882159774" ]\n""
(Missing operator before " ]\n"?)
syntax error at -e line 1, near ""permissibleCars = [ "C"
Illegal octal digit '9' at -e line 1, at end of line
Execution of -e aborted due to compilation errors.
Can you help me with same ?
Regards
Try this:
export PARTS=${part[*]}
perl -lni -e 'print; print "permissibleCars = [".join(",",split/ /,$ENV{PARTS})."]" if $. == 2' query/containerId_count.js
And
In linux platform we should use single quote for one liner. From Perl black book see page number 19 and 20.
I am trying to use sed script to remove the content of an array in a file. I have tried to delete the content to only leave the brackets (). However I can't get the sed script to work over multiple lines.
I am trying to change the current state of the file:
LIST = ( "content"
"content1"
"content3")
to this:
LIST = ()
However the sed script I am using only changes the file to this:
LIST = ()
"content"
"content1"
"content2"
sed -e 's/LIST=\([^)]*\)/LIST=() /g' filename
I should also mention there are other sets of brackets in the file which I don't want affected.
e.g
LISTNUMBER2("CONTENT")
should not be emptied.
this sed one-liner works for your example:
sed -n '1!H;1h;${x;s/(.*)/()/;p}'
test:
kent$ echo 'LIST = ( "content"
"content1"
"content3")'|sed -n '1!H;1h;${x;s/(.*)/()/;p}'
LIST = ()
if you could use awk, this one-liner works for your example too:
awk -v RS="" '{sub(/\(.*\)/,"()")}1'
test:
kent$ echo 'LIST = ( "content"
"content1"
"content3")'|awk -v RS="" '{sub(/\(.*\)/,"()")}1'
LIST = ()
EDIT for OP's comment
multi brackets situation:
awk
awk -v RS="\0" -v ORS="" '{gsub(/LIST\s*=\s*\([^)]*\)/,"LIST = ()")}1' file
test:
kent$ cat file
LISTKEEP2("CONTENT")
LIST = ( "content"
"content1"
"content3")
LISTNUMBER2("CONTENT")
kent$ awk -v RS="\0" -v ORS="" '{gsub(/LIST\s*=\s*\([^)]*\)/,"LIST = ()")}1' file
LISTKEEP2("CONTENT")
LIST = ()
LISTNUMBER2("CONTENT")
sed:
sed -nr '1!H;1h;${x;s/(LIST\s*=\s*\()[^)]*\)/\1)/;p}' file
kent$ sed -nr '1!H;1h;${x;s/(LIST\s*=\s*\()[^)]*\)/\1)/;p}' file
LISTKEEP2("CONTENT")
LIST = ()
LISTNUMBER2("CONTENT")
Another sed solution:
sed '/LIST = (/{:next;/)/{s/(.*)/()/;b;};N;b next;}'
Here's a version that would not change any block containing a certain string ("keepme" in this example, but could be anything):
sed '/LIST = (/{:next;/)/{/keepme/b;s/(.*)/()/;b;};N;b next;}'
Since this does the keepme test after it finds the closing parenthesis that tag can be anywhere in the block.
Is it possible to encapsulate the following pseudocode using sed?
for line in lines:
if line == "foo":
print "FOO"
else:
print "- " + line
Here's the first thing I tried:
> echo 'foo
> bar
> baz' | sed -e 's/^foo$/FOO/' -e 's/^/- /'
- FOO
- bar
- baz
This is incorrect since both substitutions are applied to the first line.
Is it possible to tell sed to perform a maximum of one substitution per line?
You can limit what lines a substitution affects, by prefixing it with a pattern:
sed -e '/^foo$/! s/^/- /' -e '/^foo$/ s//FOO/' infile
A better alternative is to use the t branch command which will go to the next line if the previous substitution succeeded:
sed 's/^foo$/FOO/; t; s/^/- /' infile
Or the more portable:
sed -e 's/^foo$/FOO/' -e t -e 's/^/- /' infile
Output in both cases:
FOO
- bar
- baz
I want to print next line of matching word with sed.
I tried this command but it gives error :
sed -n '/<!\[CDATA\[\]\]>/ { N p}/' test.xml
what about grep -e -A 1 regex? It will print line below regex.
With sed, looking for pattern "dd", below works fine as you would:
sed -n '/dd/ {n;p}' file
For file content:
dd
aa
ss
aa
It prints:
aa
use awk
awk '/pattern/{getline;print}' file
I have the following example file
/etc/sysconfig/network/script.sh = -exe $Builder
run_installation 123 44 556 4 = run_installation arg1 arg2 arg3 948
EXE=somthing
EXE somthing
I have three questions (I write bash script)
how to verify by sed or awk if the string "-exe" exist after "=" character
how to verify by sed or awk if the string run_installation exist in the first of the line (the first word in the line) and after the "=" character as example below (file)
the string EXE in file can be "EXE" or as "EXE=" , how to delete by sed the EXE or EXE=
I do:
sed s'/EXE//g' | sed s'/EXE=//g'
but its not nice way to do in my bash script
• I need three different answers!
Lidia
you did not give further criteria on what to do if conditions 1 and 2 are not found...
awk '/=.*-exe/{f=1;}
/^run_installation.*=.*run_installation/{g=1}
/^EXE/{ gsub(/EXE=|EXE/,"") }
f && g{ print "ok" ;exit }
' file
The above code checks for condition 1 and condition 2 and print "ok" when both are found. The substitution of EXE for condition 3 is added for illustration purpose. State more clearly what you want to do and show your expected output next time
To verify them separately,
awk '/= -exe/{print "found"}' file
awk '/^run_installation.*=.*run_installation/{print "found"}' file